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Lista dos 5 países que estão em primeiro lugar em número de faturas.
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CREATE TABLE invoices (billing_country VARCHAR)
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SELECT billing_country, COUNT(*) FROM invoices GROUP BY billing_country ORDER BY COUNT(*) DESC LIMIT 5
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Lista dos 8 países que figuram no topo, por dimensão bruta/todo o volume da factura.
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CREATE TABLE invoices (billing_country VARCHAR, total INTEGER)
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SELECT billing_country, SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8
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Lista dos 10 países mais importantes por tamanho médio da fatura.
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CREATE TABLE invoices (billing_country VARCHAR, total INTEGER)
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SELECT billing_country, AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10
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Descobre cinco clientes que compraram algo mais recentemente.
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CREATE TABLE customers (first_name VARCHAR, last_name VARCHAR, id VARCHAR); CREATE TABLE invoices (customer_id VARCHAR, invoice_date VARCHAR)
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SELECT T1.first_name, T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY T2.invoice_date DESC LIMIT 5
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Encontre os 10 principais clientes por número total de encomendas.
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CREATE TABLE customers (first_name VARCHAR, last_name VARCHAR, id VARCHAR); CREATE TABLE invoices (customer_id VARCHAR)
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SELECT T1.first_name, T1.last_name, COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 10
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Lista os 10 principais clientes por vendas totais.
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CREATE TABLE invoices (total INTEGER, customer_id VARCHAR); CREATE TABLE customers (first_name VARCHAR, last_name VARCHAR, id VARCHAR)
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SELECT T1.first_name, T1.last_name, SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10
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Lista os 5 principais gêneros por número de faixas.
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CREATE TABLE tracks (genre_id VARCHAR); CREATE TABLE genres (name VARCHAR, id VARCHAR)
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SELECT T1.name, COUNT(*) FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 5
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Escreve o título de cada álbum.
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CREATE TABLE albums (title VARCHAR)
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SELECT title FROM albums
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Lista todos os álbuns ordenados por título de álbum em ordem ascendente.
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CREATE TABLE albums (title VARCHAR)
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SELECT title FROM albums ORDER BY title
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Lista todos os álbuns cujo título começa com A em ordem alfabética.
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CREATE TABLE albums (title VARCHAR)
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SELECT title FROM albums WHERE title LIKE 'A%' ORDER BY title
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Escreva o nome e o apelido dos clientes de 10 faturas menos caras.
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CREATE TABLE customers (first_name VARCHAR, last_name VARCHAR, id VARCHAR); CREATE TABLE invoices (customer_id VARCHAR)
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SELECT T1.first_name, T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY total LIMIT 10
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Lista de montante total da fatura de Chicago, IL.
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CREATE TABLE invoices (total INTEGER, billing_city VARCHAR, billing_state VARCHAR)
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SELECT SUM(total) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL"
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Escreva o número de faturas de Chicago, IL.
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CREATE TABLE invoices (billing_city VARCHAR, billing_state VARCHAR)
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SELECT COUNT(*) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL"
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Indicar o número de faturas dos EUA, agrupadas por estado.
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CREATE TABLE invoices (billing_state VARCHAR, billing_country VARCHAR)
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SELECT billing_state, COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state
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Escreva o estado dos EUA com mais faturas.
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CREATE TABLE invoices (billing_state VARCHAR, billing_country VARCHAR)
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SELECT billing_state, COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state ORDER BY COUNT(*) DESC LIMIT 1
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Escreva o número de faturas e o total das faturas da Califórnia.
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CREATE TABLE invoices (billing_state VARCHAR, total INTEGER)
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SELECT billing_state, COUNT(*), SUM(total) FROM invoices WHERE billing_state = "CA"
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Lista dos álbuns do Aerosmith.
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CREATE TABLE artists (id VARCHAR, name VARCHAR); CREATE TABLE albums (title VARCHAR, artist_id VARCHAR)
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SELECT T1.title FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Aerosmith"
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Quantos álbuns tem o Billy Cobham?
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CREATE TABLE artists (id VARCHAR, name VARCHAR); CREATE TABLE albums (artist_id VARCHAR)
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SELECT COUNT(*) FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Billy Cobham"
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Eduardo Martins é cliente de que empresa?
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CREATE TABLE customers (company VARCHAR, first_name VARCHAR, last_name VARCHAR)
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SELECT company FROM customers WHERE first_name = "Eduardo" AND last_name = "Martins"
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Qual é o e-mail e o número de telefone da Astrid Gruber?
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CREATE TABLE customers (email VARCHAR, phone VARCHAR, first_name VARCHAR, last_name VARCHAR)
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SELECT email, phone FROM customers WHERE first_name = "Astrid" AND last_name = "Gruber"
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Quantos clientes vivem na cidade de Praga?
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CREATE TABLE customers (city VARCHAR)
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SELECT COUNT(*) FROM customers WHERE city = "Prague"
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Quantos clientes no estado da CA?
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CREATE TABLE customers (state VARCHAR)
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SELECT COUNT(*) FROM customers WHERE state = "CA"
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Em que país vive Roberto Almeida?
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CREATE TABLE customers (country VARCHAR, first_name VARCHAR, last_name VARCHAR)
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SELECT country FROM customers WHERE first_name = "Roberto" AND last_name = "Almeida"
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Lista o nome dos álbuns que são lançados por aristista cujo nome tem 'Led'
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CREATE TABLE artists (id VARCHAR, name VARCHAR); CREATE TABLE albums (title VARCHAR, artist_id VARCHAR)
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SELECT T2.title FROM artists AS T1 JOIN albums AS T2 ON T1.id = T2.artist_id WHERE T1.name LIKE '%Led%'
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Quantos clientes é que o Steve Johnson tem?
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CREATE TABLE employees (id VARCHAR, first_name VARCHAR, last_name VARCHAR); CREATE TABLE customers (support_rep_id VARCHAR)
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SELECT COUNT(*) FROM employees AS T1 JOIN customers AS T2 ON T2.support_rep_id = T1.id WHERE T1.first_name = "Steve" AND T1.last_name = "Johnson"
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Qual é o título, telefone e data de contratação de Nancy Edwards?
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CREATE TABLE employees (title VARCHAR, phone VARCHAR, hire_date VARCHAR, first_name VARCHAR, last_name VARCHAR)
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SELECT title, phone, hire_date FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"
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Encontrar o nome completo dos empregados que se reportam a Nancy Edwards?
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CREATE TABLE employees (id VARCHAR, first_name VARCHAR, last_name VARCHAR); CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, reports_to VARCHAR)
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SELECT T2.first_name, T2.last_name FROM employees AS T1 JOIN employees AS T2 ON T1.id = T2.reports_to WHERE T1.first_name = "Nancy" AND T1.last_name = "Edwards"
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Qual é o endereço da empregada Nancy Edwards?
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CREATE TABLE employees (address VARCHAR, first_name VARCHAR, last_name VARCHAR)
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SELECT address FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"
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Encontre o nome completo do funcionário que apoiou o maior número de clientes.
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CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, id VARCHAR); CREATE TABLE customers (support_rep_id VARCHAR)
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SELECT T1.first_name, T1.last_name FROM employees AS T1 JOIN customers AS T2 ON T1.id = T2.support_rep_id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1
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Quantos funcionários vivem no Canadá?
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CREATE TABLE employees (country VARCHAR)
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SELECT COUNT(*) FROM employees WHERE country = "Canada"
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Qual é o número de telefone da empregada Nancy Edwards?
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CREATE TABLE employees (phone VARCHAR, first_name VARCHAR, last_name VARCHAR)
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SELECT phone FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"
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Quem é o empregado mais jovem da empresa? Escreva o nome e o apelido do empregado.
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CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, birth_date VARCHAR)
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SELECT first_name, last_name FROM employees ORDER BY birth_date DESC LIMIT 1
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Lista de 10 empregados que trabalharam mais tempo na empresa.
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CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, hire_date VARCHAR)
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SELECT first_name, last_name FROM employees ORDER BY hire_date LIMIT 10
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Encontre o número de funcionários cujo título é o pessoal de TI de cada cidade?
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CREATE TABLE employees (city VARCHAR, title VARCHAR)
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SELECT COUNT(*), city FROM employees WHERE title = 'IT Staff' GROUP BY city
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Qual empregado gerencia o maior número de pessoas? Liste o nome e sobrenome do empregado e o número de pessoas que se reportam a esse empregado.
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CREATE TABLE employees (first_name VARCHAR, last_name VARCHAR, id VARCHAR); CREATE TABLE employees (reports_to VARCHAR)
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SELECT T2.first_name, T2.last_name, COUNT(T1.reports_to) FROM employees AS T1 JOIN employees AS T2 ON T1.reports_to = T2.id GROUP BY T1.reports_to ORDER BY COUNT(T1.reports_to) DESC LIMIT 1
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Quantos pedidos tem o Lucas Mancini?
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CREATE TABLE invoices (customer_id VARCHAR); CREATE TABLE customers (id VARCHAR, first_name VARCHAR, last_name VARCHAR)
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SELECT COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = "Lucas" AND T1.last_name = "Mancini"
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Qual é a quantia total de dinheiro gasto por Lucas Mancini?
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CREATE TABLE invoices (total INTEGER, customer_id VARCHAR); CREATE TABLE customers (id VARCHAR, first_name VARCHAR, last_name VARCHAR)
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SELECT SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = "Lucas" AND T1.last_name = "Mancini"
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Lista todos os tipos de mídia.
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CREATE TABLE media_types (name VARCHAR)
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SELECT name FROM media_types
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Lista todos os diferentes tipos de gênero.
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CREATE TABLE genres (name VARCHAR)
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SELECT DISTINCT name FROM genres
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Escreva o nome de todas as playlists.
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CREATE TABLE playlists (name VARCHAR)
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SELECT name FROM playlists
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Quem é o compositor da faixa "Fast As a Shark"?
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CREATE TABLE tracks (composer VARCHAR, name VARCHAR)
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SELECT composer FROM tracks WHERE name = "Fast As a Shark"
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Quanto tempo dura o "Fast As a Shark"?
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CREATE TABLE tracks (milliseconds VARCHAR, name VARCHAR)
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SELECT milliseconds FROM tracks WHERE name = "Fast As a Shark"
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Como se chamam as faixas cujo gênero é rock?
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CREATE TABLE genres (id VARCHAR, name VARCHAR); CREATE TABLE tracks (name VARCHAR, genre_id VARCHAR)
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SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = "Rock"
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Qual é o título do álbum do qual a faixa "Balls to the Wall" pertence?
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CREATE TABLE tracks (genre_id VARCHAR, name VARCHAR); CREATE TABLE albums (title VARCHAR, id VARCHAR)
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SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T2.name = "Balls to the Wall"
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Lista de nomes de todas as faixas de "Balls to the Wall".
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CREATE TABLE tracks (name VARCHAR, genre_id VARCHAR); CREATE TABLE albums (id VARCHAR, title VARCHAR)
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SELECT T2.name FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.title = "Balls to the Wall"
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Lista de títulos de álbuns com o número de faixas maior que 10.
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CREATE TABLE tracks (album_id VARCHAR); CREATE TABLE albums (title VARCHAR, id VARCHAR)
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SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.album_id GROUP BY T1.id HAVING COUNT(T1.id) > 10
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Liste o nome das faixas pertencentes ao gênero Rock e cujo tipo de mídia é arquivo de áudio MPEG.
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CREATE TABLE genres (id VARCHAR, name VARCHAR); CREATE TABLE tracks (name VARCHAR, genre_id VARCHAR, media_type_id VARCHAR); CREATE TABLE media_types (id VARCHAR, name VARCHAR)
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SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = "Rock" AND T3.name = "MPEG audio file"
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Lista o nome das faixas pertence ao gênero Rock ou o tipo de mídia é o arquivo de áudio MPEG.
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CREATE TABLE genres (id VARCHAR, name VARCHAR); CREATE TABLE tracks (name VARCHAR, genre_id VARCHAR, media_type_id VARCHAR); CREATE TABLE media_types (id VARCHAR, name VARCHAR)
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SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = "Rock" OR T3.name = "MPEG audio file"
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Lista o nome das faixas pertence ao gênero Rock ou gênero Jazz.
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CREATE TABLE genres (id VARCHAR, name VARCHAR); CREATE TABLE tracks (name VARCHAR, genre_id VARCHAR)
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SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = "Rock" OR T1.name = "Jazz"
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Listar o nome de todas as faixas nas playlists de Filmes.
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CREATE TABLE playlists (id VARCHAR, name VARCHAR); CREATE TABLE playlist_tracks (track_id VARCHAR, playlist_id VARCHAR); CREATE TABLE tracks (name VARCHAR, id VARCHAR)
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SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T3.id = T2.playlist_id WHERE T3.name = "Movies"
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Escreva o nome da lista de reprodução que tem número de faixas maior do que 100.
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CREATE TABLE playlist_tracks (playlist_id VARCHAR, track_id VARCHAR); CREATE TABLE playlists (name VARCHAR, id VARCHAR)
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SELECT T2.name FROM playlist_tracks AS T1 JOIN playlists AS T2 ON T2.id = T1.playlist_id GROUP BY T1.playlist_id HAVING COUNT(T1.track_id) > 100
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Listar todas as faixas compradas pelo cliente Daan Peeters.
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CREATE TABLE invoices (id VARCHAR, customer_id VARCHAR); CREATE TABLE invoice_lines (track_id VARCHAR, invoice_id VARCHAR); CREATE TABLE tracks (name VARCHAR, id VARCHAR); CREATE TABLE customers (id VARCHAR, first_name VARCHAR, last_name VARCHAR)
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SELECT T1.name FROM tracks AS T1 JOIN invoice_lines AS T2 ON T1.id = T2.track_id JOIN invoices AS T3 ON T3.id = T2.invoice_id JOIN customers AS T4 ON T4.id = T3.customer_id WHERE T4.first_name = "Daan" AND T4.last_name = "Peeters"
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Quanto custa a faixa Fast As a Shark?
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CREATE TABLE tracks (unit_price VARCHAR, name VARCHAR)
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SELECT unit_price FROM tracks WHERE name = "Fast As a Shark"
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Encontre o nome das faixas que estão na playlist de filmes, mas não na playlist de música.
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CREATE TABLE playlists (id VARCHAR, name VARCHAR); CREATE TABLE playlist_tracks (track_id VARCHAR, playlist_id VARCHAR); CREATE TABLE tracks (name VARCHAR, id VARCHAR)
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SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' EXCEPT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music'
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Encontre o nome das faixas que estão em ambas as listas de reprodução de filmes e música.
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CREATE TABLE playlists (id VARCHAR, name VARCHAR); CREATE TABLE playlist_tracks (track_id VARCHAR, playlist_id VARCHAR); CREATE TABLE tracks (name VARCHAR, id VARCHAR)
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SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' INTERSECT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music'
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Encontrar o número de faixas em cada gênero?
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CREATE TABLE tracks (genre_id VARCHAR); CREATE TABLE genres (name VARCHAR, id VARCHAR)
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SELECT COUNT(*), T1.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id GROUP BY T1.name
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Quantos editores há?
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CREATE TABLE editor (Id VARCHAR)
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SELECT COUNT(*) FROM editor
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Escreva os nomes dos editores em ordem ascendente de idade.
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CREATE TABLE editor (Name VARCHAR, Age VARCHAR)
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SELECT Name FROM editor ORDER BY Age
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Quais são os nomes e idades dos editores?
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CREATE TABLE editor (Name VARCHAR, Age VARCHAR)
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SELECT Name, Age FROM editor
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Escreva os nomes dos editores com mais de 25 anos.
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CREATE TABLE editor (Name VARCHAR, Age INTEGER)
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SELECT Name FROM editor WHERE Age > 25
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Mostrar os nomes dos editores com 24 ou 25 anos.
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CREATE TABLE editor (Name VARCHAR, Age VARCHAR)
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SELECT Name FROM editor WHERE Age = 24 OR Age = 25
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Qual é o nome do editor mais novo?
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CREATE TABLE editor (Name VARCHAR, Age VARCHAR)
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SELECT Name FROM editor ORDER BY Age LIMIT 1
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Qual é a idade dos editores?
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CREATE TABLE editor (Age VARCHAR)
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SELECT Age, COUNT(*) FROM editor GROUP BY Age
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Por favor, indique a idade mais comum dos editores.
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CREATE TABLE editor (Age VARCHAR)
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SELECT Age FROM editor GROUP BY Age ORDER BY COUNT(*) DESC LIMIT 1
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Mostrar os temas distintos dos periódicos.
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CREATE TABLE journal (Theme VARCHAR)
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SELECT DISTINCT Theme FROM journal
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Indique os nomes dos editores e o tema das revistas para as quais eles servem em comitês.
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CREATE TABLE journal_committee (Editor_ID VARCHAR, Journal_ID VARCHAR); CREATE TABLE editor (Name VARCHAR, Editor_ID VARCHAR); CREATE TABLE journal (Theme VARCHAR, Journal_ID VARCHAR)
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SELECT T2.Name, T3.Theme FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID
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Mostrar os nomes e idades dos editores e o tema das revistas para as quais eles servem em comitês, em ordem alfabética ascendente do tema.
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CREATE TABLE journal_committee (Editor_ID VARCHAR, Journal_ID VARCHAR); CREATE TABLE editor (Name VARCHAR, age VARCHAR, Editor_ID VARCHAR); CREATE TABLE journal (Theme VARCHAR, Journal_ID VARCHAR)
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SELECT T2.Name, T2.age, T3.Theme FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID ORDER BY T3.Theme
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Mostrar os nomes dos editores que estão no comitê de revistas com vendas maiores que 3000.
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CREATE TABLE journal_committee (Editor_ID VARCHAR, Journal_ID VARCHAR); CREATE TABLE editor (Name VARCHAR, Editor_ID VARCHAR); CREATE TABLE journal (Journal_ID VARCHAR, Sales INTEGER)
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SELECT T2.Name FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID WHERE T3.Sales > 3000
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Mostrar a identidade, o nome de cada editor e o número de comitês de revistas em que eles estão.
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CREATE TABLE editor (editor_id VARCHAR, Name VARCHAR, Editor_ID VARCHAR); CREATE TABLE journal_committee (Editor_ID VARCHAR)
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SELECT T1.editor_id, T1.Name, COUNT(*) FROM editor AS T1 JOIN journal_committee AS T2 ON T1.Editor_ID = T2.Editor_ID GROUP BY T1.editor_id
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Mostrar os nomes dos editores que estão em pelo menos dois comitês de revistas.
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CREATE TABLE editor (Name VARCHAR, Editor_ID VARCHAR); CREATE TABLE journal_committee (Editor_ID VARCHAR)
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SELECT T1.Name FROM editor AS T1 JOIN journal_committee AS T2 ON T1.Editor_ID = T2.Editor_ID GROUP BY T1.Name HAVING COUNT(*) >= 2
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Escreva os nomes dos editores que não fazem parte de nenhum comitê de revistas.
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CREATE TABLE editor (Name VARCHAR, editor_id VARCHAR); CREATE TABLE journal_committee (Name VARCHAR, editor_id VARCHAR)
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SELECT Name FROM editor WHERE NOT editor_id IN (SELECT editor_id FROM journal_committee)
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Escreva a data, o tema e as vendas da revista que não tinha nenhum dos editores listados servindo no comitê.
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CREATE TABLE journal_committee (journal_ID VARCHAR); CREATE TABLE journal (date VARCHAR, theme VARCHAR, sales VARCHAR); CREATE TABLE journal (date VARCHAR, theme VARCHAR, sales VARCHAR, journal_ID VARCHAR)
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SELECT date, theme, sales FROM journal EXCEPT SELECT T1.date, T1.theme, T1.sales FROM journal AS T1 JOIN journal_committee AS T2 ON T1.journal_ID = T2.journal_ID
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Qual é a média de vendas dos jornais que têm um editor cujo tipo de trabalho é 'Foto'?
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CREATE TABLE journal_committee (journal_ID VARCHAR, work_type VARCHAR); CREATE TABLE journal (sales INTEGER, journal_ID VARCHAR)
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SELECT AVG(T1.sales) FROM journal AS T1 JOIN journal_committee AS T2 ON T1.journal_ID = T2.journal_ID WHERE T2.work_type = 'Photo'
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Quantas contas temos?
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CREATE TABLE Accounts (Id VARCHAR)
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SELECT COUNT(*) FROM Accounts
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Mostrar identidades, clientes, nomes de todas as contas.
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CREATE TABLE Accounts (account_id VARCHAR, customer_id VARCHAR, account_name VARCHAR)
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SELECT account_id, customer_id, account_name FROM Accounts
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Mostrar outros dados da conta para a conta com o nome 338.
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CREATE TABLE Accounts (other_account_details VARCHAR, account_name VARCHAR)
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SELECT other_account_details FROM Accounts WHERE account_name = "338"
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Qual é o nome, apelido e telefone do cliente com o nome da conta 162?
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CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_phone VARCHAR, customer_id VARCHAR); CREATE TABLE Accounts (customer_id VARCHAR, account_name VARCHAR)
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SELECT T2.customer_first_name, T2.customer_last_name, T2.customer_phone FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.account_name = "162"
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Quantas contas tem o cliente com o nome Art e o apelido Turcotte?
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CREATE TABLE Accounts (customer_id VARCHAR); CREATE TABLE Customers (customer_id VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR)
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SELECT COUNT(*) FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Art" AND T2.customer_last_name = "Turcotte"
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Mostrar todas as identidades dos clientes e o número de contas de cada cliente.
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CREATE TABLE Accounts (customer_id VARCHAR)
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SELECT customer_id, COUNT(*) FROM Accounts GROUP BY customer_id
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Mostrar o número de conta e o número de cliente com a maioria das contas.
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CREATE TABLE Accounts (customer_id VARCHAR)
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SELECT customer_id, COUNT(*) FROM Accounts GROUP BY customer_id ORDER BY COUNT(*) DESC LIMIT 1
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Qual é o primeiro cliente, nome e identidade com menor número de contas.
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CREATE TABLE Accounts (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR)
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SELECT T2.customer_first_name, T2.customer_last_name, T1.customer_id FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY COUNT(*) LIMIT 1
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Mostrar o número de todos os clientes sem uma conta.
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CREATE TABLE Customers (customer_id VARCHAR); CREATE TABLE Accounts (customer_id VARCHAR)
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SELECT COUNT(*) FROM Customers WHERE NOT customer_id IN (SELECT customer_id FROM Accounts)
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Mostrar os nomes e apelidos dos clientes sem qualquer conta.
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CREATE TABLE Accounts (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR)
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SELECT customer_first_name, customer_last_name FROM Customers EXCEPT SELECT T1.customer_first_name, T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id
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Mostrar nomes e apelidos distintos para todos os clientes com uma conta.
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CREATE TABLE Accounts (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR)
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SELECT DISTINCT T1.customer_first_name, T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id
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Quantos clientes têm uma conta?
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CREATE TABLE Accounts (customer_id VARCHAR)
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SELECT COUNT(DISTINCT customer_id) FROM Accounts
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Quantos clientes temos?
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CREATE TABLE Customers (Id VARCHAR)
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SELECT COUNT(*) FROM Customers
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Mostre identificação, nome, apelido e telefone de todos os clientes.
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CREATE TABLE Customers (customer_id VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR, customer_phone VARCHAR)
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SELECT customer_id, customer_first_name, customer_last_name, customer_phone FROM Customers
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Qual é o telefone e e-mail do cliente com nome Aniyah e sobrenome Feest?
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CREATE TABLE Customers (customer_phone VARCHAR, customer_email VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR)
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SELECT customer_phone, customer_email FROM Customers WHERE customer_first_name = "Aniyah" AND customer_last_name = "Feest"
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Mostre o número de cartões de cliente.
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CREATE TABLE Customers_cards (Id VARCHAR)
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SELECT COUNT(*) FROM Customers_cards
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Mostrar identificação, identificação do cliente, códigos do tipo de cartão, números de cartão para todos os cartões.
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CREATE TABLE Customers_cards (card_id VARCHAR, customer_id VARCHAR, card_type_code VARCHAR, card_number VARCHAR)
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SELECT card_id, customer_id, card_type_code, card_number FROM Customers_cards
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Indicar a data de validade a partir e a data de validade até ao cartão com o número de cartão "4560596484842".
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CREATE TABLE Customers_cards (date_valid_from VARCHAR, date_valid_to VARCHAR, card_number VARCHAR)
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SELECT date_valid_from, date_valid_to FROM Customers_cards WHERE card_number = "4560596484842"
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Qual é o nome, apelido e telefone do cliente com cartão 4560596484842.
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CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_phone VARCHAR, customer_id VARCHAR); CREATE TABLE Customers_cards (customer_id VARCHAR, card_number VARCHAR)
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SELECT T2.customer_first_name, T2.customer_last_name, T2.customer_phone FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.card_number = "4560596484842"
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Quantos cartões tem o cliente Art Turcotte?
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CREATE TABLE Customers_cards (customer_id VARCHAR); CREATE TABLE Customers (customer_id VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR)
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SELECT COUNT(*) FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Art" AND T2.customer_last_name = "Turcotte"
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Quantos cartões de débito temos?
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CREATE TABLE Customers_cards (card_type_code VARCHAR)
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SELECT COUNT(*) FROM Customers_cards WHERE card_type_code = "Debit"
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Quantos cartões de crédito tem a cliente Blanche Huels?
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CREATE TABLE Customers_cards (customer_id VARCHAR, card_type_code VARCHAR); CREATE TABLE Customers (customer_id VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR)
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SELECT COUNT(*) FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Blanche" AND T2.customer_last_name = "Huels" AND T1.card_type_code = "Credit"
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Mostrar todas as identidades dos clientes e o número de cartões de cada cliente.
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CREATE TABLE Customers_cards (customer_id VARCHAR)
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SELECT customer_id, COUNT(*) FROM Customers_cards GROUP BY customer_id
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Qual é a identificação do cliente com mais cartões, e quantos ele tem?
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CREATE TABLE Customers_cards (customer_id VARCHAR)
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SELECT customer_id, COUNT(*) FROM Customers_cards GROUP BY customer_id ORDER BY COUNT(*) DESC LIMIT 1
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Mostrar o número de identificação, o nome e o apelido de todos os clientes com pelo menos dois cartões.
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CREATE TABLE Customers_cards (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR)
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SELECT T1.customer_id, T2.customer_first_name, T2.customer_last_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING COUNT(*) >= 2
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Qual é o número de clientes, nome e sobrenome com o menor número de contas.
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CREATE TABLE Customers_cards (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR)
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SELECT T1.customer_id, T2.customer_first_name, T2.customer_last_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY COUNT(*) LIMIT 1
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Indicar todos os códigos do tipo de cartão e o número de cartões de cada tipo.
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CREATE TABLE Customers_cards (card_type_code VARCHAR)
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SELECT card_type_code, COUNT(*) FROM Customers_cards GROUP BY card_type_code
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