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Arithmetic calculation | How many times does the number 3 appear from 1 to 31? | 6 | 1 31 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 3 [OP_LIST_FIND_NUM] 1 [OP_ADD] | var_a = 1
var_b = 31
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d=""
for i in list_a:
i = str(i)
var_d = var_d + i
list_b = []
var_d = int(var_d)
while var_d//10 > 0:
list_b.append(var_d%10)
var_d = var_d//10
list_b.append(var_d%10)
list_b = list_b[::-1]
var_e = 3
var_f = 0
var_e = int(var_e)
for i in list_b:
i = int(i)
if i == var_e:
var_f = var_f + 1
var_g = 1
var_h = var_f + var_g
print(int(var_h)) |
Geometry | What is the area in square centimeters (cm2) of a rectangle that can be formed by attaching 3.2 squares with sides of 8.5 centimeters (cm) in a row? | 231.2 | 8.5 2 [OP_POW] 3.2 [OP_MUL] | var_a = 8.5
var_b = 2
var_c = var_a ** var_b
var_d = 3.2
var_e = var_c * var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Arithmetic calculation | 24 sheets of colored paper and 18 sheets of drawing paper will be distributed equally to as many students as possible. How many people can get the papers? | 6 | 24 18 [OP_GCD] | var_a = 24
var_b = 18
var_c = math.gcd(int(var_b), int(var_a))
print(int(var_c)) |
Comparison | In a line of 27 people, if Minyoung is standing in the13th from the back, where is she placed from the front? | 15 | 27 13 [OP_SUB] 1 [OP_ADD] | var_a = 27
var_b = 13
var_c = var_a - var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Possibility | If one blue ball is removed from a box containing 3 red balls, 2 blue balls and 5 yellow balls, what is the number of red balls? | 3 | 3 | var_a = 3
print(int(var_a)) |
Possibility | How many four-digit numbers can be formed by using all even numbers less than or equal to 9 once? | 96 | 0 9 [OP_LIST_EVEN] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 0
var_b = 9
list_a = []
if var_a%2!=0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
var_c = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_c))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_d = len(list_b)
print(int(var_d)) |
Arithmetic calculation | There were some tangerines in the basket. Eunji ate 9 pieces, and mother put 5 more in the basket, and it became 20 pieces. How many tangerines were in the basket at the beginning? | 24 | 20 9 [OP_ADD] 5 [OP_SUB] | var_a = 20
var_b = 9
var_c = var_a + var_b
var_d = 5
var_e = var_c - var_d
print(int(var_e)) |
Comparison | If you weigh on the moon, it is said to be 1/6 of your weight on Earth. Yeonjin weighed 50 kilograms (kg) on Earth, and Hodong weighed 8 and 4/6 kilograms (kg) when measured on the moon. Find the answer of who weighs more on the moon. | Hodong | [OP_LIST_SOL] Yeonjin Hodong [OP_LIST_EOL] [OP_LIST_SOL] 50 1/6 [OP_MUL] 8 4/6 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Yeonjin'
var_b = 'Hodong'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 50
var_d = 0.16666666666666666
var_e = var_c * var_d
var_f = 8
var_g = 0.6666666666666666
var_h = var_f + var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | Among the natural numbers between 200 and 500, find the value whose remainder when divided by 5 is 2, when divided by 8 is 3, and when divided by 9 is 0. | 387 | 200 500 1 [OP_LIST_ARANGE] 5 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 3 [OP_LIST_DIVIDE_AND_REMAIN] 9 0 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET] | var_a = 200
var_b = 500
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 5
var_e = 2
list_b = []
var_d = int(var_d)
var_e = int(var_e)
if var_e < 0:
var_e = var_e + var_d
for i in list_a:
i = int(i)
if i%var_d == var_e:
list_b.append(i)
var_f = 8
var_g = 3
list_c = []
var_f = int(var_f)
var_g = int(var_g)
if var_g < 0:
var_g = var_g + var_f
for i in list_b:
i = int(i)
if i%var_f == var_g:
list_c.append(i)
var_h = 9
var_i = 0
list_d = []
var_h = int(var_h)
var_i = int(var_i)
if var_i < 0:
var_i = var_i + var_h
for i in list_c:
i = int(i)
if i%var_h == var_i:
list_d.append(i)
var_j = 1
var_k = list_d[var_j-1]
print(int(var_k)) |
Possibility | How many two-digit natural numbers can be formed by choosing two figures among 0, 1, and 2? | 4 | [OP_LIST_SOL] 0 1 2 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 0
var_b = 1
var_c = 2
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = len(list_b)
print(int(var_e)) |
Correspondence | The three-digit number A76 rounded down to the hundreds place is 700. Find the value of A. | 7 | A76 [OP_GEN_POSSIBLE_LIST] 700 [OP_LIST_MORE_EQUAL] 700 100 [OP_ADD] [OP_LIST_LESS] A76 A [OP_LIST_FIND_UNK] | var_a = 'A76'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 700
list_b = []
for i in list_a:
if i >= var_b:
list_b.append(i)
var_c = 700
var_d = 100
var_e = var_c + var_d
list_c = []
for i in list_b:
if i < var_e:
list_c.append(i)
var_f = 'A76'
var_g = 'A'
var_f = str(var_f)
var_g = str(var_g)
unk_idx = var_f.index(var_g)
var_h = 0
for elem in list_c:
elem = str(elem)
var_h = int(elem[unk_idx])
print(int(var_h)) |
Correspondence | If a three-digit number has a hundredth place of 9 and is divisible by 7, how many three-digit numbers satisfy this condition? | 14 | 9 100 [OP_MUL] 9 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 9
var_b = 100
var_c = var_a * var_b
var_d = 9
var_e = 100
var_f = var_d * var_e
var_g = 99
var_h = var_f + var_g
var_i = 1
list_a = [i for i in range(var_c, var_h + 1, var_i)]
var_j = 7
list_b = []
var_j = int(var_j)
for i in list_a:
i = int(i)
if i % var_j == 0:
list_b.append(i)
var_k = len(list_b)
print(int(var_k)) |
Possibility | Find the number of possibilities when choosing to buy 3 out of 5 different sweets. | 10 | 5 3 [OP_COMB] | var_a = 5
var_b = 3
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
print(int(var_c)) |
Geometry | Jeong Su's house has a rectangular flower garden with an area of 143.2 square meters (㎡). If the length of this flower field is 4 meters (m), how many meters (m) is the width? | 35.8 | 143.2 4 [OP_DIV] | var_a = 143.2
var_b = 4
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Geometry | Hyunji bought 25 bags having 16 candies. If Hyunji shared candy with Soohyeon equally, how many candies did Hyunji get? | 200 | 25 16 [OP_MUL] 2 [OP_DIV] | var_a = 25
var_b = 16
var_c = var_a * var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Arithmetic calculation | Among the students in class (A), 25 students like social studies, 32 students like music, and 27 students like both social studies and music. If there is no student who dislikes both social studies and music, how many students are in class (A)? | 30 | 25 32 [OP_ADD] 27 [OP_SUB] | var_a = 25
var_b = 32
var_c = var_a + var_b
var_d = 27
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | There are 7 crates of apples of the same weight in the mart. After removing 20 kilograms (kg) of apples from each box, the weight of the 7 boxes of apples was equal to the weight of the original 3 boxes of apples. How many kilograms (kg) does one original box of apples weigh? | 35 | 20 7 [OP_MUL] 7 3 [OP_SUB] [OP_DIV] | var_a = 20
var_b = 7
var_c = var_a * var_b
var_d = 7
var_e = 3
var_f = var_d - var_e
var_g = var_c / var_f
print(int(var_g)) |
Correspondence | Cheolsu adds -5/12 to a certain number and then subtracted -5/2 from it and got 1/3. Find out that certain number. | -1.75 | 1/3 -5/2 [OP_ADD] -5/12 [OP_SUB] | var_a = 0.3333333333333333
var_b = -2.5
var_c = var_a + var_b
var_d = -0.4166666666666667
var_e = var_c - var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Arithmetic calculation | At a math academy, 120 students participated in a math olympiad. If there are 36 more students who received certificates than those who did not, find how many students received certificates. | 78 | 120 36 [OP_SUB] 2 [OP_DIV] 36 [OP_ADD] | var_a = 120
var_b = 36
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
var_f = 36
var_g = var_e + var_f
print(int(var_g)) |
Correspondence | If you divide 66 strawberries and 49 grapes equally into a bag, there will be 6 strawberries left and 4 grapes left. Find how many bags there are. | 15 | 49 4 [OP_SUB] 66 6 [OP_SUB] [OP_GCD] | var_a = 49
var_b = 4
var_c = var_a - var_b
var_d = 66
var_e = 6
var_f = var_d - var_e
var_g = math.gcd(int(var_f), int(var_c))
print(int(var_g)) |
Geometry | How many balls are left when 3 balls are removed from a box of 10 balls? | 7 | 10 3 [OP_SUB] | var_a = 10
var_b = 3
var_c = var_a - var_b
print(int(var_c)) |
Geometry | Ye-jin stacked boxes 53 centimeters (cm) 7 millimeters (mm) high to take out books, climbed on top of them, and measured her height from the floor. It was 190 centimeters (cm). However, if the height is not enough, pile up more boxes, stand on top of them, and measure her height from the floor. It was 232 centimeters (cm) and 5 millimeters (mm), find out how tall the boxes are now stacked. | 96.2 | 232 5 10 [OP_DIV] [OP_ADD] 190 [OP_SUB] 53 7 10 [OP_DIV] [OP_ADD] [OP_ADD] | var_a = 232
var_b = 5
var_c = 10
var_d = var_b / var_c
var_e = var_a + var_d
var_f = 190
var_g = var_e - var_f
var_h = 53
var_i = 7
var_j = 10
var_k = var_i / var_j
var_l = var_h + var_k
var_m = var_g + var_l
print('{:.2f}'.format(round(var_m+1e-10,2))) |
Geometry | A rectangular parallelepiped water container with two sides of the base each measuring 6 meters (m) 40 centimeters (cm) and 9 meters (m), and a height of 5 meters (m) 20 centimeters (cm) is filled with water. You want to divide water into several water containers whose volume is 1 cubic meter (m3). How many water containers do you need at least? | 300 | 6 40 100 [OP_DIV] [OP_ADD] 9 [OP_MUL] 5 20 100 [OP_DIV] [OP_ADD] [OP_MUL] 1 [OP_DIV] 1 [OP_CEIL] | var_a = 6
var_b = 40
var_c = 100
var_d = var_b / var_c
var_e = var_a + var_d
var_f = 9
var_g = var_e * var_f
var_h = 5
var_i = 20
var_j = 100
var_k = var_i / var_j
var_l = var_h + var_k
var_m = var_g * var_l
var_n = 1
var_o = var_m / var_n
var_p = 1
var_q=int(((var_o+9*10**(var_p-2))//(10**(var_p-1)))*10**(var_p-1))
print(int(var_q)) |
Arithmetic calculation | There is a box containing 3 blue balls and 2 red balls. How many balls are in the box? | 5 | 3 2 [OP_ADD] | var_a = 3
var_b = 2
var_c = var_a + var_b
print(int(var_c)) |
Arithmetic calculation | There is a virus that reproduces twice as many times as the first time every second. Initially, the sum of the weight of the beaker and 100 viruses contained in the beaker was 23.97 grams (g), and after 5 seconds, the sum of the weight of the beaker and the viruses contained in the beaker was 155.1 grams (g). How many grams (g) are 10000 replicated viruses? | 423 | 155.1 23.97 [OP_SUB] 100 2 5 [OP_POW] [OP_MUL] 100 [OP_SUB] [OP_DIV] 10000 [OP_MUL] | var_a = 155.1
var_b = 23.97
var_c = var_a - var_b
var_d = 100
var_e = 2
var_f = 5
var_g = var_e ** var_f
var_h = var_d * var_g
var_i = 100
var_j = var_h - var_i
var_k = var_c / var_j
var_l = 10000
var_m = var_k * var_l
print(int(var_m)) |
Possibility | Find the number of ways to draw two cards out of nine cards numbered 1 through 9 so that the sum becomes an odd number. | 40 | 1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 2 1 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN] | var_a = 1
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_c=[]
for i in list_b:
var_e = 0
i = int(i)
while i//10 > 0:
var_e = var_e + i%10
i = i//10
var_e = var_e + i%10
list_c.append(var_e)
var_f = 2
var_g = 1
list_d = []
var_f = int(var_f)
var_g = int(var_g)
if var_g < 0:
var_g = var_g + var_f
for i in list_c:
i = int(i)
if i%var_f == var_g:
list_d.append(i)
var_h = len(list_d)
print(int(var_h)) |
Arithmetic calculation | Three friends are about to share a strawberry juice. Seonghwa drank 1/6 of the total and Siyeon drank 2/5 of the rest. And if the amount of juice after Youngmin drank 2/3 of the remaining juice was 120 milliliters (㎖), how many milliliters (㎖) of strawberry juice was there at the beginning? | 720 | 120 1 1/6 [OP_SUB] [OP_DIV] 1 2/5 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV] | var_a = 120
var_b = 1
var_c = 0.16666666666666666
var_d = var_b - var_c
var_e = var_a / var_d
var_f = 1
var_g = 0.4
var_h = var_f - var_g
var_i = var_e / var_h
var_j = 1
var_k = 0.6666666666666666
var_l = var_j - var_k
var_m = var_i / var_l
print(int(eval('{:.2f}'.format(round(var_m+1e-10,2))))) |
Arithmetic calculation | It takes 5 minutes for Jeong-woo and 3 minutes for Shin-ji to complete one lap around the playground. In a situation where Jeong-woo and Shin-ji add their number of completed laps, how many minutes will it take them to reach a total of 16 laps? | 30 | 1 16 [OP_MUL] 1 5 [OP_DIV] 1 3 [OP_DIV] [OP_ADD] [OP_DIV] | var_a = 1
var_b = 16
var_c = var_a * var_b
var_d = 1
var_e = 5
var_f = var_d / var_e
var_g = 1
var_h = 3
var_i = var_g / var_h
var_j = var_f + var_i
var_k = var_c / var_j
print(int(var_k)) |
Geometry | The library at Hyunwoo's school is square with a side measuring 14.25 meters (m). Find the area of the library. | 203.06 | 14.25 2 [OP_POW] | var_a = 14.25
var_b = 2
var_c = var_a ** var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Correspondence | Adding 4.372 to a number and subtracting 43.72 gives us 16.398. Find out what the number is. | 55.75 | 16.398 43.72 [OP_ADD] 4.372 [OP_SUB] | var_a = 16.398
var_b = 43.72
var_c = var_a + var_b
var_d = 4.372
var_e = var_c - var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Possibility | Find the quotient of making the smallest quotient (three digit number)/(double digit number) using the cards 4, 2, 8, 1, 9 and each card can be used only once. | 10 | [OP_LIST_SOL] 4 2 8 1 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_LIST_POP] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_FDIV] | var_a = 4
var_b = 2
var_c = 8
var_d = 1
var_e = 9
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[var_g-1]
var_i = 2
list_d = [str(i) for i in list_a]
list_d = list(itertools.permutations(list_d, var_i))
list_d = [''.join(num_list) for num_list in list_d]
list_d = [str_num for str_num in list_d if str_num[0] != '0']
list_d = [float(i) for i in list_d]
var_j = 1
list_e=list_d.copy()
list_e.sort()
var_k = list_e[var_j-1]
var_l = var_h // var_k
print(int(var_l)) |
Geometry | I made a square by arranging colored paper of the same size without gaps. There are a total of 36 colored paper placed around the perimeter of this square. How many pieces of colored paper are on the outermost of one side? | 10 | 36 4 [OP_DIV] 1 [OP_ADD] | var_a = 36
var_b = 4
var_c = var_a / var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Geometry | There are 2 different cards. When held upright and released, how many cases will be there for the cards to fall facing up? | 1 | 1 | var_a = 1
print(int(var_a)) |
Geometry | The living room of Eugene's house is said to be rectangular. If the width of the living room is 14 meters (m) and the area is 215.6 square meters (m2), what is the length of the living room in meters (m)? | 15.4 | 215.6 14 [OP_DIV] | var_a = 215.6
var_b = 14
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Correspondence | You want to subtract 24 from a number. If the answer when you mistakenly subtract 42 from it is 50, what would be the result if you correctly calculate it? | 68 | 50 42 [OP_ADD] 24 [OP_SUB] | var_a = 50
var_b = 42
var_c = var_a + var_b
var_d = 24
var_e = var_c - var_d
print(int(var_e)) |
Comparison | Several children stand in a circle equally spaced apart. The 11th child and the 6th child are facing each other counterclockwise from one child. How many children are there in total? | 10 | 11 6 [OP_SUB] 2 [OP_MUL] | var_a = 11
var_b = 6
var_c = var_a - var_b
var_d = 2
var_e = var_c * var_d
print(int(var_e)) |
Arithmetic calculation | If there are 10 boxes and there are 100 marbles per box, what is the total number of marbles? | 1000 | 100 10 [OP_MUL] | var_a = 100
var_b = 10
var_c = var_a * var_b
print(int(var_c)) |
Comparison | There are 24 colored pencils. The red colored pencils are 1/4 of the total, the blue colored pencils are 6 more than the red colored pencils, and the rest are yellow colored pencils. Find which colored pencils have the most. | blue | [OP_LIST_SOL] red blue yellow [OP_LIST_EOL] [OP_LIST_SOL] 24 4 [OP_DIV] 24 4 [OP_DIV] 6 [OP_ADD] 24 24 4 [OP_DIV] 6 [OP_ADD] [OP_SUB] 24 4 [OP_DIV] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'red'
var_b = 'blue'
var_c = 'yellow'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 24
var_e = 4
var_f = var_d / var_e
var_g = 24
var_h = 4
var_i = var_g / var_h
var_j = 6
var_k = var_i + var_j
var_l = 24
var_m = 24
var_n = 4
var_o = var_m / var_n
var_p = 6
var_q = var_o + var_p
var_r = var_l - var_q
var_s = 24
var_t = 4
var_u = var_s / var_t
var_v = var_r - var_u
list_b= []
if "/" in str(var_v):
var_v = eval(str(var_v))
list_b.append(var_v)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_w = 1
list_c=list_b.copy()
list_c.sort()
var_x = list_c[-var_w]
var_y = list_b.index(var_x)+1
var_z = list_a[var_y-1]
print(var_z) |
Possibility | I'm trying to line up two elementary school students and two middle school students. In how many ways can elementary school students stand side by side? | 12 | 2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 2 [OP_MUL] | var_a = 2
var_b = 1
var_c = var_a + var_b
var_d = 2
var_e = 1
var_f = var_d + var_e
var_g = 1
var_c = int(var_c)
var_f = int(var_f)
for i, elem in enumerate(range(var_f)):
var_g = var_g * (var_c-i)
var_h = 2
var_i = var_g * var_h
print(int(var_i)) |
Comparison | Nine people stand in a line in order from shortest to tallest. Hoseok stands at the front, and Yuna stands right behind Hoseok. If they line up again in order of tallest people, what number will Yuna stand from the front? | 8 | 9 1 [OP_SUB] 1 [OP_SUB] 1 [OP_ADD] | var_a = 9
var_b = 1
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
var_f = 1
var_g = var_e + var_f
print(int(var_g)) |
Arithmetic calculation | There are numbers 36, 17, 32, 54, 28, and 3. Find the sum of the numbers. | 170 | [OP_LIST_SOL] 36 17 32 54 28 3 [OP_LIST_EOL] [OP_LIST_SUM] | var_a = 36
var_b = 17
var_c = 32
var_d = 54
var_e = 28
var_f = 3
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
list_a = [float(i) for i in list_a]
var_g = sum(list_a)
print(int(var_g)) |
Correspondence | I had to divide 96 by a number but mistakenly subtracted 9 by the number to get 3. Find the correctly calculated value. | 16 | 96 9 3 [OP_SUB] [OP_DIV] | var_a = 96
var_b = 9
var_c = 3
var_d = var_b - var_c
var_e = var_a / var_d
print(int(var_e)) |
Possibility | I'm trying to pick the class president and vice president from Minhyung's class. There are 3 candidates for class president and 5 candidates for vice president. How many ways can you choose one class president and one vice president? | 15 | 3 1 [OP_COMB] 5 1 [OP_COMB] [OP_MUL] | var_a = 3
var_b = 1
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
var_d = 5
var_e = 1
var_f = 1
var_d = int(var_d)
var_e = int(var_e)
for i, elem in enumerate(range(var_e)):
var_f = var_f * (var_d-i)
for i, elem in enumerate(range(var_e)):
var_f = var_f / (i+1)
var_g = var_c * var_f
print(int(var_g)) |
Arithmetic calculation | Seojun did 1/3 of the homework yesterday and 2/5 of the total today. Find the total amount of homework remaining. | 0.27 | 1 1/3 [OP_SUB] 2/5 [OP_SUB] | var_a = 1
var_b = 0.3333333333333333
var_c = var_a - var_b
var_d = 0.4
var_e = var_c - var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Comparison | A total of 20 students are running a race. Yoongi reached the finish line before the 11 students. How many students came in before Yoongi? | 8 | 20 11 [OP_SUB] 1 [OP_SUB] | var_a = 20
var_b = 11
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | There is a string that is 90 centimeters (cm) long. 30 centimeters (cm) of the string was given to Yoojung, and 8/15 of the remaining string was used to tie the box. How many centimeters (cm) is the string used to tie the box? | 32 | 90 30 [OP_SUB] 8/15 [OP_MUL] | var_a = 90
var_b = 30
var_c = var_a - var_b
var_d = 0.5333333333333333
var_e = var_c * var_d
print(int(var_e)) |
Arithmetic calculation | I rode a bicycle back and forth between the two points A and B, traveling at 15 kilometers per hour (km) on the way and 10 kilometers (km) per hour on the way back, and it took 30 minutes longer to come back. Find the total time it took to come back. | 1.5 | 10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV] 30 60 [OP_DIV] [OP_ADD] | var_a = 10
var_b = 30
var_c = 60
var_d = var_b / var_c
var_e = var_a * var_d
var_f = 15
var_g = 10
var_h = var_f - var_g
var_i = var_e / var_h
var_j = 30
var_k = 60
var_l = var_j / var_k
var_m = var_i + var_l
print('{:.2f}'.format(round(var_m+1e-10,2))) |
Arithmetic calculation | Jungkook has 4 fewer marbles than Jimin. If Jungkook has 3 marbles, how many marbles do both of them have? | 10 | 3 3 4 [OP_ADD] [OP_ADD] | var_a = 3
var_b = 3
var_c = 4
var_d = var_b + var_c
var_e = var_a + var_d
print(int(var_e)) |
Correspondence | Seonwoo wants to combine 35 pencils and 5 erasers and hand them out to 5 friends in equal numbers. Find how many of them should he hand out to each friend. | 8 | 35 5 [OP_ADD] 5 [OP_DIV] | var_a = 35
var_b = 5
var_c = var_a + var_b
var_d = 5
var_e = var_c / var_d
print(int(var_e)) |
Comparison | We filled a 1 liter (l) 400 milliliter (ml) vase and a 2800 milliliter (ml) milk bottle with water, and then poured it all into a basin, which made the basin full. Between this basin a tank with 4 liters (L) and 100 milliliters (ml), which one can have more water inside? | basin | [OP_LIST_SOL] tank basin [OP_LIST_EOL] [OP_LIST_SOL] 4 1000 [OP_MUL] 100 [OP_ADD] 2800 1 1000 [OP_MUL] 400 [OP_ADD] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'tank'
var_b = 'basin'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 4
var_d = 1000
var_e = var_c * var_d
var_f = 100
var_g = var_e + var_f
var_h = 2800
var_i = 1
var_j = 1000
var_k = var_i * var_j
var_l = 400
var_m = var_k + var_l
var_n = var_h + var_m
list_b= []
if "/" in str(var_n):
var_n = eval(str(var_n))
list_b.append(var_n)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
list_b.reverse()
var_o = 1
list_c=list_b.copy()
list_c.sort()
var_p = list_c[-var_o]
var_q = list_b.index(var_p)+1
var_r = list_a[var_q-1]
print(var_r) |
Arithmetic calculation | How many three-digit numbers are divisible by the four numbers 6, 5, 8, and 9? | 2 | 100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 100
var_b = 999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 6
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 5
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = 8
list_d = []
var_f = int(var_f)
for i in list_c:
i = int(i)
if i % var_f == 0:
list_d.append(i)
var_g = 9
list_e = []
var_g = int(var_g)
for i in list_d:
i = int(i)
if i % var_g == 0:
list_e.append(i)
var_h = len(list_e)
print(int(var_h)) |
Comparison | There are five types of shapes: triangular-prism, quadrangular-prism, triangular-pyramid, quadrangular-pyramid, and truncated-quadrangular-pyramid. Given that you place a sticker on the center of each face of each shape, which shape needs the least number of stickers? | triangular-pyramid | [OP_LIST_SOL] triangular-prism quadrangular-prism triangular-pyramid quadrangular-pyramid truncated-quadrangular-pyramid [OP_LIST_EOL] [OP_LIST_SOL] 3 2 [OP_ADD] 4 2 [OP_ADD] 3 1 [OP_ADD] 4 1 [OP_ADD] 4 2 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'triangular-prism'
var_b = 'quadrangular-prism'
var_c = 'triangular-pyramid'
var_d = 'quadrangular-pyramid'
var_e = 'truncated-quadrangular-pyramid'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
var_g = 2
var_h = var_f + var_g
var_i = 4
var_j = 2
var_k = var_i + var_j
var_l = 3
var_m = 1
var_n = var_l + var_m
var_o = 4
var_p = 1
var_q = var_o + var_p
var_r = 4
var_s = 2
var_t = var_r + var_s
list_b= []
if "/" in str(var_t):
var_t = eval(str(var_t))
list_b.append(var_t)
if "/" in str(var_q):
var_q = eval(str(var_q))
list_b.append(var_q)
if "/" in str(var_n):
var_n = eval(str(var_n))
list_b.append(var_n)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
list_b.reverse()
var_u = 1
list_c=list_b.copy()
list_c.sort()
var_v = list_c[var_u-1]
var_w = list_b.index(var_v)+1
var_x = list_a[var_w-1]
print(var_x) |
Geometry | There are two cubes of different sizes. When the sum of the lengths of all edges of the large cube is 82.8 centimeters (cm), and the length of one edge of the small cube is 1/3 of the length of one edge of the large cube, select each one of the edges of the two cubes and determine its length. Add up to how many centimeters (cm)? | 9.2 | 82.8 4 3 [OP_MUL] [OP_DIV] 1/3 [OP_MUL] 82.8 4 3 [OP_MUL] [OP_DIV] [OP_ADD] | var_a = 82.8
var_b = 4
var_c = 3
var_d = var_b * var_c
var_e = var_a / var_d
var_f = 0.3333333333333333
var_g = var_e * var_f
var_h = 82.8
var_i = 4
var_j = 3
var_k = var_i * var_j
var_l = var_h / var_k
var_m = var_g + var_l
print('{:.2f}'.format(round(var_m+1e-10,2))) |
Arithmetic calculation | Which four-digit number is the smallest common multiple of 5, 6, and 2? | 1020 | 1000 9999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN] | var_a = 1000
var_b = 9999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 5
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 6
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = 2
list_d = []
var_f = int(var_f)
for i in list_c:
i = int(i)
if i % var_f == 0:
list_d.append(i)
var_g = 1
list_e=list_d.copy()
list_e.sort()
var_h = list_e[var_g-1]
print(int(var_h)) |
Correspondence | Yoongi wants to subtract 57 from a three-digit number. Yoongi misread the three-digit ones digit 9 as a 6. When Yoongi's car is 819, find the correct calculation result. | 822 | 819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB] 57 [OP_SUB] | var_a = 819
var_b = 57
var_c = var_a + var_b
var_d = 6
var_e = 9
var_f = var_d - var_e
var_g = var_c - var_f
var_h = 57
var_i = var_g - var_h
print(int(var_i)) |
Comparison | Suzy has a wire of 9 centimeters (cm) 8 millimeters (mm), Yeongju has 8.9 centimeters (cm), and Youngho has 9.3 centimeters (cm). Who has the shortest wire length? | Yeongju | [OP_LIST_SOL] Suzy Yeongju Youngho [OP_LIST_EOL] [OP_LIST_SOL] 9 8 10 [OP_DIV] [OP_ADD] 8.9 9.3 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Suzy'
var_b = 'Yeongju'
var_c = 'Youngho'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 9
var_e = 8
var_f = 10
var_g = var_e / var_f
var_h = var_d + var_g
var_i = 8.9
var_j = 9.3
list_b= []
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
list_b.reverse()
var_k = 1
list_c=list_b.copy()
list_c.sort()
var_l = list_c[var_k-1]
var_m = list_b.index(var_l)+1
var_n = list_a[var_m-1]
print(var_n) |
Comparison | Jungkook has 0.8, Yoongi has 1/2, Yoojeong has 0.9, and Yuna has 1/3 written on their cards. How many people have cards with numbers less than 0.3 written? | 0 | [OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 0.8
var_b = 0.5
var_c = 0.9
var_d = 0.3333333333333333
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 0.3
list_b = []
for i in list_a:
if i < var_e:
list_b.append(i)
var_f = len(list_b)
print(int(var_f)) |
Arithmetic calculation | When Jimin counted the money he had, there were 5 100 won coins and 1 50 won coin. If Seok-jin, who was next to him, had 2 100-won coins and 7 10-won coins, what would be the most expensive item the two of them could buy with the money they had? | 820 | 100 5 [OP_MUL] 50 1 [OP_MUL] [OP_ADD] 100 2 [OP_MUL] [OP_ADD] 10 7 [OP_MUL] [OP_ADD] | var_a = 100
var_b = 5
var_c = var_a * var_b
var_d = 50
var_e = 1
var_f = var_d * var_e
var_g = var_c + var_f
var_h = 100
var_i = 2
var_j = var_h * var_i
var_k = var_g + var_j
var_l = 10
var_m = 7
var_n = var_l * var_m
var_o = var_k + var_n
print(int(var_o)) |
Arithmetic calculation | You are trying to find a two-digit number that is divisible by 3 and 4 and divided by 5 has a remainder of 4. What is the smallest two-digit number you can make? | 24 | 10 99 1 [OP_LIST_ARANGE] 3 4 [OP_LCM] [OP_LIST_DIVISIBLE] 5 4 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN] | var_a = 10
var_b = 99
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
var_e = 4
var_f = var_e * var_d / math.gcd(int(var_e), int(var_d))
list_b = []
var_f = int(var_f)
for i in list_a:
i = int(i)
if i % var_f == 0:
list_b.append(i)
var_g = 5
var_h = 4
list_c = []
var_g = int(var_g)
var_h = int(var_h)
if var_h < 0:
var_h = var_h + var_g
for i in list_b:
i = int(i)
if i%var_g == var_h:
list_c.append(i)
var_i = 1
list_d=list_c.copy()
list_d.sort()
var_j = list_d[var_i-1]
print(int(var_j)) |
Possibility | What is the largest possible sum that can be calculated in an addition expression comprised of two-digit numbers that were made using 1, 7, 9, and 2 once? | 163 | [OP_LIST_SOL] 1 7 9 2 [OP_LIST_EOL] 1 [OP_LIST_MAX] 10 [OP_MUL] 1 [OP_LIST_MIN] [OP_ADD] 2 [OP_LIST_MAX] 10 [OP_MUL] 2 [OP_LIST_MIN] [OP_ADD] [OP_ADD] | var_a = 1
var_b = 7
var_c = 9
var_d = 2
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 1
list_b=list_a.copy()
list_b.sort()
var_f = list_b[-var_e]
var_g = 10
var_h = var_f * var_g
var_i = 1
list_c=list_a.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = var_h + var_j
var_l = 2
list_d=list_a.copy()
list_d.sort()
var_m = list_d[-var_l]
var_n = 10
var_o = var_m * var_n
var_p = 2
list_e=list_a.copy()
list_e.sort()
var_q = list_e[var_p-1]
var_r = var_o + var_q
var_s = var_k + var_r
print(int(var_s)) |
Comparison | 1000 marbles are divided between class 1 and 2, but class 1 has 50 more marbles. Then, the students in class 2 were divided into two teams of boys and girls and shared the marbles they brought, and the boys got 35 more. If 17 male students in class 2 share the marbles equally, find how many marbles each male student in class 2 has. | 15 | 1000 50 [OP_SUB] 2 [OP_DIV] 35 [OP_SUB] 2 [OP_DIV] 35 [OP_ADD] 17 [OP_DIV] | var_a = 1000
var_b = 50
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
var_f = 35
var_g = var_e - var_f
var_h = 2
var_i = var_g / var_h
var_j = 35
var_k = var_i + var_j
var_l = 17
var_m = var_k / var_l
print(int(var_m)) |
Correspondence | When 632-AB1=41, what number should go in B? | 9 | 632-AB1=41 B [OP_DIGIT_UNK_SOLVER] | var_a = '632-AB1=41'
var_b = 'B'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Arithmetic calculation | Minyoung drank 7/9 liters (L) of water, and Yuna drank 2 liters (L). Find how many times the amount of water Minyoung drank compared to the amount of water Yuna drank. | 0.39 | 7/9 2 [OP_DIV] | var_a = 0.7777777777777778
var_b = 2
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Comparison | There are a total of three numbers: 0.8, 1/2, and 0.5. How many of these numbers are less than or equal to 3? | 3 | [OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] | var_a = 0.8
var_b = 0.5
var_c = 0.5
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = []
for i in list_a:
if i <= var_d:
list_b.append(i)
var_e = len(list_b)
print(int(var_e)) |
Correspondence | 27 times a number plus 143 is 9693. Find the number. | 216 | 9693 27 [OP_DIV] 143 [OP_SUB] | var_a = 9693
var_b = 27
var_c = var_a / var_b
var_d = 143
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | Yulgi and Dongmin had 5,000 won in total. Yulgi paid all the money he had, and Dongmin paid 300 won more than Yulgi to buy a doll of 4,500 won. How much money did Dongmin have at first? | 2900 | 5000 4500 300 [OP_SUB] 2 [OP_DIV] [OP_SUB] | var_a = 5000
var_b = 4500
var_c = 300
var_d = var_b - var_c
var_e = 2
var_f = var_d / var_e
var_g = var_a - var_f
print(int(var_g)) |
Arithmetic calculation | Roosters outnumber hens by 16. How many chickens are there on the farm when there are 52 hens? | 120 | 52 52 16 [OP_ADD] [OP_ADD] | var_a = 52
var_b = 52
var_c = 16
var_d = var_b + var_c
var_e = var_a + var_d
print(int(var_e)) |
Arithmetic calculation | Street lamps are erected on a bridge over a river that is 1650 meters (m) at intervals of 50 meters (m). If there are street lamps from the beginning to the end of the bridge, how many lamps are there on both sides of the bridge? | 68 | 1650 50 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL] | var_a = 1650
var_b = 50
var_c = var_a / var_b
var_d = 1
var_e = var_c + var_d
var_f = 2
var_g = var_e * var_f
print(int(var_g)) |
Comparison | Nine people stand in a line in order from shortest to tallest. Hoseok is the tallest, and Yuna stands 5th ahead of Hoseok. If you line up again in order of tallest people, what number will Yuna stand from the front? | 6 | 9 9 [OP_SUB] 5 [OP_ADD] 1 [OP_ADD] | var_a = 9
var_b = 9
var_c = var_a - var_b
var_d = 5
var_e = var_c + var_d
var_f = 1
var_g = var_e + var_f
print(int(var_g)) |
Correspondence | A and B are single-digit numbers. A is 3 greater than 5, and B is 2 less than A. Calculate the sum of A and B. | 14 | 5 3 [OP_ADD] 5 3 [OP_ADD] 2 [OP_SUB] [OP_ADD] | var_a = 5
var_b = 3
var_c = var_a + var_b
var_d = 5
var_e = 3
var_f = var_d + var_e
var_g = 2
var_h = var_f - var_g
var_i = var_c + var_h
print(int(var_i)) |
Correspondence | You had to add 2 to a certain number, but you mistakenly subtracted it, and the result was 5. What is the value if it is correctly calculated? | 9 | 5 2 [OP_ADD] 2 [OP_ADD] | var_a = 5
var_b = 2
var_c = var_a + var_b
var_d = 2
var_e = var_c + var_d
print(int(var_e)) |
Geometry | When the entire school students were arranged in a large square, there were 240 students standing at the perimeter. How many students were there in all? | 3721 | 240 4 [OP_DIV] 1 [OP_ADD] 2 [OP_POW] | var_a = 240
var_b = 4
var_c = var_a / var_b
var_d = 1
var_e = var_c + var_d
var_f = 2
var_g = var_e ** var_f
print(int(var_g)) |
Geometry | A large square was created by arranging the square-shaped tiles regularly without any gaps. If the number of tiles arranged at the perimeter was 240, how many tiles in total were used? | 3721 | 240 4 [OP_DIV] 1 [OP_ADD] 2 [OP_POW] | var_a = 240
var_b = 4
var_c = var_a / var_b
var_d = 1
var_e = var_c + var_d
var_f = 2
var_g = var_e ** var_f
print(int(var_g)) |
Arithmetic calculation | There are 2.3 liters (L) of Coke extract. It is said that 3 bottles of cola are made with 400 milliliters (ml) of cola extract. How many bottles of Coke can you make? (However, 3 bottles of Coke can be made at a time.) | 15 | 2.3 1000 [OP_MUL] 400 [OP_FDIV] 3 [OP_MUL] | var_a = 2.3
var_b = 1000
var_c = var_a * var_b
var_d = 400
var_e = var_c // var_d
var_f = 3
var_g = var_e * var_f
print(int(var_g)) |
Arithmetic calculation | I'm going to distribute 400 notebooks to each of the Yellow, Red, and Blue class students. If the number of students in each class is 30, 27, and 28, how many notebooks are left? | 60 | 400 30 27 [OP_ADD] 28 [OP_ADD] 4 [OP_MUL] [OP_SUB] | var_a = 400
var_b = 30
var_c = 27
var_d = var_b + var_c
var_e = 28
var_f = var_d + var_e
var_g = 4
var_h = var_f * var_g
var_i = var_a - var_h
print(int(var_i)) |
Arithmetic calculation | Find the average of the natural numbers that are divisible by 6 and are between 30 and 50. | 39 | 30 50 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] [OP_LIST_MEAN] | var_a = 30
var_b = 50
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 6
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
list_b = [float(i) for i in list_b]
var_e = sum(list_b)/len(list_b)
print(int(var_e)) |
Comparison | (c) fruit is heavier than (b) fruit and lighter than (a) fruit. What is the heaviest fruit? | (a) | [OP_LIST_SOL] (a) (b) (c) [OP_LIST_EOL] [OP_LIST_SOL] (c) (b) > (c) (a) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = '(a)'
var_b = '(b)'
var_c = '(c)'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = '(c)'
var_e = '(b)'
var_f = '>'
var_g = '(c)'
var_h = '(a)'
var_i = '<'
list_b= []
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_j = 1
var_k = list_c[var_j-1]
print(var_k) |
Comparison | Choose a number less than 1.1 from 1.4, 9/10, 1.2, 0.5, 13/10 and find the sum of the selected numbers | 1.4 | [OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] [OP_LIST_SUM] | var_a = 1.4
var_b = 0.9
var_c = 1.2
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1.1
list_b = []
for i in list_a:
if i < var_f:
list_b.append(i)
list_b = [float(i) for i in list_b]
var_g = sum(list_b)
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Geometry | There is a prism with the sum of the number of edges and vertices equal to 30. What is the number of sides of this prism plus 2? | 8 | 30 2 3 [OP_ADD] [OP_DIV] 2 [OP_ADD] | var_a = 30
var_b = 2
var_c = 3
var_d = var_b + var_c
var_e = var_a / var_d
var_f = 2
var_g = var_e + var_f
print(int(var_g)) |
Correspondence | A is a number from 1 to 9. What is the sum of all As that satisfy 0.4<0.A, 6.A<6.8, and 3.A<A.4? | 18 | 0.4<0.A A [OP_DIGIT_UNK_SOLVER] 6.A<6.8 A [OP_DIGIT_UNK_SOLVER] [OP_SET_INTERSECT] 3.A<A.4 A [OP_DIGIT_UNK_SOLVER] [OP_SET_INTERSECT] [OP_LIST_SUM] | var_a = '0.4<0.A'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = []
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k].append(int(c[i]))
list_a = list(set(ans_dict[var_b]))
var_c = '6.A<6.8'
var_d = 'A'
ans_dict = dict()
var_c = var_c.replace('×','*')
var_c = var_c.replace('x','*')
var_c = var_c.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_c):
if v in variable_candi:
ans_dict[v] = []
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_c
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_c):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k].append(int(c[i]))
list_b = list(set(ans_dict[var_d]))
list_c = list(set(list_a) & set(list_b))
var_e = '3.A<A.4'
var_f = 'A'
ans_dict = dict()
var_e = var_e.replace('×','*')
var_e = var_e.replace('x','*')
var_e = var_e.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_e):
if v in variable_candi:
ans_dict[v] = []
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_e
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_e):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k].append(int(c[i]))
list_d = list(set(ans_dict[var_f]))
list_e = list(set(list_c) & set(list_d))
list_e = [float(i) for i in list_e]
var_g = sum(list_e)
print(int(var_g)) |
Comparison | At a constant speed, a taxi travels a distance of 17.28 kilometers (km) in 16 minutes, and a car travels a distance of 8.52 kilometers (km) in 6 minutes. If you start from the same place and drive for 15 minutes, which goes farther: a taxi or a car? | car | [OP_LIST_SOL] taxi car [OP_LIST_EOL] [OP_LIST_SOL] 17.28 16 [OP_DIV] 15 [OP_MUL] 8.52 6 [OP_DIV] 15 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'taxi'
var_b = 'car'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 17.28
var_d = 16
var_e = var_c / var_d
var_f = 15
var_g = var_e * var_f
var_h = 8.52
var_i = 6
var_j = var_h / var_i
var_k = 15
var_l = var_j * var_k
list_b= []
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
list_b.reverse()
var_m = 1
list_c=list_b.copy()
list_c.sort()
var_n = list_c[-var_m]
var_o = list_b.index(var_n)+1
var_p = list_a[var_o-1]
print(var_p) |
Correspondence | When 9A3B was rounded up to the tens place, it was 9430. What is A? | 4 | 9A3B [OP_GEN_POSSIBLE_LIST] 9430 [OP_LIST_MORE_EQUAL] 9430 10 [OP_ADD] [OP_LIST_LESS] 9A3B A [OP_LIST_FIND_UNK] | var_a = '9A3B'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 9430
list_b = []
for i in list_a:
if i >= var_b:
list_b.append(i)
var_c = 9430
var_d = 10
var_e = var_c + var_d
list_c = []
for i in list_b:
if i < var_e:
list_c.append(i)
var_f = '9A3B'
var_g = 'A'
var_f = str(var_f)
var_g = str(var_g)
unk_idx = var_f.index(var_g)
var_h = 0
for elem in list_c:
elem = str(elem)
var_h = int(elem[unk_idx])
print(int(var_h)) |
Arithmetic calculation | Hoseok jumped the rope 34 times and Minyoung jumped it 51 times. How many more times does Hoseok have to jump to get the same number of jumps as Minyoung? | 17 | 51 34 [OP_SUB] | var_a = 51
var_b = 34
var_c = var_a - var_b
print(int(var_c)) |
Arithmetic calculation | There are 5 consecutive natural numbers whose sum is 100. What is the smallest of these numbers? | 18 | 100 5 [OP_DIV] 5 2 [OP_FDIV] [OP_SUB] | var_a = 100
var_b = 5
var_c = var_a / var_b
var_d = 5
var_e = 2
var_f = var_d // var_e
var_g = var_c - var_f
print(int(var_g)) |
Comparison | There are five boxes: A, B, C, D, and E. D box is larger than B box and smaller than A box. B box is larger than E box. A box is smaller than C box. Which box is the largest? | C | [OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] D B > D A < B E > A C < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = 'A'
var_b = 'B'
var_c = 'C'
var_d = 'D'
var_e = 'E'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 'D'
var_g = 'B'
var_h = '>'
var_i = 'D'
var_j = 'A'
var_k = '<'
var_l = 'B'
var_m = 'E'
var_n = '>'
var_o = 'A'
var_p = 'C'
var_q = '<'
list_b= []
if "/" in str(var_q):
var_q = eval(str(var_q))
list_b.append(var_q)
if "/" in str(var_p):
var_p = eval(str(var_p))
list_b.append(var_p)
if "/" in str(var_o):
var_o = eval(str(var_o))
list_b.append(var_o)
if "/" in str(var_n):
var_n = eval(str(var_n))
list_b.append(var_n)
if "/" in str(var_m):
var_m = eval(str(var_m))
list_b.append(var_m)
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_r = 1
var_s = list_c[var_r-1]
print(var_s) |
Correspondence | The quotient of a number divided by 8 is 0.65. Find the value of the quotient of the number divided by 5 multiplied by 7. | 7 | 0.65 8 [OP_MUL] 5 [OP_FDIV] 7 [OP_MUL] | var_a = 0.65
var_b = 8
var_c = var_a * var_b
var_d = 5
var_e = var_c // var_d
var_f = 7
var_g = var_e * var_f
print(int(var_g)) |
Arithmetic calculation | There were 7 buses in the parking lot and 6 more came a few minutes later. How many buses are in the parking lot right now? | 13 | 7 6 [OP_ADD] | var_a = 7
var_b = 6
var_c = var_a + var_b
print(int(var_c)) |
Correspondence | A number subtracted by 5 multiplied by 4 equals the number multiplied by 2. Find the number. | 10 | 5 4 [OP_MUL] 4 2 [OP_SUB] [OP_DIV] | var_a = 5
var_b = 4
var_c = var_a * var_b
var_d = 4
var_e = 2
var_f = var_d - var_e
var_g = var_c / var_f
print(int(var_g)) |
Arithmetic calculation | There are 5 tuna and 2 spearfish in the sea. What is the total number of fish in the sea? | 7 | 5 2 [OP_ADD] | var_a = 5
var_b = 2
var_c = var_a + var_b
print(int(var_c)) |
Geometry | A large cube was made out of eight dices of the same size. If the surface area of one die is 96 square centimeters (cm2), find the volume in cubic centimeters (cm3) of the cube created. | 512 | 96 6 [OP_DIV] 1/2 [OP_POW] 8 2 [OP_DIV] 2 [OP_DIV] [OP_MUL] 3 [OP_POW] | var_a = 96
var_b = 6
var_c = var_a / var_b
var_d = 0.5
var_e = var_c ** var_d
var_f = 8
var_g = 2
var_h = var_f / var_g
var_i = 2
var_j = var_h / var_i
var_k = var_e * var_j
var_l = 3
var_m = var_k ** var_l
print(int(var_m)) |
Comparison | The number of students at Sejeong's School is 1443. However, there are 141 more male students than female students. How many male students are there? | 792 | 1443 141 [OP_SUB] 2 [OP_DIV] 141 [OP_ADD] | var_a = 1443
var_b = 141
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
var_f = 141
var_g = var_e + var_f
print(int(var_g)) |
Arithmetic calculation | Taehyung is 5 years older than his younger brother, and this year Taehyung's younger brother is 7 years old. How old is his mother when the age difference between Taehyung and his mother is 31 years? | 43 | 7 5 [OP_ADD] 31 [OP_ADD] | var_a = 7
var_b = 5
var_c = var_a + var_b
var_d = 31
var_e = var_c + var_d
print(int(var_e)) |
Correspondence | A and B are two natural numbers. If B is the number obtained by multiplying A by 9 and then adding 13, what is the remainder when B is divided by 9? | 4 | 13 9 [OP_MOD] | var_a = 13
var_b = 9
var_c = var_a % var_b
print(int(var_c)) |
Possibility | How many ways are possible to make a three-digit number by selecting three of 1, 3, 5, 7, and 9? | 60 | [OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 1
var_b = 3
var_c = 5
var_d = 7
var_e = 9
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = len(list_b)
print(int(var_g)) |
Possibility | Jungkook has 5 red balls, 4 blue balls, and 3 yellow balls. When Yoongi gives Jungkook one red ball, how many yellow balls does Jungkook have? | 3 | 3 | var_a = 3
print(int(var_a)) |
Geometry | If you bend a 12 centimeters (cm) wire in half, and then bend the bent wire in half again, how many centimeters (cm) is the current length of the wire? | 3 | 12 2 [OP_DIV] 2 [OP_DIV] | var_a = 12
var_b = 2
var_c = var_a / var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | If you add 10 to A, you get 15. How much is A? | 5 | 15 10 [OP_SUB] | var_a = 15
var_b = 10
var_c = var_a - var_b
print(int(var_c)) |
Correspondence | Students are trying to line up on the playground. When they are stood in 5 lines, 2 students were left out, when stood in 8 lines, 3 students were left, and when stood in 9 lines, it fit perfectly. Find how many students there are in total. However, the number of students in the playground is between 200 and 500. | 387 | 200 500 1 [OP_LIST_ARANGE] 5 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 3 [OP_LIST_DIVIDE_AND_REMAIN] 9 0 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET] | var_a = 200
var_b = 500
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 5
var_e = 2
list_b = []
var_d = int(var_d)
var_e = int(var_e)
if var_e < 0:
var_e = var_e + var_d
for i in list_a:
i = int(i)
if i%var_d == var_e:
list_b.append(i)
var_f = 8
var_g = 3
list_c = []
var_f = int(var_f)
var_g = int(var_g)
if var_g < 0:
var_g = var_g + var_f
for i in list_b:
i = int(i)
if i%var_f == var_g:
list_c.append(i)
var_h = 9
var_i = 0
list_d = []
var_h = int(var_h)
var_i = int(var_i)
if var_i < 0:
var_i = var_i + var_h
for i in list_c:
i = int(i)
if i%var_h == var_i:
list_d.append(i)
var_j = 1
var_k = list_d[var_j-1]
print(int(var_k)) |
Arithmetic calculation | There are 6 (A) animals, 8 (B) animals, and 4 (C) animals. How many animals are there in all? | 18 | 6 8 [OP_ADD] 4 [OP_ADD] | var_a = 6
var_b = 8
var_c = var_a + var_b
var_d = 4
var_e = var_c + var_d
print(int(var_e)) |
Geometry | There is a cube with a side with an area of 64 square centimeters (cm2). What is the volume of this cube? | 512 | 64 1/2 [OP_POW] 3 [OP_POW] | var_a = 64
var_b = 0.5
var_c = var_a ** var_b
var_d = 3
var_e = var_c ** var_d
print(int(var_e)) |
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