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https://whatisconvert.com/234-gallons-in-imperial-tablespoons | math | Convert 234 Gallons to Imperial Tablespoons
To calculate 234 Gallons to the corresponding value in Imperial Tablespoons, multiply the quantity in Gallons by 266.45574020752 (conversion factor). In this case we should multiply 234 Gallons by 266.45574020752 to get the equivalent result in Imperial Tablespoons:
234 Gallons x 266.45574020752 = 62350.643208559 Imperial Tablespoons
234 Gallons is equivalent to 62350.643208559 Imperial Tablespoons.
How to convert from Gallons to Imperial Tablespoons
The conversion factor from Gallons to Imperial Tablespoons is 266.45574020752. To find out how many Gallons in Imperial Tablespoons, multiply by the conversion factor or use the Volume converter above. Two hundred thirty-four Gallons is equivalent to sixty-two thousand three hundred fifty point six four three Imperial Tablespoons.
Definition of Gallon
The gallon (abbreviation "gal"), is a unit of volume which refers to the United States liquid gallon. There are three definitions in current use: the imperial gallon (≈ 4.546 L) which is used in the United Kingdom and semi-officially within Canada, the United States (liquid) gallon (≈ 3.79 L) which is the commonly used, and the lesser used US dry gallon (≈ 4.40 L).
Definition of Imperial Tablespoon
An imperial tablespoon (abbreviation tbsp, "Tb." or T.) is exactly 15 ml (0.51 US fl oz). A tablespoon is a large spoon used for serving or eating. In many English-speaking regions, the term now refers to a large spoon used for serving, however, in some regions, including parts of Canada, it is the largest type of spoon used for eating. By extension, the term is used as a measure of volume in cooking.
Using the Gallons to Imperial Tablespoons converter you can get answers to questions like the following:
- How many Imperial Tablespoons are in 234 Gallons?
- 234 Gallons is equal to how many Imperial Tablespoons?
- How to convert 234 Gallons to Imperial Tablespoons?
- How many is 234 Gallons in Imperial Tablespoons?
- What is 234 Gallons in Imperial Tablespoons?
- How much is 234 Gallons in Imperial Tablespoons?
- How many uk tbsp are in 234 gal?
- 234 gal is equal to how many uk tbsp?
- How to convert 234 gal to uk tbsp?
- How many is 234 gal in uk tbsp?
- What is 234 gal in uk tbsp?
- How much is 234 gal in uk tbsp? | s3://commoncrawl/crawl-data/CC-MAIN-2023-23/segments/1685224653501.53/warc/CC-MAIN-20230607010703-20230607040703-00082.warc.gz | CC-MAIN-2023-23 | 2,292 | 23 |
http://birdsallgraphics.com/error-bound/error-bound-for-taylor-polynomials-examples.php | math | The system returned: (22) Invalid argument The remote host or network may be down. I'll give the formula, then explain it formally, then do some examples. We have where bounds on the given interval . Arbetar ... http://birdsallgraphics.com/error-bound/error-bound-taylor-polynomials.php
You can change this preference below. Krista King 13 943 visningar 12:03 Find error bound for approximating f(x) values with a Taylor polynomial - Längd: 8:40. for some z in [0,x]. Automatisk uppspelning När automatisk uppspelning är aktiverad spelas ett föreslaget videoklipp upp automatiskt. http://math.jasonbhill.com/courses/fall-2010-math-2300-005/lectures/taylor-polynomial-error-bounds
So, we force it to be positive by taking an absolute value. So the error at "a" is equal to f of a minus p of a, and once again I won't write the sub n and sub a, you can just assume Ideally, the remainder term gives you the precise difference between the value of a function and the approximation Tn(x). What we can continue in the next video, is figure out, at least can we bound this, and if we're able to bound this, if we're able to figure out an
CAL BOYS 4 721 visningar 3:32 Find degree of Taylor polynomial so error is less than a given error value - Längd: 6:02. F of a is equal to p of a, so there error at "a" is equal to zero. Now let's think about something else. Lagrange Error Bound Proof Here is a list of the three examples used here, if you wish to jump straight into one of them.
Now, if we're looking for the worst possible value that this error can be on the given interval (this is usually what we're interested in finding) then we find the maximum And this general property right over here, is true up to and including n. DrPhilClark 38 394 visningar 9:33 Lagrange Error Bound Problem - Längd: 3:32. https://www.khanacademy.org/video/proof-bounding-the-error-or-remainder-of-a-taylor-polynomial-approximation Since takes its maximum value on at , we have .
And we've seen that before. Error Bound Formula Statistics Logga in om du vill rapportera olämpligt innehåll. Logga in Dela Mer Rapportera Vill du rapportera videoklippet? Basic Examples Find the error bound for the rd Taylor polynomial of centered at on .
Explanation We derived this in class. http://math.oregonstate.edu/home/programs/undergrad/CalculusQuestStudyGuides/SandS/PowerSeries/error_bounds.html The first derivative is 2x, the second derivative is 2, the third derivative is zero. Lagrange Error Bound Formula The following example should help to make this idea clear, using the sixth-degree Taylor polynomial for cos x: Suppose that you use this polynomial to approximate cos 1: How accurate is Lagrange Error Bound Problems What is this thing equal to, or how should you think about this.
Toggle navigation Search Submit San Francisco, CA Brr, it´s cold outside Learn by category LiveConsumer ElectronicsFood & DrinkGamesHealthPersonal FinanceHome & GardenPetsRelationshipsSportsReligion LearnArt CenterCraftsEducationLanguagesPhotographyTest Prep WorkSocial MediaSoftwareProgrammingWeb Design & DevelopmentBusinessCareersComputers Online Courses this contact form Thus, we have In other words, the 100th Taylor polynomial for approximates very well on the interval . The distance between the two functions is zero there. If we assume that this is higher than degree one, we know that these derivatives are going to be the same at "a". Lagrange Error Bound Khan Academy
So it's literally the n+1th derivative of our function minus the n+1th derivative of our nth degree polynomial. Logga in Transkription Statistik 2 934 visningar 8 Gillar du videoklippet? And what I want to do in this video, since this is all review, I have this polynomial that's approximating this function, the more terms I have the higher degree of have a peek here However, you can plug in c = 0 and c = 1 to give you a range of possible values: Keep in mind that this inequality occurs because of the interval
Visa mer Läser in ... Alternating Series Error Bound And then plus go to the third derivative of f at a times x minus a to the third power, (I think you see where this is going) over three factorial, The following theorem tells us how to bound this error.
Let me actually write that down, because it's an interesting property. It's a first degree polynomial... Your email Submit RELATED ARTICLES Calculating Error Bounds for Taylor Polynomials Calculus Essentials For Dummies Calculus For Dummies, 2nd Edition Calculus II For Dummies, 2nd Edition Calculus Workbook For Dummies, 2nd Lagrange Error Bound Ap Calculus Bc What is the (n+1)th derivative of our error function.
It considers all the way up to the th derivative. Of course, this could be positive or negative. what's the n+1th derivative of it. Check This Out But what I want to do in this video is think about, if we can bound how good it's fitting this function as we move away from "a".
Here's the formula for the remainder term: So substituting 1 for x gives you: At this point, you're apparently stuck, because you don't know the value of sin c. VisningsköKöVisningsköKö Ta bort allaKoppla från Läser in ... So this is an interesting property. CalculusSeriesTaylor series approximationsVisualizing Taylor series approximationsGeneralized Taylor series approximationVisualizing Taylor series for e^xMaclaurin series exampleFinding power series through integrationEvaluating Taylor Polynomial of derivativePractice: Finding taylor seriesError of a Taylor polynomial approximationProof:
We define the error of the th Taylor polynomial to be That is, error is the actual value minus the Taylor polynomial's value. numericalmethodsguy 20 427 visningar 6:44 Taylor Polynomials of a Function of Two Variables - Längd: 12:51. If x is sufficiently small, this gives a decent error bound. And not even if I'm just evaluating at "a".
So because we know that p prime of a is equal to f prime of a when we evaluate the error function, the derivative of the error function at "a" that Försök igen senare. You built both of those values into the linear approximation. Läser in ...
Use a Taylor expansion of sin(x) with a close to 0.1 (say, a=0), and find the 5th degree Taylor polynomial. What you did was you created a linear function (a line) approximating a function by taking two things into consideration: The value of the function at a point, and the value So, the first place where your original function and the Taylor polynomial differ is in the st derivative. Funktionen är inte tillgänglig just nu.
That is, we're looking at Since all of the derivatives of satisfy , we know that . So for example, if someone were to ask: or if you wanted to visualize, "what are they talking about": if they're saying the error of this nth degree polynomial centered at You can get a different bound with a different interval. | s3://commoncrawl/crawl-data/CC-MAIN-2018-05/segments/1516084890874.84/warc/CC-MAIN-20180121195145-20180121215145-00740.warc.gz | CC-MAIN-2018-05 | 6,852 | 17 |
http://www.data.scec.org/Module/sec1pg17.html | math | The slip rate of a fault is the speed with which one side of the fault moves with respect to the other. Since tectonic plates move very slowly, these speeds are measured in units quite different from those we usually associate with measured speeds (for instance, highway traffic moving at kilometers per hour). Slip rates are generally measured in millimeters per year (mm/yr) -- in California, slip rates for faults range from 0 to about 38 mm/yr, though anything over 10 mm/yr is generally considered fast (a slip rate around 1 to 2 mm/yr might be considered average for a major, active fault).
A key fact about slip rates to keep in mind is that they do not represent constant motion along a fault, even though the motions of tectonic plates are constant. Instead, slip rates are averages of the total slip along a fault over a long period of time. Thus, a rate of 2 mm/yr does not mean that two points, one on each side of the fault, which are adjacent to begin with will be exactly two millimeters apart one year later. Instead, it might mean that the two points will remain adjacent for hundreds or thousands of years, then suddenly slide away from each other in a single episode of slip, typically consisting of several centimeters or even meters of offset.
If, as we said, the slip rate of the fault is 2 mm/yr, then the time it takes to move the two points away from each other, divided into the amount of distance between the two points at the end of that time, should yield a rate of roughly 2 mm/yr. This simply follows the formula for finding any average speed:
Figuring out the rate of slip along faults is a key in understanding the relative "importance" of faults in an area, and the hazard those faults present to local residents and developments. Slip rates can also tell us about changes in faults that have happened long ago -- well before recorded history.
There are several ways to determine the slip rate of a fault, and in the following pages, we will investigate how these methods work, and how different methods can produce different results. | s3://commoncrawl/crawl-data/CC-MAIN-2014-52/segments/1418802775669.60/warc/CC-MAIN-20141217075255-00040-ip-10-231-17-201.ec2.internal.warc.gz | CC-MAIN-2014-52 | 2,068 | 5 |
http://es.wikidoc.org/index.php/Block_design | math | In combinatorial mathematics, a block design (more fully, a balanced incomplete block design) is a particular kind of set system, which has long-standing applications to experimental design (an area of statistics) as well as purely combinatorial aspects.
Given a finite set X (of elements called points) and integers k, r, λ ≥ 1, we define a 2-design B to be a set of k-element subsets of X, called blocks, such that the number r of blocks containing x in X is independent of x, and the number λ of blocks containing given distinct points x and y in X is also independent of the choices.
Here v (the number of elements of X, called points), b (the number of blocks), k, r, and λ are the parameters of the design. (Also, B may not consist of all k-element subsets of X; that is the meaning of incomplete.) The design is called a (v, k, λ)-design or a (v, b, r, k, λ)-design. The parameters are not all independent; v, k, and λ determine b and r, and not all combinations of v, k, and λ are possible. The two basic equations connecting these parameters are
A fundamental theorem (Fisher's inequality) is that b ≥ v in any block design. The case of equality is called a symmetric design; it has many special features.
Examples of block designs include the lines in finite projective planes (where X is the set of points of the plane and λ = 1), and Steiner triple systems (k = 3). The former is a relatively simple example of a symmetric design.
Given any integer t ≥ 2, a t-design B is a class of k-element subsets of X (the set of points) , called blocks, such that the number r of blocks that contain any point x in X is independent of x, and the number λ of blocks that contain any given t-element subset T is independent of the choice of T. The numbers v (the number of elements of X), b (the number of blocks), k, r, λ, and t are the parameters of the design. The design may be called a t-(v,k,λ)-design. Again, these four numbers determine b and r and the four numbers themselves cannot be chosen arbitrarily. The equations are
where bi is the number of blocks that contain any i-element set of points.
Examples include the d-dimensional subspaces of a finite projective geometry (where t = d + 1 and λ = 1).
The term block design by itself usually means a 2-design.
- van Lint, J.H., and R.M. Wilson (1992), A Course in Combinatorics. Cambridge, Eng.: Cambridge University Press. | s3://commoncrawl/crawl-data/CC-MAIN-2020-29/segments/1593657146845.98/warc/CC-MAIN-20200713194203-20200713224203-00411.warc.gz | CC-MAIN-2020-29 | 2,402 | 10 |
https://dev.cemetech.net/forum/viewtopic.php?t=14605&view=next | math | - Linear regression through origin on casio fx7400 GII
- 23 Oct 2018 09:40:28 am
Hi! I'm currently taking a class where for a given problem we have a set of data, where the line of best fit must pass through the origin (conversion must equal zero when time is zero). I own a casio FX7400 GII and the only tipes of linear regression I found were y=ax+b or y=a+bx. Is it posible to find a way to make the y-intercept be zero on this calculator? | s3://commoncrawl/crawl-data/CC-MAIN-2024-18/segments/1712296818337.62/warc/CC-MAIN-20240422175900-20240422205900-00244.warc.gz | CC-MAIN-2024-18 | 442 | 3 |
http://vkb.bathroomshowercurtains.info/bumper-sticker-essay.html | math | In fact, Mandelbrot also argues for this strategy. Taleb co-authored a paper arguing that most people systematically underestimate volatility. Furthermore, he argues there exists not only a lack of appreciation of fat tails, but a preference for positive skew , in that people prefer assets that jump up, not down, which would imply the superiority of buying out-of-the-money puts as opposed to calls because those negative tails that increase the price of puts are is affiliate with some fund that tend to be long tail risk, presumably by being long deep out-of-the-money options, but selling at-the-money options, a locally delta and vega neutral strategy.
These assertions present some straightforward tests, which a Popperian like Taleb should embrace. Specifically, buying out-of-the-money options, especially puts (because of negative skew), should, on average, make money. But insurance companies, which basically are selling out-of-the-money options, tend to do as well as any industry (Warren Buffet has always favored insurance companies, especially re-insurers, as equity investments). Studies by Shumway and Coval (2001) and Bondarenko (2003) have documented that selling puts is where all the extranormal profit seems to be. Of all the option strategies, selling, not buying, out-of-the-money puts has been the best performer historically. Further, Sophie Ni finds that out-of-the-money options are more overexpensive the degree they are out-of-the-money. | s3://commoncrawl/crawl-data/CC-MAIN-2018-05/segments/1516084886979.9/warc/CC-MAIN-20180117212700-20180117232700-00440.warc.gz | CC-MAIN-2018-05 | 1,468 | 2 |
http://ieeexplore.ieee.org/xpl/articleDetails.jsp?reload=true&arnumber=1195655&contentType=Journals+%26+Magazines | math | Skip to Main Content
In the circuit model of receiving antennas, it is commonly assumed that there is no coupling between the load and the equivalent generator. Then the equivalent generator voltage is assumed to be the open-circuit voltage and the generator internal impedance is assumed to be the input impedance in the transmitting mode. In this investigation, these voltages and impedances are computed numerically for cylindrical antennas. From the numerical results, it is found that these two assumptions are not correct individually. However, it is found that the uncoupled-circuit model can yield correct results for the load current. Further, the validity of the uncoupled-circuit formula of the load current is proved by using the reciprocity theorem. Thereby, it is concluded that the uncoupled-circuit model can yield the correct result for the load current, but the open-circuit voltage and the input impedance are not at all identical to the equivalent generator voltage and the generator internal impedance, respectively. | s3://commoncrawl/crawl-data/CC-MAIN-2014-42/segments/1414119658026.51/warc/CC-MAIN-20141024030058-00035-ip-10-16-133-185.ec2.internal.warc.gz | CC-MAIN-2014-42 | 1,037 | 2 |
https://royalpitch.com/5-out-of-20-as-a-percentage/ | math | There are many ways to express fractions, including using the five out of twenty as a percentage. Fractions are a common way to express fractions. Whether you want to be more precise or use the simplest method possible, a fraction calculator is a helpful tool. You can also input decimal values to the calculator. After you have entered the desired percentage, the calculator will calculate it using the following method.
First, multiply the fractions by 100. This will make the fractions look like decimals. Remember, this doesn’t change the value. Use the formula “3/5 = 100” to divide the numerator by denominator, and then multiply the result with 100%. This will give you the correct fraction. Then, you can multiply the result by 100 to get the correct percentage.
Then, multiply the result by five, so that the percentage becomes five. Five out of twenty equals five. The formula is 5/100. Add three to get the percentage you need. Likewise, you can multiply the answer by twenty to get a higher percentage. Similarly, seventy percent is equal to twenty-five, which is ten percent of twenty-five.
Then, take the fifth out of twenty and divide it by twenty. This gives you a percentage of seventy five. Then, divide the result by a hundred to get the percentage of five. This is a great way to convert fractions because the decimal part is the exact same as the numerator. It is easy to convert fractions into percent.
Another trick to use to convert fractions to percents is to divide the numerator by the denominator. Divide the numerator by its denominator to convert a fraction into a percent. To get a percentage, multiply the result 100 times. Then, you can divide by 5 and the result will be 60 percent. A C grade is between seventy-eighty and eighty, while an F grade is less than sixty.
A fifth grade is a sixth grade. The same applies to a fourth grade. A fifth out of twenty is fifty five percent, and a twenty five-percent is fourth. This means that a fifth grade student earned a B-grade and the other student received a A-grade. A five-out-of-twenty is a ninth-grade. Using a five-out-of-twenty as a percentage is an eighth-grade-in-fraction.
A fifth grade student is a sixth-grade student. It is a fifth-grade student. A ten-grade student is a ninth-grade grade. A five-grade second-grade student has a C-grade. A five-point score is a quarter of a point. A ten-point third-grade pupil scores are a ten-point average. The fourth-grade equivalent is a fifth-grade second-grade learner.
A third-grade student is a fourth-grade student. A fourth-grade student can be considered a fifth grade student. A seventh-grade student has a fourth-grade education. A sixth-grade scholar is an eighth-grade learner. A ninth-grade learner is a D. A college-level-student. If you earn a D, you’re barely passing. A D-grade is a twenty-five point grade.
Five-point students can also understand how to calculate the percentage five-point students. A five-point student can use a calculator to calculate the percentage of a percent of a student. Those who don’t know the formula can refer to a standardized tenth-grade student. You can convert a percentage if you are unsure how to represent it.
To convert a percent to a percentage, multiply your original number by the percent student. Add this number to the original value. The percent-point discount will be the result. The discounted value will be the discounted value. This is not difficult. However, it may not be as cool as juggling torches. Then, it will be worth it. If you’re a fifth-grade student, this method can be useful. | s3://commoncrawl/crawl-data/CC-MAIN-2023-40/segments/1695233510300.41/warc/CC-MAIN-20230927135227-20230927165227-00761.warc.gz | CC-MAIN-2023-40 | 3,600 | 10 |
https://www.homeofshanghai.com/properties/exquisite-2br-apartment-with-terrace-in-casa-lakeville/ | math | Popular Shanghai Rental Xintiandi Jing an French Concession Xujiahui Zhong Shan Park Hongqiao Gubei Nanjing West Road People Square Pudong Lujiazui Pudong century park Pudong International school Old house rent Shanghai Old apartment rent Shanghai New apartment rent Shanghai Serviced apartment Shanghai Service apartment rent Villa rent Shanghai Rent apartment Shanghai Houses in Shanghai Shanghai Expat housing
Shanghai Xintiandi 2BR Apartment to rent with Terrace in Casa Lakeville
33,000 per month
Wonderful apartment for rent in Xintiandi’s Casa Lakeville (the newest phase of the Lakevilles). With its generous floor plan for 2 bedrooms in Shanghai, this new apartment has a whopping 154sqm of space. The bright and warm living room, from where the terrace can be accessed, is the unit’s heart. Both the spacious master bedroom and the guest bedroom have a sunny and inviting atmosphere due to the large windows, letting in plenty of sunlight. The two bathrooms (one with bathtub) come with noble marble finishing and top quality fittings. The Western kitchen, as usual in this prime residential compound, leaves nothing to desire and features premium brand, imported appliances. The floorplan is completed by a storage room and a laundry balcony.
- Property Size: 154 square meters
- Bedrooms: 2
- Bathrooms: 2
Home entertainment system | s3://commoncrawl/crawl-data/CC-MAIN-2023-50/segments/1700679516047.98/warc/CC-MAIN-20231211174901-20231211204901-00833.warc.gz | CC-MAIN-2023-50 | 1,626 | 8 |
http://ikib.myq-see.com/ggwbwai.html | math | Koleksi tante girang
Partial fractions decomposition is the opposite of adding fractions, we are trying to break a rational expression into simpler fractions. It takes a lot of work, but is . This online calculator will simplify given rational expression.The detailed explanation is provided.This online calculator performs multiplication and division of algebraic fractions. The detailed explanation is provided.Rational Expressions Calculator (or Simplify Rational Expressions Calculator) is a rational calculator that finds the factors of a rational expression. If takes a . Oct 25, 2012 . Multiplying and Dividing Rational Expressions Calculator. Enter First Rational Expression, Enter Second Rational Expression. Enter the . Algebra Calculator is a free step-by-step calculator and algebra solver.. Adding Fractions: 1/3 + 1/4; Multiplying Fractions: (1/3) * (3/4). Solving Equations.This calculator will simplify fractions, polynomial, rational, radical, exponential, logarithmic, trigonometric, hyperbolic expressions.MathCelebrity.com's Simplify Radical Expressions Calculator – This calculator provides. .. MathPortal.org's Simplifying Rational Expressions Calculators – This . Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions. Rational Expressions and Equations.Explains how to simplify rational expressions, using many worked examples. Corrects the major mistake many students make. | s3://commoncrawl/crawl-data/CC-MAIN-2018-09/segments/1518891812579.21/warc/CC-MAIN-20180219091902-20180219111902-00312.warc.gz | CC-MAIN-2018-09 | 1,463 | 2 |
https://darkwing.uoregon.edu/~stevev/sd-archive/prelist/msg00044.html | math | [Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
ReplyTo : The Nitwit
ReplyFrom : Nitpicker Timothy
Hi Steve, I'm sorry to have frustrated you.
The reason I'm doing that is because you are always finding these wonderful
solutions and I can't stand that. :) No, not really of course, but it is
really difficult, as we all know by now, to find a method to harnas these
amounts of energy. I guess, if there was a easy and cheap way we would have
found it by now. We all are hoping to find some ingenious way to get around
all the problems at once, so all solutions are welcome. But also there is a
great possibility that these solutions will fail.
The only thing I can write is, let the new ideas come and try to explain why
you think they work.
Before you read any further I have to warn you :)
TAKE SOME VALIUM TABLETS AND TRY TO RELAX...
>see my web page
>for an idea that is consistant with Steve and Timothy's objections.
I almost dare not saying it but, how accurate is your calculator?
Let me recalculate the values of the various components:
a=55.47 m/s^2 (purple) b=27.73 m/s^2 (red)
Purple x-comp = a sin( 21) = 19.88 (you got 51.62)
Purple y-comp = a cos( 21) = 51.79 (you got 20.3023)
Red x-comp = b cos(-48) = -18.55 (you got -18.9)
Red y-comp = b sin(-48) = -20.61 (you got -20.3021)
I checked all cos and sin formulas in the drawing and all seem to be OK, the
only things that are wrong are the final decimal numbers.
If you now sum the several components:
y=51.79-20.61=31.18 (This value is too high to compensate)
(You wrote the formulas where you calculated the accelerations wrong but the
answers seemed right)
If you think other angles would make your system work, I still am certain it
If you want to give it a try here are more general formulas:
t is the angle for which you took 21
a=2b (reflected momentum is twice the absorbed momentum)
remember t is between 0 and 90
x=Px+Rx=2b sin(t) + b cos(-2t)
y=Py+Ry=2b cos(t) + b sin(-2t)
only t=90 will make y equal to zero, but t=90 means the light goes straight
on, whithout touching the mirror or absorber. | s3://commoncrawl/crawl-data/CC-MAIN-2023-14/segments/1679296949025.18/warc/CC-MAIN-20230329182643-20230329212643-00620.warc.gz | CC-MAIN-2023-14 | 2,099 | 39 |
http://ecoworldquiz.com/2018/05/25/micro-static/ | math | Demand and supply are two principal variables that determine the equilibrium level for market. The quantity demanded of a good at a time is generally considered to be related to the price of that particular time. Same way supply is also related to price at particular static time. Thus microeconomics tries to find out the equality of demand and supply at a particular point of time or static time. This static analysis is the study of static relationship between two variable called demand and supply, which is known by micro static. In other words, if the functional relationship is established between two principles variable at a same period of time, such analysis is known by micro static. This situation is also known by equilibrium situation of variables. This equilibrium determines the equilibrium price and quantity. According to Schumpeter, “By static analysis, we mean, method of dealing with economic phenomena that tries to established relations between elements of the economic systems-prices and quantities of commodities all of which have the same time subscript, that is to say, refer to the same point of time.” He further said, “Static analysis tries to establish relation between elements of the economic system which refer to the same point of time.”
The concept of micro static is given below with the help of diagram.
In the diagram given above, DD shows demand curve and SS shows supply curve. Both curves intersect at point ‘E’ that gives the equilibrium price- P and quantity- Q at particular time period. This is static analysis. | s3://commoncrawl/crawl-data/CC-MAIN-2021-17/segments/1618038069133.25/warc/CC-MAIN-20210412175257-20210412205257-00449.warc.gz | CC-MAIN-2021-17 | 1,569 | 3 |
http://rac.mynewsdesk.com/latest_news/tag/defra | math | Tag / Defra
News • Apr 27, 2016 11:50 BST
The RAC's Nick Lyes comments on the findings of a new air quality report from a Government select committee
News • Sep 17, 2015 10:56 BST
On 12 September, Defra published a consultation on air quality to seek views from local and transport authorities, businesses and members of the public on what local action can be taken to improve air quality. | s3://commoncrawl/crawl-data/CC-MAIN-2018-34/segments/1534221212598.67/warc/CC-MAIN-20180817143416-20180817163416-00338.warc.gz | CC-MAIN-2018-34 | 397 | 5 |
https://books.google.la/books?id=sEcTJe38T4QC&pg=PA276&focus=viewport&vq=remarks&dq=editions:OCLC1012786239&output=text | math | « PreviousContinue »
that the phenomena of the precession and nutation must be the same in the actual state of our terraqueous spheroid, as if the whole was a solid mass; and that this is true, whatever be the irregularity of the depth of the sea. He shows also, that currents in the sea, rivers, trade-winds, even earthquakes, can have no effect in altering the earth's rotation on its axis. The conclusions with regard to the constitution of the earth that are found to agree with the actual quantity of the precession of the equinoxes are, that the density of the earth increases from the circumference toward the centre; that it has the form of an ellipsoid of revolution, or, as we use to call it, of an elliptic spheroid, and that the compression of this spheroid at the poles is between the limits of and part of the radius of the equator.
The Second part of La Place's work, has, for its object, a fuller development of the disturbances of the planets, both primary and secondary, than was compatible with the limits of the First part. After the ample detail into which we have entered concerning two of these subjects, the theory of the moon, and the perturbations of the primary planets, we need not enlarge on them further, though they are prosecuted in the second part of this work, and form the subject of the Sixth and Seventh books. In the Second book, the inequalities had been explained, that depend on the simple power of the eccentricity: here we have those that depend on the second and higher powers of the same quantity; and such are the secular equations of Jupiter and Saturn, abovementioned. The numeral computations are then performed, and every thing prepared for the complete construction of astronomical tables, as the final result of all these investigations. The calculations, of course, are of vast extent and difficulty, and incredibly laborious. In carrying them on, La Place had the assistance, as he informs us, of De Lambre, Bouvard, and other members of the institute. The labour is indeed quite beyond the power of any individual to execute.
The same may be said of the Seventh book, which is devoted to a similar development of the lunar theory. We can enter into no further detail on this subject. One fact we cannot help mentioning, which is to the credit of two British astronomers, Messrs Mason and Dixon, who gave a new edition of Mayer's tables, more diligently compared with observation, and therefore more accurate, than the original one. Among other improvements, was an empirical equation, amounting to a little more than 20" when a maximum, which was not founded on theory, but was employed because it made the tables agree better with observation. As this equation, however, was not derived from
principle (for the two astronomers, just named, though accurate observers and calculators, were not skilled enough in the mathematics to attempt deducing it from principle), it was generally rejected by other astronomers. La Place, however, found that it was not to be rejected; but, in reality, proceeded from the compression of the earth at the poles, which prevents the gravitation to the earth from decreasing, precisely as the squares of the distances increase, and by that means produces this small irregularity. The quantity of the polar compression that agrees best with this, and some other of the lunar irregularities, is nearly that which was stated aboved, of the mean radius of the earth. The ellipticity of the sun does, in like manner, affect the primary planets; but, as its influence diminishes fast as the distance increases, it extends no further (in any sensible degree) than the orbit of Mercury, where its only effect is to produce a very small direct movement of the line of the apsides, and an equal retrograde motion of the nodes, relatively to the sun's equator. We may judge from this, to what minuteness the researches of this author have extended: and, in general, when accuracy is the object to be obtained, the smaller the quantity to be determined, the more difficult the investigation.
The Eighth book has for its object, to calculate the disturbances produced by the action of the secondary planets on one another; and particularly refers to the satellites of Jupiter, the only system of secondary planets on which accurate observations have been, or, probably, can be made. Though these satellites have been known only since the invention of the telescope, yet the quickness of their revolutions has, in the space of two centuries, exhibited all the changes which time develops so slowly in the system of the primary planets; so that there are abundant materials for a comparison between fact and theory. The general principles of the theory are the same that were explained in the Second book; but there are some peculiarities, that arise from the constitution of Jupiter's system, that deserve to be considered. We have seen, above, what is the effect of commensurability, or an approach to it, in the mean motion of contiguous planets; and here we have another example of the same. The mean motions of the three first satellites of Jupiter, are nearly as the numbers 4, 2, and ; and hence a periodical system of inequalities, which our astronomer Bradley was sharp-sighted enough to discover in the observation of the eclipses of these satellites, and to state as amounting to 437.6 days. This is now fully explained from the theory of the action of the satellites.
Another singularity in this secondary system, is, that the mean longitude of the first satellite minus three times that of
the second, plus twice that of the third, never differs from two right angles but by a quantity almost insensible.
One can hardly suppose that the original motions were so adjusted as to answer exactly to this condition; it is more natural to suppose that they were only nearly 'so adjusted, and that the exact comcidence has been brought about by their mutual action. This conjecture is verified by the theory, where it is demonstrated that such a change might have been actually produced in the mean motion by the mutual action of those planetary bodies, after which the system would remain stable, and no further change in those motions would take place.
Not only are the mutual actions of the satellites taken into account in the estimate of their irregularities, but the effect of Jupiter's spheroidal figure is also introduced. Even the masses of the satellites are inferred from their effect in disturbing the motions of one another.
In the Ninth book La Place treats of Comets, of the methods of determining their orbits, and of the disturbances they suffer from the planets. We cannot follow him in this; and have only to to add, that his profound and elaborate researches are such as we might expect from the author of the preceding investigations.
The Tenth book is more miscellaneous than any of the preceding; it treats of different points relative to the system of the world. One of the most important of these is astronomical refraction. The rays of light from the celestial bodies, on entering the earth's atmosphere, meet with strata that are more dense the nearer they approach to the earth's surface; they are therefore bent continually toward the denser medium, and describe curves that have their concavity turned toward the earth. The angle formed by the original direction of the ray, and its direction at the point where it enters the eye, is called the astronomical refraction. La Place seeks to determine this angle by tracing the path of the ray through the atmosphere; a research of no inconsiderable difficulty, and in which the author has occasion to display his skill both in mathematical and in inductive investigation. The method he pursues in the latter is deserving of attention, as it is particularly well adapted to cases that occur often in the more intricate kinds of physical discussion.
The path of the ray would be determined from the laws of refraction, did we know the law by which the density of the air decreases from the earth upwards. This last, however, is not known, except for a small extent near the surface of the earth, so that we appear here to be left without sufficient data for continuing the investigation. We must, therefore, ei
ther abandon the problem altogether, or resolve it hypothetically, that is, by assuming some hypothesis as to the decrease of the density of the atmosphere. Little would be gained by this last, except as an exercise in mathematical investigation, if it were not that the total quantity of the refraction for a given altitude can be accurately determined by observation. La Place, availing himself of this consideration, begins with making a supposition concerning the law of the density, that is not very remote from the truth, (as we are assured of from the relation between the density of air and the force with which it is compressed); and he compares the horizontal refraction calculated on this assumption with that which is known to be its true quantity. The first hypothesis which he assumes, is that of the density being the same throughout; this gives the total refraction too small, and falls on that account to be rejected, even if it were liable to no other objection. The second hypothesis supposes a uniform temperature through the whole extent of the atmosphere, or it supposes that the density decreases in geometrical proportion, while the distance from the earth increases in arithmetical. The refraction which results is too great; so that this supposition must also be rejected.
If we now suppose the density of the air to decrease in arithmetical progression, while the height does the same, and integrate the differential equation to the curve described by the ray, on this hypothesis, the horizontal refraction is too small, but nearer the truth than on the first hypothesis. A supposition intermediate between that which gave the refraction too great, and this which gives it too small, is therefore to be assumed as that which approaches the nearest to the truth. It is this way of limiting his conjectures by repeated trials, and of extracting from each, by means of the calculus, all the consequences involved in it, that we would recommend to experimenters, as affording one of the most valuable and legitimate uses of hypothetical reasoning. He then employs an intermediate hypothesis for the diminution of the density of the air; which it is not easy to express in words, but from which he obtains a result that agrees with the horizontal refraction, and from which, of course, he proceeds to deduce the refraction for all other altitudes. The table, so constructed, we have no doubt, will be found to contribute materially to the accuracy of astronomical observation.
The researches which immediately follow this, relate to the terrestrial refraction, and the measurement of heights by the barometer. The formula given for the latter, is more complicated than that which is usually employed with us in Britain, where
this subject has been studied with great care. In one respect, it is more general than any of our formulas; it contains an allowance for the difference of latitude. We are not sure whether this correction is of much importance, nor have we had leisure to compare the results with those of General Roy and Sir George Schuckborough. We hardly believe, that in point of accuracy, the two last can easily be exceeded.
The book concludes with a determination of the masses of the planets, more accurate than had been before given; and even of the satellites of Jupiter. Of all the attempts of the Newtonian philosophy,' says the late Adam Smith in his History of Astronomy, that which would appear to be the most above the reach of human reason and experience, is the attempt to compute the weights and densities of the sun, and of the several planets. What would this philosopher have said, if he had lived to see the same balance in which the vast body of the sun had been weighed, applied to examine such minute atoms as the satellites of Jupiter?
Such is the work of La Place, affording an example, which is yet solitary in the history of human knowledge, of a theory entirely complete; one that has not only accounted for all the phenomena that were known, but that has discovered many before unknown, which observation has since recognized. In this theory, not only the elliptic motion of the planets, relatively to the sun, but the irregularities produced by their mutual action, whether of the primary on the primary, of the primary on the secondary, or of the secondary on one another, are all deduced from the principle of gravitation, that mysterious power, which unites the most distant regions of space, and the most remote periods of duration. To this we must add the great truths brought in view and fully demonstrated, by tracing the action of the same power through all its mazes: That all the inequalities in our system are periodical; that, by a fixt appointment in nature, they are each destined to revolve in the same order, and between the same limits; that the mean distances of the planets from the sun, and the time of their revolutions round that body, are susceptible of no change whatsoever; that our system is thus secured against natural decay; order and regularity preserved in the midst of so many disturbing causes ;-and anarchy and misrule eternally proscribed.
The work where this sublime picture is delineated, does honour, not to the author only, but to the human race; and marks, undoubtedly, the highest point to which man has yet ascended in the scale of intellectual attainment. The glory, therefore, of having produced this work, belongs not to the author | s3://commoncrawl/crawl-data/CC-MAIN-2024-10/segments/1707947474470.37/warc/CC-MAIN-20240223221041-20240224011041-00519.warc.gz | CC-MAIN-2024-10 | 13,706 | 20 |
http://3dpogo.com/pdf/accessible-physics-a-guided-coursebook-for-a-level | math | By Francis Azzopardi
This quantity and its accompanying "Solutions Manual", may still permit scholars to be successful in a degree physics. It covers the obligatory cores of the entire significant syllabuses, together with the Northern Board's large Nuclear unit. The textual content is supported by means of transparent line diagrams to give an explanation for complicated recommendations. consciousness is concentrated on crucial rules, the authors aiming to supply scholars with a regular direction better half, but providing the appropriate heritage element and functions. reasons are complete, and the e-book may be compatible for guided self-study. Guided examples lead steadily throughout the significant syllabuses for 1996 and past. Self-assessments visual display unit growth, with a decision of "qualitative" and "quantitative" questions and a suite of suggestions to be had to academics. additional assistance is supplied with mathematical ideas anyplace essential to produce a booklet with the intention to gain scholars of all degrees of skill.
Read Online or Download Accessible Physics: A Guided Coursebook for A-Level PDF
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5 J T=Ia where I= moment of inertia of wheel [kg m2 ] .. 157] :. 3] + J .. 1] [kgm2 ][rads-1 ] :. 9 Rotational Motion of Rigid Bodies (236) 7 12(a) Using the principles of conservation of angular momentum: where 11. 4] .. 5) (c) The skater's rotational kinetic energy is increased as a result of the work done by the skater in bringing her arms and legs closer to axis of rotation. e. 7 X 10-11 ] X (75] X .. 8x10 6 f .. 7 X 10-11 ] 4R .. 12 X 10 7 ] 2 .. 361 x 10 3 = 0 25 (i e • . 0x 10 24 ] 2 10"34 N X [256x 10 7 ] 2 ..
JW=lOm ~ f[rti] acceleration due to gravity [m s"2} Using Newton' s 2nd Law: resultant force = mass x acceleration R - mg=Fc where R == normal reaction of seat on pilot [N] mg = weight of pilot [N] .. 75m]+[10m] [N] :. 9 ROTATIONAL MOTION OF RIGID BODIES Guided examples (1) 2 (a) (i) Angular acceleration (a) of the flywheel is given by: 1 (a) Initial angular velocity, OJ. ' =[ 15 0]x [2;r] [revmin" 1 ][radrev· 1 ] OJ f-(f)i [s min" 1 ] a=~-- t where OJ; ,OJ1 = initial and final angular velocity values Final angular velocity, t = time interval during which acceleration occurs [s] [rad s· 1] - [rad s" ] .
_-· .. _.... 30m Let x = distance from A at which C must be placed so thatFR=O. 15 m (a) The magnitude ofthe gravitational force. 10 x2 Taking the square root of both sides gives: (RE ) p= T G R 3 37r 2 E 1 37r X (200) 3 0. 316 x :. e. 21 m from A 4 (a) The centripetal force (Fe) on the satellite is provided by the gravitational force acting between the satellite and the Earth. 4x10 6 ] 2 c [N m 2 kg"2 ][kg][kg] [m]2 where Rs = mean radius of Earth's orbit around the Sun [m] Ts = period of Earth's orbit [s] G = universal gravitational constant [N m2 kg-2] . | s3://commoncrawl/crawl-data/CC-MAIN-2021-21/segments/1620243989616.38/warc/CC-MAIN-20210513234920-20210514024920-00247.warc.gz | CC-MAIN-2021-21 | 4,230 | 11 |
http://dev.goldbook.iupac.org/terms/view/P04694 | math | A number indicative of column performance, calculated from the following equations which depend on the selection of the peak width expression:
The value of 5.545 stands for . These expressions assume a Gaussian (symmetrical) peak. In these expressions the units for the quantities inside the brackets must be consistent so that their ratio is dimensionless: i.e. if the numerator is a volume, then peak width must also be expressed in terms of volume. In former nomenclature the expressions 'number of theoretical plates' or 'theoretical plate number' were used for the same term. For simplification, the present name is suggested.
PAC, 1993, 65, 819 (Nomenclature for chromatography (IUPAC Recommendations 1993)) on page 847 | s3://commoncrawl/crawl-data/CC-MAIN-2018-13/segments/1521257648431.63/warc/CC-MAIN-20180323180932-20180323200932-00369.warc.gz | CC-MAIN-2018-13 | 725 | 3 |
http://www.transtutors.com/questions/interior-angle-452325.htm | math | Estimated amount: $15
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what is the sum of the measures of the interior angles of a decagon(10 sided polygon).?
Find the measure of an interior angle of a regular pentagon
calculate interior and exterior angles of a polygon
Find the sum of the measures of the exterior angles of a convex21-gon. A. 21 B.180 C.360 D. 3420 Show Work Please.
Find the value of "n" for each regular "n"-gon described. 24. Each interior angle of the regular "n"-gon has a measure of 156 degrees. Please show all necessary work, including any
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http://www.talks.cam.ac.uk/talk/index/39880 | math | |COOKIES: By using this website you agree that we can place Google Analytics Cookies on your device for performance monitoring.|
The "Mumford conjecture" package, and applications
If you have a question about this talk, please contact Ivan Smith.
I will describe how recent work inspired by Madsen and Weiss’ proof of Mumford’s conjecture (on the stable cohomology of the moduli space of Riemann surfaces) gives a conceptual and computational understanding of moduli spaces of Riemann surfaces with extra structure.
In particular, I will focus on two interesting examples: the moduli spaces of r-Spin Riemann surfaces, and the universal Picard variety over the moduli space of curves, and explain how these methods can be used to compute their integral Picard groups.
This talk is part of the Differential Geometry and Topology Seminar series.
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Other talksDo changes in Subjective Probability Distributions reflect a Prediction Error driven learning process? Contact-line motion with mass transfer TBA The persistence of large-scale compositional heterogeneity in the Earth’s mantle Exploring psychotic experiences in ‘non-need for care’ populations: Findings from the UNIQUE study Decoding Molecular Plasticity in the Dark Proteome | s3://commoncrawl/crawl-data/CC-MAIN-2017-17/segments/1492917126538.54/warc/CC-MAIN-20170423031206-00108-ip-10-145-167-34.ec2.internal.warc.gz | CC-MAIN-2017-17 | 1,425 | 10 |
http://mangalore4u.blogspot.com/2009/12/usefull-mobile-codes.html | math | To check the IMEI (International Mobile Equipment Identity) type: *#06#
Information you get from the IMEI:
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TAC FAC SNR SP
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SP = Spare (always SP=0).
To check the phone's software (firmware revision information) type: *#0000# ( or for some phones outher then Nokia 61XX you can try *#model nummber# ex. for 8110 *#8110#)
Information you can get from the phone's software version:
1st line: Software version.
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Some versions and dates:
V 3.14 28/11/97
V 4.73 22/04/98
V 5.24 14/9/98 | s3://commoncrawl/crawl-data/CC-MAIN-2018-22/segments/1526794863689.50/warc/CC-MAIN-20180520205455-20180520225455-00029.warc.gz | CC-MAIN-2018-22 | 696 | 17 |
https://www.geeksforgeeks.org/isro-isro-cs-2011-question-9/?ref=rp | math | ISRO | ISRO CS 2011 | Question 9
What is the raw throughput of USB 2.0 technology?
(A) 480 Mbps
(B) 400 Mbps
(C) 200 Mbps
(D) 12 Mbps
Explanation: USB 2.0 has a maximum signaling rate of 480 Mbit/s (High Speed or High Bandwidth).
Option (A) is correct.
Quiz of this Question
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http://nrich.maths.org/public/leg.php?code=72&cl=2&cldcmpid=896 | math | Triangle numbers can be represented by a triangular array of squares. What do you notice about the sum of identical triangle numbers?
What would be the smallest number of moves needed to move a Knight
from a chess set from one corner to the opposite corner of a 99 by
99 square board?
Imagine starting with one yellow cube and covering it all over with
a single layer of red cubes, and then covering that cube with a
layer of blue cubes. How many red and blue cubes would you need?
Here are some arrangements of circles. How many circles would I need to make the next size up for each? Can you create your own arrangement and investigate the number of circles it needs?
If you can copy a network without lifting your pen off the paper and without drawing any line twice, then it is traversable.
Decide which of these diagrams are traversable.
How could Penny, Tom and Matthew work out how many chocolates there
are in different sized boxes?
The aim of the game is to slide the green square from the top right
hand corner to the bottom left hand corner in the least number of
Here are two kinds of spirals for you to explore. What do you notice?
Only one side of a two-slice toaster is working. What is the
quickest way to toast both sides of three slices of bread?
Can you work out how to win this game of Nim? Does it matter if you go first or second?
In this problem we are looking at sets of parallel sticks that
cross each other. What is the least number of crossings you can
make? And the greatest?
Square numbers can be represented as the sum of consecutive odd
numbers. What is the sum of 1 + 3 + ..... + 149 + 151 + 153?
This article for teachers describes several games, found on the
site, all of which have a related structure that can be used to
develop the skills of strategic planning.
One block is needed to make an up-and-down staircase, with one step up and one step down. How many blocks would be needed to build an up-and-down staircase with 5 steps up and 5 steps down?
Imagine an infinitely large sheet of square dotty paper on which you can draw triangles of any size you wish (providing each vertex is on a dot). What areas is it/is it not possible to draw?
Four bags contain a large number of 1s, 3s, 5s and 7s. Pick any ten numbers from the bags above so that their total is 37.
In each of the pictures the invitation is for you to: Count what you see. Identify how you think the pattern would continue.
How many ways can you find to do up all four buttons on my coat? How about if I had five buttons? Six ...?
For this challenge, you'll need to play Got It! Can you explain the strategy for winning this game with any target?
Are these statements relating to odd and even numbers always true, sometimes true or never true?
This challenge asks you to imagine a snake coiling on itself.
Can you describe this route to infinity? Where will the arrows take you next?
Draw a square. A second square of the same size slides around the
first always maintaining contact and keeping the same orientation.
How far does the dot travel?
Watch this video to see how to roll the dice. Now it's your turn! What do you notice about the dice numbers you have recorded?
Nim-7 game for an adult and child. Who will be the one to take the last counter?
It starts quite simple but great opportunities for number discoveries and patterns!
Three circles have a maximum of six intersections with each other.
What is the maximum number of intersections that a hundred circles
Find a route from the outside to the inside of this square, stepping on as many tiles as possible.
Can you dissect an equilateral triangle into 6 smaller ones? What
number of smaller equilateral triangles is it NOT possible to
dissect a larger equilateral triangle into?
Start with any number of counters in any number of piles. 2 players
take it in turns to remove any number of counters from a single
pile. The winner is the player to take the last counter.
Can you find all the ways to get 15 at the top of this triangle of numbers?
Euler discussed whether or not it was possible to stroll around Koenigsberg crossing each of its seven bridges exactly once. Experiment with different numbers of islands and bridges.
Find the sum and difference between a pair of two-digit numbers. Now find the sum and difference between the sum and difference! What happens?
Choose a couple of the sequences. Try to picture how to make the next, and the next, and the next... Can you describe your reasoning?
A collection of games on the NIM theme
This task follows on from Build it Up and takes the ideas into three dimensions!
An article for teachers and pupils that encourages you to look at the mathematical properties of similar games.
Can you tangle yourself up and reach any fraction?
These squares have been made from Cuisenaire rods. Can you describe
the pattern? What would the next square look like?
In how many different ways can you break up a stick of 7 interlocking cubes? Now try with a stick of 8 cubes and a stick of 6 cubes.
Think of a number, square it and subtract your starting number. Is the number you’re left with odd or even? How do the images help to explain this?
What are the areas of these triangles? What do you notice? Can you generalise to other "families" of triangles?
Try entering different sets of numbers in the number pyramids. How does the total at the top change?
Can you see why 2 by 2 could be 5? Can you predict what 2 by 10
What size square corners should be cut from a square piece of paper to make a box with the largest possible volume?
How many centimetres of rope will I need to make another mat just
like the one I have here?
Find out what a "fault-free" rectangle is and try to make some of
The Egyptians expressed all fractions as the sum of different unit
fractions. Here is a chance to explore how they could have written
Can you find an efficient method to work out how many handshakes
there would be if hundreds of people met?
Sweets are given out to party-goers in a particular way. Investigate the total number of sweets received by people sitting in different positions. | s3://commoncrawl/crawl-data/CC-MAIN-2017-09/segments/1487501170380.12/warc/CC-MAIN-20170219104610-00281-ip-10-171-10-108.ec2.internal.warc.gz | CC-MAIN-2017-09 | 6,095 | 74 |
https://www.varsitytutors.com/salem-oh-pre_calculus-tutoring | math | Recent Tutoring Session Reviews
"The student and I spent the session working with conic sections. We began with an overview of the general form equations, looking at major similarities and differences. I showed her how to plot each conic section using the general form equation, and then had her do a few for practice. We then went over some problems from a review sheet she had that involved producing an equation from some specific details such as vertex and focus. We ended our session by working on more complete conic section problems, where we began with an equation that was not in general form and simplified it. I reviewed completing the square with her and walked her through the process once before asking her to try. She picked it up very quickly and was solving them with very little assistance by the end of our session."
"We covered solving inequality equations. Factoring out so the problem could be easily solved helped her out once we did a few. She has been doing pretty well of late. She felt confident about this material. She received a high B on her last quiz. Her grade has steadily risen since we've started."
"Today when I met with the student we began to do his final exam review that his professor assigned. The material we were able to cover were some of the fundamentals. Basically just the distance formula, the midpoint formula, all equations of a line, how to find a line with a perpendicular/parallel slope given a point and a line equation, system of equations through multiple methods, and testing for symmetry. He seemed to do well with the concepts. After he would think about the answer, he would understand what the answer would be. We are scheduled to have a 2 hour session this Saturday to finish reviewing for his final."
"I assisted the student with a review of her pre-calculus homework, which consisted of sequence and summation notation problems. The student had one sequence problem that she had quite a bit of difficulty with, but I helped her through it. She also got the hang of summation notation rather quickly. The student did a great job today!"
"In this session, the student and I worked on complex numbers. We started with what a complex number is and how it fits into our other number systems. We then went into plotting complex numbers on a real and imaginary axis. After that, we began to work through the algebraic properties of complex numbers. The student picked up on the topics pretty quickly. We had done a lot of work with polar coordinates previously, so when working with De Moivre's theorem, the student was doing well with the calculations. After working through the material and notes related to his homework, we made sure to review the remaining topics in the chapter. This included taking nth roots of complex numbers, division, multiplication, and exponential powers of complex numbers."
"We worked on a test review. We talked about systems of equations and inequalities, and how to solve them and graph them. We also talked about how to solve different kinds of equations and extraneous solutions. Finally, we ended up by discussing bias and how this applies to statistics questions." | s3://commoncrawl/crawl-data/CC-MAIN-2017-09/segments/1487501170696.61/warc/CC-MAIN-20170219104610-00198-ip-10-171-10-108.ec2.internal.warc.gz | CC-MAIN-2017-09 | 3,160 | 7 |
https://www.maths.tcd.ie/~dwilkins/Courses/MA232A/Euclid_ETexts/EuclidBookI_Lardner1855/EuclidBookIAxioms_Lardner1855.php | math | |(43)||I.||Magnitudes which are equal to the same are equal to each other.|
|(44)||II.||If equals be added to equals the sums will be equal.|
|(45)||III.||If equals be taken away from equals the remainders will be equal.|
|(46)||IV.||If equals be added to unequals the sums will be unequal.|
|(47)||V.||If equals be taken away from unequals the remainders will be unequal.|
|(48)||VI.||The doubles of the same or equal magnitudes are equal.|
|(49)||VII.||The halves of the same or equal magnitudes are equal.|
|(50)||VIII.||Magnitudes which coincide with one another, or exactly fill the same space, are equal.|
|(51)||IX.||The whole is greater than its part.|
|(52)||X.||Two right lines cannot include a space.|
|(53)||XI.||All right angles are equal.|
|(54)||XII.||If two right lines (A B, C D) meet a third right line (A C) so as to make the two interior angles (B A C and D C A) on the same side less than two right angles, these two right lines will meet if they be produced on that side on which the angles are less than two right angles.|
(55) The geometrical axioms are certain general propositions, the truth of which is taken to be self-evident, and incapable of being established by demonstration. According to the spirit of this science, the number of axioms should be as limited as possible. A proposition, however self-evident, has no title to be taken as an axiom, if its truth can be deduced from axioms already admitted. We have a remarkable instance of the rigid adherence to this principle in the twentieth proposition of the first book, where it is proved that ‘two sides of a triangle taken together are greater than the third;’ a proposition which is quite as self-evident as any of the received axioms, and much more self-evident than several of them.
On the other hand, if the truth of a proposition cannot be established by demonstration, we are compelled to take it as an axiom, even though it be not self-evident. Such is the case with the twelfth axiom. We shall postpone our observations on this axiom, however, for the present, and have to request that the student will omit it until he comes to read the commentary on the twenty-eighth proposition. See Appendix II.
Two magnitudes are said to be equal when they are capable of exactly covering one another, or filling the same space. In the most ordinary practical cases we use this test for determining equality; we apply the two things to be compared one to the other, and immediately infer their equality from their coincidence.
By the aid of this definition of equality we conceive that the second and third axioms might easily be deduced from the first. We shall not however pursue the discussion here.
★★★ The fourth and fifth axioms are not sufficiently definite. After the addition or subtraction of equal quantities, unequal quantities continue to be unequal. But it is also evident, that their difference, that is, the quantity by which the greater exceeds the less, will be the same after such addition or subtraction as before it.
The sixth and seventh axioms may very easily be inferred from the preceding ones.
The tenth axiom may be presented under various forms. It is equivalent to stating, that between any two points only one right line can be drawn. For if two different right lines could be drawn from one point to another, they would evidently enclose a space between them. It is also equivalent to stating, that two right lines being infinitely produced cannot intersect each other in more than one point; for if they intersected at two points, the parts of the lines between these points would enclose a space.
The eleventh axiom admits of demonstration. Let A B and E F be perpendicular to D C and H G. Take any equal parts E H, E G on H G measured from the point E, and on D C take parts from A equal to these (Prop. III. Book I.) Let the point H be conceived to be placed upon the point D. The points G and C must then be in the circumference of a circle described round the centre D, with the distance D C or H G as radius. Hence, if the line H G be conceived to be turned round this centre D, the point G must in some position coincide with C. In such a position every point of the line H G must coincide with C D (ax. 10.), and the middle points A and E must evidently coincide. Let the perpendiculars E F and A B be conceived to be placed at the same side of D C. They must then coincide, and therefore the right angle F E G will be equal to the right angle B A C. For if E F do not coincide with A B, let it take the position A K. The right angle K A C is equal to K A D (11), and therefore greater than B A D; but B A D is equal to B A C (11), and therefore K A C is greater than B A C. But K A C is a part of B A C, and therefore less than it, which is absurd; and therefore E F must coincide with A B, and the right angles B A C and F E G are equal.
The postulates may be considered as axioms. The first postulated, which declares the possibility of one right line joining two given points, is as much an axiom as the tenth axiom, which declares the impossibility of more than one right line joining them.
In like manner, the second postulate, which grants the power of producing a line, may be considered as an axiom, declaring that every finite straight line may have another placed at its extremity so to form with it one continued straight line. In fact, the straight line thus placed will be its production. This postulate is assumed as an axiom in the fourteenth proposition of the first book.
(56) Those results which are obtained in geometry by a process of reasoning are called propositions. Geometrical propositions are of two species, problems and theorems.
A problem is a proposition in which something is proposed to be done; as a line to be drawn under some given conditions, some figure to be constructed, &c. The solution of the problem consists in showing how the thing required may be done by the aid of the rule and compass. The demonstration consists in proving that the process indicated in the solution really attains the required end.
A theorem is a proposition in which the truth of some principle is asserted. The object of the demonstration is to show how the truth of the proposed principle may be deduced from the axioms and definitions or other truths previously and independently established.
A problem is analogous to a postulate, and a theorem to an axiom.
A postulate is a problem, the solution of which is assumed.
An axiom is a theorem, the truth of which is granted without demonstration.
In order to effect the demonstration of a proposition, it frequently happens that other lines must be drawn besides those which are actually engaged in the enunciation of the proposition itself. The drawing of such lines is generally called the construction.
A corollary is an inference deduced immediately from a proposition.
A scholium is a note or observation on a proposition not containing any inference, or, at least, none of sufficient importance to entitle it to the name of a corollary.
A lemma is a proposition merely introduced for the purpose of establishing some more important proposition.
Book I: Euclid, Book I (ed. Dionysius Lardner, 11th Edition, 1855)
Next: Euclid, Book I, Proposition 1 (ed. Dionysius Lardner, 11th Edition, 1855)
Axioms or Common Notions in other editions: | s3://commoncrawl/crawl-data/CC-MAIN-2019-04/segments/1547583795042.29/warc/CC-MAIN-20190121152218-20190121174218-00127.warc.gz | CC-MAIN-2019-04 | 7,345 | 35 |
https://www.coursehero.com/file/6658411/ay45c4-page27/ | math | Unformatted text preview: Here the right hand sides are completely known, so we infer the lefthand sides. These data only give masses if we know the inclination of the
orbit, i. But, in general, we will not know this, so our data only measure a
combination of masses and i.
For one special group of stars, we do get M1 and M2 directly | from
\eclipsing" binaries, where the light curve shows an eclipse (see gure). light flux, F/(F1 +F2 ) 1.2 τ 1
0 0 .5 1
time, t /τ 1.5 Here, the stars are eclipsing one another . This scenario is only possible
if i 90 (provided that the stellar radii separation, which we can check
in the above equations; if this is not true, the stars are so distorted that we
cannot use this method anyway). Thus, sin i 1. Errors in i have little
eect on the masses derived, because sin i changes slowly at i 90.
In fact, the best data on masses of stars comes from eclipsing spectroscopic
double-lined binaries, even though these are hard to nd.
An alternative approach is to measure many noneclipsing binaries, assume
i to be selected at random, and use statistics to derive the distribution of
masses, M1 and M2.
View Full Document
- Fall '09
- Planet, Left-handedness, The Masses, Right-hand rule, right hand sides | s3://commoncrawl/crawl-data/CC-MAIN-2018-22/segments/1526794863901.24/warc/CC-MAIN-20180521004325-20180521024325-00073.warc.gz | CC-MAIN-2018-22 | 1,242 | 19 |
https://soleadea.org/cfa-level-1/utility-theory | math | Level 1 CFA® Exam:
As a rule, the measures of risk don't take into consideration the subjective experience of risk. Risk is considered from a subjective perspective because of the psychology of each entity investing in any financial instrument.
One theory that takes into consideration the subjective perception of risk by an investor is the utility theory. Despite criticism, it has been one of the most popular theories considering the individual psychological characteristics of an investor.
The utility theory is based on the utility function. The function differs from person to person and can change over time (for example as the investor is growing more experienced).
The utility function assigns a particular utility value – that can be understood as the level of a person's satisfaction – to a given monetary value. According to the utility theory, every person should seek to maximize his or her utility. From the point of view of an investor, the utility function can be perceived in terms of risk and return. An investor's utility function for a particular investment can be described this way:
A graph representing the utility function is called an indifference curve. At each point of the indifference curve, an investor's utility is the same.
Based on an investor's attitude to risk, we can distinguish among 3 types of investors.
Let's determine the utility of an investment with an expected return of 20% and a standard deviation of 30%. Additionally, we assume that the investor's risk aversion coefficient is 4.
Let's try and determine the utility of an investment with the same expected return of 20% and the same standard deviation of 30%. This time, however, we assume that the investor's risk aversion is 2.
Note: When an investor is characterized by lower risk aversion, he achieves greater utility for a given expected return and standard deviation. Also, what follows from the utility function is that all else equal the higher the expected return, the higher the utility for all 3 types of investors.
A risk-neutral investor is not sensitive to risk. The higher the risk, the higher the utility of risk-seeking investor, and the lower the utility of risk-averse investor.
Utility alone does not tell us much. What can we tell about an investor if we know that his utility of investment is 0.02 or 0.11? The number alone does not tell us much, but utility allows us to rank investments from the most to the least beneficial for the investor.
Note: The lower the risk aversion, the higher the risk tolerance. And conversely, the higher the risk aversion, the lower the risk tolerance.
A properly defined utility function can help us select the right portfolio for an investor. The most popular way to present an investment is in risk-return pairs. An optimal investor portfolio is located at the tangent of the function describing an investment, called the capital allocation line (CAL) and the indifference curve.
The capital allocation line is a line connecting a risk-free asset with the portfolio of risky assets. It reflects the return of an investor's portfolio depending on risk measured with standard deviation. It can be expressed with this formula to be used in your level 1 CFA exam:
Which can be rewritten in the following way:
- The utility theory is based on the utility function.
- The utility function assigns a particular utility value – that can be understood as the level of a person's satisfaction – to a given monetary value.
- According to the utility theory, every person should seek to maximize his or her utility.
- At each point of the indifference curve, an investor's utility is the same.
- An investor with a convex utility function is characterized by risk aversion and is therefore called a risk-averse investor.
- A risk-neutral investor is not sensitive to risk.
- A concave utility function characterizes a risk-seeking investor.
- The lower the risk aversion, the higher the risk tolerance.
- An optimal investor portfolio is located at the tangent of the capital allocation line (CAL) and the indifference curve. | s3://commoncrawl/crawl-data/CC-MAIN-2023-40/segments/1695233511075.63/warc/CC-MAIN-20231003092549-20231003122549-00261.warc.gz | CC-MAIN-2023-40 | 4,082 | 25 |
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US Citizen in Poland more than 90 days in a 180 day period
From what I understand, it is legal for a US citizen to spend up to 90 days in Poland, leave for one day, and re-enter for another 90 day period. Sources I called the Polish embassy in New York and ...
May 16 '12 at 19:31
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http://www.diva-portal.org/smash/record.jsf?pid=diva2:757682 | math | Saturated Fusion Systems
Independent thesis Basic level (degree of Bachelor), 10 credits / 15 HE creditsStudent thesis
A fusion system is a category on a nite p-group, P, which encodes "conjugacy" relations among the subgroups of P. In this thesis fusion systems of nite groups and ways to prove saturation of abstract fusion systems is investigated. First an introduction to fusion systems of nite groups and the notion of abstract fusion systems is given. Theorems of Burnside and Frobenius regarding fusion systems of nite groups are considered and proven. Alperins fusion theorem formulated for nite groups is considered and used in the proofs. It is proved that all fusion systems of nite groups are saturated.
An investigation in simpler ways of proving that a fusion system is saturated is done. First Alperins fusion theorem formulated for abstract fusion systems is considered which says that, a fusion system, denoted by F, is generated by the automorphism groups of some special subgroups. Further investigation is done in how this set of special groups, that generates F, can be used to check if F is saturated. A theorem of Craven, though originally stated by Puig, is then considered and proven. The theorem says that is suffices to check that the conjugacy classes of, so called, F-centric subgroups are saturated in order to check that the fusion system F is saturated. Also a theorem of is considered and proven. The theorem says that an even smaller set of conjugacy classes than the set of F-centric subgroups is needed to check saturation.
Section 1-2 are written together with Karl Amundsson and Eric Ahlqvist.
Place, publisher, year, edition, pages
2014. , 30 p.
IdentifiersURN: urn:nbn:se:kth:diva-154556OAI: oai:DiVA.org:kth-154556DiVA: diva2:757682
Master of Science in Engineering -Engineering Physics
Bauer, Tilman, Universitetslektor | s3://commoncrawl/crawl-data/CC-MAIN-2016-44/segments/1476988718303.21/warc/CC-MAIN-20161020183838-00214-ip-10-171-6-4.ec2.internal.warc.gz | CC-MAIN-2016-44 | 1,862 | 10 |
https://physics.stackexchange.com/questions/127499/momentum-acceleration-in-space/127578 | math | I'm an engineering student and have a few ideas to bat at the scientific community. First premise is based upon common sense. I understand that if I am standing on a skateboard on a relatively smooth surface and a stone of significant mass is thrown to me and I catch it, the momentum of the projectile is transferred to me causing a forward acceleration.
My question: Suppose that a system is designed to provided constant acceleration in space utilizing the aforementioned intuitive concept. In the simplest form I can idealize such a system as a basketball constantly striking a flat surface. Opposed to a ball consider an arbitrary mass striking a greater mass. I suppose that if creative means are applied to control the striking action (e.g. magnetism, mechanical means) then this action can be repeated to provide constant acceleration without the use of carrying fuel loads. Would it not be possible to reset the system to an initial state without canceling the resulting acceleration?
Due to the length of this question I will post the next question later. Thx | s3://commoncrawl/crawl-data/CC-MAIN-2021-21/segments/1620243988753.97/warc/CC-MAIN-20210506114045-20210506144045-00274.warc.gz | CC-MAIN-2021-21 | 1,069 | 3 |
http://fastsnap.com.au/product/model-3/ | math | Model 3.0 is state of the art inversion software for 1-D layered earth modelling. With plug-ins available for advanced functions such as accounting for IP effects and data collected using grounded lines.
Modelling is the final stage of TEM data manipulation and is of particular use where the depth and electrical resistivity of layers is useful for interpretation. Modelling allows a quantitative interpretation of TEM data and the result when individual models are compiled can be a very accurate geo-electric cross-sections of the earth. Model 3 is a complete layered earth modelling package for ground based TEM data.
• Can be configured to import almost any file type
• can model up to 100 layers
• Model 3 inverts TEM data with 1-D inversion to a layered earth model
• Automatically imports GPS data (including elevation data) collected during survey
• Parameters of layers are set according to a priori information if available
• Induced Polarisation parameters can be taken into account in inversion (with IP plug-in)
• The effect of Ramp (current turn-off duration) can also be estimated
• Inversion can be performed for many different loop sizes and configurations
• Forward modelling capabilities
• Confidence values calculated for inverted models | s3://commoncrawl/crawl-data/CC-MAIN-2019-43/segments/1570986693979.65/warc/CC-MAIN-20191019114429-20191019141929-00055.warc.gz | CC-MAIN-2019-43 | 1,278 | 12 |
https://www.reference.com/web?q=one+mole+of+any+element+contain+the&qo=contentPageRelatedSearch&o=600605&l=dir | math | One mole of any element contains the Ask for details ; Follow Report by Bi3ll7keralchrirg 03/27/2016 Log in to add a comment Answer. Answered by Moleporocky247 +1. klondikegj and 1 more users found this answer helpful One mole of any elements contains 6.02X10^23 unit 1.0 2 votes 2 votes Rate! Rate! Thanks. 0. Comments; Report Log in to add a ...
Multi choice. STUDY. PLAY. Terms in this set (...) D. Unit of molar masses A) grames per mole B)atoms per gram C)mol/ gram D)grams/mole. B. one mole of any element contains A) molecules B) atoms C) grams D) g/mole. B. What is the concentration of a solution that contains 4.0moles of a substance dissolved in 2.0 L of water
Mole Concept. One of the values of the mole is that every mole of any element has the same number of atoms in it. We have not yet discussed what that number is in this course (we will deal with that later when we consider the size of atoms), but we do know that it is the same amount for each element.
A mole contains the same number of units by definition, which is regardless of the substance. A mole is also related to atomic weight or mass. For example, one mole of carbon-12 atoms has an atomic weight of 12 grams, while a mole of oxygen, which also contains Avogadro's number of units, has an atomic weight of 16 grams.
There may be about 6.022 x 10 23 atoms in one mole, but we must ask this question: a mole of what?While a mole of a substance contains about 6.022 x 10 23 particles of that substance, the ...
Now, if you know that one mole of any element gives the same number of atoms of that element as one mole of any other element does, and since one mole of any element equals its atomic weight in grams, you can then figure out how many grams or milligrams, or tons, of any elements you need in order to give you the right number of atoms of each to ...
Best Answer: One mole contains 6.022 x 10^23 representative units. The unit in question depends on the context of the question. It could be molecules as in one mole of water molecules. It could be atoms as in "How many moles of atoms are in one mole of water molecules?" When discussing the Faraday, a unit ...
A mole of any substance always contains Avogardo's number of represenative particles, or 6.02 x 10^23 particles. How is the atomic mass of an element related to the molar mass of the element? The atomic mass of an element expressed in grams is the mass of a mole of the element.
Any element can me measured in molar quantities. One mole of any element has 6.02 x 10 23 atoms of that element. Hydrogen is the simplest element to use.
where: − The amount of moles represented by a number, − The amount of particles of the given substance or element, − The Avogadro's number. For example, one mole of hydrogen atoms will be defined as containing 6.022 140 76 × 10 23 of hydrogen atoms, which has a mass of 1.008 grams.. The molar mass of a substance is the mass of a sample divided by the amount of substance in that sample. | s3://commoncrawl/crawl-data/CC-MAIN-2019-22/segments/1558232256227.38/warc/CC-MAIN-20190521042221-20190521064221-00519.warc.gz | CC-MAIN-2019-22 | 2,980 | 10 |
https://www.rfwireless-world.com/calculators/Earth-Station-to-Satellite-Link-Calculator.html | math | Earth Station to Satellite Link Calculator
This page of converters and calculators section covers Earth Station to Satellite Link Calculator. The calculator takes RF transmission frequency(GHz), Antenna diameter (meters), transmitting power(dBW), efficiency of antenna and satellite distance from the Earth as input parameters. The calculator calculates path loss, parabolic reflector transmitting antenna gain, EIRP and received power at satellite.
INPUTS: Transmission Frequency= 6 ,Antenna Diameter=7.2, Transmit power = 8000 , satellite distance= 39920 ,antenna efficiency= 0.7
OUTPUTS: Path loss= 199.98 dB, Transmit antenna gain= 51.56 dB , EIRP= 90.59 dBW , received power at satellite= -109.39 dBW
Figure depicts the scenario for this calculator. As shown in the figure, calculator calculates satellite received power and other parameters as mentioned above.
Earth Station to Satellite Link Equation
The Earth station to Satellite link is used by many applications specifically in TV channel broadcasting etc. All the TV channel frequencies are combined and uplinked to the satellite which in turn broadcasts the TV channel information to the larger area of the earth. Hence this link is very important. Following equation or formula is used for Earth Station to Satellite Link Calculator.
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Satellite Capacity Allocation
Satellite Network Configuration
Satellite Launch Procedure
Remote sensing satellites
Satellite Launch Service Providers
Satellite Parts Manufacturers | s3://commoncrawl/crawl-data/CC-MAIN-2021-21/segments/1620243991288.0/warc/CC-MAIN-20210518160705-20210518190705-00048.warc.gz | CC-MAIN-2021-21 | 1,591 | 17 |
http://fitnhealthywomen.weebly.com/teris-workout-log/22812-workout-b | math | -Cable 180 Rotations: 2s x 8r x 22.5# -TRX Abd/Add/Jackknife/Pike: 2s x 8r
A1-Step Ups (7 risers under each side of bench... the higher you go, within reason of course, the more you work the Glutes): 3s x 8r ea leg x 20#. Going up next time to 22.5# dbs, one in each hand during step up.
A2- Incline DB Alternating Bench Press: 2x8x27.5#/ 1x7
B1- Sgl Leg Romanian Deadlift 1x8x30#/ 1x8x32.5#/ 1.8.35# (go UP.)
C1- Push Pull (handle clips chewed the heck out of my upper arms, so I'm going back down in weight and up in reps): 2x8x25/ 1x8x20
C2- Sgl Arm Push Press: 1x8x17.5#/20#/22.5#
Post workout: Foam rolling, | s3://commoncrawl/crawl-data/CC-MAIN-2019-26/segments/1560628000545.97/warc/CC-MAIN-20190626194744-20190626220744-00300.warc.gz | CC-MAIN-2019-26 | 612 | 7 |
https://www.physicsforums.com/threads/completely-not-understanding-moments-help.300627/ | math | there are 2 questions which are driving me insane because I jus don't understand what to do! I hope that if someone could go through the questions in detail then I'll finally understand how to go about answering. 5. A rod AB of mass 6kg and length 3m has its centre of mass 1.2m from A. It is suspended horizontally from the ceiling by two vertical strings one attached at A and the other at point C where AC is 2.5m. Find the magnitude of the tensions in the strings. 7. A uniform plank AB is 6m long and is resting in a horizontal posotion on two supports at A and B. The mass of the plank is 20kg. A body of mass 30kg is placed on the plank 1m from A and a second body of mass 30kg is placed on the plank 4.5m from A. Calculate the reaction at A and B. the answers for 5 are 30.6N, 28.2N the answers for 7 are 417N , 368N thank you! | s3://commoncrawl/crawl-data/CC-MAIN-2018-30/segments/1531676594018.55/warc/CC-MAIN-20180722213610-20180722233610-00270.warc.gz | CC-MAIN-2018-30 | 835 | 1 |
http://www.solutioninn.com/the-figure-in-the-preceding-exercise-shows-the-ph-curves | math | Question: The figure in the preceding exercise shows the pH curves
The figure in the preceding exercise shows the pH curves for the titrations of six different acids with NaOH. Make a similar plot for the titration of three different bases with 0.10 M HCl. Assume 50.0 mL of 0.20 M of the bases, and assume the three bases are a strong base (KOH), a weak base with Kb = 1 × 10-5, and another weak base with Kb = 1 × 10-10.
Answer to relevant QuestionsRepeat the procedure in Exercise 65 for the titration of 25.0 mL of 0.100 M propanoic acid (HC3H5O2, Ka = 1.3 × 10-5) with 0.100 M KOH. What is an acid–base indicator? Define the equivalence (stoichiometric) point and the endpoint of a titration. Why should you choose an indicator so that the two points coincide? Do the pH values of the two points have to ...When a diprotic acid, H2A, is titrated with NaOH, the protons on the diprotic acid are generally removed one at a time, resulting in a pH curve that has the following generic shape: a. Notice that the plot has essentially ...The solubility of the ionic compound M2X3, having a molar mass of 288 g/ mol, is 3.60 × 10-7 g/ L. Calculate the Ksp of the compound. Nanotechnology has become an important field, with applications ranging from high-density data storage to the design of “nano machines.” One common building block of nanostructured architectures is manganese oxide ...
Post your question | s3://commoncrawl/crawl-data/CC-MAIN-2017-34/segments/1502886117519.82/warc/CC-MAIN-20170823020201-20170823040201-00310.warc.gz | CC-MAIN-2017-34 | 1,417 | 4 |
https://www.quesba.com/questions/factory-overhead-budget-overhead-application-rate-sami-stitches-ltd-produce-256483 | math | Factory overhead budget and overhead application rate
Sami Stitches Ltd produces two types of sewing machines, a standard model and a deluxe model. The budgeted factory overhead costs for the production operation during 2020 are as follows.
Production of 18 000 standard sewing machines and 12 000 deluxe sewing machines is budgeted for 2020. Each standard machine requires 2.4 machine hours, and each deluxe machine requires only 2 machine hours because of the use of component parts. The company expects to sell all machines produced.
Required (a) Prepare a factory overhead budget for 2020 based on the estimated production level. (b) Calculate the predetermined overhead rate based on machine hours. | s3://commoncrawl/crawl-data/CC-MAIN-2021-10/segments/1614178350706.6/warc/CC-MAIN-20210225012257-20210225042257-00020.warc.gz | CC-MAIN-2021-10 | 703 | 4 |
https://aviation.stackexchange.com/tags/takeoff/new | math | At low altitude engine loss you have no choice but to land straight ahead. Anything but the slightest heading adjustments will most probably end catastrofically. Your memory items are (at least, depends on complexity of aircraft):
Gently but decisevily lower the nose
Close fuel valve
Adjust airspeed for landing
Flare and land
How do you determine if you have enough runway ahead? That's a tricky one, and in this situation you quite possibly have milliseconds to make that determination. It's going to be an estimate at best because you certainly wont have time to do any calculations. As a general rule I'd say if you have around half the runway length left you're probably good.
With an emergency, the objective is not to fly the quickest pattern possible, it's to be back safely on the ground as soon as possible, with the greatest probability of success. If you save 10 seconds by doing something that substantially increases the risk of wrecking the aircraft because you flew it into something, that's probably a poor tradeoff.
In the ...
The quickest and safest way is to fly the standard pattern, especially if you are at an uncontrolled airport. Why? Because that is where everyone else is looking for you to be. Per the Airplane Flying Handbook Chapter 7 states:
compliance with the basic rectangular traffic pattern reduces the
possibility of conflicts at airports without an operating ...
Temperature and humidity both affect air density and engine power. $H_2O$ molecules are lighter than the $N_2$ and $O_2$ molecules they displace in a volume of humid air.
1. Air Density. The graph below from this site shows that at 40°C, which is a high atmospheric temperature, dry air is about 0.94 density at 20°C, while 100% humidity reduces the density to ... | s3://commoncrawl/crawl-data/CC-MAIN-2021-31/segments/1627046153860.57/warc/CC-MAIN-20210729140649-20210729170649-00257.warc.gz | CC-MAIN-2021-31 | 1,768 | 13 |
https://answersdrive.com/why-is-pi-day-in-2015-so-special-6190913 | math | Why is Pi Day in 2015 so special?
It's a most auspicious holiday for math lovers. Saturday, March 14, 2015 is Pi Day, a celebration of the irrational number that describes the ratio of a circle's diameter to its circumference. Pi is approximately 3.141592653, but it continues at random to infinity.
Pi Day is an annual celebration of the mathematical constant π (pi). Pi Day is observed on March 14 (3/14 in the month/day format) since 3, 1, and 4 are the first three significant digits of π.
- Archimedes of Syracuse
- The record for finding consecutive numbers, from 3.14 onward to the final digit, is held by Fabrice Bellard, who announced in January that he had calculated pi to 2.7 trillion digits.
- Transcript of what is the relationship between the symbol PI and the word. The symbol comes from the Greek alphabet. In mathematical symbol Pi, sometimes written as Pi, is approximately equal to 3.14159.. Pi gets its name from the Greek words for periphery and perimeter, which both begin with the Greek letter, pi.
The concept of pi is important to mathematics because of its relationship to the circle; it is a constant representing the ratio of a circle's circumference to its diameter.
- The digits of pi never repeat because it can be proven that π is an irrational number and irrational numbers don't repeat forever. If you write out the decimal expansion of any irrational number (not just π) you'll find that it never repeats. That means that π is irrational, and that means that π never repeats.
- A chord of a circle is a straight line segment whose endpoints both lie on the circle. A secant line, or just secant, is the infinite line extension of a chord. More generally, a chord is a line segment joining two points on any curve, for instance an ellipse. The word chord is from the Latin chorda meaning bowstring.
- How to find the circumference of a circle:
- The circumference of a circle can be found by multiplying pi ( π = 3.14 ) by the diameter of the circle.
- If a circle has a diameter of 4, its circumference is 3.14*4=12.56.
- If you know the radius, the diameter is twice as large.
Pi Day is celebrated on March 14th (3/14) around the world. Pi (Greek letter “π”) is the symbol used in mathematics to represent a constant — the ratio of the circumference of a circle to its diameter — which is approximately 3.14159.
- A chord that passes through the center of a circle is called a diameter, and is the longest chord.
- A circle is a set of all points in a plane that are all an equal distance from a single point, the center. The distance from a circle's center to a point on the circle is called the radius of the circle. A line segment that crosses the circle by passing through the center of the circle is called the diameter.
- Circles and ovals are both types of ellipses. An 'oval' is really the informal term for an 'ellipse', whereas a 'circle' is an ellipse where the semi-major and semi-minor axes are equal. If you're talking about higher-dimensions, the word you are looking for is probably ellipsoid. (A sphere is an example.)
Updated: 7th December 2019 | s3://commoncrawl/crawl-data/CC-MAIN-2020-05/segments/1579251799918.97/warc/CC-MAIN-20200129133601-20200129163601-00245.warc.gz | CC-MAIN-2020-05 | 3,115 | 18 |
http://nrich.maths.org/public/leg.php?code=-99&cl=3&cldcmpid=849 | math | You need to find the values of the stars before you can apply normal Sudoku rules.
This is a variation of sudoku which contains a set of special clue-numbers. Each set of 4 small digits stands for the numbers in the four cells of the grid adjacent to this set.
Solve the equations to identify the clue numbers in this Sudoku problem.
The challenge is to find the values of the variables if you are to
solve this Sudoku.
Advent Calendar 2011 - a mathematical activity for each day during the run-up to Christmas.
A Sudoku with a twist.
An extra constraint means this Sudoku requires you to think in
diagonals as well as horizontal and vertical lines and boxes of
You are given the Lowest Common Multiples of sets of digits. Find
the digits and then solve the Sudoku.
Label this plum tree graph to make it totally magic!
You have twelve weights, one of which is different from the rest.
Using just 3 weighings, can you identify which weight is the odd
one out, and whether it is heavier or lighter than the rest?
This article for teachers describes several games, found on the
site, all of which have a related structure that can be used to
develop the skills of strategic planning.
Use the differences to find the solution to this Sudoku.
Four numbers on an intersection that need to be placed in the
surrounding cells. That is all you need to know to solve this
The puzzle can be solved by finding the values of the unknown digits (all indicated by asterisks) in the squares of the $9\times9$ grid.
Pentagram Pylons - can you elegantly recreate them? Or, the
European flag in LOGO - what poses the greater problem?
Bellringers have a special way to write down the patterns they
ring. Learn about these patterns and draw some of your own.
Problem solving is at the heart of the NRICH site. All the problems
give learners opportunities to learn, develop or use mathematical
concepts and skills. Read here for more information.
Each clue number in this sudoku is the product of the two numbers in adjacent cells.
In this Sudoku, there are three coloured "islands" in the 9x9 grid. Within each "island" EVERY group of nine cells that form a 3x3 square must contain the numbers 1 through 9.
Special clue numbers related to the difference between numbers in
two adjacent cells and values of the stars in the "constellation"
make this a doubly interesting problem.
This Sudoku combines all four arithmetic operations.
This second Sudoku article discusses "Corresponding Sudokus" which are pairs of Sudokus with terms that can be matched using a substitution rule.
A Sudoku with clues as ratios.
Find out about Magic Squares in this article written for students. Why are they magic?!
The puzzle can be solved with the help of small clue-numbers which
are either placed on the border lines between selected pairs of
neighbouring squares of the grid or placed after slash marks on. . . .
Four small numbers give the clue to the contents of the four
60 pieces and a challenge. What can you make and how many of the
pieces can you use creating skeleton polyhedra?
A pair of Sudoku puzzles that together lead to a complete solution.
Label the joints and legs of these graph theory caterpillars so that the vertex sums are all equal.
This Sudoku puzzle can be solved with the help of small clue-numbers on the border lines between pairs of neighbouring squares of the grid.
This Sudoku, based on differences. Using the one clue number can you find the solution?
A Sudoku with clues as ratios or fractions.
This pair of linked Sudokus matches letters with numbers and hides a seasonal greeting. Can you find it?
A Sudoku that uses transformations as supporting clues.
Two sudokus in one. Challenge yourself to make the necessary
Remember that you want someone following behind you to see where
you went. Can yo work out how these patterns were created and
Try to solve this very difficult problem and then study our two suggested solutions. How would you use your knowledge to try to solve variants on the original problem?
Countries from across the world competed in a sports tournament. Can you devise an efficient strategy to work out the order in which they finished?
A particular technique for solving Sudoku puzzles, known as "naked pair", is explained in this easy-to-read article.
Take three whole numbers. The differences between them give you
three new numbers. Find the differences between the new numbers and
keep repeating this. What happens?
You have been given nine weights, one of which is slightly heavier
than the rest. Can you work out which weight is heavier in just two
weighings of the balance?
Each of the main diagonals of this sudoku must contain the numbers
1 to 9 and each rectangle width the numbers 1 to 4.
A Sudoku with clues given as sums of entries.
We're excited about this new program for drawing beautiful mathematical designs. Can you work out how we made our first few pictures and, even better, share your most elegant solutions with us?
This Sudoku requires you to do some working backwards before working forwards.
Arrange the digits 1, 1, 2, 2, 3 and 3 so that between the two 1's
there is one digit, between the two 2's there are two digits, and
between the two 3's there are three digits.
This sudoku requires you to have "double vision" - two Sudoku's for the price of one | s3://commoncrawl/crawl-data/CC-MAIN-2017-09/segments/1487501171834.68/warc/CC-MAIN-20170219104611-00614-ip-10-171-10-108.ec2.internal.warc.gz | CC-MAIN-2017-09 | 5,301 | 72 |
https://brainmass.com/statistics/quantative-analysis-of-data/standard-deviation-gambling-scenario-219445 | math | Two craps tables collect an average of $500 per hour. One table has a standard deviation of $50 while the other has a standard deviation of $150. What conclusion can be drawn from the data? Normally, would one want a larger of smaller standard deviation? Please discuss and show any work associated with this question. Thanks© BrainMass Inc. brainmass.com March 4, 2021, 9:07 pm ad1c9bdddf
I would suspect that the one with the larger standard deviation plays larger amounts than the one with smaller standard deviation. It is also ...
The answer clearly explains the concept of risk and return using the example in the question. The answer does an excellent job of explaining the concepts. Overall, a great answer. | s3://commoncrawl/crawl-data/CC-MAIN-2021-31/segments/1627046152168.38/warc/CC-MAIN-20210727010203-20210727040203-00157.warc.gz | CC-MAIN-2021-31 | 716 | 3 |
https://oxford-man.ox.ac.uk/event/trend-following-and-momentum-strategies-in-futures-markets/ | math | Tuesday 22nd May 2012 – 14:15 to 15:15
Speaker: Robert Kosowski (Imperial)
Constructing a time-series momentum strategy involves the volatility-adjusted aggregation of univariate strategies and therefore relies heavily on the efficiency of the volatility estimator and on the quality of the momentum trading signal. Using a dataset with intra-day quotes of 12 futures contracts from November 1999 to October 2009, we investigate these dependencies and their relation to timeseries momentum profitability and reach a number of novel findings. First, momentum trading signals generated by fitting a linear trend on the asset price path maximise the out-of-sample performance while minimizing the portfolio turnover, hence dominating the ordinary momentum trading signal in literature, the sign of past return. Second, the results show strong momentum patterns at the monthly frequency of rebalancing, relatively strong momentum patterns at the weekly frequency and relatively weak momentum patterns at the daily frequency. In fact, significant reversal effects are documented at the very short-term horizon. Finally, regarding the volatility-adjusted aggregation of univariate strategies, the Yang-Zhang range estimator constitutes the optimal choice for volatility estimation in terms of maximizing efficiency and minimizing the bias and the ex-post portfolio turnover.
Co-authored by Akindynos-Nikolaos Baltas
Part of the OMI Seminar Series | s3://commoncrawl/crawl-data/CC-MAIN-2024-18/segments/1712296820065.92/warc/CC-MAIN-20240425000826-20240425030826-00898.warc.gz | CC-MAIN-2024-18 | 1,442 | 5 |
http://www.residentadvisor.net/dj/herlock/feed?item=39470 | math | Sat, 21 Sep 2013 / Post a comment
a small impression of my actual project
Fri, 20 Sep 2013 / Post a comment
a small impression of my recent work.
stay tuned and enjoy it.
Tue, 02 Jul 2013 / Post a comment
its been a long time i shouldn*t have left you.
enjoy it and spread it to the world.
Sun, 23 Dec 2012 / Post a comment
The last Mix for this year enjoy it and share the love!
Sun, 04 Nov 2012 / Post a comment
this is the new podcast from me for sonnenkinder podcast series.
Tue, 09 Oct 2012 / Post a comment
just yesterday a small but very distinctive track arrived at hour soundcloud account. the persons behind those one are unknown yet, but i will find them.
Thu, 14 Jun 2012 / Post a comment
In front of the first sampler from one to one records who is available from the 15th of june i thought it could be great to do a new mix who connects and shows the ability of electronic music. Thats why i decided to mix digital, vinyl and netlabel stuff togheter because i think all kinds of electronic music shell find some listeners.
Hope you enjoy it and maybe share it if you like it.
Sun, 10 Jun 2012 / Post a comment
From friday you can buy the hole sampler at your favorite digital shops.
Thu, 07 Jun 2012 / Post a comment
It's on. After a long time im very happy that one track from me made it and will be available on the first sampler from one to one records.
more about it soon.
Fri, 27 Jan 2012 / Post a comment
its on tonight we will fly to london to celebrate and enjoy some good music
Thu, 12 Jan 2012 / Post a comment
new years eve is hardly gone, but no time for tears.
a small mix who connects vinyl and netlabel releases.
enjoy it and feel free to drop a comment!
Fri, 16 Dec 2011 / Post a comment
an actual track by myself enjoy it and have a nice weekend.... | s3://commoncrawl/crawl-data/CC-MAIN-2013-48/segments/1386163052593/warc/CC-MAIN-20131204131732-00046-ip-10-33-133-15.ec2.internal.warc.gz | CC-MAIN-2013-48 | 1,828 | 30 |
https://911electronic.com/skin-effect-electrical-skin-depth-theory-definition-formulas/ | math | Skin effect – a phenomenon occurring in AC circuits that causes the current density near the surface of a conductor to be greater than inside it. Skin effect increases the effective AC resistance of the conductor, causing an increase in power losses in the conductor. The value characterizing the skin effect is the penetration depth (of magnetic field or current into the conductor). This quantity depends on resistivity, magnetic permeability of the medium and frequency of the current.
Skin effect results from the interaction of a magnetic field and an electric field. Alternating current flowing in a conductor creates an alternating magnetic field. This field induces an alternating, oppositely directed electric field. This in turn causes secondary currents, flowing in the conductor in the opposite direction of the primary current. These currents reduce both the magnetic field strength and the local current density. Since the strongest electric field is induced inside the wire, this is also where the current disappears most strongly.
Skin effect can also be explained by the principle of so-called magnetic diffusion defined by Maxwell’s equations. A current in a wire creates a magnetic field around itself. Since this field is time-varying, it enters the conductor as an electromagnetic wave and is attenuated due to the lossiness of the medium. At the surface of the conductor, currents are induced that add to the source current, while inside the conductor, the source current is reduced by them. If the thickness of the conductor is large and the frequency is high (the electromagnetic wave then has a small length), a situation may occur when the currents coming from the magnetic field are summed larger than the source current and then inside the conductor a current starts to flow in the opposite direction, which is a very unfavorable phenomenon.
Consider a cylindrical wire of radius a and infinite length. A current I = I0 cos ωt flows through the wire. For not very large frequencies ω we can neglect the displacement current, which is equivalent to neglecting the effect of radiating energy through the wire in the form of an electromagnetic wave. The current density and the electric and magnetic field strengths are written in complex form, with harmonic dependence on time
Faraday’s and Ampere’s laws for the fields inside the wire are:
where σ – specific conductivity, μ – relative magnetic permeability of the wire material. For rotation in cylindrical coordinates the following formulas are valid:
Assuming that the wire is directed along the z-axis, equations (1) in the cylindrical system can be written as:
where H = Hφ, E = Ez. By differentiating the second equation (3) after r, we can write the differential equation for the electric field strength
Introducing the variable x = qr we obtain the equation
This is a Bessel equation of zero order. Its general solution is the linear combination of Bessel functions of the first and second kind A J0(x) + B Y0(x). We must discard the Bessel function of the second kind Y0 because Y0(0) = ∞. The electric field on the axis of the wire, for r = 0, cannot be infinitely large. The electric field inside the wire is therefore
where C = const. Using the second of equations (3) we can calculate the magnetic field strength inside the wire
Using the formula for the derivative of the Bessel function
From equations (3), one can verify that the differential equation for H is indeed a Bessel equation of order 1. According to the integral version of Ampere’s law, the value of the magnetic field strength at the surface of the wire should be
Hence the integration constant C is
Finally, the electric and magnetic field strengths inside the wire are
According to Ohm’s differential law, the current density inside the wire is
The ratio of the current density inside the conductor to the current density on its surface, for r = a
where ξ = r/a < 1. We are dealing with Bessel functions from a composite argument, which physically means that at different distances from the wire axis the time dependence of the current density is phase shifted. In the argument of the Bessel function there is a dimensionless constant
dependent on the conductor radius a, the current frequency ω, and the material constants σ and μ of the metal from which the conductor is made.
Figure 1 shows the absolute value of the ratio of the current density inside the wire to its value on the surface, for several selected values of the parameter ka. It can be seen that for sufficiently high values of ka, the current flows practically entirely on the surface of the conductor. This effect is called the skin effect.
The table below shows values of the ka parameter for a conductor with a diameter of 1 mm, for selected current frequencies. For copper σ = 5.8 – 10^7 S/m, for steel σ = 1.0 – 10^7 S/m, μ = 1000.
|f||50 Hz||10 kHz||100 MHz|
The skin effect is of great practical importance in electrical engineering. For high-frequency currents, the resistance of a conductor comes entirely from the thin layer of material on the surface. Since copper and aluminum, from which electrical conductors are made, tend to oxidize, this resistance can be much greater than the specific conductivity value of the pure metal would suggest. It may also be noted that most of the metal inside the wire does not participate at all in the transmission of electric current, and that increasing the diameter of the wire does not lead to a decrease in resistance. For high-frequency currents, therefore, a braided wire consisting of many thin conductors is often used.
Skin effect in a finite thickness conductor
Consider an infinite layer of conductor with thickness d = 2a. Let us assume that on both surfaces of the layer a homogeneous harmonic magnetic field of strength H0 is given, parallel to the surface of the layer. Such a field configuration exists in the core of a transformer consisting of many layers of insulated thin steel sheet.
If the transformer core were made from a single thick piece of conductor, large eddy currents induced by a time-varying magnetic field would flow in the cross-section of the core, and thus large Joule Lenz heat would be emitted in the core. Inside the conductor, Faraday’s law applies:
and Amper’s law:
The density of current induced in a conductor is related to the electric field strength:
Where σ – specific conductivity. Material equations:
Let’s write Faraday’s and Ampere’s law in Cartesian terms. If the conductor is infinite in the x and y directions, then the fields can only depend on the variablez. For large intrinsic conductivity σ and small field frequency ω, we can neglect the shift current in Amper’s law. For harmonic fields, we replace the derivative after time by the factor iω.
The electric field and the current density inside the conductor are directed along the x-axis. Thus the magnetic field inside the conductor satisfies the following differential equation
where the complex constant
The root of the imaginary number is:
The general solution of the differential equation (5) is a linear combination of exponential functions:
The magnetic field at the layer surface for z = -a and z = a must satisfy the following boundary condition:
Hence the integration constants are:
The solution of equation (5) satisfying the boundary conditions (7) is of the form:
Based on equation (4), we can also give an expression for the induced current density in the layer is:
The current density induced at the layer surface for z = a is
It is easy to see that jx(-z) = – jx(z), so at the center of the layer the current does not flow, and at the surface z = -a it has the opposite direction than at the surface z = a. By introducing the following dimensionless notations: ξ = z/a, β = ba we can write an expression for the modulus of the current density related to the value at the surface of the layer:
As can be seen from figure (1), for the value of dimensionless parameter β > 3 there appears a skin effect – the current starts to flow mainly near the surface of the conductor. To calculate equation (12) we need expressions for hyperbolic functions from the complex argument:
and their modules
In a similar way, we can write the expression for the modulus of magnetic induction related to its value at the surface of the layer:
Let the frequency of the external magnetic field be f = 50 Hz. The magnetic steel has a specific conductivity equal to σ = 10^7 S/m, and its relative magnetic permeability is μ = 1000. The parameter b is then equal to 1.4 mm-1. The depth of field penetration into the conductor λ = 2π/b is about 5 mm. The following table shows the dependence of the dimensionless parameter β appearing in equations (12) and (15) as a function of film thickness:
One of the quantities important in eddy current testing is the equivalent penetration depth of the electromagnetic field δ (also called standard penetration depth or simply penetration depth). This quantity conventionally defines the thickness of the material layer under test. The current density induced in a semi-infinite conducting plate by a sinusoidal time-varying plane electromagnetic wave penetrating it varies exponentially with distance from the surface. The value of this density for a particular depth z depends on the frequency f and the material parameters of the plate. Assuming that in a Cartesian coordinate system whose z-axis is perpendicular to the plate surface, the magnetic field strength vector has only a tangential component to the surface, the current density also has only a tangential component to the surface. The modulus of the current density varies according to the relation:
Where J0 is the modulus of the current density at the surface of the object.
Figure 3 shows graphs of eddy current density values induced in a copper plate by a three-winding flat coil energized at frequencies of 10, 20, 50, 100, 200, 500, and 1000 Hz. The graphs show the absolute values of the currents along the z-axis from the surface (0 mm) to the bottom of the plate (20 mm), for the coordinate r = 20 mm (position of the central coil). The highest values of the current density induced on the surface occur for the highest of the adopted frequencies (black line). At the same time, for this frequency, the values of current decrease most rapidly along the depth of the plate, taking values close to zero at its bottom surface.
The expression for the current density can be represented as:
It can be seen that δ is the depth at which the amplitude of the current density decreases e-fold. The penetration depth δ can also be thought of as the thickness of the layer in which the total current of constant density is induced, and beyond which no current is induced at all. The value of the penetration depth δ depends on the frequency of the field and on the magnetic permeability and electrical conductivity of the material under consideration. An effective penetration depth of 3δ is also determined, at which the induced currents decrease below 5% of the value of the current density at the surface. At the same time, as the amplitude of the current density decreases, the phase delay angle of the current with respect to the current at the surface increases. The value of this angle (in radians) is:
Figure 4 shows the phase delay angle of the induced current (in radians). | s3://commoncrawl/crawl-data/CC-MAIN-2023-40/segments/1695233506421.14/warc/CC-MAIN-20230922170343-20230922200343-00140.warc.gz | CC-MAIN-2023-40 | 11,431 | 50 |
http://www.mynewsdesk.com/investstockholm/pressreleases/tag/foreign-direct-investments | math | Press Releases • Mar 13, 2019 08:58 UTC
The planned construction projects within the Stockholm region show a total investment volume of €111 billion until the year 2040. According to Invest Stockholm’s report released today, the largest investment share is in housing, with an investment volume of €60,7 billion, followed by infrastructure investments in railway, subway and lightrail, with an investment volume of 9,6 billion €.
Press Releases • Jan 31, 2019 06:45 UTC
The health tech sector in Stockholm is booming. Six new health tech companies are entering the Life Science Hotlist, a list of carefully curated investment opportunities in the Stockholm-Uppsala region. Invest Stockholm has screened 95 health tech companies to identify the “hot” investment cases. Today, Brighter, Camino Care, CareLigo, Encare, Hnry and Minnity are added to the list.
Press Releases • Dec 11, 2018 13:27 UTC
The two municipalities Gävle and Sandviken in the Stockholm region have decided to sell a total of 130 hectares of land to Microsoft for SEK 269 million, thereby creating conditions for a major international investment.
Press Releases • Oct 18, 2018 08:21 UTC
Despite a substantial increase in the number of hotel rooms in Stockholm last year, the demand for more hotels in the Swedish capital continues to develop. Changed travel habits, a growing middle class in Asia and cheaper flights have contributed to the increase in the proportion of private hotel guests, which is now almost as big as the business segment.
Press Releases • Sep 03, 2018 06:15 UTC
During the first two weeks of September, Stockholm welcomes thousands of investors, entrepreneurs, talents and journalists, to discover one of the best tech ecosystems in the world. With 14 conferences and 50+ events, Stockholm Tech Week offers visitors to experience what's going to happen next in the world. Welcome to connect with the early starters of the Stockholm tech ecosystem!
Press Releases • Jul 09, 2018 07:54 UTC
The American community platform WeWork today announced its expansion into Stockholm. During the spring of 2019, the first location of the leading provider of shared office space around the globe will open its doors at the newly renovated property Urban Escape, offering office and community space for 1000 future members.
Press Releases • Jun 11, 2018 12:47 UTC
When sustainable eyewear brand Karün from Patagonia were looking for the best market in Europe to launch their new product; sunglasses made out of recycled fishing nets, they chose Stockholm. Why? You may ask. Stockholm has far from the amount of sunshine that many other European cities can boast with. The answer, however, is not to be found in the weather, but rather in the Swedish values.
Press Releases • Mar 26, 2018 07:15 UTC
The Vilsta ski slope in Eskilstuna in the Stockholm region, will become 10 meters higher just in time for the winter season next year. All thanks to shaft masses from the construction of Amazon Web Services (AWS)’s data center in Eskilstuna.
Press Releases • Mar 13, 2018 11:29 UTC
For the first time in many years, the City of Stockholm has land to sell in the city center. The gross floor area is about 20 000 square meters. The property has the Central station, the City Hall and the open waters of Riddarfjärden as neighbours.
Press Releases • Nov 16, 2017 10:26 UTC
Packed with statistics, key facts and detailed descriptions of shopping districts in Stockholm, the Swedish retail guide has landed. For everyone considering entering the Stockholm retail market, this guide saves weeks of market research.
Press Releases • Oct 19, 2017 14:30 UTC
The City of Västerås, west of Stockholm, has been chosen as the location where Northvolt will place their R&D facility for the next generation lithium-ion batteries. This is the fourth major investment in the Stockholm Region in the last six months, creating another 300 to 400 jobs in Västerås.
Press Releases • Oct 06, 2017 05:50 UTC
Through stable growth, Stockholm has reached record levels of RevPAR (revenue per available room), and surging occupancy has created a great need for additional guest room capacity. While demand has become increasingly diverse, supply has remained homogeneous and regional operators dominate the market. The time is ripe for international investors to conquer a share of emerging market segments.
The ROCKWOOL Group, the leading provider of stone wool solutions, invests in land in the Stockholm region
Press Releases • Oct 05, 2017 08:17 UTC
The Danish industrial Group, ROCKWOOL, has today confirmed the purchase of 180,000 square meters of land in the Eskilstuna Logistics Park (Eskilstuna Logistikpark), which will lay the foundation for future expansion to serve the Swedish construction market. The future facility has the potential to create about 150 new jobs in Eskilstuna.
Press Releases • Oct 03, 2017 08:38 UTC
Need for labor to carry out planned construction investments in the Stockholm region is estimated at over 100,000 job opportunities in 2017 and 2018. The demand is greatest for building and construction workers, construction craftsmen, painters and finishers.
Press Releases • Jul 26, 2017 07:30 UTC
The strong construction market in Stockholm has created lucrative opportunities for international companies. A requirement to be able to seize these opportunities is to understand the regulations of the industry. To help foreign companies enter the market, Invest Stockholm, Tyréns and SABO today launched a unique intensive course covering the fundamentals of the Swedish construction industry.
Press Releases • Apr 04, 2017 06:16 UTC
Today, Amazon Web Services (AWS) announced the establishment of a new datacenter region in the Stockholm area, positioning Sweden as the location of choice for delivery of advanced cloud services in the Nordics. The new AWS EU (Stockholm) Region will be operational in 2018.
Press Releases • Mar 13, 2017 12:42 UTC
The Stockholm region is growing faster than the rest of Europe and the investment potential is estimated to be EUR 95 billion through 2030 in the areas of housing, infrastructure and innovation. A sweeping 340,000 new dwellings will be built, which alone will require investments at a record level of EUR 53 billion.
Press Releases • Mar 22, 2016 08:36 UTC
The Stockholm-Uppsala Life Science Investment Hotlist is growing. Now being welcomed are 5 new companies, all in digital health, in the search for foreign investments and partnerships. Including the new companies, the list now includes 41 companies, almost half of which are in the field of digital health.
Press Releases • Oct 07, 2015 08:23 UTC
The next five years will see a major investment to increase the life science companies in the Stockholm region. The aim is to double the number of identified companies which are ripe for investment.
Press Releases • Jun 23, 2015 06:00 UTC
In the past five years, Stockholm-based companies received 18 percent of all private placements in FinTech companies across Europe. The numbers show that Stockholm continuously, year after year, attracts almost one fifth of the overall FinTech investments in Europe. | s3://commoncrawl/crawl-data/CC-MAIN-2019-18/segments/1555578528481.47/warc/CC-MAIN-20190420020937-20190420042937-00092.warc.gz | CC-MAIN-2019-18 | 7,247 | 41 |
https://rgmccutcheon.wordpress.com/2015/09/03/could-this-be-the-worst-paper-in-the-history-of-philosophy/ | math | Notwithstanding that, Robert Northcott’s paper A Dilemma for the Doomsday Argument is (and by a comfortable margin) the worst paper I have reviewed (i.e. trashed) on this blog. In the paper, the following Doom scenario is presented:
“Imagine that a large asteroid…is…heading…towards Earth…astronomers calculate that it has a 0.5 probability of colliding with us, the uncertainty being due to measurement imprecision regarding its exact path…any collision would be certain to destroy all human life..what is now the rational expectation of humanity’s future duration…a 0.5 probability that humanity will last just the few days…(‘Doom-Now’), and a 0.5 probability that it will last however long it would have otherwise. What does DA (Doomsday Argument) say? Either it is deemed to modify these empirical probabilities; or it is not.”
Doomsday practitioners of course would revise the probability of Doom-Now upward significantly. For convenience, let’s say that humanity would last another million years otherwise, with a total number of people numbering 1 quadrillion. if we take ourselves to have been sampled uniformly at random from the total population past present and future, our birth rank of 60 billion or so looks very, very unlikely conditioned on Doom Later. It looks more plausible conditioned on Doom Now. So DA would revise P(DoomNow) upwards, close to 1. That’s how the Doomsday argument works. But Northcott writes:
“…according to DA, a priori considerations show that the expected duration for humanity is much greater than just a few days. The probability of Doom-Now should accordingly be modified downwards.”
First of all, the expected duration just is half a million years, which is already much greater than a few days. So the first sentence makes no sense. Second, the DA advocates in favor of Doom-Now…not against it. (That’s why it’s called the Doomsday argument.) A footnote here sheds no light whatsoever:
“True, DA reasoning implies that the single most likely total number of humans is the current number, i.e. 60 billion. But although the mode of the distribution is thus 60 billion, the mean is much greater. Thus, Doom-Now is not favoured.”
Obviously Doom-Now is favored by DA. I mean, of course the expected number of humans is around half of a quadrillion. That’s not DA reasoning, that’s just what it is. Not relevant though because DA assumes that the world is sampled by objective chance and then you are sampled uniformly from the observers in that world. The fact that some unlikely worlds have enormous population doesn’t dilute the worlds that have smallish population. That’s the whole point of DA. Nor is the gaffe a typo…Northcott goes on thinking that DA revises the probability of Doom-Now downward for the rest of the paper. Part of the paper involves miracles. I won’t go into that but the publication of this paper in Ratio is proof that they do happen.
The next passage is not to be believed:
“…an unbiased combined estimate (of the mean) can be achieved via inverse-variance weighting. Roughly, the higher an estimate’s variance, the more uncertain that estimate is, and so the less weight we should put on it. In the DA case, how we balance competing DA and empirical estimates of a probability turns – and must turn – on exactly this issue….Some toy numbers will illustrate. By assumption, the empirical estimate of the asteroid collision’s probability, and thus of Doom-Now’s, is very certain. Suppose that the density function of that estimate is a normal distribution with a mean of 0.5 and, representing the scientists’ high degree of certainty, a small standard deviation of 0.001. Next, suppose initially that for DA the equivalent figures are a mean of 0.001 and the same small standard deviation of 0.001. In this case, because the two variances are the same, so an unbiased estimate of the mean would be midway between the two component estimates of it, i.e. midway between 0.5 and 0.001, i.e. approximately 0.25.”
This is so wrongheaded in so many different ways I don’t really know where to start. So I will start with what is worst. Yes, there is a method in statistical meta-analysis of taking a weighted average of two estimators to get an unbiased third estimator that is of minimum variance, among all weighted averages, and yes it goes by taking the inverse variances as weights. But, first, the estimators you start with have to themselves be unbiased. The two “estimators” considered here can’t both be unbiased estimators of the same parameter, because they have different means, and what it means for an estimator to be unbiased is for it to have mean equal to the true value of the parameter being estimated. Perhaps more troubling, however, is that it’s not at all clear what they could be estimating…the only thing around to estimate is the objective chance that the asteroid hits the earth, which is either zero or one–unless it’s something like “the credence an ideal rational agent would have in this epistemic position”. Surely though that would have to be at least mentioned. The next thing that is wrongheaded is just what was mentioned before—the latter mean shouldn’t be .001 but rather something like .999…DA wants to raise the probability of Doom-Now. Finally…assuming that p is in fact the credence of an ideal rational agent in the current epistemic situation and assuming that both the scientists and DA are trying to estimate p, does it not strike the author as odd that the scientists are so damn certain that p is very close to 1/2 and DA is so damn certain that p is very close to .001? The compromise suggested is, perhaps it bears mentioning, 250 standard deviations away from the mean for both parties. Normally this would be a moment where the meta-statistician might say “hmm…maybe these estimators aren’t estimating the same thing….”.
Not that it matters much at this point, but the most amusing passage is this:
“we can calculate a second scenario, with new toy numbers…this time, suppose that for DA the equivalent figures are still a mean of 0.001 but now, say, a standard deviation of 0.1….”
Sorry, but it’s not possible for a credence estimator (which must take on values in [0,1]) to have a mean of .001 and a standard deviation of .1.
Don’t get me wrong. My beef is not with the author, who I assume is not perpetrating a hoax but just sincerely trying to say something important. The question, for me, is not how did this mess come to be written, but how did this mess come to be published in a respectable journal? Ratio isn’t some obscure, fly-by-night outfit. Ernest Sosa, for example, is on the editorial board. In fact, it seems there is a list of 49 “Most popular journals” used by PhilPapers to identify when someone is a “professional author” in philosophy, and Ratio is on it!
So perhaps congratulations are in order…by slipping this awful manuscript past the editors of this journal, this author is (if he wasn’t before) now and forevermore a “professional author” of philosophy, meaning that PhilPaper editors shall be obliged to archive every stupid thing he ever writes, even if no one on earth or in heaven will touch it.
Okay…but back to my question. How did this ridiculous manuscript come to be published? The question is intended for the editors of Ratio…I’m inviting reply. What was the process? Of course any public reply would obviously be just “we sent it off for double blind refereeing, got a positive report and it was voted in by the editors…blah, blah blah”. So, well…never mind, I guess.
But come on guys….my job isn’t supposed to be this easy. | s3://commoncrawl/crawl-data/CC-MAIN-2017-39/segments/1505818694719.89/warc/CC-MAIN-20170926032806-20170926052806-00085.warc.gz | CC-MAIN-2017-39 | 7,743 | 17 |
https://www.omicsonline.org/scholarly-articles/abstracts/a-comparative-study-of-non-linear-and-linear-system-of-three-speciesrnecological-model-16296.html | math | 700 Journals and 15,000,000 Readers Each Journal is getting 25,000+ ReadersThis Readership is 10 times more when compared to other Subscription Journals (Source: Google Analytics)
Review Article Open Access
The present paper is devoted to Numerical investigation of three species ecological model with a Prey ( 1 N ), a predator ( 2 N ) and a competitor ( ) 3 N to the both prey ( 1 N ) and Predator ( 2 N ). In addition to that, the species are provided with alternative food. The model is characterized by a set of first order non-linear ordinary differential equations. All the eight equilibrium points of the model are identified and study the comparison between linear system of equations and nonlinear system of equations using Numerical example with mat lab simulation.
To read the full article Peer-reviewed Article PDF
Author(s): Papa Rao A V Lakshmi Narayan K and Shahnaz Bathul
Prey, Predator, Competitor, Equilibrium points, Numerical example., Equilibrium points | s3://commoncrawl/crawl-data/CC-MAIN-2017-47/segments/1510934806569.66/warc/CC-MAIN-20171122103526-20171122123526-00475.warc.gz | CC-MAIN-2017-47 | 975 | 6 |
http://lib.physcon.ru/doc?id=1ac7559e860e | math | Guaranteed estimation of speech fundamental frequency with bounded complexity algorithm
he first stage of the Pitch estimation for a short time speech signal analysis consists of an exhaustive search of all integer Pitch periods in the harmonic model. For each Pitch period the cost function is calculated and then optimized. The general complexity is proportional to N2 where N is the length of the window in samples.
It is shown in this paper that the cost function can be approximated with the geometric rate of accuracy while the complexity of the algorithm remains around N log2 N. The trade-off between accuracy and complexity is discussed.
CYBERNETICS AND PHYSICS, Vol. 5, No. 1, 2016, 21–35. | s3://commoncrawl/crawl-data/CC-MAIN-2023-50/segments/1700679100651.34/warc/CC-MAIN-20231207090036-20231207120036-00862.warc.gz | CC-MAIN-2023-50 | 701 | 4 |
https://ncatlab.org/nlab/show/split+inclusion+of+von+Neumann+algebras | math | The split property for inclusions of von Neumann algebras was first introduced by Detlev Buchholz in the study of the AQFT approach to quantum field theory, but has become a much used concept in the mathematical structure theory as well.
Let be two von Neumann algebras with . This inclusion is called split if there is a type I-factor with
The inclusion is split iff there exist faithful normal representations of , of such that the map given by
extends to a spatial isomorphism, the tensor product used here is the spatial tensor product.
Definition 5.4.1 und Lemma 5.4.2 in | s3://commoncrawl/crawl-data/CC-MAIN-2017-17/segments/1492917121355.9/warc/CC-MAIN-20170423031201-00478-ip-10-145-167-34.ec2.internal.warc.gz | CC-MAIN-2017-17 | 576 | 5 |
https://forum.solidworks.com/thread/236587 | math | Hello, I am looking for some input on how to make an appearance for a layered material. The material that I am working with is called G-10. I'm just not exactly sure how to approach this problem as I've only done materials which have the same color throughout. Attached is a picture of the type of material that I am working with. Thank you all for your input. | s3://commoncrawl/crawl-data/CC-MAIN-2020-50/segments/1606141686635.62/warc/CC-MAIN-20201202021743-20201202051743-00620.warc.gz | CC-MAIN-2020-50 | 360 | 1 |
https://repositorioslatinoamericanos.uchile.cl/handle/2250/2642502 | math | Artículos de revistas
Generalized exponential distribution: A Bayesian approach using MCMC methods
International Journal of Industrial Engineering Computations, v. 6, n. 1, p. 511-524, 2015.
Universidade Estadual Paulista (Unesp)
Universidade de São Paulo (USP)
The generalized exponential distribution could be a good option to analyse lifetime data, as an alternative for the use of standard existing lifetime distributions as exponential, Weibull or gamma distributions. Assuming different non-informative prior distributions for the parameters of the model, we introduce a Bayesian analysis using Markov Chain Monte Carlo (MCMC) methods. Some numerical illustrations considering simulated and real lifetime data are presented to illustrate the proposed methodology, especially the effects of different priors on the posterior summaries of interest. | s3://commoncrawl/crawl-data/CC-MAIN-2023-06/segments/1674764500356.92/warc/CC-MAIN-20230206145603-20230206175603-00599.warc.gz | CC-MAIN-2023-06 | 854 | 6 |
https://www.imacs.org/from-aristotle-to-apple-how-mathematical-logic-shapes-the-world-we-live-in/ | math | What is mathematical logic?
What do you get when you combine math, computer science, philosophy, and linguistics? Mathematical logic! The big goal of mathematical logic is to link human language and thinking with math. In short, mathematical logic tries to understand math concepts through patterns that feel natural to your brain. Mathematicians who study mathematical logic also try to uncover and figure out contradictions and unsolved problems in the field of mathematics.
What do mathematical logicians study?
Most of the time, we learn math as a science. We learn formulas, and we test answers to get results. But mathematical logicians study math as a language. They study mathematical content, not just problems and solutions. Mathematical logic explores the language of math in two ways: syntactic and semantic. The syntactic dimension focuses on understanding the correct structure of a mathematical “sentence.” A mathematician studying syntax might be working on translating a “sentence” from the language of math into a set of instructions that a computer can understand. The semantic dimension has to do with interpretation or use of a mathematical “sentence.” A mathematician studying semantics would focus more on making mathematical “sentences” or concepts more easily understandable by humans.
Where and when did mathematical logic originate?
Although the study of logic in the language of math is relatively new, the study of logic in human languages is very old. One of the first thinkers in the field of logic was Aristotle. Aristotle’s logic was more like the sort of logic you might use to write an essay– he dealt with arguments, fallacies, language, and the other kinds of things a debate coach would teach you. For centuries, logic was only expressed through speech and writing. However, a few hundred years ago, the field of mathematical logic began to develop.
What is the difference between classical logic and mathematical logic?
In the beginning, mathematical logic looked pretty similar to Aristotle’s logic– it just used symbols instead of words. Although mathematicians mostly agreed that this new idea was powerful and influential, they had a harder time agreeing on the new language of symbols. It wasn’t until George Boole invented Boolean logic in the 1800s that mathematicians could agree on a universal logic language.
Why is mathematical logic important? The connection between mathematical logic and language.
The languages that we speak in our everyday lives– English, Chinese, Spanish, etc. –are known as “natural languages.” This means that they evolved naturally through thousands of years of humans trying to get better at communicating with each other. Mathematical logic, on the other hand, is a “formal language.” That means that its grammar and vocabulary were constructed intentionally by mathematicians and logicians to serve a specific purpose.
While formal and natural languages are different in many ways, they also have a lot in common! They both have specific rule sets, known as grammars. In English, grammar might tell you to change a verb based on when its action is happening: he runs vs. he ran. In mathematical logic, grammar might tell you that you can’t use an “or” operator to replace an “xor” operator (pronounced “Ex-Or”; we’ll learn what this means in a few paragraphs). Both grammars have the same effect on the language: they help writers generate expressions with consistent structures, and they help readers decide if a “sentence” is correct or not.
Mathematical logic and the human mind.
Have you ever wondered what makes humans so different from other animals? Scientists have wondered this too! About twenty years ago, three linguistic scientists named Marc Hauser, Noam Chomsky, and W. Tecumseh Fitch set out to argue that what makes humans so unique is how we understand language and communication. Humans have a particular area in our brain called Broca’s area. This part of our brain allows us to be much better at processing and understanding language than other animals. Our brains have allowed our languages to have something very unique: grammar!
While other animals have methods of communication, Hauser, Chomsky, and Fitch claimed that human language has a far more complicated structure than other languages. Human grammar allows us to talk about things that happened in the past, things that will happen in the future, and even things that might happen, but we’re not sure about yet. Those are some pretty complicated ideas! Mathematical logic is based on how good we are as humans at understanding structures and patterns. Mathematical logic evolved from Aristotelian logic, which evolved from human speech and language. The biggest thing that mathematical logic has in common with the language you speak every day is its strict structure with clear rules. So, while those rules may look very different from the grammar rules you learn in school, your ability to understand them comes from the same special part of your brain!
Mathematical logic and computer science.
Mathematical logic and computer science are very closely related. Many of the most famous computer scientists of the past were also mathematicians who studied logic. Alan Turing, who some people credit with building the first computer, based much of his work on mathematical logic concepts. Logic and computer science have the most overlap in a field of study called computability theory. This field works on improving our ability to find efficient ways to solve problems. In both logic and computer science, researchers work on techniques to automatically check and find mathematical proofs and theorems. However, even within this field, computer scientists and logicians focus on slightly different things. Computer scientists study how computability relates to real computers, problems, and programming languages: in essence, how to make computers faster and better. On the other hand, mathematical logic researchers focus on the theoretical concept of computability and are less concerned with how computability affects the day-to-day improvement of computers. Sometimes mathematicians or computer scientists working on mathematical logic will also research modal logic (or modal theory), propositional logic, recursion theory, and set theory.
Would you be good at mathematical logic?
The theory of multiple intelligences.
In 1983, Harvard psychologist Howard Gardner proposed his theory of Multiple Intelligences (http://www.pz.harvard.edu/projects/multiple-intelligences). Gardner believed that it was wrong to think of intelligence as a singular thing that each person possessed in a certain amount. Instead, Gardner believed that there are eight types of intelligence and that any person could possess intelligence in any number of categories.
Howard Gardner’s eight types of intelligence.
- Visual-spatial intelligence has to do with understanding images, directions, maps, and other visual elements.
- Linguistic-verbal intelligence has to do with reading, writing, and communication.
- Bodily-kinesthetic intelligence has to do with athletics, coordination, touch, and understanding the space around oneself.
- Musical intelligence has to do with rhythm, tone, and auditory elements.
- Interpersonal intelligence is the ability to understand and be understood by others.
- On the other hand, intrapersonal intelligence is the ability to examine and understand oneself.
- Naturalistic intelligence has to do with categorization– understanding the natural world and having profound empathy for all life.
- Finally, logical mathematical intelligence has to do with reasoning, recognizing patterns, and thinking conceptually about numbers and hierarchies.
Gardner also suggested the possibility of a ninth category: existential intelligence. Those with strong existential abilities would have an aptitude for considering deep and profound questions and deep empathy and understanding for humans on a broad societal level, not just an individual level.
Many other psychologists and researchers disagree with Gardner’s theory. They point out that he does not have much scientific evidence to back his ideas up. They argue that his intelligences are closer to a personality quiz than an empirical scientific theory. And while this may be true, you might still find Gardner’s theory useful to gain a better understanding of your own interests and the way you prefer to learn.
More about Howard Gardner’s idea of logical-mathematical intelligence.
According to Gardner’s theory, logical-mathematical learners are usually very organized and systematic. They think in clear and linear terms, making them very good at mental math and memorization. They also use patterns and sequences to absorb information– for example, logical-mathematical learners might have a precise planner or to-do list system. Simultaneously and paradoxically, they are comfortable with abstractions because of their ability to extract patterns and find consistency. Logical-mathematical learners are also heavily reliant on rules and structure. They will seek them out or make them if they are in a situation with few dictates, and they might feel anxious or less confident without regulations and routines. They also will probably feel frustrated when those around them ignore procedures.
How can you get better at mathematical logic?
Can you develop logical mathematical intelligence?
Many people seem to believe that being “good” at math is something you are born with. They see math skill as a talent that can only be strengthened if you have a “natural gift.” This is false. Your math ability is like a muscle: getting better at math is a lot like getting better at running or weightlifting! The way to improve your logical mathematical intelligence is to exercise that muscle. Like any exercise routine, it is essential to choose challenging activities and dedicate yourself to doing them regularly.
What jobs are well suited for people with logical-mathematical intelligence?
While there should be no pressure to decide on a career without exploring plenty of subjects and paths, you will likely enjoy a career in STEM fields if you enjoy building your logical-mathematical intelligence skills. Whether you want to develop next-generation machine learning at Apple or AI language models at OpenAI, the most cutting-edge tech research requires powerful analytic skills. Being a researcher, professor, mathematician, data scientist, computer programmer, or even a doctor are interesting jobs that reward well-developed mathematical intelligence. Even if you are interested in other types of work, growing your logical-mathematical intelligence will help you in everything from the debate team to robotics, from planning a complex landscaping project to making a roster and tournament schedule for a sports team.
How do you learn and practice your mathematical logic skills?
Mathematical logic symbols and operators.
One of the biggest and most well-known branches of mathematical logic is Boolean logic. And while Boolean logic can be incredibly challenging and difficult, its building blocks are so simple that anyone can understand them!
Boolean logic only deals with two numbers: one and zero. In the “language” of Boolean logic, one means “true,” and zero means “false.” Let’s talk about what this means in plain English by expressing a real-life situation in Boolean terms. Let’s say we are trying to test whether Annie and Sam went to the store. We would ask two questions. One: did Annie go to the store? Two: did Sam go to the store? If the answer to question one is yes, and the answer to question two is yes (and only if the answer to both is yes), then the answer to our test is yes, Annie and Sam went to the store! If the answer to either question one or question two is no, then the answer to our test is no!
In Boolean logic, each individual query we ask (“Annie goes to the store” and “Sam goes to the store”) is called an input, and the answer to our larger question is called an output. The list of all possible outputs for all of the different combinations of inputs is called a “truth table.”
Let’s look at a truth table for “Annie and Sam went to the store.”
|Annie||Sam||Did Annie Annie and Sam go to the store?|
|Annie did not go.||Sam did not go.||It is FALSE to say, “Annie and Sam went to the store.”|
|Annie did not go.||Yes! Sam went!||It is FALSE to say, “Annie and Sam went to the store.”|
|Yes! Annie went!||Sam did not go.||It is FALSE to say, “Annie and Sam went to the store.”|
|Yes! Annie went!||Yes! Sam went!||It is TRUE to say, “Annie and Sam went to the store.”|
What are the basic Boolean logical operators?
Instead of using the operators of the math that you are used to– plus, minus, times, divide –Boolean logic uses the operators “and,” “or,” “xor,” and “not.” There are other operators, too, but these are the most common. For most operators, just like in our example with Annie and Sam, there are two inputs (called “truth values”) and one output. Each operator has its own rule set that tells you how to respond to different combinations of inputs. The truth table shows the outputs corresponding to the combination of inputs you enter. Let’s look at the truth tables of the most common operators:
How “AND” works in Boolean logic
|Input 1||Input 2||Output|
Compare this to our truth table about Annie and Sam going to the store above. Did you notice it is the same? Here, in this Boolean truth table, we have represented “No,” “Not,” and “False” with a “0” and “Yes” (“True”) with a “1”. As you can see, the AND operator outputs a “true” answer if (and only if) the first and second inputs are true. Thinking about Annie and Sam, can you guess what the other operators might do?
Here is the truth table for OR.
Imagine asking if Annie or Sam are going to the store. Do you see why our output is “1” (or “True”) in three of the four possible cases?
|Input 1||Input 2||Output|
The OR operator outputs a “true” answer if either the first, or the second, or both inputs are true. So, if Annie went to the store, OR if Sam went to the store, OR if they both went to the store, our output is true.
“Or” is a word we use every day in English, but we don’t use the next one: “XOR” ever. Nevertheless, XOR is a conjunction of two words that you do know: “exclusively or.” Do you have a guess about what the truth table for XOR might be?
Here is the truth table for XOR
|Input 1||Input 2||Output|
The XOR operator, which stands for “eXclusively OR,” outputs a “true” answer if either the first or the second inputs, but not both, are true. The XOR operator will only give a true output if EITHER Annie or Sam went to the store. It will show a false output (“0”) if they both went to the store.
The truth table for NOT:
You might notice that the NOT operator’s truth table looks a bit different. That is because the NOT operator only takes one input, not two! It simply reverses whatever input is entered. The NOT operator can only consider one person at a time. If Annie did go to the store, the NOT operator will give a false output, and if she didn’t, it will give a true output.
Try these! Mathematical logic questions and answers.
Now that we know the rules of the most common operators let’s use them to solve a few problems! In our problems, we will use switches and lightbulbs to represent problems and solutions. “On” means true, or one, and “off” means false, or zero.
We will solve all of these problems on the logic.ly website. Before we start you should head over there and play around with the tool!
We’ll start with a tutorial. Let’s try to turn a lightbulb on and off with one switch. First, we will drag a toggle switch from the menu into the workspace.
Then, we will drag a lightbulb into the workspace.
Finally, we will connect the node on the switch with the node on the lightbulb. This sounds tricky, but it is straightforward once you know how to do it. Grab the little circle on the switch, hold down your mouse and drag the line to the little circle at the base of the lightbulb!
Now, by clicking the switch, we can turn the lightbulb on and off!
Great! Now here are some fun problems to try. All of the following exercises should be completed here: https://logic.ly/demo/
- Turn a lightbulb on and off using two switches. But the lightbulb should be on if, and only if, both switches are on. (In other words, if the first switch AND the second switch are on, then the lightbulb will be on. If either switch is off, or both switches are off, the lightbulb will also be off.)
- Turn a lightbulb on and off with two switches, but the lightbulb will only be on if any switch is on. (This means it will be on if either switch is on or if both switches are on.)
- Turn a lightbulb on and off with two switches, but the lightbulb can be on if either switch is on, but not both.
- Turn a light bulb on and off with one switch, but make it so that the lightbulb is on when the switch is off and off when the switch is on.
If you want to check your answers, you’ll find the solutions at the bottom of this blog article. If you enjoyed these Boolean logic problems, IMACS classes would be an excellent option to further develop your mathematical and logical skills while having a lot of fun!
What books and courses will strengthen your logical-mathematical intelligence?
Logic games and puzzles can be great exercises for your mental mathematical muscles. These can be found in books you work through on your own or in courses you work through with a knowledgeable teacher and peers. Here are some great books and courses to improve your logical-mathematical intelligence:
Some of our favorite mathematical logic books:
One of the most famous books on mathematical logic is a book with the unsurprising title: Mathematical Logic, by Joseph R. Shoenfield. This book is among the pioneers in the field and is an excellent resource for learning advanced mathematics logic concepts.
Some other books about mathematical logic and a recommended audiobook provide mathematical logic exercises and puzzles for those just getting started in the subject.
Where to find mathematical logic courses?
Most mathematical logic courses are not taught until university. The field is often considered too complex for younger students to learn. However, for younger students with a passion for math or computers, IMACS offers courses that teach mathematical reasoning. This is a perfect stepping stone for future logicians. IMACS makes mathematical logic fun and engaging and will improve the problem-solving skills of any eager student. For advanced secondary school students, IMACS offers a university-level logic course. Read more about what our alumni have to say about IMACS and try a free placement class to learn more.
Answers to the fun Boolean logic problems!
Turn a lightbulb on and off using two switches. But the lightbulb should only be on if, and only if, both switches are on. (In other words, if the first switch AND the second switch are on, then the lightbulb will be on. If either switch is off, or both switches are off, the lightbulb will also be off.)
Turn a lightbulb on and off with two switches, but the lightbulb will only be on if any switch is on.
If you solved this problem correctly, you can also turn the lightbulb by having both switches turned on.
Turn a lightbulb on and off with two switches, but the lightbulb can be on if either switch is on, but not both.
Turn a light bulb on and off with one switch, but make it so that the lightbulb is on when the switch is off, and off when the switch is on. | s3://commoncrawl/crawl-data/CC-MAIN-2023-40/segments/1695233510603.89/warc/CC-MAIN-20230930050118-20230930080118-00342.warc.gz | CC-MAIN-2023-40 | 19,856 | 89 |
http://www.jstor.org/stable/2290332 | math | You are not currently logged in.
Access JSTOR through your library or other institution:
Comparison of Smoothing Parameterizations in Bivariate Kernel Density Estimation
M. P. Wand and M. C. Jones
Journal of the American Statistical Association
Vol. 88, No. 422 (Jun., 1993), pp. 520-528
Stable URL: http://www.jstor.org/stable/2290332
Page Count: 9
You can always find the topics here!Topics: Data smoothing, Density estimation, Density, Estimators, Wands, Parameterization, Coordinate systems, Covariance, Average linear density, Statistical estimation
Were these topics helpful?See somethings inaccurate? Let us know!
Select the topics that are inaccurate.
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The basic kernel density estimator in one dimension has a single smoothing parameter, usually referred to as the bandwidth. For higher dimensions, however, there are several options for smoothing parameterization of the kernel estimator. For the bivariate case, there can be between one and three independent smoothing parameters in the estimator, which leads to a flexibility versus complexity trade-off when using this estimator in practice. In this article the performances of the different possible smoothing parameterizations are compared, using both the asymptotic and exact mean integrated squared error. Our results show that it is important to have independent smoothing parameters for each of the coordinate directions. Although this is enough for many situations, for densities with high amounts of curvature in directions different to those of the coordinate axes, substantial gains can be made by allowing the kernel mass to have arbitrary orientations. The "sphering" approaches to choosing this orientation are shown to be detrimental in general, however.
Journal of the American Statistical Association © 1993 American Statistical Association | s3://commoncrawl/crawl-data/CC-MAIN-2017-13/segments/1490218189239.16/warc/CC-MAIN-20170322212949-00539-ip-10-233-31-227.ec2.internal.warc.gz | CC-MAIN-2017-13 | 1,841 | 14 |
https://www.cosmostat.org/uncategorized/cosmosclub-ariel-sanchez | math | CosmosClub Ariel Sánchez
Date: July 9th 2020, 10.00 a.m.
Speaker: Ariel Sánchez (MPE Garching/ Max-Planck-Institut für extraterrestrische Physik )
Title: Let us bury the prehistoric h: arguments against using h−1Mpc units in observational cosmology
Room: Zoom Meeting (connection details will be updated soon)
It is common to express cosmological measurements in units of h^-1 Mpc. Here, we review some of the complications that originate from this practice. A crucial problem caused by these units is related to the normalization of the matter power spectrum, which is commonly characterized in terms of the linear-theory rms mass fluctuation in spheres of radius 8h^-1 Mpc, σ8. This parameter does not correctly capture the impact of h on the amplitude of density fluctuations. We show that the use of σ8 has caused critical misconceptions for both the so-called σ8 tension regarding the consistency between low-redshift probes and cosmic microwave background data, and the way in which growth-rate estimates inferred from redshift-space distortions are commonly expressed. We propose to abandon the use of h^−1 Mpc units in cosmology and to characterize the amplitude of the matter power spectrum in terms of σ12, defined as the mass fluctuation in spheres of radius 12Mpc, whose value is similar to the standard σ8 for h∼0.67. | s3://commoncrawl/crawl-data/CC-MAIN-2024-18/segments/1712296819971.86/warc/CC-MAIN-20240424205851-20240424235851-00715.warc.gz | CC-MAIN-2024-18 | 1,344 | 6 |
https://community.ptc.com/t5/Assembly-Design/Creo-Simulate-Element-Birth-and-Death-Capabilities/m-p/305178 | math | Creo Simulate Element Birth and Death Capabilities
Hello everyone, does anyone know whether creo simulate 3.0 has any type of element birth and death mesh capabilities? I know other fea software can limit a part's mesh to a stiffness of nearly 0 as time moves through a non-linear analysis. This would be really helpful in simulating a weld as the weld pool only exists as a function of time.
Any insight into Creo's capabilities would be appreciated!
Re: Creo Simulate Element Birth and Death Capabilities
If I recall correctly, you can defined a function for the Young's Modulus that is dependent on temperature. In you material properties definition box, right-click on the property and see if the pop-up menu has 'function' in it. | s3://commoncrawl/crawl-data/CC-MAIN-2020-40/segments/1600402088830.87/warc/CC-MAIN-20200929190110-20200929220110-00777.warc.gz | CC-MAIN-2020-40 | 734 | 5 |
https://justaaa.com/statistics-and-probability/511583-question-1-we-want-to-estimate-the-mean-change-in | math | We want to estimate the mean change in score µ in the population of all high school seniors. An SRS of 430 high school seniors gained an average of x¯¯¯x¯ = 22 points in their second attempt at the SAT Mathematics exam. Assume that the change in score has a Normal distribution with standard deviation 48.114.
Find σx¯¯¯σx¯, the standard deviation of the mean change x¯¯¯x¯. (±±0.001).
Using the 68-95-99.7 Rule (Empirical Rule), give a 99.7% confidence interval for μμ based on this sample.
Confidence interval (±±0.001) is between and
A class survey in a large class for first-year college students asked, "About how many hours do you study in a typical week?". The mean response of the 431 students was x¯¯¯x¯ = 17 hours. Suppose that we know that the study time follows a Normal distribution with standard deviation 7 hours in the population of all first-year students at this university.
What is the 99% confidence interval (±±0.001) for the population mean?
Confidence interval is from to hours.
Get Answers For Free
Most questions answered within 1 hours. | s3://commoncrawl/crawl-data/CC-MAIN-2023-40/segments/1695233510358.68/warc/CC-MAIN-20230928031105-20230928061105-00635.warc.gz | CC-MAIN-2023-40 | 1,089 | 9 |
https://core.ac.uk/display/192287 | math | Abstract. We define secondary theories and characteristic classes for simplicial smooth manifolds generalizing Karoubi’s multiplicative Ktheory and multiplicative cohomology groups for smooth manifolds. As a special case we get versions of the groups of differential characters of Cheeger and Simons for simplicial smooth manifolds. Special examples include classifying spaces of Lie groups and Lie groupoids
To submit an update or takedown request for this paper, please submit an Update/Correction/Removal Request. | s3://commoncrawl/crawl-data/CC-MAIN-2018-47/segments/1542039743247.22/warc/CC-MAIN-20181116235534-20181117021534-00432.warc.gz | CC-MAIN-2018-47 | 518 | 2 |
https://nrich.maths.org/7286&part= | math | Or search by topic
Imagine flipping a coin three times.
What's the probability you will get a head on at least one of the flips?
Charlie drew a tree diagram to help him to work it out:
He put a tick by all the outcomes that included at least one head.
How could Charlie use his tree diagram to work out the probability of getting at least one head?
How could he use it to work out the probability of getting no heads?
What do you notice about these two probabilities?
Devise a quick way of working out the probability of getting at least one head when you flip a coin 4, 5, 6... times.
What is the probability of getting at least one head when you flip a coin ten times?
Once you've worked out a neat strategy for the coins problem, take a look at these related questions which can be solved in a similar way:
Imagine choosing a ball from this bag (which contains six red balls and four blue balls) and then replacing it.
If you did this three times, what's the probability that you would pick at least one green ball?
What if you didn't replace the ball each time?
Imagine a class with 15 girls and 13 boys.
Three children are chosen at random to represent the class at School Council
What is the probability that there will be at least one boy?
Why not try the problem Same Number! next?
Your partner chooses two beads and places them side by side behind a screen. What is the minimum number of guesses you would need to be sure of guessing the two beads and their positions?
Discs are flipped in the air. You win if all the faces show the same colour. What is the probability of winning?
Are these games fair? How can you tell? | s3://commoncrawl/crawl-data/CC-MAIN-2024-18/segments/1712296816939.51/warc/CC-MAIN-20240415014252-20240415044252-00627.warc.gz | CC-MAIN-2024-18 | 1,630 | 21 |
https://m.ebook.de/de/product/3269688/freddy_delbaen_walter_schachermayer_the_mathematics_of_arbitrage.html | math | The Mathematics of Arbitrage
Lieferbar innerhalb von 2-3 Tagen
BeschreibungProof of the "Fundamental Theorem of Asset Pricing" in its general form by Delbaen and Schachermayer was a milestone in the history of modern mathematical finance and now forms the cornerstone of this book.
Puts into book format a series of major results due mostly to the authors of this book.
Embeds highest-level research results into a treatment amenable to graduate students, with introductory, explanatory background.
Awaited in the quantitative finance community.
InhaltsverzeichnisA Guided Tour to Arbitrage Theory.- The Story in a Nutshell.- Models of Financial Markets on Finite Probability Spaces.- Utility Maximisation on Finite Probability Spaces.- Bachelier and Black-Scholes.- The Kreps-Yan Theorem.- The Dalang-Morton-Willinger Theorem.- A Primer in Stochastic Integration.- Arbitrage Theory in Continuous Time: an Overview.- The Original Papers.- A General Version of the Fundamental Theorem of Asset Pricing (1994).- A Simple Counter-Example to Several Problems in the Theory of Asset Pricing (1998).- The No-Arbitrage Property under a Change of Numéraire (1995).- The Existence of Absolutely Continuous Local Martingale Measures (1995).- The Banach Space of Workable Contingent Claims in Arbitrage Theory (1997).- The Fundamental Theorem of Asset Pricingfor Unbounded Stochastic Processes (1998).- A Compactness Principle for Bounded Sequences of Martingales with Applications (1999).
PortraitWalter Schachermeyer, born in 1950 in Linz, Austria, has received--as the first mathematician--the 1998 Wittgenstein Award, Austria's highest honor for scienctific achievement. Since 1998 he holds the Chair for Actuarial and Financial Mathematics at the Vienna University of Technolgoy. Among his achievements is the proof of the "Fundamental Theorem of Asset Pricing" in its general form, which was done in joint work with Freddy Delbaen.
Freddy Delbaen, born in 1946 in Duffel/Antwerpen, Belgium, is Professor for Financial Mathematics at the ETH in Zurich since 1995.
PressestimmenFrom the reviews:
"As a learning device, I think this works really well. The second half of the book allows readers to 'put to use' the mathematics they learn in the first half. I really like the authors' writing style. They provide plenty of intuitive insights and historical notes along the way as they formally develop concepts. ... I recommend it highly to theoretically-inclined financial engineers and researchers." (www.riskbook.com, September, 2006)
"The aim of the book, as the authors state ... is to give the reader a guided tour through the mathematics of arbitrage. ... The book will be of invaluable help to new researchers in the area of incomplete markets. A new graduate student wishing to do such research would start by reading the papers in the book. She or he now has a very good book to assist this study." (Angelos Dassios, Mathematical Reviews, Issue 2007 a)
Untertitel: 'Springer Finance'. 1st ed. 2006. 2nd printing 2008. Book. Sprache: Englisch.
Erscheinungsdatum: Oktober 2011
Seitenanzahl: 392 Seiten | s3://commoncrawl/crawl-data/CC-MAIN-2017-22/segments/1495463608665.33/warc/CC-MAIN-20170526124958-20170526144958-00280.warc.gz | CC-MAIN-2017-22 | 3,101 | 15 |
http://www.mathnet.ru/php/archive.phtml?wshow=paper&jrnid=admat&paperid=10&option_lang=rus | math | Adv. Math., 2013, том 238, страницы 322–411
Parameterized Picard–Vessiot extensions and Atiyah extensions
H. Gilleta, S. Gorchinskiyb, A. Ovchinnikovcd
a University of Illinois at Chicago, Department of Mathematics Statistics, and Computer Science, 851 S Morgan Street
b Steklov Mathematical Institute, Gubkina str. 8
c CUNY Queens College, Department of Mathematics, 65-30 Kissena Blvd.
d CUNY Graduate Center, Department of Mathematics, 365 Fifth Avenue
Generalizing Atiyah extensions, we introduce and study differential abelian tensor categories over differential rings. By a differential ring, we mean a commutative ring with an action of a Lie ring by derivations. In particular, these derivations act on a differential category. A differential Tannakian theory is developed. The main application is to the Galois theory of linear differential equations with parameters. Namely, we show the existence of a parameterized Picard-Vessiot extension and, therefore, the Galois correspondence for many differential fields with, possibly, non-differentially closed fields of constants, that is, fields of functions of parameters. Other applications include a substantially simplified test for a system of linear differential equations with parameters to be isomonodromic, which will appear in a separate paper. This application is based on differential categories developed in the present paper, and not just differential algebraic groups and their representations.
Реферативные базы данных:
MSC: Primary 12H05; Secondary 12H20; 13N10; 20G05; 20H20; 34M15
Поступила в редакцию: 21.05.2012
Язык публикации: английский
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http://www.expertsmind.com/questions/application-of-linear-equations-30151148.aspx | math | Application of Linear Equations
We are going to talk about applications to linear equations. Or, put in other terms, now we will start looking at story problems or word problems.
Process for Working Story/Word Problems
1. READ THE PROBLEM.
2. READ THE PROBLEM AGAIN. Okay, this might be a little bit of overkill here.
Though, the point of these first two steps is that you have to read the problem. This step is the most important step, however it is also the step that most people don't do correctly.
You need to carefully read the problem and as several times as it takes. You are only done with this step while you have wholly understood what the problem is asking you to do. It includes identifying all the provided information and identifying what you being asked to determine.
Again, it can't be stressed sufficient that you've to carefully read the problem. Sometimes a single word can totally change how the problem is worked. If you only skim the problem you may well miss that extremely important word.
3. Represent one of the unknown quantities along with variable and attempt to associate all the other unknown quantities (if there are any of course) to this variable.
4. If applicable, sketch a figure reveling the situation. it may seem like a silly step, however it can be incredibly helpful with the next step on occasion.
5. Make an equation which will relate known quantities to the unknown quantities. In order to does this make use of known formulas and frequently the figure sketched in the previous step can be used to make the equation.
6. Solve out the equation formed in the previous step and write the answer to all the questions. It is significant to answer all the questions which you were asked. Generally you will be asked for many quantities in the answer and the equation will only give one of them.
7. Check your answer. Do this through plugging into the equation; however also use intuition to ensure that the answer makes sense. Mistakes can frequently be identified by acknowledging that the answer doesn't just make sense.
Let's begin things off with a couple of fairly fundamental examples to illustrate the procedure. Note as well that at this point it is supposed that you are able of solving fairly simple linear equations and hence not much detail will be given for the real solution stage. The instance of this section is more on the set up of the equation than the solving of the equation. | s3://commoncrawl/crawl-data/CC-MAIN-2020-50/segments/1606141515751.74/warc/CC-MAIN-20201130222609-20201201012609-00275.warc.gz | CC-MAIN-2020-50 | 2,433 | 14 |
http://nikafadul.com/index.php/ebooks/pioneers-in-mathematics-1900-to-1950-modern-mathematics | math | By Michael J Bradley
Through the first half the twentieth century, arithmetic turned a world self-discipline that ended in significant advances in technology and know-how. sleek arithmetic: 1900 to 1950 offers an eye-opening creation to these 5 ancient many years via interpreting the development of the sector throughout the accomplishments of 10 major mathematicians. From David Hilbert and Emmy Noether, who brought the endless dimensional vector areas and algebraic earrings that undergo their names, to Norbert Wiener, the founding father of cybernetics, this in-depth quantity is a wonderful selection for libraries aiming to supply a number assets overlaying the heritage of arithmetic.
Read or Download Pioneers in mathematics, 1900 to 1950, Modern Mathematics PDF
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Additional resources for Pioneers in mathematics, 1900 to 1950, Modern Mathematics
With concepts that came to be known as Noetherian rings and Noetherian ideals, this and subsequent papers revolutionized the study of abstract algebra. Noether published 15 papers on ideal theory and presented six of them at meetings of the DMV. The publications included the 1923 paper “Eliminationstheorie und allgemeine Idealtheorie” (Elimination theory and the general theory of ideals) and the 1927 paper “Abstrakter Aufbau der Idealtheorie in algebraischen Zahl- und Funcktionenkörpern” (Abstract structures of ideal theory in algebraic Amalie Emmy Noether 47 In the ring of integers, all the multiples of an integer n form an ideal that is denoted (n).
He published two of these results in the journal Elemente der Mathematik. In a 1962 paper titled “Sur une propriété des nombres tétraédraux” (On a property of tetrahedral numbers), he proved that there are infinitely many positive integers x, y, and z that satisfy the equation , where the notation coefficient represents the binominal . In his 1963 paper titled “Trois nom- bres tétraédraux en progression arithmétique” (Three tetrahedral numbers in arithmetic progression), he proved that the equation also had infinitely many positive integers solutions.
In this paper she proved a pair of theorems and their converses that are today collectively referred to as Noether’s theorem. Working with finite and infinite symmetry groups, she determined the conditions under which symmetries of a group action corresponded Amalie Emmy Noether 45 to conserved quantities of a physical system. Because the principle of conservation of energy and momentum is a special case of these general results, Noether’s theorem forms one of the cornerstones of the theory of general relativity. | s3://commoncrawl/crawl-data/CC-MAIN-2019-51/segments/1575540527205.81/warc/CC-MAIN-20191210095118-20191210123118-00257.warc.gz | CC-MAIN-2019-51 | 4,176 | 15 |
https://rd.springer.com/book/10.1007/978-1-4020-6964-2 | math | Table of contents
About these proceedings
Physical laws are for the most part expressed in terms of differential equations, and natural classes of these are in the form of conservation laws or of problems of the calculus of variations for an action functional. These problems can generally be posed as Hamiltonian systems, whether dynamical systems on finite dimensional phase space as in classical mechanics, or partial differential equations (PDE) which are naturally of infinitely many degrees of freedom. This volume is the collected and extended notes from the lectures on Hamiltonian dynamical systems and their applications that were given at the NATO Advanced Study Institute in Montreal in 2007. Many aspects of the modern theory of the subject were covered at this event, including low dimensional problems as well as the theory of Hamiltonian systems in infinite dimensional phase space; these are described in depth in this volume. Applications are also presented to several important areas of research, including problems in classical mechanics, continuum mechanics, and partial differential equations. These lecture notes cover many areas of recent mathematical progress in this field, including the new choreographies of many body orbits, the development of rigorous averaging methods which give hope for realistic long time stability results, the development of KAM theory for partial differential equations in one and in higher dimensions, and the new developments in the long outstanding problem of Arnold diffusion. It also includes other contributions to celestial mechanics, to control theory, to partial differential equations of fluid dynamics, and to the theory of adiabatic invariants. In particular the last several years has seen major progress on the problems of KAM theory and Arnold diffusion; accordingly, this volume includes lectures on recent developments of KAM theory in infinite dimensional phase space, and descriptions of Arnold diffusion using variational methods as well as geometrical approaches to the gap problem. The subjects in question involve by necessity some of the most technical aspects of analysis coming from a number of diverse fields. Before the present volume, there has not been one text nor one course of study in which advanced students or experienced researchers from other areas can obtain an overview and background to enter this research area. This volume offers this, in an unparalleled series of extended lectures encompassing this wide spectrum of topics in PDE and dynamical systems. | s3://commoncrawl/crawl-data/CC-MAIN-2018-17/segments/1524125945668.34/warc/CC-MAIN-20180422232447-20180423012447-00576.warc.gz | CC-MAIN-2018-17 | 2,551 | 3 |
http://sayf.info/2020/01/28/exactly-what-does-perimeter-indicates-in-z/ | math | Now you should be aware that the job of arithmetic major curriculum is all about dealing with numbers.
Whenever you examine math, you will find it is a topic that’s made up of science , math and literature allin one. That’s math Categories are known as Categories in the branches. After you examine using amounts, you figure out how to connect mathematics.
When studying mathematics the first thing which you must consider is that you have to find something which interests you. You’ve got to get a subject that you simply enjoy, After you learn math is about amounts. You may love the simple fact that algebra is a part of a bachelor’s degree. You might perhaps not be interested in physics, or biology. There are hundreds of topics that you can realize that you like.
Then you definitely can move ahead to some bachelor’s level in math In the event you find that mathematics can be your own major. In this type of level, you will learn about how mathematics is outlined, and you’ll see more.
In the event that you want to enlarge your knowing as you get farther together, you can think about gaining a master’s level in mathematics. Then you are able to move on to a Ph.D. level in mathematics in the event you’d love to research and more see more.
Along with the standard issues of algebra, geometry, trigonometry, calculus and numbers, there are. http://en.wikipedia.com/wiki/College_admissions_in_the_United_States What exactly does midsize means in math? When you learn this basic piece of advice, it can be used by you from the areas of math and numbers. Why Algebra’s work became important, can you determine? Why it is termed algebra, do you determine? It’s an interest that addresses angles with numbers.
1 thing that you will need to be conscious of is what exactly will proportional me an in math. Whenever you’re currently choosing you are able to learn regarding the idea of quantity. In the event you find yourself with a excellent summary of this topic, you need to use it. You are able to utilize it to determine fractions.
Upon getting a feel for this particular matter, you could take still another course that deals with using numbers to determine amounts. Then you can find out the way buyessay they will be able to help you with this subject and concerning Roman numerals. You are able to get yourself a certificate within this area.
What exactly does what mean in mathematics? After you examine this subject, you may use it to comprehend purposes that are terminal. This will make you better at solving quadratic equations and solving equations.
You should know that there was a lot far more to a topic. It will direct you towards working together with math’s other subjects which manage shapes along with geometry. There was a lot more than looking at a straight line. You might also find out more on the topic of volume and the areas once you review with calculus.
With the curriculum that you picked for your Math significant, you might get going for quite a mathematician. Then you are able to move on to additional topics, When you get a superior grasp of the task of volumes and areas. You should use it in order to help you from the fields of volume and area if you choose an introductory class in geometry. You’re able to take advantage of these notions to use in themes of mathematics.
These are only two or three of all things you need to learn in what exactly does perimeter way in mathematics. You’ll find other subjects. | s3://commoncrawl/crawl-data/CC-MAIN-2020-16/segments/1585370492125.18/warc/CC-MAIN-20200328164156-20200328194156-00303.warc.gz | CC-MAIN-2020-16 | 3,484 | 12 |
http://news.hampshire.police.uk/latest_news/tag/country-watch | math | Tag / Country Watch
News • Dec 07, 2018 15:57 GMT
Officers tackling rural crime took part in a joint operation to disrupt criminals coming into the north of the county.
News • Oct 12, 2018 12:24 BST
Keep full control of your dog when out and about in the countryside – or you could face prosecution.
Press releases • Sep 06, 2018 16:57 BST
Officers on the Isle of Wight are investigating a suspected animal attack after a farmer found more than 20 of his sheep had died. | s3://commoncrawl/crawl-data/CC-MAIN-2019-30/segments/1563195526714.15/warc/CC-MAIN-20190720214645-20190721000645-00057.warc.gz | CC-MAIN-2019-30 | 484 | 7 |
https://www.enotes.com/homework-help/drop-water-falls-from-ledge-tall-building-from-462692 | math | The drop of water falls from a ledge of a tall building from a height 320 m.
An object initially traveling at speed u m/s and accelerating at a m/s^2, in time t, travels a distance equal to S = u*t + (1/2)*a*t^2. The velocity of the body after time t is equal to v = u + a*t.
When the drop falls, its initial speed is 0. Ignore resistance due to air and take the acceleration due to gravity to be constant and equal to 9.8 m/s^2.
The distance traveled by the drop in the first second is 0*1 + (1/2)*9.8*1 = 4.9 m.
At the start of the 3rd second the speed of the drop is 0 + 9.8*2 = 19.6 m/s. The distance traveled by the drop in the third second is 19.6*1 + (1/2)*9.8*1 = 19.6 + 4.9 = 24.5
The difference between 24.5 and 4.9 is 19.6.
In the 3rd second the drop travels a distance 19.6 m more than it did in the first second after it fell off the ledge. | s3://commoncrawl/crawl-data/CC-MAIN-2022-49/segments/1669446710417.25/warc/CC-MAIN-20221127173917-20221127203917-00609.warc.gz | CC-MAIN-2022-49 | 853 | 7 |
http://johnhemming.blogspot.com/2010/04/retention-swing-vs-universal-swing-lib.html | math | Retention Swing vs Universal Swing (Lib Dem Surge)
It does appear that the traditional UNS methodology for seat projections cannot cope with a Lib Dem surge.
I have done some calculations on a retention swing. That is a calcalation on the basis that in each seat the national transfer of votes is replicated. However, if Labour have lost a third of their votes nationally they lose a third of their votes that were cast previously in each seat rather than the same percentage of the total vote in each seat.
This is a more complex calculation, but it produces more reliable results.
It needs more work, but a first cut of the data is available here | s3://commoncrawl/crawl-data/CC-MAIN-2017-17/segments/1492917121305.61/warc/CC-MAIN-20170423031201-00460-ip-10-145-167-34.ec2.internal.warc.gz | CC-MAIN-2017-17 | 648 | 5 |
https://books.google.com/books/about/Introductory_econometrics.html?id=GjS0AAAAIAAJ&hl=en | math | Introductory Econometrics: A Modern Approach
Econometrics has moved from a specialized mathematical description of economics to an applied interpretation based on empirical research techniques - and the modern approach of this innovative book is proof. Introductory Econometrics bridges the gap between the mechanics of econometrics and modern applications of econometrics by employing a systematic approach motivated by the major problems currently facing applied researchers. Offering a solid foundation for social science research, the book provides important knowledge used for empirical work and carrying out research projects in a variety of fields.
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The Nature of Econometrics and Economic Data
REGRESSION ANALYSIS WITH CROSSSECTIONAL DATA
The Simple Regression Model
37 other sections not shown
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2SLS applied assume asymptotic average bias binary ceteris paribus Chapter coefficient compute confidence interval covariance crime critical value cross-sectional data set degrees of freedom denote dependent differencing dummy variable econometric economic endogenous error term esti example exogenous expected value exper explain explanatory variables F statistic factors fitted values fixed effects forecast Gauss-Markov assumptions heteroskedasticity heteroskedasticity-robust homoskedasticity income increase independent variables instrumental variables intercept interpretation least squares matrix mean multiple regression normal distribution null hypothesis observations obtain og(wage OLS estimators OLS regression OLS residuals omitted variables p-value panel data parameters partial effect percentage population predicted probability problem properties random sample random variable regression analysis regression model restrictions salary Section serial correlation significance level simple regression slope estimates squared residuals standard errors statistically significant sum of squared Suppose Theorem tion Tobit model trend unbiased estimator uncorrected uncorrelated unit root variance wage zero | s3://commoncrawl/crawl-data/CC-MAIN-2019-30/segments/1563195524111.50/warc/CC-MAIN-20190715195204-20190715221204-00087.warc.gz | CC-MAIN-2019-30 | 2,134 | 10 |
https://cafedoing.com/unit-conversion-metric-units-converting/ | math | Unit Conversion Metric Units Converting
Unit Conversion Metric Units Converting.
Com where you can measure up, measure down or measure all around this page includes measurement worksheets for length, area, angles, volume, capacity, mass, time and temperature in metric, u.s. and imperial units. measurement concepts and skills give students the ability to perform tasks related to everyday life.
Converting fractions decimals percents card sort activity grade math expressions. Maths mathematics lessons resources bundles keywords helpful classroom posters math lesson plans. Hr time chart elapsed worksheets hour grade math. Worksheet weathering rates soil earth science resources homework sheet. Converting comparing speeds whiteboard basketball speed tricks. Dimensional analysis problems worksheet worksheets nursing dosage calculation practice calculations math. Activity student practice finding percent number change unit rate middle school math resources probability worksheets. | s3://commoncrawl/crawl-data/CC-MAIN-2021-21/segments/1620243988759.29/warc/CC-MAIN-20210506175146-20210506205146-00421.warc.gz | CC-MAIN-2021-21 | 986 | 4 |
https://goodriddlesnow.com/riddles/easy/page:382 | math | Question: The warden of a circular jail is extremely hyper one day so he begins running around opening cells. The jail has 100 cells numbered from 1 to 100. He runs in a circle and opens all of the cells. Next he runs around and closes every 2nd cell (starting with cell 2, 4, 6 , etc.). If a cell is open he closes it and if a cell is closed he opens it. When he finishes running by all 100 cells he opens/closes every 3rd cell (starting with 3, 6, 9, 12 etc.), then every 4th cell (starting with 4, 8, 12, etc.) and so on. He does this until he goes around and only changes the 100th cell.
When he is done what cells will be open?
Answer: The cells 1, 4, 9, 16, 25, 36, 49, 64, 81, and 100 will be open. Only the cells that have two of the same factors (4 = 2 * 2) will be open because they are opened and closed the same number of times (except 1 which is just opened). Since they have the same factor twice their number of factors is odd.
John has some chickens that have been laying him plenty of eggs. He wants to give away his eggs to several of his friends, but he wants to give them all the same number of eggs. He figures out that he needs to give 7 of his friends eggs for them to get the same amount, otherwise there is 1 extra egg left.
What is the least number of eggs he needs for this to be true?
Answer: 301 eggs. The number of eggs must be one more than a number that is divisible by 2, 3, 4, 5, and 6 since each of these numbers leave a remainder of 1. For this to be true one less than the number must be divisible by 5, 4, and 3 (6 is 2*3 and 2 is a factor of 4 so they will automatically be a factor). 5 * 4 * 3 = 60. Then you just must find a multiple of 60 such that 60 * n + 1 is divisible by 7. 61 / 7, 121 / 7, 181 / 7, 241 / 7 all leave remainders but 301 / 7 doesn't.
Question: My first is often at the front door.
My second is found in the cereal family.
My third is what most people want.
My whole is one of the united states.
What am I?
Answer: Matrimony (mat rye money). Which is certainly a united state!
Question: A town only has one barber (he is male). The barber only shaves all of the people who do not shave themselves.
So who shaves the barber?
Answer: It's a paradox, if he shaves himself then the second sentence would be false because he only shaves those who do not shave themselves. If he does not shave himself, then according to the second statement he must shave himself.
Question: You have been given the task of transporting 3,000 apples 1,000 miles from Appleland to Bananaville. Your truck can carry 1,000 apples at a time. Every time you travel a mile towards Bananaville you must pay a tax of 1 apple but you pay nothing when going in the other direction (towards Appleland).
What is highest number of apples you can get to Bananaville?
Answer: 833 apples.
Step one: First you want to make 3 trips of 1,000 apples 333 miles. You will be left with 2,001 apples and 667 miles to go.
Step two: Next you want to take 2 trips of 1,000 apples 500 miles. You will be left with 1,000 apples and 167 miles to go (you have to leave an apple behind).
Step three: Finally, you travel the last 167 miles with one load of 1,000 apples and are left with 833 apples in Bananaville.
Follow us and get the Riddle of the Day, Joke of the Day, and interesting updates. | s3://commoncrawl/crawl-data/CC-MAIN-2022-49/segments/1669446710808.72/warc/CC-MAIN-20221201085558-20221201115558-00279.warc.gz | CC-MAIN-2022-49 | 3,303 | 22 |
https://forums.fido.ca/t5/General-Support/Downgrade-Fee/td-p/161629 | math | Hi! I would like to downgrade my plan, I am currently in a 4gb data plan for 55$ and I would like to change it to 10gb data plan for the same price. What will happen if I'll do it? Do I need to pay my remaining balance in full? or do I need to pay it monthly like 55$ a month? | s3://commoncrawl/crawl-data/CC-MAIN-2024-18/segments/1712296816024.45/warc/CC-MAIN-20240412132154-20240412162154-00730.warc.gz | CC-MAIN-2024-18 | 276 | 1 |
http://mathhelpforum.com/calculus/206082-integral-how-solve.html | math | I think you might make some progress by substituting u=ln(x), so du=(dx/x).
Well, this is interesting. After substituting:
And then substituting again:
Now integrating by parts gives:
and we are stuck since can not be integrated in terms of elementary functions. See Exponential integral - Wikipedia, the free encyclopedia
Can anyone else help? Maybe I made a mistake somewhere. | s3://commoncrawl/crawl-data/CC-MAIN-2016-50/segments/1480698540698.78/warc/CC-MAIN-20161202170900-00013-ip-10-31-129-80.ec2.internal.warc.gz | CC-MAIN-2016-50 | 378 | 6 |
https://m.ebook.de/de/product/3597994/peter_giblin_primes_and_programming_an_introduction_to_number_theory_with_computing.html | math | Primes and Programming: An Introduction to Number Theory with Computing
Bisher € 70,72
Lieferbar innert 2 Wochen
BeschreibungIn this book, Peter Giblin describes, in the context of an introduction to the theory of numbers, some of the more elementary methods for factorization and primality testing; that is, methods independent of a knowledge of other areas of mathematics. Indeed everything is developed from scratch so the mathematical prerequisites are minimal.
InhaltsverzeichnisPreface; 1. The fundamental theorem, GCDs and LCMs; 2. Listing primes; 3. Congruences; 4. Powers and pseudoprimes; 5. Miller's test and strong pseudoprimes; 6. Euler's theorem, orders and primality testing; 7. Cryptography; 8. Primitive roots; 9. The number of divisors d and the sum of divisors; 10. Continued fractions and factoring; 11. Quadratic residues; References; Index.
Pressestimmen"An interesting, sophisticated introduction to number theory..." American Mathematical Monthly "Of the many volumes I have seen about 'number theory and computing', this delightful, if unorthodox, introductory text is probably the finest...a great strength of this book is its emphasis on computing and on computing examples. There are several programs included in the text, often different algorithms for achieving the same computational result, and both theoretical and practical reasons for preferring one method over another are discussed. The programming language is Pascal, which is perfectly appropriate...[and] there are a great many numerial exercises and examples...only the deadest of students could possibly consider this dry; the author has brought life and energy to the subject by his presentation." Duncan Buell, Mathematical Reviews
Untertitel: Sprache: Englisch.
Verlag: CAMBRIDGE UNIV PR
Erscheinungsdatum: Juli 1992
Seitenanzahl: 252 Seiten | s3://commoncrawl/crawl-data/CC-MAIN-2017-22/segments/1495463608953.88/warc/CC-MAIN-20170527113807-20170527133807-00211.warc.gz | CC-MAIN-2017-22 | 1,838 | 10 |
https://www.coursehero.com/file/7812394/32-Answers-b-y-x2-2x-8-1-a-y-x2-1-The-graph-has/ | math | Unformatted text preview: or, if you can believe it! 1.3 Graphs of Equations 1.3.1 27 Exercises 1. For each equation given below
• Find the x- and y -intercept(s) of the graph, if any exist.
• Following the procedure in Example 1.3.2, create a table of sample points on the graph
of the equation.
• Plot the sample points and create a rough sketch of the graph of the equation.
• Test for symmetry. If the equation appears to fail any of the symmetry tests, find a
point on the graph of the equation whose reflection fails to be on the graph as was done
at the end of Example 1.3.3
(a) y = x2 + 1
(b) y = x2 − 2x − 8 (c) y = x3 − x
(d) y =
(e) y = x3
√ − 3x x−2
(f) y = 2 x + 4 − 2 (g) 3x − y = 7
(h) 3x − 2y = 10
(i) (x + 2)2 + y 2 = 16
(j) x2 − y 2 = 1
(k) 4y 2 − 9x2 = 36
(l) x3 y = −4 2. The procedures which we have outlined in the Examples of this section and used in the exercises given above all rely on the fact that the equations were “well-behaved”. Not everything
in Mathematics is quite so tame, as the following equations will show you. Discuss with your
classmates how you might approach graphing these equations. What difficulties arise when
trying to apply the various tests and procedures given in this section? For more information,
including pictures of the curves, each curve name is a link to its page at www.wikipedia.org.
For a much longer list of fascinating curves, click...
View Full Document | s3://commoncrawl/crawl-data/CC-MAIN-2018-05/segments/1516084889542.47/warc/CC-MAIN-20180120083038-20180120103038-00331.warc.gz | CC-MAIN-2018-05 | 1,457 | 25 |
http://northadams.com/news?page=4 | math | |BRPC Considering Expanding Role In Education Task Force|
PITTSFIELD, Mass. — The Berkshire Education Task Force has asked BRPC to take an expanded role in helping school districts regionalize.
The task force had already released its recommendation that eventually the county should have a single school district. That process will take years and have many challenging steps. The
|North Adams Enters Agreement To Sell DPW Facility |
NORTH ADAMS, Mass. — The City Council voted to enter into a purchase and sales agreement with Cumberland Farms for the DPW facility.
Mayor Richard Alcombright asked the Council to approve an agreement Wednesday between the city and Cumberland Farms that would start the process of a $575,000 purchase from the city - $475,000
|Williamstown Elementary Holds Fall Children's Clothing Sale on Oct. 14|
Bins of goodies await shoppers on Oct. 14.
WILLIAMSTOWN, Mass. — The Williamstown Elementary School PTO's annual clothing sale enters its second decade on Saturday, Oct. 14, from 8:30 a.m. to 2:30 p.m. As an added bonus, items will be half-price for customers receiving a hand stamp and entering after 1:30 p.m.
|Berkshire Health Systems Named a 2017 WWCMA WorkWell Massachusetts|
PITTSFIELD, Mass. — Berkshire Health Systems and its Wellness at Work program have been named a WorkWell Massachusetts Award Program Gold Level winner for exemplary worksite health promotion.
The award recognizes Berkshire Health System's achievements developing, implementing, and participating in corporate health improvement and
|International Investing: Still a Journey to Consider|
Columbus Day was observed on October 9. And while it may be true that Leif Erikson and the Vikings beat Columbus to the New World, Columbus Day nonetheless remains important in the public eye, signifying themes such as exploration and discovery. As an investor, you don't have to "cross the ocean blue," as Columbus did, to find
|Barrett Runs Away with 1st Berkshire Democratic Primary|
NORTH ADAMS, Mass. -- Claiming a victory on behalf of the forgotten middle class, John Barrett III on Tuesday emerged the winner in a four-person Democratic primary to run in the Nov. 7 special election to fill the 1st Berkshire District seat in the House of Representatives.
With the vast majority of the
|Grieve to Speak at Baseball in the Berkshires Exhibit|
LANESBOROUGH, Mass. -- Baseball in the Berkshires will have a special "Talkin' Baseball" program with Pittsfield native Tom Grieve on Thursday, Oct 12, from 6 to 7 p.m.
Grieve was a Major League outfielder and designated hitter with the Washington Senators, Texas Rangers, New York Mets and St. Louis Cardinals. He
|North Adams Police Investigating Home Invasion|
NORTH ADAMS, Mass. — State and local police are investigating a reported armed home invasion on Washington Avenue.
According to a safety alert sent out by Massachusetts College of Liberal Arts campus police, three men left the scene in a blue Volvo late Tuesday morning.
One was armed with a handgun.
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http://users.humboldt.edu/rpaselk/C109.S13/Chem_Discuss/ThermChem.html | math | |Exercise: Thermal Chemistry||
Heat = q = mCT; C = the heat capacity of a substance
1. How much heat will it take to raise the temperature of a 15.0 g gold bracelet from 16.1 °C to 49.3 °C? Assume a constant heat capacity of 25.4 J °C-1mol-1 over this temperature range.
2. A 0.95 kg cast iron pan is heated from room temperature (20.0 °C) to 125.0 °C on a gas stove. Assuming the heat capacity of the pan remains constant over this temperature range, calculate the quantity of heat absorbed by the pan ( heat capacity of Fe = 25.1 J °C-1mol-1).
3. What is the heat capacity of a calorimeter that contains 125.0 g of water, if it took 40.0 kJ to raise the temperature of the calorimeter and the water 14.00 °C? (The heat capacity of water is 4.184 Jg-1°C-1)
4. A 75.0 g bar of copper metal at 128.2 °C is dropped into a liter of cool water in an insulated container where its temperature drops to 24.1 °C, in equilibrium with the water. Assuming all of the heat goes to heat up the water (the container has a heat capacity of zero), what was the initial temperature of the water? (The molar heat capacity of copper is 24.4 Jmol-1°C-1, the heat capacity of water is 4.184 Jg-1°C-1.)
5. A 0.828 g sample of methanol is completely combusted in a bomb calorimeter with excess oxygen. The calorimeter contains 1.35 kg of water and the instrument has a heat capacity of 1.06 kJ °C-1 without water. Combustion of the methanol increases the temperature of the calorimeter from 23.10 to 25.90°C. Find the molar heat of combustion of methanol (heat released in burning one mole of methanol).
Section 6.2 in your textbook—you should be able to do the examples and exercises in the assigned problems listed on the Schedule.
1. Find the value of H for the reaction below at 25°C:
NH3(g) + HCl(g) NH4Cl(s)
2. Calculate the value of H for the reaction below at 25°C:
Na2O(s) + H2O(l) 2 NaOH(s)
3. Find the molar heat of combustion of methanol (CH3OH) in oxygen to give water and carbon dioxide.
In addition to these exercises you should familiarize yourself with the text materials referenced below.
© R A Paselk
Last modified 2 March 2011 | s3://commoncrawl/crawl-data/CC-MAIN-2017-43/segments/1508187825473.61/warc/CC-MAIN-20171022222745-20171023002745-00804.warc.gz | CC-MAIN-2017-43 | 2,143 | 16 |
http://english.stackexchange.com/questions/36745/other-ways-to-say-im-rooting-for-you/36747 | math | What are other ways one can say that have the same meaning as, "I'm rooting for you?"
Some other ways:
protected by RegDwigнt♦ Sep 22 '12 at 11:26
This question is protected to prevent "thanks!", "me too!", or spam answers by new users. To answer it, you must have earned at least 10 reputation on this site. | s3://commoncrawl/crawl-data/CC-MAIN-2014-10/segments/1394010444750/warc/CC-MAIN-20140305090724-00081-ip-10-183-142-35.ec2.internal.warc.gz | CC-MAIN-2014-10 | 311 | 4 |
https://questions.tripos.org/part-ia/2015-17/ | math | Write down the Lorentz transform relating the components of a 4-vector between two inertial frames.
A particle moves along the -axis of an inertial frame. Its position at time is , its velocity is , and its 4 -position is , where is the speed of light. The particle's 4-velocity is given by and its 4 -acceleration is , where proper time is defined by . Show that
where and .
The proper 3-acceleration a of the particle is defined to be the spatial component of its 4-acceleration measured in the particle's instantaneous rest frame. By transforming to the rest frame, or otherwise, show that
Given that the particle moves with constant proper 3 -acceleration starting from rest at the origin, show that
and that, if , then . | s3://commoncrawl/crawl-data/CC-MAIN-2024-18/segments/1712296816820.63/warc/CC-MAIN-20240413144933-20240413174933-00334.warc.gz | CC-MAIN-2024-18 | 725 | 6 |
http://www.omgsnap.com/read/spatial-statistics-and-micromechanics-of-materials-mtls-sci | math | By K. Mecke, et al.,
Read or Download Spatial Statistics and Micromechanics of Materials [mtls sci] PDF
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Additional info for Spatial Statistics and Micromechanics of Materials [mtls sci]
Thus, for a finite hypothesis set H, R(h) ≤ R(h) + O log2 |H| m . As already pointed out, log2 |H| can be interpreted as the number of bits needed to represent H. Several other remarks similar to those made on the generalization bound in the consistent case can be made here: a larger sample size m guarantees better generalization, and the bound increases with |H|, but only logarithmically. 2 |H| ; it varies as the square But, here, the bound is a less favorable function of logm root of this term.
No, since hS is not a fixed hypothesis, but a random variable depending on the training sample S drawn. 3), the generalization error R(hS ) is a random variable and in general distinct from the expectation E[R(hS )], which is a constant. Thus, as in the proof for the consistent case, we need to derive a uniform convergence bound, that is a bound that holds with high probability for all hypotheses h ∈ H. 2 Learning bound — finite H, inconsistent case Let H be a finite hypothesis set. Then, for any δ > 0, with probability at least 1 − δ, the following inequality holds: ∀h ∈ H, R(h) ≤ R(h) + log |H| + log 2δ .
2 Growth function Here we will show how the Rademacher complexity can be bounded in terms of the growth function. ,xm }⊆X h(x1 ), . . , h(xm ) : h ∈ H . 19) Thus, ΠH (m) is the maximum number of distinct ways in which m points can be classified using hypotheses in H. This provides another measure of the richness of the hypothesis set H. However, unlike the Rademacher complexity, this measure does not depend on the distribution, it is purely combinatorial. 2 Growth function 39 To relate the Rademacher complexity to the growth function, we will use Massart’s lemma. | s3://commoncrawl/crawl-data/CC-MAIN-2019-51/segments/1575540487789.39/warc/CC-MAIN-20191206095914-20191206123914-00158.warc.gz | CC-MAIN-2019-51 | 4,243 | 15 |
https://cfpub.epa.gov/ols/catalog/advanced_brief_record.cfm?&FIELD1=SUBJECT&INPUT1=EPA%20method%206&TYPE1=EXACT&LOGIC1=AND&COLL=&SORT_TYPE=MTIC&item_count=15&item_accn=141602 | math | In 1988, the Quality Assurance Division conducted the National Audits for Stationary Source Test Methods. The audit materials consisted of: a disposable gas cylinder for Method 3 (Orsat analyzer), a calibrated orifice for Method 5 (DGM only), five simulated liquid samples each for Method 6 (SO2) and Method 7 (NOx), and two coal samples for Method 19. Participating laboratories sent their data to the Source Branch and in return received a written report comparing their results to EPA's. In the Method 3 audit, each parameter had only one concentration. The mean for CO2 was 4.2% from the expected (EPA) value. The mean for O2 was 0.4%. In the Method 5 audit, the mean value for all participants differed by 3.1% from the expected value. For the Method 6 audit, the average mean differed by 3.9% from the expected value, and in the Method 7 audit, the average mean differed by 23.7%. In the two coal audits, the parameters measured were sulfur, moisture, ash, and Btu content. On the average, for the sulfur analysis, 91% of the participants measured within 10% of the expected value; for Btu, 97% of the participants measured within 10% of the expected value. | s3://commoncrawl/crawl-data/CC-MAIN-2021-21/segments/1620243991562.85/warc/CC-MAIN-20210519012635-20210519042635-00509.warc.gz | CC-MAIN-2021-21 | 1,163 | 1 |
https://www.usingenglish.com/forum/threads/217432-a-the | math | I have a book. The book is about physics.
To call a noun known or unknown (to put a/an OR the before it), I believe in this statement: an unknown object is something that the speaker knows but the audience does not. And a known object is something that both the speaker and the audience know.
First I wanted to know whether I'm right in finding it in my definition?
It's a test I found in 'Digest,' a grammar book I'm teaching in a class now.
Can you lend me .... pencil so that I can finish ..... test?
the answer is "a-the" but I think "a-a" can be correct too, am I right?
Yes, you are right in both cases. | s3://commoncrawl/crawl-data/CC-MAIN-2016-44/segments/1476988721555.36/warc/CC-MAIN-20161020183841-00120-ip-10-171-6-4.ec2.internal.warc.gz | CC-MAIN-2016-44 | 609 | 7 |
https://graduatepapertutors.com/1-create-a-function-that-will-draw-an-octagonal-prism-as-shown-below-the-base-of-the-5346485/ | math | 1)Create a function that will draw an octagonal prism as shown below. The base of the prism is a regular octagon (all the sides are equal). This function should have 3 function inputs (input parameters): an array that contains the xyz values of the point of origin, P0; a scalar value for the side of the octagonal prism, and a scalar value for the height of the octagonal prism. Generate the x,y,z arrays that define the 9 faces of the pyramid (octagonal base and 8 triangles. Use fill3 command to create the faces (faces with parallel bases should be in the same color). You may either plot the front faces, set the transparency, then draw the back faces as shown below or plot all the faces and then set the transparency. You do not have to label the axes or show the point of origin. In the script file prompt the user to enter the values for the origin, the side of the base and the height and call the function.
https://graduatepapertutors.com/wp-content/uploads/2019/10/logo-300x60.png 0 0 Joseph https://graduatepapertutors.com/wp-content/uploads/2019/10/logo-300x60.png Joseph2021-01-20 13:20:312021-01-20 13:20:311 create a function that will draw an octagonal prism as shown below the base of the 5346485 | s3://commoncrawl/crawl-data/CC-MAIN-2022-40/segments/1664030336921.76/warc/CC-MAIN-20221001195125-20221001225125-00076.warc.gz | CC-MAIN-2022-40 | 1,215 | 2 |
https://homelovehamilton.com/helpful-tools/ | math | Helpful calculators to estimate buying costs
Calculate your potential costs and expenses here:
Payment Calculator: This calculator can help you find out what your monthly payments will be when you assume a mortgage.
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https://ui.adsabs.harvard.edu/abs/1969RSPSA.313..453T | math | Fine jets of slightly conducting viscous fluids and thicker jets or drops of less viscous ones can be drawn from conducting tubes by electric forces. As the potential of the tube relative to a neighbouring plate rises, viscous fluids become nearly conical and fine jets come from the vertices. The potentials at which these jets or drops first appear was measured and compared with calculations. The stability of viscous jets depends on the geometry of the electrodes. Jets as small as 20 μ m in diameter and 5 cm long were produced which were quite steady up to a millimetre from their ends. Attempts to describe them mathematically failed. Their stability seems to be due to mechanical rather than electrical causes, like that of a stretched string, which is straight when pulled but bent when pushed. Experiments on the stability of water jets in a parallel electric field reveal two critical fields, one at which jets that are breaking into drops become steady and another at which these steady jets become unsteady again, without breaking into drops. Experiments are described in which a cylindrical soap film becomes unstable under a radial electric field. The results are compared with calculations by A. B. Basset and after a mistake in his analysis is corrected, agreement is found over the range where experiments are possible. Basset's calculations for axisymmetrical disturbances are extended to those in which the jet moves laterally. Though this is the form in which the instability appears, calculations about uniform jets do not seem to be relevant. In an appendix M. D. Van Dyke calculates the attraction between a long cylinder and a perpendicular plate at a different potential. | s3://commoncrawl/crawl-data/CC-MAIN-2022-40/segments/1664030334987.39/warc/CC-MAIN-20220927033539-20220927063539-00235.warc.gz | CC-MAIN-2022-40 | 1,698 | 1 |
https://exzoon.com/guess-and-check-logic-math-2-items-one-has-more-the-origin-of-the-11d-world-membrane-as-a-pascal-conic-section-of-a-6d-string-in-5d-projective-space/ | math | You are searching about Guess And Check Logic Math 2 Items One Has More, today we will share with you article about Guess And Check Logic Math 2 Items One Has More was compiled and edited by our team from many sources on the internet. Hope this article on the topic Guess And Check Logic Math 2 Items One Has More is useful to you.
The Origin of the 11D World Membrane As a Pascal Conic Section of a 6D-String in 5D Projective Space
David Hilbert’s biography discusses a debate over whether it was an intellectual mistake to advocate advancing the 2000-year-old Pappus theorem to axiom status. This issue is notable from a number of perspectives, one of which is his 1920 proposal that established the Hilbert Program for formulating mathematics and/or geometry in a more robust and complete manner. logical basis that conforms to inclusively larger “metamathematical principles”.
However, at the time, he proposed that this could be done if: 1. all mathematics follows from a complete or correctly chosen finite system of axiomsand 2. this system of axioms is demonstrably consistent through some means such as its epsilon calculus. Although this formalism has had a successful influence on Hilbert’s work in algebra and functional analysis, it was not committed in the same way to his interests in logic as well as in physics, for not talk about his axiomatization of geometry, given the scheme. question of considering Pappus’ theorem as an axiom. Similarly, a similar problem arose when Bertrand Russell rejected Cantor’s proof that there was no “maximum” cardinal number and defended the “logicism” of his and AN Whitehead’s proposition in Mathematical principles that all mathematics is in some important sense reducible to logic. But both Hilbert’s and Russell’s support for an axiomatized mathematical system of definite principles that could banish theoretical uncertainties “forever” would end in failure in 1931.
Because Kurt Gödel showed that any non-contradictory (self-consistent) formal system complete enough to include at least arithmetic, could not (both) demonstrate its completeness (and/or, conversely, its categorical consistency) by its own axioms . Which means that Hilbert’s program was impossible as stated, since there is no way that the second point can be rationally combined with assumption-1 as long as the system of axioms is actually finite; otherwise you will have to add an endless series of new axioms, starting, I. guess, with Pappus’s! Equally, Gödel’s incompleteness theorem reveals that neither Mathematical principles, nor any other consistent system of recursive arithmetic, could decide whether each proposition, and/or its negation, was provable within that system. However, beyond Hilbert’s misstep over Pappus, it should be noted that Gödel’s theorem itself, in a realist sense, supports Hilbert’s basic idea of a deeper, more inclusive environment, ‘metallurgical’ foundation like a ‘Gödelian cartographywhich “covers” all mathematics and geometry. In fact, it was Hilbert Gentzen’s student who used a Gödel map “orders” of “trans-infinite” number systems to demonstrate Gödel’s theorem: so really metalogically valid ordinary arithmetic. In any case, although this conclusion also fits loosely with Russell’s logistical ideas, it also demonstrates a great improvement over his criticism of Cantor’s proof for an infinite series of cardinal numbers, which, after all, is the point of Cantor’s arguments in the sense that some ‘continuity axiom’ like that of Archimedes is required to generate an infinite field of real numbers. Which makes Hilbert’s Pappian faux pas seem almost trivial by comparison, since I’d like to know how Russell expected to find some “larger cardinal number” as well as how he expected to axiomatically describe continuity for an infinite range of numbers or points. a line; that is, before, let alone after, any infinite axiomatic system became an additional problem!
In any case, if Russell, or Hilbert, had actually taken up Occam’s razor, they probably would have cut their own throats with it before revealing their biased assumptions and inconsistencies for the world to see for eternity. Which simply means why elevate some provable theorem to the status of an axiomatic assumption, or introduce your own inconsistent system of assumptions, when it is clearly better to leave everything as it is. However, I am happy to use this razor properly in order to cut these icons a little posthumously, as if God had torn them from his suicidal hands, just to thank them in return for the indulgent opportunity to show everyone a again why fools seem routinely skewed as absurd fodder for us “lesser” fools or “commoners” in some exclusive or “formal” organizational hierarchy. That’s why the wisest people just say: the higher the monkey climbs the tree, the more it exposes itself to those below! (But also always be careful underneath, before something pops that hole in your face again!!)
In any case, this brings us back to another older and equally pressing issue is directly connected with Pappus’ “hexagon theorem” as generalized by Blaise Pascal in a projective conical sectionor 6-point oval, in 1639, when he was only 16 years old. Naturally impressed by Desargues’s work on conics, he produced, as a means of proof, a short treatise on what he called the “Mystic Hexagram”, better known since then simply as Pascal’s theorem . It basically (as defined by Wikipedia) states that if an arbitrary hexagon is inscribed in any conic section, where opposite sides extend to meet, the three points of intersection will lie on a straight line, called “Pascal line” of this configuration.
Although this simple description verbally suffices, it may fail to convey the fuller and truly “mystical” aspects that give Pascal’s theorem and configuration the distinction of being regarded as the most central fundamental construction of geometry projective And while diagrams would help clear things up, especially the descriptions below, it’s hard enough to reformat the content of these articles from the preferred notebook text to fit the different formats of different e-journals or distribution services. web articles In any case, it is no coincidence that I have not only made Pascal’s conic the cover figure of my text covering the projective and its subgeometries, but include a frontispiece of various 6-element conics relevant to all, including Brianchon’s projective dual to Pascal’s. So any interested reader can go to the resource box and pull out at least the Pascal cover figure, if not the frontispiece.
Anyway, the figure on the cover of the text illustrates Pascal’s theorem represented in a simple hexagon formed by mutually inscribing a full line of 6 points (15 lines) and 6 full lines (15 points) representing the respective plane sections of a complete line of six dimensions. -into a point and a full 6-derivative three-dimensional plane recursively intersecting a full five-dimensional 6-dimensional point it is the simplest representation as a spatially extended maximal projective set of vertices for this object. This description thus underlines its profound importance in terms of the scope of the entire dimensional gamete of the “axioms of incidence” (previously the additional set necessary to establish the meaning and that of continuity is introduced), starting with the simplest dimensional axioms extension and 5D closure, along with its projective dual of six lines on a point, which is then sectioned down to the final incidence ratios corresponding to six full points on a line and six full lines through a point. Similarly, the space of 5 can be added with the dimensions of 6 lines to get an 11D manifold that serves as a coverage space to map what amounts to a finished projecting geometry that is at the same time is both complete i categorically consistent (since it does not refer to infinite ranges of points or numbers, it is not restricted by Gödel’s reasoning, but again it admits). So, for example, it is quite interesting that JW Hirschfeld points out in his text on finite projective groups that there are no six conics of dimension greater than eleven.
Which brings us to the crux of this article as far as math is concerned physics of (super) stringand ‘M’ or membranetheory – which I have yet seen reduced by Occam’s blade to its essence in the basics of geometry, so the summary here is comprehensible to a wider segment of intelligent people. Superstring theory is based on a four-dimensional spacetime or physical metric, which together with a six-dimensional internal (Kauler) manifold (or compact Calabi-Yau space) for what can now be thought of as strings 1D of 6 -line-to-point; forming a total system of 10 dimensions. But by the 1980s it became clear that a promising unification of physics within a theory of quantum gravitation of superstrings was impossible, as they branched off into five 10 different mathematical groups (leading to the situation in which a number of mathematical eggheads, mostly with little interest in physics). per se, began to dominate theoretical physics departments). Which led to a second “superstring revolution” in the mid-1990s, when Ed Witten concluded that each of the 10D superstring theories is a different aspect of what was originally called a single “membrane theory’ (see http://en.wikipedia.org/wiki/Membrane_Theory), the entirety of which is naturally eleven dimensional and establishes interrelationships between the different superchain group theories described by various “dualities”. Because just as 1D strings are more manageable, finite extensions of singular points, groups of strings in a plane form “sheets of the world” as literal “2D membranes”, where these so-called “branes” can be defined of any dimension, starting with a 0-brane or point.
Thus, while the total system may properly be called an “11D world membrane,” Witten prefers generically to call it “M-theory,” where M can stand for membrane, mother, math, matrix, master, mystery, magic, or after , as Pascal would forcefully add: Mystic! In any case, there is little doubt that one day a complete 6-dimensional representation of 1D strings packed into 5D spacetime will fulfill Einstein’s dream of a fully unified physical theory. But personally, I’m much less concerned with “theoretical” unifications than I am with a comprehensive interpretation of physics and cosmology, replete with a host of confirmable data. Because I have developed the first dimensionless or “pure” scale system (Planck) which I call “Mumbers” or “membrane numbers”. and that covers precisely the whole spectrum of particle physics and space-time. And while I don’t have the IQ, inclination, or patience to follow or pursue higher mathematics for theoretical purposes, on the other hand, I’ve tried many, but I’ve yet to find anyone, physicist or mathematician, who can successfully write a pure numerical equation even for a relationship between different physical states. Similarly, standard super-string or M-theory has yet to make any confirmed, or even confirmable, predictions, no more than I, at least, have seen anyone point to the geometric underpinnings of M-theory as a Pascal’s 11-dimensional section. a projective double space of 5 and a six-string 6D at one point. So regardless of my mathematical inadequacies, I can guarantee that no viable “unified M-theory of physics” can be developed until the intellectual community accepts the metalogical tautology of both Pascal’s mysterious 6-conic that underlies the foundations of geometry, as well as the accompanying unified “dimensionless” scale that already represents a proven system that encompasses all of physics.
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#Origin #11D #World #Membrane #Pascal #Conic #Section #6DString #Projective #Space | s3://commoncrawl/crawl-data/CC-MAIN-2023-06/segments/1674764500250.51/warc/CC-MAIN-20230205063441-20230205093441-00206.warc.gz | CC-MAIN-2023-06 | 13,019 | 24 |
https://academiaservices.net/21147638278/ | math | Please see attachments to see the questions, need all correct answers, show work!
1. Perform the indicated operation. Note that the denominators are different. Simplify the result, if possible. 2. Consider the rational function, a) Find , shown in the graph given above. b) What are the vertical asymptotes of ? Note: If there is more than one, list each separated by a comma: "x=a, x=b". Do not include spaces around the equals sign. Type, for example, "x=1", not "x = 1". Answer: c) If you were to continue the graph to the right, the graph would tend to look like a horizontal line. What is
the equation for the horizontal asymptote? Answer: 3. REVIEW: The graph of a linear equation, where is shown above. Find the interval . Answer: 4. Suppose that . Evaluate each of the following: = = 5.- Differentiate Answer: 6.- Given the following functions: and 7. Find an equation of the tangent line to the curve at the point . Tangent line: 8.- ) Find and so that the function is both continuous and differentiable. = . Find: = 9.- Calculate the second and the third derivative of 10.- Calculate the derivative indicated. 11.- Find as a function of if 12.- Find the derivative of . | s3://commoncrawl/crawl-data/CC-MAIN-2020-50/segments/1606141732835.81/warc/CC-MAIN-20201203220448-20201204010448-00495.warc.gz | CC-MAIN-2020-50 | 1,179 | 3 |
https://bmcbioinformatics.biomedcentral.com/articles/10.1186/1471-2105-12-24/figures/2 | math | GDD-agreement between the viral PPI networks and the model networks. GDD-agreement between the viral PPI networks and the model networks. Points on the horizontal axis correspond to viral PPI networks of: EBV, HSV-1, KSHV, mCMV, and VZV herpes viruses. Lines with different labels correspond to different model networks. The vertical axis represents the average GDD-agreement between the corresponding data and model networks. For each data network, we generated 30 network model instances, each constrained to be of the size of the data. The plot reports the averaged the GDD-agreement values and standard deviations of their GDD-agreement with the data. Higher values of GDD-agreement reflect higher similarities between the networks. This plot was generated by GraphCrunch 2. | s3://commoncrawl/crawl-data/CC-MAIN-2022-27/segments/1656103877410.46/warc/CC-MAIN-20220630183616-20220630213616-00480.warc.gz | CC-MAIN-2022-27 | 778 | 1 |
https://slideplayer.com/slide/3425672/ | math | Presentation on theme: "D 2 Law For Liquid Droplet Vaporization References: Combustion and Mass Transfer, by D.B. Spalding (1979, Pergamon Press). “Recent advances in droplet."— Presentation transcript:
D 2 Law For Liquid Droplet Vaporization References: Combustion and Mass Transfer, by D.B. Spalding (1979, Pergamon Press). “Recent advances in droplet vaporization and combustion”, C.K. Law, Progress in Energy and Combustion Science, Vol. 8, pp. 171-201, 1982. Fluid Dynamics of Droplets and Sprays, by W.A. Sirignano (1999, Cambridge University Press).
Gas-Phase Streamlines Droplet With Internal Circulation Gas-Phase Streamlines Droplet With Internal Circulation Heat Fuel Vapour Buoyancy and droplet size destroy spherical symmetry evaporation Spherical Symmetry Model
Mass Transfer I DEFINITIONS IN USE: density – mass of mixture per unit volume ρ [kg/m 3 ] species - chemically distinct substances, H 2 O, H 2, H, O 2, etc. partial density of A – mass of chemical compound (species) A per unit volume ρ A [kg/m 3 ] mass fraction of A – ρ A /ρ = m A note: ρ A + ρ B + ρ C + … = ρ m A + m B + m C + … = 1
DEFINITIONS IN USE: total mass velocity of mixture in the specified direction (mass flux density) – mass of mixture crossing unit area normal to this direction in unit time G TOT [kg/m 2 s], G TOT = u (density x velocity) total mass velocity of A in the specified direction = G TOT,A [kg/m 2 s] note: G TOT,A + G TOT,B + G TOT,C …= G TOT convective mass velocity of A in the specified direction m A G TOT = ( ρ A /ρ) G TOT = G CONV,A note: G CONV,A + G CONV,B + G CONV,C …= G TOT but generally, G CONV,A ≠ G TOT,A diffusive mass velocity of A in the specified direction G TOT,A – G CONV,A = G DIFF,A note: G DIFF,A + G DIFF,B + G DIFF,C + … = 0
DEFINITIONS IN USE: velocity of mixture in the specified direction = G TOT / [m/s] concentration – a word used for partial density or for mass fraction (or for mole fraction, partial pressure, etc.) composition of mixture – set of mass fractions
The d 2 Law - assumptions (i)Spherical symmetry: forced and natural convection are neglected. This reduces the analysis to one-dimension. (ii) No spray effect: the droplet is an isolated one immersed in an infinite environment. (iii) Diffusion being rate controlling. The liquid does not move relative to the droplet center. Rather, the surface regresses into the liquid as vaporization occurs. Therefore heat and mass transfer in the liquid occur only because of diffusion with a moving boundary (droplet surface) but without convection. (iv) Isobaric processes – constant pressure. (v) Constant gas-phase transport properties. This causes the major uncertainty in estimation the evaporation rate (can vary by a factor of two to three by using different, but reasonable, averaged property value – specific heats, thermal conductivity, diffusion coefficient, vapour density, etc). (vi) Gas-phase quasi-steadiness. Because of the significant density disparity between liquid and gas. Liquid properties at the droplet surface (regression rate, temperature, species concentration) changes at rates much slower than those of gas phase transport processes. This assumption breaks down far away from the droplet surface where the characteristic diffusion time is of the same order as the surface regression time.
Gas-phase QUASI-steadiness – characteristic times analysis. In standard environment the gas-phase heat and mass diffusivities, g and g are of the same order of 10 0 cm 2 s -1, whereas the droplet surface regression rate, K = -d(D 0 2 )/dt is of the order of 10 -3 cm 2 s -1 for conventional hydrocarbon droplet vaporizing in standard atmosphere. Thus, there ratio is of the same order as the ratio of the liquid-to-gas densities,. It means that gas mass and heat diffusion occurs much faster than droplet surface regression time. If we further assume that properties of the environment also change very slowly, then during the characteristic gas-phase diffusion time the boundary locations and conditions can be considered to be constant. Thus the gas-phase processes can be treated as steady (time independent because the surface almost “freezes”), with the boundary variations occurring at longer time scales. When (at which value of D ∞ ) this assumption breaks down, i.e. when the diffusion time is equal to the surface regression time? When surface regression characteristic time becomes equal to gas mass/heat diffusion time, i.e. when D ∞ 2 / g ≈ D 0 2 /K? Remembering that must still be valid (it doesn’t depend on the distance from the droplet), we can conclude that the steady assumption breaks down when. For standard atmospheric conditions it breaks down at It means that our model will be valid for the distances less than this one.
The d 2 Law – assumptions (vii) Single fuel species. Thus it is unnecessary to analyze liquid- phase mass transport (no diffusion term). (viii) Constant and uniform droplet temperature. This implies that there is no droplet heating. Where all the heat goes? Combined with (vii), we see that liquid phase heat and mass transport processes are completely neglected. Therefore the d 2 Law is essentially a gas-phase model. (ix) Saturation vapour pressure at droplet surface. This is based on the assumption that the phase-change process between liquid and vapour occurs at a rate much faster than those for gas- phase transport. Thus, evaporation at the surface is at thermodynamic equilibrium, producing fuel vapour which is at its saturation pressure corresponding to the droplet surface temperature. (x) No Soret (mass flow because of the temperature gradient), Dufour (heat flow because of the concentration gradient) and radiation effects (how this effects the validity of the model?).
Rate of accumulation of mass of component j Mass flow rate of component j into the system Mass flow rate of component j out of system Rate of generation of mass of component j from reaction Rate of depletion of mass of component j from reaction
Droplet evaporation I (no energy concerns) The phenomenon considered: A small sphere of liquid in an infinite gaseous atmosphere vaporizes and finally disappears. What is to be predicted? Time of vaporization as a function of the properties of liquid, vapor and environment. Assumptions: spherical symmetry (non-radial motion is neglected) (quasi-) steady state in gas Γ VAP independent of radius large distance between droplets no chemical reaction
Vapor concentration distribution m VAP in the gas. roro r GoGo G = G TOT,VAP
m VAP,0 has a strong influence, but is not usually known, it depends on temperature. relative motion of droplet and air augments the evaporation rate (inner circulation of the liquid) by causing departures from spherical symmetry. the vapour field of neighboring droplets interact m VAP,0 and m VAP,∞ may both vary with time. Γ VAP usually depends on temperature and composition. Limitations
y = -x 0 1 So, a positive G 0 reduces the rate of heat transfer at the liquid surface. It means that if the heat is transferred to some let us say solid surface, that we want to prevent from heating up, we should eject the liquid to the thermal boundary layer (possibly through little holes). This liquid jets will accommodate a great part of the heat on vaporization of the liquid. Thus, we’ll prevent the surface from heating – transpiration cooling. The smaller the holes the smaller a part of heat towards the liquid interior and, subsequently towards the solid surface.
Equilibrium vaporization – droplet is at such a temperature that the heat transfer to its surface from the gas is exactly equals the evaporation rate times the latent heat of vaporization: This implies: What if –Q 0 ≠ G 0 L
Cases of interest: (i)When T ∞ is much greater than the boiling-point temperature T BOILING, m VAP,0 is close to 1 and T 0 is close to T BOILING. Then the vaporization rate is best calculated from: (ii)When T ∞ is low, and m VAP,∞ is close to zero, T 0 is close to T ∞. This implies T 0 ≈T ∞. Thus, m VAP,0 is approximately equal to the value given by setting T 0 =T ∞ in and the vaporization rate can be calculated by: As in example with water droplet evaporating at 10 0 C
Evaporation rate [m 2 /s] The choice depends on whether T 0 or m VAP,0 is easier to estimate
Droplet heat up effect on temperature and lifetime We can divide the droplet evaporation process into two stages. At first, while the droplet is cold (evaporation is slow), all the heat from the hot environment will be used for droplet interior heat up. As the droplet temperature will approach its steady state value, droplet heat up will slow down, while evaporation will accelerate. r 0 =r 0 (t)
Droplet heat up effect on temperature and lifetime Slowest limit Fastest limit Distillation limit Diffusion limit D 2 Law Center Temperature Surface Temperature T ( LIQ /r 0,INITIAL 2 )t (r /r 0,INITIAL ) 2 ( LIQ /r 0,INITIAL 2 )t Distillation limit Diffusion limit D 2 Law 300 380 0.20.1 1 0 | s3://commoncrawl/crawl-data/CC-MAIN-2020-29/segments/1593655888561.21/warc/CC-MAIN-20200705184325-20200705214325-00290.warc.gz | CC-MAIN-2020-29 | 9,058 | 19 |
https://www.doubtnut.com/question-answer/the-area-bounded-by-the-curves-yx-12yx-12-and-y1-4-is-644644216 | math | Updated On: 21-5-2021
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`(1)/(3)` sq unit. `(2)/(3)` sq unit. `(1)/(4)` sq unit. `(1)/(5)` sq unit.
|00:00 - 00:59||the question is the area bounded by the curve Y is equal to x minus 1 whole square Y is equal to X + 1 whole square and Y equal to 1 by 4 is bigger than 3 Y is equal to x minus 1 whole square then we have Y is equal to X + 1 whole square and Y is equal to 1 by 4 Get together now will need to draw the graph for is now but we should know that these are the co-ordinate Axis graph of y equal to x square we should know that is like this|
|01:00 - 01:59||something like this ok so why good to x minus 1 whole square glass would be shifted to the positive x axis and y axis minus 1 whole square is if you put 121 here then it becomes you this is the point 10 ok craft would be like this similarly the graph for X + 1 would be at X equal to minus 10 suggests metric this should move to the server control again this is equal to x minus 1 whole square graph and this is why equal to X +|
|02:00 - 02:59||1 crore are so we can draw we have two points where is 10 x is this is by axis and we have 1.0 - and craft something like this and other grasses like this difference between W A Y is equal to X + 1 whole square and the black one is Y is equal to x minus 1 whole square|
|03:00 - 03:59||ok now this is common intersection point at y axis ok because when we put X equal to zero here all photographs that one should be smarter 2014 line also this time we have one that would be less than one Amritsar wishes line y equal to 1 by the now we need to find the to find the area bounded by the speaker area bounded by this occurs if you see here is different|
|04:00 - 04:59||this is the area that we need to find now we name this point as a bi this is point P and this is quite so we need to find area bounded equal to area bounded by the curve Y is equal to area of reason a comes after spare now also due to symmetry we can say that due to symmetry we can say that|
|05:00 - 05:59||area of reason English a call to area of visit near this area this area is equal to area so India of whole reason area of a b c d a can be written as equal to 2 x of two times of any one reason that is a CD is equal to X of area in AC DJ now to find the area we need to discuss study question we know Y equal to x minus 1 whole square and we need to divide the unit to|
|06:00 - 06:59||calculate area up to this point ok we don't know the coordinates of the point the super sweet find the coordinates of point P we have yet to find the intersection of Y equal to 1 by 4 and Y is equal to x minus 1 whole square if the intersection point of X equal to 1 by 4 and Y equal to x minus 1 whole square equal to 1 by 4 here we get minus 1 whole square x minus one can be equal to 1 by 2 aur x minus one can be equal to minus 1 by 2 also know from where we get value by to and from here we get value 1 minus one by two that is one by two would we have two values now|
|07:00 - 07:59||to intersection point 1 intersection part is this and one is this we will choose the lower one to one by two here so the point is the point is point B is X is 1 by 2 and why is 1 by 4 we need to find the area here from zero X equal to zero to this is equal to 1 by from here is we will integrate the kar you get the whole area so we need to subtract the bottom area of the the area of line y equal to 1 by 4 light area of reason a c d a is|
|08:00 - 08:59||equal to integration from 0 to 1 by 2 of x minus 1 whole square x integration of x minus 1 whole square DS what is the whole area if we put this an an an area is given by this savinay to subtract the bottom which is given by - integration from 0 to 1 by 2 of why why is 1 by 4 integration of x minus 1 whole square minus x minus 1 divided by 3 from 0 to 1 by 2 minus 4 integration of DX Easter eggs from 0 to 1 by 2 + becomes equal to putting one by to hear this becomes|
|09:00 - 09:59||minus 1 by 2 minus 1 by 2 cube minus 1 by 8 is 1 by 24 - 14 0 here this becomes -1 cube that is - 10 - + and here we have minus 1 by 4 into one by two this is equal to minus 1 by 24 + 1 by 3 and minus 1 by 4 into two that is it now here we can take LCM taking calcium 24 comes - 1 + 8 minus 3 equal to 8 - 4 that is divided by 24 which is equal to 1 by 6 sote se area of region is equal to 1 by|
|10:00 - 10:59||6 hour we need to find you need to find all of this book age of ABCD so every of total reason a video equal to 2 x of 1 by 6 which is equal to 1 by 3 square units which is the final area of the boundary between these options of number one is correct 1 by 3 square unit is the area of the shaded region ABCD thank you|
Area as a definite integral
Algorithm for area calculation using horizontal strips
Area calculation using horizontal strips for modulus function
Impact of sign on area definition change according to sign of function
Find the area of the region bounded by the parabola `y^2 = 2x` and the line `x - y = 4`
Examples: Find the area of the region bounded by the curve `y^2 = 2y - x` and the y-axis.
Area of symmetrical graphs
Find the area of the region bounded by the ellipse `x^2 / a^2 + y^2 / b^2 = 1`
Integration of sin and cos function in different intervals
Examples: f(x) = x for x > 0 and f(x) = x^2 for x < 0; find area with x axis from x = -2 and x = 3.
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NEET 2021 Counselling: MCC, State Quota NEET Counseling Updates. Know NEET 2021 counselling process, list of documents required & more.
CBSE Class 10 Major Exam Begins, Check Exam Day Guidelines
CBSE Class 10 board exam begins for major subjects on 30th November 2021. Check CBSE Class 10th board exam day guidelines here. | s3://commoncrawl/crawl-data/CC-MAIN-2021-49/segments/1637964362619.23/warc/CC-MAIN-20211203091120-20211203121120-00604.warc.gz | CC-MAIN-2021-49 | 6,343 | 34 |
http://comunidadwindows.org/margin-of/statistical-articles-including-margin-of-error-and-sample-size.php | math | Statistical Articles Including Margin Of Error And Sample Size
Fiorina comes in second, with 16 percent support, up from 6 percent a month ago. I mean if I took a sample of 1000 from a population of 2000 I would think the results would have a smaller margin of error than if I took a if I get 200 from my exact sample size(240), is it representative? Most studies on surgery outcome are based on clinical improvement only few on QOL using retrospective data. http://comunidadwindows.org/margin-of/statistical-margin-of-error-sample-size.php
That said, I can't find a location for these programs. If you do not know your proportion p, it is quite common to take 0,5 as a value for p. Definition The margin of error for a particular statistic of interest is usually defined as the radius (or half the width) of the confidence interval for that statistic. The term can See table below How many individuals to choose by region for his study? https://en.wikipedia.org/wiki/Margin_of_error
Margin Of Error Formula
Plz reply Gert Van Dessel - August, 2016 reply Maryam,For 95% confidence level and 5% margin of error, you would need a sample of 43. The top portion charts probability density against actual percentage, showing the relative probability that the actual percentage is realised, based on the sampled percentage. For a margin of error of 5% at 95% confidence level, you will need a sample of 80 respondents. Compute alpha (α): α = 1 - (confidence level / 100) = 1 - 0.95 = 0.05 Find the critical probability (p*): p* = 1 - α/2 = 1 - 0.05/2
Patra Gert Van Dessel - October, 2015 reply Hi Patra,The article is only available on web: (www.checkmarket.com/2013/02/how-to-estimate-your-population-and-survey-sample-size/), published by Gert Van Dessel of research company CheckMarket on 13th February 2013 Buchura Ben Carson, second in the lead in Iowa in this poll, captures 19 percent of the support, down from 22 percent last month. Remember that your population consist of approximately 400 million adults in the EU. Margin Of Error Sample Size But if the original population is badly skewed, has multiple peaks, and/or has outliers, researchers like the sample size to be even larger.
When the sample size is smaller, the critical value should only be expressed as a t statistic. Margin Of Error Calculator We can similarly compare some of the less successful candidates in the Pew poll. But for such small populations, you might as well include the total population in your survey. http://www.dummies.com/education/math/statistics/how-to-calculate-the-margin-of-error-for-a-sample-proportion/ In some sense, the math reported in polls may be a disguise covering up bad methodology (like rich icing on a bad cake).
Could u plz tell me how to determine sample size if don't give any information (standard deviation and confidence interval). Margin Of Error Excel Retrieved 2006-05-31. Surveying has been likened to taste-testing soup – a few spoonfuls tell what the whole pot tastes like. Note: The larger the sample size, the more closely the t distribution looks like the normal distribution.
Margin Of Error Calculator
MathWorld. https://explorable.com/statistics-margin-of-error Thank you. Margin Of Error Formula The sample proportion is the number in the sample with the characteristic of interest, divided by n. Margin Of Error Definition First, assume you want a 95% level of confidence, so z* = 1.96.
Comparing percentages In a plurality voting system, where the winner is the candidate with the most votes, it is important to know who is ahead. http://comunidadwindows.org/margin-of/survey-articles-with-margin-of-error.php Chris - August, 2015 reply Sir I am to survey a population of about 10000 students. Therefore not much information available on QOL. Otherwise, we use the t statistics, unless the sample size is small and the underlying distribution is not normal. Margin Of Error In Polls
Now, remember that the size of the entire population doesn't matter when you're measuring the accuracy of polls. Acceptable Margin Of Error Whay not 6 or 8 for example? Thanks Karol Gert Van Dessel - June, 2016 reply Karol,I would go for a fixed fieldwork period, for example 1 month, and collect responses every day.
Typical choices are 90%, 95%, or 99% % The confidence level is the amount of uncertainty you can tolerate.
Maarten Marijnissen - September, 2016 reply Hi,This sample gives you a margin of error of 9,48% for 95% confidence level, which is quite high.This number is the plus-or-minus figure usually reported In other words, if all I get is 72 responses, can't I still use that and show the actual numbers instead of my computed ones? Gert Van Dessel - February, 2016 reply Andrew,With an error margin of 2% you will need 2354 respondents in your sample. Margin Of Error Vs Standard Error The size of your sample depends on the research project en the method you are using.More explanation and further information can be found in this article.
the nr. MSNBC reported these same Pew Research Center numbers with no mention at all of the margin of error—a lost opportunity, in our view, to point to the weakness of a small It's time for some math. (insert smirk here) The formula that describes the relationship I just mentioned is basically this: The margin of error in a sample = 1 divided by this content Are there any sources I can use?
You can calculate yourself with our sample size calculator Adebayo Kazeem - September, 2015 reply I am so happy to discover your website I believe God is good to me, sir, That’s what the MOE addresses. Of the media sources mentioned, only CNN can be lauded for mentioning the size of the Pew survey and the corresponding MOE. If you'd like to see how we perform the calculation, view the page source.
I n my study I will use the questionnaire about PM examination methods in. For a social science project, would a CI of 8 % and a CL of 90% seem appropriate? one response from each small firm. In other words, if we were to conduct this survey many times with different samples of 497 randomly chosen Republican voters, 95 out of 100 times the proportion of the survey
This makes intuitive sense because when N = n, the sample becomes a census and sampling error becomes moot. You can check with our sample size calculator Ofere Jmaes - October, 2015 reply I have population known that is 150 with the sample of 30 how can i calculate the Generally, 5% is taken as a maximum margin of error, this would correspond with a sample of 228. If you have a sample size of 348 and a total population of for example 5000, your margin of error will be about 5% (for the total population of all 10
Nicholas - December, 2015 reply Let's say I am conducting a research for a bank (questionnaires) for 432 branches within 2 months time. for a population of 10,000, confidence level 95% and margin of error 5%, your required sample size is 370. How do I calculate the sample for the population? The standard error (0.016 or 1.6%) helps to give a sense of the accuracy of Kerry's estimated percentage (47%).
With a confidence level of 95%, you would expect that for one of the questions (1 in 20), the percentage of people who answer yes would be more than the margin | s3://commoncrawl/crawl-data/CC-MAIN-2018-43/segments/1539583511365.50/warc/CC-MAIN-20181018001031-20181018022531-00460.warc.gz | CC-MAIN-2018-43 | 7,224 | 20 |
https://bird.bcamath.org/handle/20.500.11824/1112 | math | Pseudospectral Methods for the Fractional Laplacian on R
MetadataShow full item record
In this thesis, first, we propose a novel pseudospectral method to approximate accu- rately and efficiently the fractional Laplacian without using truncation. More pre- cisely, given a bounded regular function defined over R, we map the unbounded domain into a finite one, and represent the resulting function as a trigonometric se- ries. Therefore, a key ingredient is the computation of the fractional Laplacian of an elementary trigonometric function. As an application of the method, we do the simulation of Fisher’s equation with the fractional Laplacian in the monostable case. In addition, using complex variable techniques, we compute explicitly, in terms of the 2 F1 Gaussian hypergeometric function, the one-dimensional fractional Laplacian of the Higgins functions, the Christov functions, and their sine-like and cosine-like versions. After discussing the numerical difficulties in the implementation of the proposed formulas, we develop another method that gives exact results, by using variable precision arithmetic. Finally, we discuss some other numerical approximations of the fractional Laplacian using a fast convolution technique. While the resulting techniques are less accu- rate, they are extremely fast; furthermore, the results can be improved by the use of Richardson’s extrapolation. | s3://commoncrawl/crawl-data/CC-MAIN-2022-49/segments/1669446710902.80/warc/CC-MAIN-20221202114800-20221202144800-00238.warc.gz | CC-MAIN-2022-49 | 1,401 | 3 |
http://nrich.maths.org/public/leg.php?code=-99&cl=3&cldcmpid=1389 | math | The letters of the word ABACUS have been arranged in the shape of a
triangle. How many different ways can you find to read the word
ABACUS from this triangular pattern?
This tricky challenge asks you to find ways of going across rectangles, going through exactly ten squares.
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Many natural systems appear to be in equilibrium until suddenly a critical point is reached, setting up a mudslide or an avalanche or an earthquake. In this project, students will use a simple. . . .
We're excited about this new program for drawing beautiful mathematical designs. Can you work out how we made our first few pictures and, even better, share your most elegant solutions with us?
A Sudoku that uses transformations as supporting clues.
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In this Sudoku, there are three coloured "islands" in the 9x9 grid. Within each "island" EVERY group of nine cells that form a 3x3 square must contain the numbers 1 through 9.
Place the 16 different combinations of cup/saucer in this 4 by 4 arrangement so that no row or column contains more than one cup or saucer of the same colour.
This Sudoku puzzle can be solved with the help of small clue-numbers on the border lines between pairs of neighbouring squares of the grid.
Use the interactivity to listen to the bells ringing a pattern. Now
it's your turn! Play one of the bells yourself. How do you know
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Label the joints and legs of these graph theory caterpillars so that the vertex sums are all equal.
Given the products of diagonally opposite cells - can you complete this Sudoku?
Pentagram Pylons - can you elegantly recreate them? Or, the
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Bellringers have a special way to write down the patterns they
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Can you recreate these designs? What are the basic units? What
movement is required between each unit? Some elegant use of
procedures will help - variables not essential.
Remember that you want someone following behind you to see where
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This second Sudoku article discusses "Corresponding Sudokus" which are pairs of Sudokus with terms that can be matched using a substitution rule.
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You are given the Lowest Common Multiples of sets of digits. Find
the digits and then solve the Sudoku.
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Four small numbers give the clue to the contents of the four
Use the differences to find the solution to this Sudoku.
Whenever a monkey has peaches, he always keeps a fraction of them each day, gives the rest away, and then eats one. How long could he make his peaches last for?
Do you notice anything about the solutions when you add and/or
subtract consecutive negative numbers?
Two sudokus in one. Challenge yourself to make the necessary
The puzzle can be solved with the help of small clue-numbers which
are either placed on the border lines between selected pairs of
neighbouring squares of the grid or placed after slash marks on. . . .
Find out about Magic Squares in this article written for students. Why are they magic?!
60 pieces and a challenge. What can you make and how many of the
pieces can you use creating skeleton polyhedra?
Just four procedures were used to produce a design. How was it
done? Can you be systematic and elegant so that someone can follow
You need to find the values of the stars before you can apply normal Sudoku rules.
The puzzle can be solved by finding the values of the unknown digits (all indicated by asterisks) in the squares of the $9\times9$ grid.
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A cinema has 100 seats. Show how it is possible to sell exactly 100 tickets and take exactly £100 if the prices are £10 for adults, 50p for pensioners and 10p for children.
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Problem solving is at the heart of the NRICH site. All the problems
give learners opportunities to learn, develop or use mathematical
concepts and skills. Read here for more information.
This challenge extends the Plants investigation so now four or more children are involved.
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Given the nets of 4 cubes with the faces coloured in 4 colours, build a tower so that on each vertical wall no colour is repeated, that is all 4 colours appear.
Solve the equations to identify the clue numbers in this Sudoku problem. | s3://commoncrawl/crawl-data/CC-MAIN-2016-40/segments/1474738662507.79/warc/CC-MAIN-20160924173742-00090-ip-10-143-35-109.ec2.internal.warc.gz | CC-MAIN-2016-40 | 5,600 | 66 |
https://www.hackmath.net/en/math-problem/420 | math | If it is true that
, then the value of the expression
We will be pleased if You send us any improvements to this math problem. Thank you!
Thank you for submitting an example text correction or rephasing. We will review the example in a short time and work on the publish it.
Tips to related online calculators
You need to know the following knowledge to solve this word math problem:
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A School reports students to teacher ratio of 6:1. If there are 45 teachers in the School, how many students are there? | s3://commoncrawl/crawl-data/CC-MAIN-2021-21/segments/1620243991428.43/warc/CC-MAIN-20210514152803-20210514182803-00115.warc.gz | CC-MAIN-2021-21 | 2,504 | 33 |
https://www.varsitytutors.com/villa_park-il-pre_calculus-tutoring | math | Recent Tutoring Session Reviews
"The student studied chapter 4 for his test tomorrow, covering exponential and linear growth/ decay, and properties of exponential/ logarithmic functions."
"Reviewed for upcoming quiz the following day on zeros, synthetic division, and the various theorems used to solve for them in large polynomial equations. Went over how to do it both on paper and on the calculator as student will be allowed to use her calculator on the quiz."
"We continued going over graphing rational functions using asymptotes, intercepts, increasing and decreasing interval. Then we moved on to exponential functions and their graphs, then to logarithms and their graphs. We briefly touched on solving exponential and logarithmic equations by transforming from one to the other."
"Today, we worked on solving exponential and logarithmic equations. I recommended that the student write down problem solving steps on paper rather than doing it in his head, a habit that will make it easier when solving more difficult problems. I recommended doing the problems on a learning tool website to get practice in the skills he might have missed not having had algebra and also to just look at the skills list there to get an idea of what he might need to brush up on."
"This session was our final review for the student's Pre-Calc exam. We covered a few questions involving inverse trigonometric functions then went over several calculator-based problems. He seems to understand how to get the word problems started, but got a little stuck when it came to knowing how to translate certain parts into a solvable equation. However, he showed improvement when we worked on a few similar problems in a row. I recommended he focus on inverse trig functions for the last couple of days of studying since that's one area we've worked on the most. Finally, we went over a couple of final pointers to remember for each chapter."
"We covered trig identities and how to derive the unit circle. She had a positive mind set along with a willingness to learn. I told her that the trigonometry that she is covering requires quite a bit of memorizing. I told her what she needs to memorize, and we finished off the session learning how to derive some concepts, which helps cut a lot of the memorization out and also creates understanding as opposed to just memorizing. I told her to YouTube various ways to derive the unit circle and also explain the unit circle since knowing that is a critical part to what she is learning. This session was great for seeing where she is at overall. Algebra needs some refreshing, and that will come in future sessions." | s3://commoncrawl/crawl-data/CC-MAIN-2017-09/segments/1487501170925.44/warc/CC-MAIN-20170219104610-00411-ip-10-171-10-108.ec2.internal.warc.gz | CC-MAIN-2017-09 | 2,640 | 7 |
http://www.diagnosticpathology.org/content/5/1/73/figure/F1 | math | Difference between the resolution of the original (JPEG Quality factor compression 90) and the compressed (JPEG Quality factor compression 40) digital slide, depicting the same region of a papillary thyroid cancer. (HE-stain, 100× magnification.) The pixelation is clearly visible on the right image, after compressing the digital slide.
Fónyad et al. Diagnostic Pathology 2010 5:73 doi:10.1186/1746-1596-5-73 | s3://commoncrawl/crawl-data/CC-MAIN-2015-48/segments/1448399455473.15/warc/CC-MAIN-20151124211055-00079-ip-10-71-132-137.ec2.internal.warc.gz | CC-MAIN-2015-48 | 411 | 2 |
https://archive.org/details/NASA_NTRS_Archive_19850005822 | math | The basic equations are derived for compressible flow in a labyrinth seal. The flow is assumed to be completely turbulent in the circumferential direction where the friction factor is determined by the Blasius relation. Linearized zeroth and first-order perturbation equations are developed for small motion about a centered position by an expansion in the eccentricity ratio. The zeroth-order pressure distribution is found by satisfying the leakage equation while the circumferential velocity distribution is determined by satisfying the momentum equation. The first-order equations are solved by a separation of variables solution. Integration of the resultant pressure distribution along and around the seal defines the reaction force developed by the seal and the corresponding dynamic coefficients. The results of this analysis are compared to published test results. | s3://commoncrawl/crawl-data/CC-MAIN-2019-13/segments/1552912202433.77/warc/CC-MAIN-20190320150106-20190320172106-00467.warc.gz | CC-MAIN-2019-13 | 873 | 1 |
https://www.jiskha.com/display.cgi?id=1255909359 | math | posted by Trisan .
x to the second power + x-2
X+2 divided by x to the second power plus x-2 divided by 2x
From your description, here is what you seem to have:
(x+2)/x + (x-2)/2x
Multiply by 2x
2x + 4 + x - 2 = 3x +2
I hope this helps. Thanks for asking. | s3://commoncrawl/crawl-data/CC-MAIN-2017-34/segments/1502886110485.9/warc/CC-MAIN-20170822065702-20170822085702-00653.warc.gz | CC-MAIN-2017-34 | 255 | 8 |
https://tutorbin.com/questions-and-answers/5-10-compute-and-discuss-briefly-the-significance-of-the-following-measures-as-they-relate-to-save-a-lot-supplies-a-net | math | 5 . 10 Compute and discuss briefly the significance of the following measures as they relate to Save-A- Lot Supplies. a. Net income percentage in current year. b. Return on equity in current year. c. Working capital on December 31, current year. d. Current ratio on December 31, current year. | s3://commoncrawl/crawl-data/CC-MAIN-2023-23/segments/1685224656788.77/warc/CC-MAIN-20230609164851-20230609194851-00499.warc.gz | CC-MAIN-2023-23 | 292 | 1 |
https://crossfiteastcounty.com/workout-friday-09012017/ | math | In teams of two, complete the following: Lift 30,000 lbs. in these lifts.
Minimum of 1,000 lbs. per exercise, per person. Complete in any order, rep scheme and load. One person works at a time.
Deadlift 20 reps X 225# = 4500
Back Squat 20 reps X 185# = 3700
Shoulder Press 20 reps X 95# = 1900
Bench Press 20 reps X 135# = 2700
Power Clean 20 reps X 115# = 2300 Total = 15,100
Thank you Ray Etter for the workout. | s3://commoncrawl/crawl-data/CC-MAIN-2023-40/segments/1695233511000.99/warc/CC-MAIN-20231002132844-20231002162844-00871.warc.gz | CC-MAIN-2023-40 | 413 | 8 |
http://pub37.bravenet.com/forum/static/show.php?usernum=3172289350&frmid=10&msgid=1179612&cmd=show | math | Have a look at the following app: http://itunes.apple.com/us/app/crumbers/id443984996?mt=8#
Very challenging game. I tryed the freeware version then bought the upgrade to full....I am stuck on the 25th level and cannot figure it out!!!! It is a seriously addicting game.
Let me know if you find the solution | s3://commoncrawl/crawl-data/CC-MAIN-2023-14/segments/1679296945288.47/warc/CC-MAIN-20230324180032-20230324210032-00366.warc.gz | CC-MAIN-2023-14 | 307 | 3 |
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