id
stringlengths 25
25
| question
stringlengths 45
1.01k
| chain
stringlengths 75
4.11k
| result
stringclasses 5
values | result_float
float64 -4,212
100B
| question_without_options
stringlengths 6
962
| options
dict | annotated_formula
stringlengths 7
6.48k
| linear_formula
stringlengths 8
925
| rationale
stringlengths 1
2.74k
| category
stringclasses 6
values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__zBjSEOhOtl9kKtkN
|
Mike took a taxi to the airport and paid $2.50 to start plus $0.25 per mile. Annie took a different route to the airport and paid $2.50 plus $5.00 in bridge toll fees plus $0.25 per mile. If each was charged exactly the same amount, and Annie's ride was 14 miles, how many miles was Mike's ride? Answers
A) 28 B) 30 C) 32 D) 34 E) 36
|
<gadget id="calculator">2.5 + 5</gadget>
<output>7.5</output>
<gadget id="calculator">0.25 * 14</gadget>
<output>3.5</output>
<gadget id="calculator">7.5 + 3.5</gadget>
<output>11</output>
<gadget id="calculator">11 - 2.5</gadget>
<output>8.5</output>
<gadget id="calculator">8.5 / 0.25</gadget>
<output>34</output>
<result>D</result>
|
D
| 34 |
Mike took a taxi to the airport and paid $2.50 to start plus $0.25 per mile. Annie took a different route to the airport and paid $2.50 plus $5.00 in bridge toll fees plus $0.25 per mile. If each was charged exactly the same amount, and Annie's ride was 14 miles, how many miles was Mike's ride?
|
{
"A": "28",
"B": "30",
"C": "32",
"D": "34",
"E": "36"
}
|
divide(subtract(add(add(2.5, 5), multiply(0.25, 14)), 2.5), 0.25)
|
add(n0,n3)|multiply(n1,n5)|add(#0,#1)|subtract(#2,n0)|divide(#3,n1)
|
the cost of annie ' s ride was 2.5 + 5 + ( 0.25 * 14 ) = $ 11 let x be the distance of mike ' s ride . the cost of mike ' s ride is 2.5 + ( 0.25 * x ) = 11 0.25 * x = 8.5 x = 34 miles the answer is d .
|
general
|
math_qa__y3mzyU9JWmL6VkrW
|
a license plate in the country kerrania consists of 4 digits followed by two letters . the letters a , b , and c are used only by government vehicles while the letters d through z are used by non - government vehicles . kerrania ' s intelligence agency has recently captured a message from the country gonzalia indicating that an electronic transmitter has been installed in a kerrania government vehicle with a license plate starting with 79 . if it takes the police 10 minutes to inspect each vehicle , what is the probability that the police will find the transmitter within 3 hours ? Choose the correct choice from the following answers.
A) 18 / 79 B) 1 / 6 C) 1 / 25 D) 1 / 50 E) 1 / 900
|
<gadget id="calculator">3 * 60</gadget>
<output>180</output>
<gadget id="calculator">180 / 10</gadget>
<output>18</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">100 * 9</gadget>
<output>900</output>
<gadget id="calculator">18 / 900</gadget>
<output>1/50 = around 0.02</output>
<result>D</result>
|
D
| 0.02 |
a license plate in the country kerrania consists of 4 digits followed by two letters . the letters a , b , and c are used only by government vehicles while the letters d through z are used by non - government vehicles . kerrania ' s intelligence agency has recently captured a message from the country gonzalia indicating that an electronic transmitter has been installed in a kerrania government vehicle with a license plate starting with 79 . if it takes the police 10 minutes to inspect each vehicle , what is the probability that the police will find the transmitter within 3 hours ?
|
{
"A": "18 / 79",
"B": "1 / 6",
"C": "1 / 25",
"D": "1 / 50",
"E": "1 / 900"
}
|
divide(divide(multiply(3, const_60), 10), multiply(power(const_10, subtract(4, const_2)), power(const_3, const_2)))
|
multiply(n3,const_60)|power(const_3,const_2)|subtract(n0,const_2)|divide(#0,n2)|power(const_10,#2)|multiply(#4,#1)|divide(#3,#5)
|
if it takes 10 minutes to inspect one vehicle , the # of vehicles that can be inspected in 3 hours ( 180 minutes ) = 180 / 10 = 18 . hence , for calculating the probability that the police will find the transmitter within three hours , the favorable cases = 18 . now , we need to figure out the total # of cases . the total # of cases = total # of such cars possible . the details given about the car is that it starts with 79 , which leaves 2 more digits , both of which can be filled by all 10 numbers ( 0 - 9 ) . in addition , we have 3 letters , each of which can be filled by any from the set { a , b , c } . hence the total # of such cars possible = 10 * 10 * 3 * 3 = 900 so , the probability that the police will find the transmitter within three hours = 18 / 900 = 1 / 50 . option d
|
physics
|
math_qa__DXmTFH7AwOW6Xdbp
|
A particular library has 75 books in a special collection, all of which were in the library at the beginning of the month. These book are occasionally loaned out through an inter-library program. If, by the end of the month, 65 percent of books that were loaned out are returned and there are 61 books in the special collection at that time, how many books of the special collection were loaned out during that month? Pick one:
A) 20
B) 30
C) 35
D) 40
E) 55
|
<gadget id="calculator">75 - 61</gadget>
<output>14</output>
<gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">1 - (13/20)</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">14 / (7/20)</gadget>
<output>40</output>
<result>D</result>
|
D
| 40 |
A particular library has 75 books in a special collection, all of which were in the library at the beginning of the month. These book are occasionally loaned out through an inter-library program. If, by the end of the month, 65 percent of books that were loaned out are returned and there are 61 books in the special collection at that time, how many books of the special collection were loaned out during that month?
|
{
"A": "20",
"B": "30",
"C": "35",
"D": "40",
"E": "55"
}
|
divide(subtract(75, 61), subtract(const_1, divide(65, const_100)))
|
divide(n1,const_100)|subtract(n0,n2)|subtract(const_1,#0)|divide(#1,#2)|
|
"the total number of books is 75 . let x be the number of books which were loaned out . 65 % of books that were loaned out are returned . 35 % of books that were loaned out are not returned . now , there are 61 books , thus the number of un - returned books is 75 - 61 = 14 books . 0.35 x = 14 x = 40 the answer is d ."
|
gain
|
math_qa__HWVqPeWyEdMl4YjR
|
one - sixth of the light switches produced by a certain factory are defective . 4 - fifths of the defective switches are rejected and 1 / 15 of the non defective switches are rejected by mistake . if all the switches not rejected are sold , what percent of the switches sold by the factory are defective ? Pick: A) 1.8 % B) 2.9 % C) 4.1 % D) 5.6 % E) 6.4 %
|
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 20</gadget>
<output>16</output>
<gadget id="calculator">20 - 16</gadget>
<output>4</output>
<result>C</result>
|
C
| 4.1 |
one - sixth of the light switches produced by a certain factory are defective . 4 - fifths of the defective switches are rejected and 1 / 15 of the non defective switches are rejected by mistake . if all the switches not rejected are sold , what percent of the switches sold by the factory are defective ?
|
{
"A": "1.8 %",
"B": "2.9 %",
"C": "4.1 %",
"D": "5.6 %",
"E": "6.4 %"
}
|
subtract(multiply(divide(1, add(4, 1)), const_100), multiply(divide(4, add(4, 1)), multiply(divide(1, add(4, 1)), const_100)))
|
add(n0,n1)|divide(n1,#0)|divide(n0,#0)|multiply(#1,const_100)|multiply(#2,#3)|subtract(#3,#4)
|
1 / 6 of the switches are defective . the defective switches that are not rejected are 1 / 5 * 1 / 6 = 1 / 30 = 3 / 90 of all switches . the non defective switches that are sold are 5 / 6 * 14 / 15 = 70 / 90 of all switches . the percent of switches sold that are defective is 3 / 73 which is about 4.1 % . the answer is c .
|
general
|
math_qa__mgGOxH76WKLFnfgY
|
A man buys a cycle for Rs. 1600 and sells it at a loss of 12%. What is the selling price of the cycle? Choose one:
A) 1410 B) 1420 C) 1430 D) 1408 E) 1540
|
<gadget id="calculator">100 - 12</gadget>
<output>88</output>
<gadget id="calculator">88 * 1_600</gadget>
<output>140_800</output>
<gadget id="calculator">140_800 / 100</gadget>
<output>1_408</output>
<result>D</result>
|
D
| 1,408 |
A man buys a cycle for Rs. 1600 and sells it at a loss of 12%. What is the selling price of the cycle?
|
{
"A": "1410",
"B": "1420",
"C": "1430",
"D": "1408",
"E": "1540"
}
|
divide(multiply(subtract(const_100, 12), 1600), const_100)
|
subtract(const_100,n1)|multiply(n0,#0)|divide(#1,const_100)
|
s . p . = 88 % of rs . 1600 = 88 / 100 x 1600 = rs . 1408 answer : d
|
gain
|
math_qa__63H2YrAfOMOeGpbO
|
At milk factory, each employee working the second shift produced 2/3 as many widgets as each employee working the first shift. If the first shift has 3/4 as many employees, what fraction of the total widgets did the second shift produce? Select the correct option: A) 8 / 17 B) 1 / 2 C) 8 / 9 D) 9 / 8 E) 17 / 8
|
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 3</gadget>
<output>2</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 + 8</gadget>
<output>17</output>
<gadget id="calculator">8 / 17</gadget>
<output>8/17 = around 0.470588</output>
<result>A</result>
|
A
| 0.470588 |
At milk factory, each employee working the second shift produced 2/3 as many widgets as each employee working the first shift. If the first shift has 3/4 as many employees, what fraction of the total widgets did the second shift produce?
|
{
"A": "8 / 17",
"B": "1 / 2",
"C": "8 / 9",
"D": "9 / 8",
"E": "17 / 8"
}
|
divide(multiply(multiply(divide(2, 3), 3), 4), add(multiply(3, 3), multiply(multiply(divide(2, 3), 3), 4)))
|
divide(n0,n1)|multiply(n1,n1)|multiply(n1,#0)|multiply(n3,#2)|add(#1,#3)|divide(#3,#4)
|
at milk factory , let the first shift have 3 employee and each produce 3 widgets , so the total number of widgets produced by the first shift is 3 * 3 = 9 ; then the second shift would have 4 employees and each second shift employee would produce 3 * 2 / 3 = 2 widgets , so the total number of widgets produced by the second shift employees would be 4 * 2 = 8 ; the ratio of the second shift production to the total is 8 / ( 9 + 8 ) = 8 / 17 . answer : a .
|
physics
|
math_qa__EZzKeYbQzlYMhqeR
|
The cost of one photocopy is $0.02. However, a 25% discount is offered on orders of more than 100 photocopies. If Steve and David have to make 80 copies each, how much will each of them save if they submit a single order of 160 copies?
Choose the correct choice from the following: A) $ 0.32 B) $ 0.40 C) $ 0.45 D) $ 0.48 E) $ 0.54
|
<gadget id="calculator">80 * 0.02</gadget>
<output>1.6</output>
<gadget id="calculator">2 * 1.6</gadget>
<output>3.2</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">160 * (3/4)</gadget>
<output>120</output>
<gadget id="calculator">120 * 0.02</gadget>
<output>2.4</output>
<gadget id="calculator">3.2 - 2.4</gadget>
<output>0.8</output>
<gadget id="calculator">0.8 / 2</gadget>
<output>0.4</output>
<result>B</result>
|
B
| 0.4 |
The cost of one photocopy is $0.02. However, a 25% discount is offered on orders of more than 100 photocopies. If Steve and David have to make 80 copies each, how much will each of them save if they submit a single order of 160 copies?
|
{
"A": "$ 0.32",
"B": "$ 0.40",
"C": "$ 0.45",
"D": "$ 0.48",
"E": "$ 0.54"
}
|
divide(subtract(multiply(const_2, multiply(80, 0.02)), multiply(multiply(160, divide(subtract(100, 25), 100)), 0.02)), const_2)
|
multiply(n0,n3)|subtract(n2,n1)|divide(#1,n2)|multiply(#0,const_2)|multiply(n4,#2)|multiply(n0,#4)|subtract(#3,#5)|divide(#6,const_2)|
|
"if steve and david submit separate orders , each would be smaller than 100 photocopies , so no discount . each would pay ( 80 ) * ( $ 0.02 ) = $ 1.60 , or together , a cost of $ 3.20 - - - that ' s the combined ` ` no discount cost ' ' . if they submit things together as one big order , they get a discount off of that $ 3.20 price - - - - 25 % or 1 / 4 of that is $ 0.80 , the discount on the combined sale . they each effective save half that amount , or $ 0.40 . answer = ( b ) ."
|
gain
|
math_qa__fusxq5ZaYUGPXWuB
|
When a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/7 taller than it was at the end of the 4th year. By how many feet did the height of the tree increase each year?
Answers.
A) 3 / 10 B) 2 / 5 C) 1 / 2 D) 2 / 3 E) 6 / 5
|
<gadget id="calculator">6 - 4</gadget>
<output>2</output>
<gadget id="calculator">2 * 7</gadget>
<output>14</output>
<gadget id="calculator">14 - 4</gadget>
<output>10</output>
<gadget id="calculator">4 / 10</gadget>
<output>2/5 = around 0.4</output>
<result>B</result>
|
B
| 0.4 |
When a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/7 taller than it was at the end of the 4th year. By how many feet did the height of the tree increase each year?
|
{
"A": "3 / 10",
"B": "2 / 5",
"C": "1 / 2",
"D": "2 / 3",
"E": "6 / 5"
}
|
divide(4, subtract(multiply(subtract(6, 4), 7), 4))
|
subtract(n1,n0)|multiply(n4,#0)|subtract(#1,n0)|divide(n0,#2)
|
say , the tree grows by x feet every year . then , 4 + 6 x = ( 1 + 1 / 7 ) ( 4 + 4 x ) or , x = 2 / 5 answer b
|
general
|
math_qa__j2ltPtNojGLJzmrV
|
A, B and C have Rs.500 between them, A and C together have Rs.200 and B and C Rs.350. How much does C have? Choose one.
A) 50 B) 88 C) 77 D) 66 E) 51
|
<gadget id="calculator">200 + 350</gadget>
<output>550</output>
<gadget id="calculator">550 - 500</gadget>
<output>50</output>
<result>A</result>
|
A
| 50 |
A, B and C have Rs.500 between them, A and C together have Rs.200 and B and C Rs.350. How much does C have?
|
{
"A": "50",
"B": "88",
"C": "77",
"D": "66",
"E": "51"
}
|
subtract(add(200, 350), 500)
|
add(n1,n2)|subtract(#0,n0)|
|
"a + b + c = 500 a + c = 200 b + c = 350 - - - - - - - - - - - - - - a + b + 2 c = 550 a + b + c = 500 - - - - - - - - - - - - - - - - c = 50 answer : a"
|
general
|
math_qa__NnSFty6GAEE0ghec
|
a man invested rs . 14400 in rs . 100 shares of a company at 20 % premium . if his company declares 5 % dividend at the end of the year , then how much does he get ? Pick one:
A) 234 B) 600 C) 388 D) 278 E) 129
|
<gadget id="calculator">20 + 100</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">14_400 / (6/5)</gadget>
<output>12_000</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">12_000 * (1/20)</gadget>
<output>600</output>
<result>B</result>
|
B
| 600 |
a man invested rs . 14400 in rs . 100 shares of a company at 20 % premium . if his company declares 5 % dividend at the end of the year , then how much does he get ?
|
{
"A": "234",
"B": "600",
"C": "388",
"D": "278",
"E": "129"
}
|
multiply(divide(14400, divide(add(20, const_100), const_100)), divide(5, const_100))
|
add(n2,const_100)|divide(n3,const_100)|divide(#0,const_100)|divide(n0,#2)|multiply(#3,#1)
|
explanation : number of shares = = 120 . face value = rs . ( 100 x 120 ) = rs . 12000 . annual income = = rs . 600 answer : b ) rs . 600
|
gain
|
math_qa__aJ5y50pvt1miHxEd
|
The sale price of an article including the sales tax is Rs. 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 15%, then the cost price of the article is:
Select: A) 500 B) 334 C) 555 D) 536 E) 5598
|
<gadget id="calculator">616 * 100</gadget>
<output>61_600</output>
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">61_600 / 110</gadget>
<output>560</output>
<gadget id="calculator">560 * 110</gadget>
<output>61_600</output>
<gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">61_600 / 115</gadget>
<output>12_320/23 = around 535.652174</output>
<result>D</result>
|
D
| 536 |
The sale price of an article including the sales tax is Rs. 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 15%, then the cost price of the article is:
|
{
"A": "500",
"B": "334",
"C": "555",
"D": "536",
"E": "5598"
}
|
divide(multiply(divide(multiply(616, const_100), add(const_100, 10)), add(const_100, 10)), add(const_100, 15))
|
add(n1,const_100)|add(n2,const_100)|multiply(n0,const_100)|divide(#2,#0)|multiply(#0,#3)|divide(#4,#1)|
|
"110 % of s . p . = 616 s . p . = ( 616 * 100 ) / 110 = rs . 560 c . p = ( 110 * 560 ) / 115 = rs . 536 answer : option d"
|
gain
|
math_qa__COpZmRhq5bIxn3I0
|
Selling an kite for Rs. 30, a shop keeper gains 35%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is? Select:
A) 8 %
B) 10 %
C) 11 %
D) 15 %
E) 21.5 %
|
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">(3/10) * 90</gadget>
<output>27</output>
<gadget id="calculator">30 * 100</gadget>
<output>3_000</output>
<gadget id="calculator">35 + 100</gadget>
<output>135</output>
<gadget id="calculator">3_000 / 135</gadget>
<output>200/9 = around 22.222222</output>
<gadget id="calculator">27 - (200/9)</gadget>
<output>43/9 = around 4.777778</output>
<gadget id="calculator">(43/9) / (200/9)</gadget>
<output>43/200 = around 0.215</output>
<gadget id="calculator">(43/200) * 100</gadget>
<output>43/2 = around 21.5</output>
<result>E</result>
|
E
| 21.5 |
Selling an kite for Rs. 30, a shop keeper gains 35%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is?
|
{
"A": "8 %",
"B": "10 %",
"C": "11 %",
"D": "15 %",
"E": "21.5 %"
}
|
multiply(divide(subtract(multiply(divide(30, const_100), subtract(const_100, 10)), divide(multiply(30, const_100), add(35, const_100))), divide(multiply(30, const_100), add(35, const_100))), const_100)
|
add(n1,const_100)|divide(n0,const_100)|multiply(n0,const_100)|subtract(const_100,n2)|divide(#2,#0)|multiply(#1,#3)|subtract(#5,#4)|divide(#6,#4)|multiply(#7,const_100)|
|
"explanation : marked price = rs . 30 c . p . = 100 / 135 * 30 = rs . 22.22 sale price = 90 % of rs . 30 = rs . 27 required gain % = 4.77 / 22.22 * 100 = 21.5 % . answer : e"
|
gain
|
math_qa__43v2ULOYxJOnfLEX
|
If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 58, what is the compound interest on the same sum at the rate and for the same time? Choose the correct choice from the following options:
A) s . 59.45
B) s . 56.22
C) s . 51.219
D) s . 59.18
E) s . 51.11
|
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 2</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">58 / (1/10)</gadget>
<output>580</output>
<gadget id="calculator">580 * 5</gadget>
<output>2_900</output>
<gadget id="calculator">2_900 / 100</gadget>
<output>29</output>
<gadget id="calculator">29 + 580</gadget>
<output>609</output>
<gadget id="calculator">609 * 5</gadget>
<output>3_045</output>
<gadget id="calculator">3_045 / 100</gadget>
<output>609/20 = around 30.45</output>
<gadget id="calculator">609 + (609/20)</gadget>
<output>12_789/20 = around 639.45</output>
<gadget id="calculator">(12_789/20) - 580</gadget>
<output>1_189/20 = around 59.45</output>
<result>A</result>
|
A
| 59.45 |
If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 58, what is the compound interest on the same sum at the rate and for the same time?
|
{
"A": "s . 59.45",
"B": "s . 56.22",
"C": "s . 51.219",
"D": "s . 59.18",
"E": "s . 51.11"
}
|
subtract(add(add(divide(multiply(divide(58, multiply(divide(5, const_100), 2)), 5), const_100), divide(58, multiply(divide(5, const_100), 2))), divide(multiply(add(divide(multiply(divide(58, multiply(divide(5, const_100), 2)), 5), const_100), divide(58, multiply(divide(5, const_100), 2))), 5), const_100)), divide(58, multiply(divide(5, const_100), 2)))
|
divide(n1,const_100)|multiply(n0,#0)|divide(n2,#1)|multiply(n1,#2)|divide(#3,const_100)|add(#4,#2)|multiply(n1,#5)|divide(#6,const_100)|add(#5,#7)|subtract(#8,#2)|
|
"explanation : sum = ( 58 * 100 ) / ( 2 * 5 ) = rs . 580 amount = [ 580 * ( 1 + 5 / 100 ) 2 ] = rs . 639.45 c . i . = ( 639.45 - 580 ) = rs . 59.45 answer : a"
|
gain
|
math_qa__Z7okR3pZDTIhwNpl
|
If a = 105 and a^3 = 21 × 25 × 45 × d, what is the value of d? Answers
A) 35
B) 42
C) 45
D) 49
E) 54
|
<gadget id="calculator">105 ** 3</gadget>
<output>1_157_625</output>
<gadget id="calculator">21 * 25</gadget>
<output>525</output>
<gadget id="calculator">525 * 45</gadget>
<output>23_625</output>
<gadget id="calculator">1_157_625 / 23_625</gadget>
<output>49</output>
<result>D</result>
|
D
| 49 |
If a = 105 and a^3 = 21 × 25 × 45 × d, what is the value of d?
|
{
"A": "35",
"B": "42",
"C": "45",
"D": "49",
"E": "54"
}
|
divide(power(105, 3), multiply(multiply(21, 25), 45))
|
multiply(n2,n3)|power(n0,n1)|multiply(n4,#0)|divide(#1,#2)|
|
"a = 105 = 3 * 5 * 7 a ^ 3 = 21 × 25 × 45 × d = > a ^ 3 = ( 7 * 3 ) x ( 5 * 5 ) x ( 3 ^ 2 * 5 ) x d = > a ^ 3 = 3 ^ 3 * 5 ^ 3 * 7 x d = > ( 3 * 5 * 7 ) ^ 3 = 3 ^ 3 * 5 ^ 3 * 7 x d d = 7 ^ 2 = 49 answer d"
|
general
|
math_qa__l2rFujvlo4FxRFDl
|
A present value of a machine is $40000. Its value depletiation rate is 5% per annum then find the machine value after 2 years?
Choose the most appropriate option:
A) $ 36540 B) $ 36100 C) $ 29580 D) $ 31256 E) $ 41250
|
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 - (1/20)</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">(19/20) ** 2</gadget>
<output>361/400 = around 0.9025</output>
<gadget id="calculator">40_000 * (361/400)</gadget>
<output>36_100</output>
<result>B</result>
|
B
| 36,100 |
A present value of a machine is $40000. Its value depletiation rate is 5% per annum then find the machine value after 2 years?
|
{
"A": "$ 36540",
"B": "$ 36100",
"C": "$ 29580",
"D": "$ 31256",
"E": "$ 41250"
}
|
multiply(40000, power(subtract(const_1, divide(5, const_100)), 2))
|
divide(n1,const_100)|subtract(const_1,#0)|power(#1,n2)|multiply(n0,#2)|
|
"p = $ 40000 r = 5 % t = 2 years machine value after 3 years = p / ( 1 - r / 100 ) ^ t = 40000 * 19 / 20 * 19 / 20 * 19 / 20 = $ 36100 answer is b"
|
gain
|
math_qa__Z6MYFvtRqpIS5had
|
Find a sum for 1st 9 prime number's? Choose one:
A) 25
B) 28
C) 30
D) 34
E) 100
|
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 + 5</gadget>
<output>10</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">10 + 7</gadget>
<output>17</output>
<gadget id="calculator">9 + 2</gadget>
<output>11</output>
<gadget id="calculator">17 + 11</gadget>
<output>28</output>
<gadget id="calculator">11 + 2</gadget>
<output>13</output>
<gadget id="calculator">28 + 13</gadget>
<output>41</output>
<gadget id="calculator">13 + 4</gadget>
<output>17</output>
<gadget id="calculator">41 + 17</gadget>
<output>58</output>
<gadget id="calculator">17 + 2</gadget>
<output>19</output>
<gadget id="calculator">58 + 19</gadget>
<output>77</output>
<gadget id="calculator">19 + 4</gadget>
<output>23</output>
<gadget id="calculator">77 + 23</gadget>
<output>100</output>
<result>E</result>
|
E
| 100 |
Find a sum for 1st 9 prime number's?
|
{
"A": "25",
"B": "28",
"C": "30",
"D": "34",
"E": "100"
}
|
add(add(add(add(add(add(add(add(const_2, const_3), add(const_2, const_3)), add(add(const_2, const_3), const_2)), add(9, const_2)), add(add(9, const_2), const_2)), add(add(add(9, const_2), const_2), const_4)), add(add(add(add(9, const_2), const_2), const_4), const_2)), add(add(add(add(add(9, const_2), const_2), const_4), const_2), const_4))
|
add(const_2,const_3)|add(n1,const_2)|add(#0,#0)|add(#0,const_2)|add(#1,const_2)|add(#2,#3)|add(#4,const_4)|add(#5,#1)|add(#6,const_2)|add(#7,#4)|add(#8,const_4)|add(#9,#6)|add(#11,#8)|add(#12,#10)
|
required sum = ( 2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 23 ) = 100 note : 1 is not a prime number option e
|
general
|
math_qa__QYNiElXg3gtbMkk8
|
A man is 25 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is?
Choose the correct option
A) 11 B) 23 C) 27 D) 22 E) 91
|
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">25 - 2</gadget>
<output>23</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">23 / 1</gadget>
<output>23</output>
<result>B</result>
|
B
| 23 |
A man is 25 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is?
|
{
"A": "11",
"B": "23",
"C": "27",
"D": "22",
"E": "91"
}
|
divide(subtract(25, subtract(multiply(const_2, const_2), const_2)), subtract(const_2, const_1))
|
multiply(const_2,const_2)|subtract(const_2,const_1)|subtract(#0,const_2)|subtract(n0,#2)|divide(#3,#1)|
|
"let the son ' s present age be x years . then , man ' s present age = ( x + 25 ) years . ( x + 25 ) + 2 = 2 ( x + 2 ) x + 27 = 2 x + 4 = > x = 23 . answer : b"
|
general
|
math_qa__UU7vWgOBlVOWrZCt
|
Calculate the sum of first 89 natural numbers. Choose the correct option.
A) 2017 B) 2647 C) 2147 D) 2045 E) 4005
|
<gadget id="calculator">89 + 1</gadget>
<output>90</output>
<gadget id="calculator">89 / 2</gadget>
<output>89/2 = around 44.5</output>
<gadget id="calculator">90 * (89/2)</gadget>
<output>4_005</output>
<result>E</result>
|
E
| 4,005 |
Calculate the sum of first 89 natural numbers.
|
{
"A": "2017",
"B": "2647",
"C": "2147",
"D": "2045",
"E": "4005"
}
|
multiply(add(89, const_1), divide(89, const_2))
|
add(n0,const_1)|divide(n0,const_2)|multiply(#0,#1)|
|
"solution we know that ( 1 + 2 + 3 + . . . . . + 89 ) = n ( n + 1 ) / 2 therefore ( 1 + 2 + 3 + . . . . + 89 ) = ( 89 × 90 / 2 ) = 4005 . answer e"
|
general
|
math_qa__11uqWrCljmlhzzDa
|
A jogger running at 10 km/hr along side a railway track is 340 m ahead of the engine of a 120 m long train running at 46 km/hr in the same direction. In how much time will the train pass the jogger?
Select.
A) 76 sec B) 67 sec C) 98 sec D) 46 sec E) 23 sec
|
<gadget id="calculator">340 + 120</gadget>
<output>460</output>
<gadget id="calculator">46 - 10</gadget>
<output>36</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">5 / 18</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">460 / 10</gadget>
<output>46</output>
<result>D</result>
|
D
| 46 |
A jogger running at 10 km/hr along side a railway track is 340 m ahead of the engine of a 120 m long train running at 46 km/hr in the same direction. In how much time will the train pass the jogger?
|
{
"A": "76 sec",
"B": "67 sec",
"C": "98 sec",
"D": "46 sec",
"E": "23 sec"
}
|
divide(add(340, 120), multiply(subtract(46, 10), divide(divide(const_10, const_2), divide(subtract(46, 10), const_2))))
|
add(n1,n2)|divide(const_10,const_2)|subtract(n3,n0)|divide(#2,const_2)|divide(#1,#3)|multiply(#4,#2)|divide(#0,#5)|
|
"speed of train relative to jogger = 46 - 10 = 36 km / hr . = 36 * 5 / 18 = 10 m / sec . distance to be covered = 340 + 120 = 460 m . time taken = 460 / 10 = 46 sec . answer : d"
|
general
|
math_qa__f1jy9tHYNoyeQNTL
|
An amount of Rs. 10000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 3/4 %, then the amount invested at 11% was? Options.
A) 2377
B) 3750
C) 2997
D) 2677
E) 1987
|
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">9 + (3/4)</gadget>
<output>39/4 = around 9.75</output>
<gadget id="calculator">(39/4) / 100</gadget>
<output>39/400 = around 0.0975</output>
<gadget id="calculator">10_000 * (39/400)</gadget>
<output>975</output>
<gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">10_000 * (9/100)</gadget>
<output>900</output>
<gadget id="calculator">975 - 900</gadget>
<output>75</output>
<gadget id="calculator">11 / 100</gadget>
<output>11/100 = around 0.11</output>
<gadget id="calculator">(11/100) - (9/100)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">75 / (1/50)</gadget>
<output>3_750</output>
<result>B</result>
|
B
| 3,750 |
An amount of Rs. 10000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 3/4 %, then the amount invested at 11% was?
|
{
"A": "2377",
"B": "3750",
"C": "2997",
"D": "2677",
"E": "1987"
}
|
divide(subtract(multiply(10000, divide(add(9, divide(3, 4)), const_100)), multiply(10000, divide(9, const_100))), subtract(divide(11, const_100), divide(9, const_100)))
|
divide(n4,n5)|divide(n1,const_100)|divide(n2,const_100)|add(n1,#0)|multiply(n0,#1)|subtract(#2,#1)|divide(#3,const_100)|multiply(n0,#6)|subtract(#7,#4)|divide(#8,#5)
|
let the sum invested at 9 % be rs . x and that invested at 11 % be rs . ( 10000 - x ) . then , ( x * 9 * 1 ) / 100 + [ ( 10000 - x ) * 11 * 1 ] / 100 = ( 10000 * 39 / 4 * 1 / 100 ) ( 9 x + 110000 - 11 x ) / 100 = 3900 / 4 = 975 ( 9 x + 110000 - 11 x ) = 97500 x = 6250 sum invested at 9 % = rs . 6250 sum invested at 11 % = rs . ( 10000 - 6250 ) = rs . 3750 . answer : b
|
gain
|
math_qa__NS4YWXakLXh9mZIU
|
The present population of a town is 300. Population increase rate is 10% p.a. Find the population of town after 1 years? Choose the correct answer
A) 100 B) 120 C) 200 D) 220 E) 330
|
<gadget id="calculator">300 * 10</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 100</gadget>
<output>30</output>
<gadget id="calculator">300 + 30</gadget>
<output>330</output>
<result>E</result>
|
E
| 330 |
The present population of a town is 300. Population increase rate is 10% p.a. Find the population of town after 1 years?
|
{
"A": "100",
"B": "120",
"C": "200",
"D": "220",
"E": "330"
}
|
add(300, divide(multiply(300, 10), const_100))
|
multiply(n0,n1)|divide(#0,const_100)|add(n0,#1)
|
p = 300 r = 10 % required population of town = p * ( 1 + r / 100 ) ^ t = 300 * ( 1 + 10 / 100 ) = 300 * ( 11 / 10 ) = 330 answer is e
|
gain
|
math_qa__z1oHM3Yzzdh1INyB
|
A powder tin has a square base with side 8 cm and height 14 cm. Another tin has a circular base with diameter 8 cm and height 14 cm. The difference in their capacities is : Choose one:
A) 168 cm ³
B) 192 cm ³
C) 228 cm ³
D) 236 cm ³
E) none
|
<gadget id="calculator">8 * 8 * 14</gadget>
<output>896</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">pi * (4 ** 2) * 14</gadget>
<output>224*pi = around 703.716754</output>
<gadget id="calculator">896 - (224*pi)</gadget>
<output>896 - 224*pi = around 192.283246</output>
<result>B</result>
|
B
| 192 |
A powder tin has a square base with side 8 cm and height 14 cm. Another tin has a circular base with diameter 8 cm and height 14 cm. The difference in their capacities is :
|
{
"A": "168 cm ³",
"B": "192 cm ³",
"C": "228 cm ³",
"D": "236 cm ³",
"E": "none"
}
|
subtract(volume_rectangular_prism(8, 8, 14), volume_cylinder(divide(8, const_2), 14))
|
divide(n0,const_2)|volume_rectangular_prism(n0,n0,n1)|volume_cylinder(#0,n1)|subtract(#1,#2)
|
sol . difference in capacities = [ 8 * 8 * 14 - 22 / 7 * 4 * 4 * 14 ] cm ³ = 192 cm ³ answer b
|
geometry
|
math_qa__TgRxfs50vZbNuPLY
|
Today David, who is 40 years old, and his daughter, who is 12 years old, celebrate their birthdays. How many years will pass before David’s age is twice his daughter’s age? Select the correct option:
A) 22 B) 20 C) 16 D) 18 E) 14
|
<gadget id="calculator">40 + 12</gadget>
<output>52</output>
<gadget id="calculator">52 + 2</gadget>
<output>54</output>
<gadget id="calculator">54 / 2</gadget>
<output>27</output>
<gadget id="calculator">27 - 12</gadget>
<output>15</output>
<gadget id="calculator">15 + 1</gadget>
<output>16</output>
<result>C</result>
|
C
| 16 |
Today David, who is 40 years old, and his daughter, who is 12 years old, celebrate their birthdays. How many years will pass before David’s age is twice his daughter’s age?
|
{
"A": "22",
"B": "20",
"C": "16",
"D": "18",
"E": "14"
}
|
add(subtract(divide(add(add(40, 12), const_2), const_2), 12), const_1)
|
add(n0,n1)|add(#0,const_2)|divide(#1,const_2)|subtract(#2,n1)|add(#3,const_1)
|
forget conventional ways of solving math questions . in ps , ivy approach is the easiest and quickest way to find the answer . after x years passes david ’ s age will be ( 40 + x ) years old , and his daughter ’ s age will be ( 12 + x ) years old . since the david ’ s age is twice his daughter ’ s age ( 40 + x ) = 2 * ( 12 + x ) - - - > 40 + x = 24 + 2 x - - - > x = 16 the answer is ( c ) .
|
general
|
math_qa__SEGwAaOstg3o1HJe
|
Earl can stuff advertising circulars into envelopes at the rate of 36 envelopes per minutes and Ellen requires a minutes and half to stuff the same number of envelops.Working together,how long will it take Earl and Ellen to stuff 120 envelopes Choose the most appropriate option:
A) 2 minutes B) 5 minutes C) 7 minutes D) 3 minutes E) 4 minutes
|
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">36 / (3/2)</gadget>
<output>24</output>
<gadget id="calculator">36 + 24</gadget>
<output>60</output>
<gadget id="calculator">120 / 60</gadget>
<output>2</output>
<result>A</result>
|
A
| 2 |
Earl can stuff advertising circulars into envelopes at the rate of 36 envelopes per minutes and Ellen requires a minutes and half to stuff the same number of envelops.Working together,how long will it take Earl and Ellen to stuff 120 envelopes
|
{
"A": "2 minutes",
"B": "5 minutes",
"C": "7 minutes",
"D": "3 minutes",
"E": "4 minutes"
}
|
divide(120, add(36, divide(36, divide(const_3, const_2))))
|
divide(const_3,const_2)|divide(n0,#0)|add(n0,#1)|divide(n1,#2)|
|
"earl takes 1 min . for 36 envelopes . ellen takes 3 / 2 mins for the same . so ellen can stuff ( ( 36 ) / ( 3 / 2 ) ) in 1 min . i . e . , 24 envelopes a min . so both of them when work together can stuff 36 + 24 = 60 envelopes in 1 min . for 120 envelopes they will take 120 / 60 mins . i . e . , 2 mins . answer : a"
|
physics
|
math_qa__LEZ8mDrld5xXMwAG
|
if ( 400 ) ( 7000 ) = ( 28000 ) ( 100 ^ x ) , what is the value of x ? Choose the most appropriate option:
A) 5 B) 4 C) 3 D) 2 E) 1
|
<gadget id="calculator">400 * 7_000</gadget>
<output>2_800_000</output>
<gadget id="calculator">2_800_000 / 28_000</gadget>
<output>100</output>
<gadget id="calculator">100 / 100</gadget>
<output>1</output>
<result>E</result>
|
E
| 1 |
if ( 400 ) ( 7000 ) = ( 28000 ) ( 100 ^ x ) , what is the value of x ?
|
{
"A": "5",
"B": "4",
"C": "3",
"D": "2",
"E": "1"
}
|
divide(divide(multiply(400, 7000), 28000), 100)
|
multiply(n0,n1)|divide(#0,n2)|divide(#1,n3)
|
( 400 ) ( 7,000 ) = ( 2,800 ) ( 100 ^ x ) = > ( 400 ) ( 7,000 ) / 2,800 = 100 ^ x = > 100 = 100 ^ x = > 100 ^ 1 = 100 ^ x since , base is same so powers will be same too . so , x = 1 answer will be e
|
general
|
math_qa__tYFEdNFkoA9l5tjl
|
Having received his weekly allowance, John spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $0.64 at the candy store. What is John’s weekly allowance? Choose the most appropriate option:
A) $ 2.40
B) $ 3.00
C) $ 3.20
D) $ 3.60
E) $ 4.80
|
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/3) * (2/5)</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(3/5) + (2/15)</gadget>
<output>11/15 = around 0.733333</output>
<gadget id="calculator">1 - (11/15)</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">0.64 / (4/15)</gadget>
<output>2.4</output>
<result>A</result>
|
A
| 2.4 |
Having received his weekly allowance, John spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $0.64 at the candy store. What is John’s weekly allowance?
|
{
"A": "$ 2.40",
"B": "$ 3.00",
"C": "$ 3.20",
"D": "$ 3.60",
"E": "$ 4.80"
}
|
divide(0.64, subtract(const_1, add(divide(3, 5), multiply(divide(const_1, 3), subtract(const_1, divide(3, 5))))))
|
divide(n0,n1)|divide(const_1,n0)|subtract(const_1,#0)|multiply(#1,#2)|add(#0,#3)|subtract(const_1,#4)|divide(n2,#5)|
|
"total allowance = x amount spent at the arcade = 3 / 5 x amount remaining = 2 / 5 x amount spent at the toy store = 2 / 5 * 1 / 3 x = 2 / 15 x amount remaining = 2 / 5 x - 2 / 15 x = 4 / 15 x now , 4 / 15 x = $ 0.64 therefore , x = $ 2.40 . answer a"
|
general
|
math_qa__1UBi8DfwdaKka5Ob
|
The sum of the present age of Henry and Jill is 41. What is their present ages if 7 years ago Henry was twice the age of Jill? Answers: A) and 25 B) and 24 C) and 22 D) and 29 E) of these
|
<gadget id="calculator">41 + 7</gadget>
<output>48</output>
<gadget id="calculator">48 / 3</gadget>
<output>16</output>
<gadget id="calculator">41 - 16</gadget>
<output>25</output>
<result>A</result>
|
A
| 25 |
The sum of the present age of Henry and Jill is 41. What is their present ages if 7 years ago Henry was twice the age of Jill?
|
{
"A": "and 25",
"B": "and 24",
"C": "and 22",
"D": "and 29",
"E": "of these"
}
|
subtract(41, divide(add(41, 7), const_3))
|
add(n0,n1)|divide(#0,const_3)|subtract(n0,#1)
|
let the age of jill 7 years ago be x , age of henry be 2 x x + 7 + 2 x + 7 = 41 x = 9 present ages will be 16 and 25 answer : a
|
general
|
math_qa__eoXv3akPSHQl7TlF
|
A watch was sold at a loss of 10%. If it was sold for Rs.500 more, there would have been a gain of 10%. What is the cost price? Choose the correct choice:
A) 1000 B) 2998 C) 2500 D) 2788 E) 2991
|
<gadget id="calculator">500 * 100</gadget>
<output>50_000</output>
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">110 - 90</gadget>
<output>20</output>
<gadget id="calculator">50_000 / 20</gadget>
<output>2_500</output>
<result>C</result>
|
C
| 2,500 |
A watch was sold at a loss of 10%. If it was sold for Rs.500 more, there would have been a gain of 10%. What is the cost price?
|
{
"A": "1000",
"B": "2998",
"C": "2500",
"D": "2788",
"E": "2991"
}
|
divide(multiply(500, const_100), subtract(add(const_100, 10), subtract(const_100, 10)))
|
add(const_100,n2)|multiply(n1,const_100)|subtract(const_100,n0)|subtract(#0,#2)|divide(#1,#3)|
|
"90 % 110 % - - - - - - - - 20 % - - - - 500 100 % - - - - ? = > rs . 2500 answer : c"
|
gain
|
math_qa__HObzsbrJsLoxoQGR
|
What is the area of a square field whose diagonal of length 26 m? Choose the most appropriate option: A) 287 B) 269 C) 338 D) 200 E) 230
|
<gadget id="calculator">26 ** 2</gadget>
<output>676</output>
<gadget id="calculator">676 / 2</gadget>
<output>338</output>
<result>C</result>
|
C
| 338 |
What is the area of a square field whose diagonal of length 26 m?
|
{
"A": "287",
"B": "269",
"C": "338",
"D": "200",
"E": "230"
}
|
divide(square_area(26), const_2)
|
square_area(n0)|divide(#0,const_2)|
|
"d 2 / 2 = ( 26 * 26 ) / 2 = 338 answer : c"
|
geometry
|
math_qa__tv7DtyDmDiJP3nkW
|
A book is bought for $600 and sold for $624. What is the profit in percentage?
Select the correct option
A) 2 B) 4 C) 6 D) 8 E) 10
|
<gadget id="calculator">624 - 600</gadget>
<output>24</output>
<gadget id="calculator">24 / 600</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) * 100</gadget>
<output>4</output>
<result>B</result>
|
B
| 4 |
A book is bought for $600 and sold for $624. What is the profit in percentage?
|
{
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "10"
}
|
multiply(divide(subtract(624, 600), 600), const_100)
|
subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)|
|
"624 / 600 = 1.04 the answer is b ."
|
gain
|
math_qa__gtAN3uSy6uaFLxnu
|
A trader sells 78 meters of cloth for Rs. 6788 at the profit of Rs. 29 per metre of cloth. What is the cost price of one metre of cloth? Pick
A) 22 B) 75 C) 60 D) 58 E) 11
|
<gadget id="calculator">6_788 / 78</gadget>
<output>3_394/39 = around 87.025641</output>
<gadget id="calculator">(3_394/39) - 29</gadget>
<output>2_263/39 = around 58.025641</output>
<result>D</result>
|
D
| 58 |
A trader sells 78 meters of cloth for Rs. 6788 at the profit of Rs. 29 per metre of cloth. What is the cost price of one metre of cloth?
|
{
"A": "22",
"B": "75",
"C": "60",
"D": "58",
"E": "11"
}
|
subtract(divide(6788, 78), 29)
|
divide(n1,n0)|subtract(#0,n2)|
|
"sp of 1 m of cloth = 6788 / 78 = rs . 87 cp of 1 m of cloth = sp of 1 m of cloth - profit on 1 m of cloth = rs . 87 - rs . 29 = rs . 58 . answer : d"
|
physics
|
math_qa__X3GFCyCwhrX3Y2sK
|
By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 50%?
Choose the correct choice
A) s . 429 B) s . 480 C) s . 320 D) s . 128 E) s . 419
|
<gadget id="calculator">800 * 100</gadget>
<output>80_000</output>
<gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">80_000 / 125</gadget>
<output>640</output>
<gadget id="calculator">640 * 50</gadget>
<output>32_000</output>
<gadget id="calculator">32_000 / 100</gadget>
<output>320</output>
<gadget id="calculator">640 - 320</gadget>
<output>320</output>
<result>C</result>
|
C
| 320 |
By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 50%?
|
{
"A": "s . 429",
"B": "s . 480",
"C": "s . 320",
"D": "s . 128",
"E": "s . 419"
}
|
subtract(divide(multiply(800, const_100), add(25, const_100)), divide(multiply(divide(multiply(800, const_100), add(25, const_100)), 50), const_100))
|
add(n1,const_100)|multiply(n0,const_100)|divide(#1,#0)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)|
|
"sp = 800 profit = 25 % cp = ( sp ) * [ 100 / ( 100 + p ) ] = 800 * [ 100 / 125 ] = 640 loss = 50 % = 50 % of 640 = rs . 320 sp = cp - loss = 640 - 320 = rs . 320 answer : c"
|
gain
|
math_qa__2rnILPSg6yZWZVhE
|
On a certain transatlantic crossing, 40 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 50 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets? Choices
A) 40 % B) 50 % C) 60 % D) 80 % E) 90 %
|
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 - (1/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">40 / (1/2)</gadget>
<output>80</output>
<result>D</result>
|
D
| 80 |
On a certain transatlantic crossing, 40 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 50 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?
|
{
"A": "40 %",
"B": "50 %",
"C": "60 %",
"D": "80 %",
"E": "90 %"
}
|
divide(40, subtract(const_1, divide(50, const_100)))
|
divide(n1,const_100)|subtract(const_1,#0)|divide(n0,#1)
|
let t be the total number of passengers . let x be the number of people with round trip tickets . 0.4 t had round trip tickets and took their cars . 0.5 x had round trip tickets and took their cars . 0.5 x = 0.4 t x = 0.8 t the answer is d .
|
gain
|
math_qa__Psks0ucwh7NTt0Zf
|
if log 2 = 0.30103, the number of digits in 2128 is
. Choose the correct option:
A) 38 B) 39 C) 40 D) 41 E) 56
|
<gadget id="calculator">2 * 1_000</gadget>
<output>2_000</output>
<gadget id="calculator">2_128 - 2_000</gadget>
<output>128</output>
<gadget id="calculator">0.30103 * 128</gadget>
<output>38.53184</output>
<result>B</result>
|
B
| 39 |
if log 2 = 0.30103, the number of digits in 2128 is
.
|
{
"A": "38",
"B": "39",
"C": "40",
"D": "41",
"E": "56"
}
|
multiply(0.30103, subtract(2128, multiply(const_2, const_1000)))
|
multiply(const_1000,const_2)|subtract(n2,#0)|multiply(n1,#1)
|
log ( 2128 ) = 128 log ( 2 ) = 128 × 0.30103 ≈ 38.4 ie , its characteristic = 38 hence , number of digits in 2128 = 38 + 1 = 39 answer : option b
|
other
|
math_qa__XjVmCSHsbBGgv5ud
|
If a person walks at 5 km/hr instead of 4 km/hr, he would have walked 6 km more. The actual distance traveled by him is? Choose the correct choice from the following answers: A) 14 B) 20 C) 18 D) 24 E) 21
|
<gadget id="calculator">5 - 4</gadget>
<output>1</output>
<gadget id="calculator">6 / 1</gadget>
<output>6</output>
<gadget id="calculator">4 * 6</gadget>
<output>24</output>
<result>D</result>
|
D
| 24 |
If a person walks at 5 km/hr instead of 4 km/hr, he would have walked 6 km more. The actual distance traveled by him is?
|
{
"A": "14",
"B": "20",
"C": "18",
"D": "24",
"E": "21"
}
|
multiply(4, divide(6, subtract(5, 4)))
|
subtract(n0,n1)|divide(n2,#0)|multiply(n1,#1)|
|
"let the actual distance traveled be x km . then , x / 4 = ( x + 6 ) / 5 x - 24 = > x = 24 km . answer : d"
|
general
|
math_qa__GmoGynLEW8BlpH8M
|
If Tim had lunch at $60.80 and he gave 20% tip, how much did he spend?
Select
A) $ 30.60 B) $ 60.60 C) $ 72.96 D) $ 40.60 E) $ 50.60
|
<gadget id="calculator">60.8 * 20</gadget>
<output>1_216</output>
<gadget id="calculator">1_216 / 100</gadget>
<output>304/25 = around 12.16</output>
<gadget id="calculator">60.8 + (304/25)</gadget>
<output>72.96</output>
<result>C</result>
|
C
| 72.96 |
If Tim had lunch at $60.80 and he gave 20% tip, how much did he spend?
|
{
"A": "$ 30.60",
"B": "$ 60.60",
"C": "$ 72.96",
"D": "$ 40.60",
"E": "$ 50.60"
}
|
add(60.8, divide(multiply(60.8, 20), const_100))
|
multiply(n0,n1)|divide(#0,const_100)|add(n0,#1)
|
the tip is 20 % of what he paid for lunch . hence tip = 20 % of 60.80 = ( 20 / 100 ) * 60.80 = $ 12.16 total spent 60.80 + 12.16 = $ 72.96 correct answer c
|
gain
|
math_qa__hjyNQsH6mCFBJMqR
|
A ladder 18 feet long is leaning against a wall that is perpendicular to level ground. The bottom of the ladder is 6 feet from the base of the wall. If the top of the ladder slips down 4 feet, how many feet will the bottom of the ladder slip? Select the correct option
A) 12.5 B) 15 C) 18 D) 19 E) 25
|
<gadget id="calculator">18 ** 2</gadget>
<output>324</output>
<gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">324 - 36</gadget>
<output>288</output>
<gadget id="calculator">288 ** (1/2)</gadget>
<output>12*sqrt(2) = around 16.970563</output>
<gadget id="calculator">(12*sqrt(2)) - 4</gadget>
<output>-4 + 12*sqrt(2) = around 12.970563</output>
<gadget id="calculator">(-4 + 12*sqrt(2)) ** 2</gadget>
<output>(-4 + 12*sqrt(2))**2 = around 168.235498</output>
<gadget id="calculator">324 - ((-4 + 12*sqrt(2))**2)</gadget>
<output>324 - (-4 + 12*sqrt(2))**2 = around 155.764502</output>
<gadget id="calculator">(324 - (-4 + 12*sqrt(2))**2) ** (1/2)</gadget>
<output>sqrt(324 - (-4 + 12*sqrt(2))**2) = around 12.480565</output>
<result>A</result>
|
A
| 12.5 |
A ladder 18 feet long is leaning against a wall that is perpendicular to level ground. The bottom of the ladder is 6 feet from the base of the wall. If the top of the ladder slips down 4 feet, how many feet will the bottom of the ladder slip?
|
{
"A": "12.5",
"B": "15",
"C": "18",
"D": "19",
"E": "25"
}
|
sqrt(subtract(power(18, const_2), power(subtract(sqrt(subtract(power(18, const_2), power(6, const_2))), 4), const_2)))
|
power(n0,const_2)|power(n1,const_2)|subtract(#0,#1)|sqrt(#2)|subtract(#3,n2)|power(#4,const_2)|subtract(#0,#5)|sqrt(#6)|
|
"18 ^ 2 - 6 ^ 2 = 288 it means that the height is equal to 16.9 . since the top of the ladder slips down 4 feet , then the height of the wall = 16.9 - 4 = 12.9 the bottom = sqrt ( 18 ^ 2 - 12.9 ^ 2 ) = sqrt ( 324 - 166.41 ) = 12.5 ans is a"
|
gain
|
math_qa__CWtswkKbG085g68R
|
Johnny makes $3.25 per hour at his work. If he works 8 hours, how much money will he earn? Choose the most appropriate option:
A) $ 30
B) $ 54
C) $ 26
D) $ 12
E) $ 9.60
|
<gadget id="calculator">3.25 * 8</gadget>
<output>26</output>
<result>C</result>
|
C
| 26 |
Johnny makes $3.25 per hour at his work. If he works 8 hours, how much money will he earn?
|
{
"A": "$ 30",
"B": "$ 54",
"C": "$ 26",
"D": "$ 12",
"E": "$ 9.60"
}
|
multiply(3.25, 8)
|
multiply(n0,n1)|
|
3.25 * 8 = 26 . answer is c .
|
physics
|
math_qa__WsMGaBJ8rTlefK5z
|
An article is bought for Rs.1280 and sold for Rs.900, find the loss percent?
Choose the correct answer: A) 28 % B) 29 % C) 16 % D) 26 % E) 32 %
|
<gadget id="calculator">900 * 100</gadget>
<output>90_000</output>
<gadget id="calculator">90_000 / 1_280</gadget>
<output>1_125/16 = around 70.3125</output>
<gadget id="calculator">100 - (1_125/16)</gadget>
<output>475/16 = around 29.6875</output>
<result>B</result>
|
B
| 29 |
An article is bought for Rs.1280 and sold for Rs.900, find the loss percent?
|
{
"A": "28 %",
"B": "29 %",
"C": "16 %",
"D": "26 %",
"E": "32 %"
}
|
subtract(const_100, divide(multiply(900, const_100), 1280))
|
multiply(n1,const_100)|divide(#0,n0)|subtract(const_100,#1)|
|
"1280 - - - - 380 100 - - - - ? = > 29 % answer : b"
|
gain
|
math_qa__bls7sEEKz4ij95T6
|
What is the rate percent when the simple interest on Rs.800 amount to Rs.160 in 3 Years?
Select: A) 5 % B) 6.6 % C) 9 % D) 2 % E) 4 %
|
<gadget id="calculator">100 * 160</gadget>
<output>16_000</output>
<gadget id="calculator">800 * 3</gadget>
<output>2_400</output>
<gadget id="calculator">16_000 / 2_400</gadget>
<output>20/3 = around 6.666667</output>
<result>B</result>
|
B
| 6.6 |
What is the rate percent when the simple interest on Rs.800 amount to Rs.160 in 3 Years?
|
{
"A": "5 %",
"B": "6.6 %",
"C": "9 %",
"D": "2 %",
"E": "4 %"
}
|
divide(multiply(const_100, 160), multiply(800, 3))
|
multiply(n1,const_100)|multiply(n0,n2)|divide(#0,#1)|
|
"160 = ( 800 * 3 * r ) / 100 r = 6.6 % answer : b"
|
gain
|
math_qa__35TASihTM7f8Zey6
|
Solve below question 2x + 1 = -17 Choices
A) - 8
B) - 9
C) 9
D) 8
E) - 7
|
<gadget id="calculator">17 + 1</gadget>
<output>18</output>
<gadget id="calculator">-18</gadget>
<output>-18</output>
<gadget id="calculator">(-18) / 2</gadget>
<output>-9</output>
<result>B</result>
|
B
| -9 |
Solve below question 2x + 1 = -17
|
{
"A": "- 8",
"B": "- 9",
"C": "9",
"D": "8",
"E": "- 7"
}
|
divide(negate(add(17, 1)), 2)
|
add(n1,n2)|negate(#0)|divide(#1,n0)|
|
"1 . subtract 1 from both sides : 2 x + 1 - 1 = - 17 - 1 2 . simplify both sides : 2 x = - 18 3 . divide both sides by 2 : 4 . simplify both sides : x = - 9 b"
|
general
|
math_qa__l3AEcyYBrtKrlix1
|
What is the difference between the largest number and the least number written with the digits 9, 3, 1, 2? Select the correct option
A) 6084 B) 3788 C) 2077 D) 8082 E) 1812
|
<gadget id="calculator">9 * 100</gadget>
<output>900</output>
<gadget id="calculator">900 * 10</gadget>
<output>9_000</output>
<gadget id="calculator">4 * 100</gadget>
<output>400</output>
<gadget id="calculator">9_000 + 400</gadget>
<output>9_400</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">9_400 + 30</gadget>
<output>9_430</output>
<gadget id="calculator">9_430 + 1</gadget>
<output>9_431</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">1_000 + 300</gadget>
<output>1_300</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">1_300 + 20</gadget>
<output>1_320</output>
<gadget id="calculator">1_320 + 9</gadget>
<output>1_329</output>
<gadget id="calculator">9_431 - 1_329</gadget>
<output>8_102</output>
<result>D</result>
|
D
| 8,082 |
What is the difference between the largest number and the least number written with the digits 9, 3, 1, 2?
|
{
"A": "6084",
"B": "3788",
"C": "2077",
"D": "8082",
"E": "1812"
}
|
subtract(add(add(add(multiply(multiply(9, const_100), const_10), multiply(const_4.0, const_100)), multiply(3, const_10)), 1), add(add(add(const_1000, multiply(3, const_100)), multiply(2, const_10)), 9))
|
multiply(n0,const_100)|multiply(const_4.0,const_100)|multiply(n1,const_10)|multiply(n1,const_100)|multiply(n3,const_10)|add(#3,const_1000)|multiply(#0,const_10)|add(#6,#1)|add(#5,#4)|add(#7,#2)|add(n0,#8)|add(n2,#9)|subtract(#11,#10)|
|
"explanation : 1239 9321 - - - - - - - - - - - - 8082 answer : d"
|
general
|
math_qa__J0ZPFshugMrxiGK7
|
If m and n are positive integer, and 1800m=n^3, what is the least possible value of m? Choose the correct choice from the following answers.
A) 2 B) 3 C) 15 D) 30 E) 45
|
<gadget id="calculator">1_800 * 2</gadget>
<output>3_600</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">3_600 ** (1/3)</gadget>
<output>2*450**(1/3) = around 15.326189</output>
<gadget id="calculator">floor(2*450**(1/3))</gadget>
<output>15</output>
<result>C</result>
|
C
| 15 |
If m and n are positive integer, and 1800m=n^3, what is the least possible value of m?
|
{
"A": "2",
"B": "3",
"C": "15",
"D": "30",
"E": "45"
}
|
floor(power(multiply(1800, const_2), const_0_33))
|
multiply(n0,const_2)|power(#0,const_0_33)|floor(#1)
|
1800 * m = n ^ 3 m = n ^ 3 / 1800 = n ^ 3 / ( 3 ^ 2 * 5 ^ 2 * 2 ^ 3 ) so n has to be 3 * 5 * 2 so that n ^ 3 is divisible by 1800 . so m = ( 2 * 3 * 5 ) ^ 3 / ( 3 ^ 2 * 5 ^ 2 * 2 ^ 3 ) m = 15 answer : c
|
general
|
math_qa__mNslwVrl7Kvmjhrp
|
The moon revolves around the earth at a speed of approximately 1.04 kilometers per second. This approximate speed is how many kilometers per hour?
Choose the correct answer: A) 60 B) 61.2 C) 3,744 D) 3,600 E) 3,672
|
<gadget id="calculator">1.04 * 3_600</gadget>
<output>3_744</output>
<result>C</result>
|
C
| 3,744 |
The moon revolves around the earth at a speed of approximately 1.04 kilometers per second. This approximate speed is how many kilometers per hour?
|
{
"A": "60",
"B": "61.2",
"C": "3,744",
"D": "3,600",
"E": "3,672"
}
|
multiply(1.04, const_3600)
|
multiply(n0,const_3600)|
|
"moon revolves around the earth at a speed of 1.02 kilometers per second . one hour equal to 60 minutes . one minute equals to 60 seconds . so one hour equals to 3600 seconds . so one hour , speed = 1.04 * 3600 = 3744 kilometers per hour . option c is correct"
|
physics
|
math_qa__SGn8KvY7rLYMTbOP
|
Two trains, A and B, started simultaneously from opposite ends of a 75-mile route and traveled toward each other on parallel tracks. Train A, traveling at a constant rate, completed the 75-mile trip in 3 hours; Train B, traveling at a constant rate, completed the 75-mile trip in 2 hours. How many miles had train A traveled when it met train B? Choose the correct choice from the following answers:
A) 20 B) 22.5 C) 30 D) 37.5 E) 45
|
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 75</gadget>
<output>30</output>
<result>C</result>
|
C
| 30 |
Two trains, A and B, started simultaneously from opposite ends of a 75-mile route and traveled toward each other on parallel tracks. Train A, traveling at a constant rate, completed the 75-mile trip in 3 hours; Train B, traveling at a constant rate, completed the 75-mile trip in 2 hours. How many miles had train A traveled when it met train B?
|
{
"A": "20",
"B": "22.5",
"C": "30",
"D": "37.5",
"E": "45"
}
|
multiply(divide(2, add(3, 2)), 75)
|
add(n2,n4)|divide(n4,#0)|multiply(n0,#1)|
|
"as the ratio of the rates of a and b is 2 to 3 then the distance covered at the time of the meeting ( so after traveling the same time interval ) would also be in that ratio , which means that x would cover 2 / ( 2 + 3 ) = 2 / 5 of 75 miles : 75 * 2 / 5 = 30 miles . answer : c ."
|
physics
|
math_qa__Ow34hyrGcJXz6zuR
|
In one alloy there is 12% chromium while in another alloy it is 8%. 15 kg of the first alloy was melted together with 30 kg of the second one to form a third alloy. Find the percentage of chromium in the new alloy.
Select the correct option:
A) 9.4 % B) 9.33 % C) 9.6 % D) 9.8 % E) 10 %
|
<gadget id="calculator">12 * 15</gadget>
<output>180</output>
<gadget id="calculator">180 / 100</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">8 * 30</gadget>
<output>240</output>
<gadget id="calculator">240 / 100</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(9/5) + (12/5)</gadget>
<output>21/5 = around 4.2</output>
<gadget id="calculator">15 + 30</gadget>
<output>45</output>
<gadget id="calculator">(21/5) / 45</gadget>
<output>7/75 = around 0.093333</output>
<gadget id="calculator">(7/75) * 100</gadget>
<output>28/3 = around 9.333333</output>
<result>B</result>
|
B
| 9.33 |
In one alloy there is 12% chromium while in another alloy it is 8%. 15 kg of the first alloy was melted together with 30 kg of the second one to form a third alloy. Find the percentage of chromium in the new alloy.
|
{
"A": "9.4 %",
"B": "9.33 %",
"C": "9.6 %",
"D": "9.8 %",
"E": "10 %"
}
|
multiply(divide(add(divide(multiply(12, 15), const_100), divide(multiply(8, 30), const_100)), add(15, 30)), const_100)
|
add(n2,n3)|multiply(n0,n2)|multiply(n1,n3)|divide(#1,const_100)|divide(#2,const_100)|add(#3,#4)|divide(#5,#0)|multiply(#6,const_100)|
|
"the amount of chromium in the new 15 + 30 = 45 kg alloy is 0.12 * 15 + 0.08 * 30 = 4.2 kg , so the percentage is 4.2 / 45 * 100 = 9.33 % . answer : b ."
|
gain
|
math_qa__fGeZUnP11FjgHCoO
|
The difference between a two-digit number and the number obtained by interchanging the positions of its digits is 45. What is the difference between the two digits of that number?
Choose the correct choice from the following options:
A) 4 B) 5 C) 6 D) 8 E) 9
|
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">45 / 9</gadget>
<output>5</output>
<result>B</result>
|
B
| 5 |
The difference between a two-digit number and the number obtained by interchanging the positions of its digits is 45. What is the difference between the two digits of that number?
|
{
"A": "4",
"B": "5",
"C": "6",
"D": "8",
"E": "9"
}
|
divide(45, subtract(const_10, const_1))
|
subtract(const_10,const_1)|divide(n0,#0)|
|
"sol . let the ten ’ s digit be x and unit ’ s digit be y , then , ( 10 x + y ) - ( 10 y + x ) = 45 ⇔ 9 ( x - y ) = 45 ⇔ x - y = 5 answer b"
|
general
|
math_qa__bjInaAxDYdKZVIX4
|
A cube is painted red on all faces. It is then cut into 27 equal smaller cubes. How many J cubes are painted on only 2 faces? Choose the most appropriate option
A) 12 B) 8 C) 6 D) 10 E) 16
|
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">27 ** (1/3)</gadget>
<output>3</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<result>A</result>
|
A
| 12 |
A cube is painted red on all faces. It is then cut into 27 equal smaller cubes. How many J cubes are painted on only 2 faces?
|
{
"A": "12",
"B": "8",
"C": "6",
"D": "10",
"E": "16"
}
|
multiply(const_4, power(27, divide(const_1, const_3)))
|
divide(const_1,const_3)|power(n0,#0)|multiply(#1,const_4)|
|
"1 ) draw a simple cube 2 ) draw 9 squares on each face of the cube ( so that it looks like a rubik ' s cube ) - this is what the cube will look like when it ' s cut into 27 equal smaller cubes . 3 ) remember that the outside of the cube is the part that ' s painted . . . . the mini - cubes with 2 painted sides are all on the edge of the cube , in themiddleof the edge . there are 4 in front , 4 in back and 4 more on thestripthat runs around the left / top / right / bottom of the cube . j = 4 + 4 + 4 = 12 . answer a"
|
geometry
|
math_qa__SnbpfJp8NHvvxlAV
|
At present the ratio between the ages of Arun and Deepak is 5:7. After 6years, Arun's age will be 36 years. What is the age of Deepak at present? Choose the correct choice from the following answers: A) 35 years B) 25 years C) 42 years D) 39 years E) 40 years
|
<gadget id="calculator">36 - 6</gadget>
<output>30</output>
<gadget id="calculator">30 * 7</gadget>
<output>210</output>
<gadget id="calculator">210 / 5</gadget>
<output>42</output>
<result>C</result>
|
C
| 42 |
At present the ratio between the ages of Arun and Deepak is 5:7. After 6years, Arun's age will be 36 years. What is the age of Deepak at present?
|
{
"A": "35 years",
"B": "25 years",
"C": "42 years",
"D": "39 years",
"E": "40 years"
}
|
divide(multiply(subtract(36, 6), 7), 5)
|
subtract(n3,n2)|multiply(n1,#0)|divide(#1,n0)|
|
"let the present ages of arun and deepak be 5 x years and 7 x years respectively 5 x + 6 = 36 5 x = 30 x = 6 deepak ' s age = 7 x = 42 years answer is c"
|
other
|
math_qa__iCDFWJyBn7FMGEXS
|
Excluding stoppages, the speed of a bus is 75 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour? Choose one.
A) 15 B) 24 C) 17 D) 19 E) none of these
|
<gadget id="calculator">75 - 45</gadget>
<output>30</output>
<gadget id="calculator">30 / 75</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">60 * (2/5)</gadget>
<output>24</output>
<result>B</result>
|
B
| 24 |
Excluding stoppages, the speed of a bus is 75 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
|
{
"A": "15",
"B": "24",
"C": "17",
"D": "19",
"E": "none of these"
}
|
multiply(const_60, divide(subtract(75, 45), 75))
|
subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_60)|
|
"due to stoppages , it covers 30 km less . time taken to cover 30 km = ( ( 30 / 75 ) ã — 60 ) = 24 min . option ( b ) is correct"
|
physics
|
math_qa__7BTr0rBBVUHC5Map
|
The visitors of a modern art museum who watched a certain Picasso painting were asked to fill in a short questionnaire indicating whether they had enjoyed looking at the picture and whether they felt they had understood it. According to the results of the survey, all 130 visitors who did not enjoy the painting also did not feel they had understood the painting, and the number of visitors who enjoyed the painting was equal to the number of visitors who felt they had understood the painting. If 3/4 of the visitors who answered the questionnaire both enjoyed the painting and felt they had understood the painting, then how many visitors answered the questionnaire? Options.
A) 90 B) 120 C) 160 D) 360 E) 520
|
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">130 / (1/4)</gadget>
<output>520</output>
<result>E</result>
|
E
| 520 |
The visitors of a modern art museum who watched a certain Picasso painting were asked to fill in a short questionnaire indicating whether they had enjoyed looking at the picture and whether they felt they had understood it. According to the results of the survey, all 130 visitors who did not enjoy the painting also did not feel they had understood the painting, and the number of visitors who enjoyed the painting was equal to the number of visitors who felt they had understood the painting. If 3/4 of the visitors who answered the questionnaire both enjoyed the painting and felt they had understood the painting, then how many visitors answered the questionnaire?
|
{
"A": "90",
"B": "120",
"C": "160",
"D": "360",
"E": "520"
}
|
divide(130, subtract(const_1, divide(3, 4)))
|
divide(n1,n2)|subtract(const_1,#0)|divide(n0,#1)
|
if we exclude those cases and take the question at face value , then it seems straightforward . group # 1 = ( did n ' t like , did n ' t understand ) = 130 group # 2 = ( like understood ) = 3 / 4 ( 1 / 4 ) n = 130 n = 520 answer = ( e )
|
general
|
math_qa__a1ygwLVHj2cQbcFS
|
When a certain perfect square is increased by 148, the result is another perfect square. What is the value of the original perfect square? Answers:
A) 1296 B) 1369 C) 1681 D) 1764 E) 2500
|
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 4</gadget>
<output>36</output>
<gadget id="calculator">36 * 36</gadget>
<output>1_296</output>
<result>A</result>
|
A
| 1,296 |
When a certain perfect square is increased by 148, the result is another perfect square. What is the value of the original perfect square?
|
{
"A": "1296",
"B": "1369",
"C": "1681",
"D": "1764",
"E": "2500"
}
|
multiply(multiply(multiply(const_3, const_3), const_4), multiply(multiply(const_3, const_3), const_4))
|
multiply(const_3,const_3)|multiply(#0,const_4)|multiply(#1,#1)
|
let ’ s call the two perfect squares x ^ 2 and y ^ 2 , respectively . then the given information translates as x ^ 2 + 148 = y ^ 2 . subtracting x ^ 2 gives 148 = y ^ 2 − x ^ 2 , a difference of squares . this , in turn , factors as ( y + x ) ( y − x ) = 148 . the next step is tricky . it begins with factoring 148 , which breaks down as 2 ∗ 2 ∗ 37 . since we ’ re dealing with perfect squares , x and y are positive integers , and ( y + x ) and ( y − x ) must be paired integer factors of 148 . the options are 148 ∗ 1,74 ∗ 2 , and 37 ∗ 4 . but our number properties establish that ( y + x ) and ( y − x ) must be either both odd or both even , so only 74 ∗ 2 is an actual possibility . and because for any positive integers ( y + x ) > ( y − x ) , we can conclude that y + x = 74 and y – x = 2 . solving by elimination , 2 y = 76 , y = 38 , and x = 36 . finally , we just need to square 36 . but rather than multiplying it out , note that 36 ^ 2 ends in 6 – as does only one answer , choice a . this answer must be the one we want .
|
geometry
|
math_qa__3CJBiFrMc0u30OLf
|
Train A is 13 miles ahead of Train B, which is traveling the same direction along the same route as Train A. If Train A is traveling at an average speed of 37 miles per hour and Train B is traveling at an average speed of 43 miles per hour, how long will it take Train B to overtake and drive 17 miles ahead of Train A? Options:
A) 4 hours
B) 2 hours
C) 2 hours 30 minutes
D) 5 hours
E) 3 hours 20 minutes
|
<gadget id="calculator">13 + 17</gadget>
<output>30</output>
<gadget id="calculator">43 - 37</gadget>
<output>6</output>
<gadget id="calculator">30 / 6</gadget>
<output>5</output>
<result>D</result>
|
D
| 5 |
Train A is 13 miles ahead of Train B, which is traveling the same direction along the same route as Train A. If Train A is traveling at an average speed of 37 miles per hour and Train B is traveling at an average speed of 43 miles per hour, how long will it take Train B to overtake and drive 17 miles ahead of Train A?
|
{
"A": "4 hours",
"B": "2 hours",
"C": "2 hours 30 minutes",
"D": "5 hours",
"E": "3 hours 20 minutes"
}
|
divide(add(13, 17), subtract(43, 37))
|
add(n0,n3)|subtract(n2,n1)|divide(#0,#1)
|
relative speed = 43 - 37 = 6 miles per hour dist required = 13 + 17 = 30 miles time taken to overtake = 30 / 6 = 5 hours . d is the answer .
|
physics
|
math_qa__ud6ZIXc8nfidsqBo
|
On increasing the price of T.V. sets by 30%, their sale decreases by 20%. What is the effect on the revenue receipts of the shop ? Choose the correct choice from the following answers:
A) 4 B) 5 C) 56 D) 2 E) 7
|
<gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">130 * 20</gadget>
<output>2_600</output>
<gadget id="calculator">2_600 / 100</gadget>
<output>26</output>
<gadget id="calculator">26 + 100</gadget>
<output>126</output>
<gadget id="calculator">130 - 126</gadget>
<output>4</output>
<result>A</result>
|
A
| 4 |
On increasing the price of T.V. sets by 30%, their sale decreases by 20%. What is the effect on the revenue receipts of the shop ?
|
{
"A": "4",
"B": "5",
"C": "56",
"D": "2",
"E": "7"
}
|
subtract(add(const_100, 30), add(divide(multiply(add(const_100, 30), 20), const_100), const_100))
|
add(n0,const_100)|multiply(n1,#0)|divide(#1,const_100)|add(#2,const_100)|subtract(#0,#3)|
|
"explanation : let the price be = rs . 100 , and number of units sold = 100 then , sale value = rs . ( 100 × 100 ) = rs . 10000 new sale value = rs . ( 130 × 80 ) = rs . 10400 increase % = 4001000040010000 × 100 = 4 % answer : a"
|
gain
|
math_qa__9xPw73uqVkg6IuMG
|
If Sharon's weekly salary increased by 16 percent, she would earn $348 per week. If instead, her weekly salary were to increase by 10 percent, how much would she earn per week?
Choose the correct option.
A) $ 374
B) $ 330
C) $ 385
D) $ 392
E) $ 399
|
<gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">1 + (4/25)</gadget>
<output>29/25 = around 1.16</output>
<gadget id="calculator">348 / (29/25)</gadget>
<output>300</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 300</gadget>
<output>30</output>
<gadget id="calculator">300 + 30</gadget>
<output>330</output>
<result>B</result>
|
B
| 330 |
If Sharon's weekly salary increased by 16 percent, she would earn $348 per week. If instead, her weekly salary were to increase by 10 percent, how much would she earn per week?
|
{
"A": "$ 374",
"B": "$ 330",
"C": "$ 385",
"D": "$ 392",
"E": "$ 399"
}
|
add(divide(348, add(const_1, divide(16, const_100))), multiply(divide(10, const_100), divide(348, add(const_1, divide(16, const_100)))))
|
divide(n0,const_100)|divide(n2,const_100)|add(#0,const_1)|divide(n1,#2)|multiply(#1,#3)|add(#3,#4)|
|
"( 348 / 116 ) 110 = 330 in this case long division does not take much time . ( 348 / 116 ) = 3 3 * 110 = 330 ( 300 + 30 ) answer b"
|
general
|
math_qa__Py8mFdOAkAFamlR9
|
If the charge of staying in a student youth hostel $18.00/day for the first week, and $14.00/day for each additional week, How much does it cost to stay for 23 days? Options.
A) $ 160 B) $ 350 C) $ 282 D) $ 274 E) $ 286
|
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">18 * 7</gadget>
<output>126</output>
<gadget id="calculator">23 - 7</gadget>
<output>16</output>
<gadget id="calculator">14 * 16</gadget>
<output>224</output>
<gadget id="calculator">126 + 224</gadget>
<output>350</output>
<result>B</result>
|
B
| 350 |
If the charge of staying in a student youth hostel $18.00/day for the first week, and $14.00/day for each additional week, How much does it cost to stay for 23 days?
|
{
"A": "$ 160",
"B": "$ 350",
"C": "$ 282",
"D": "$ 274",
"E": "$ 286"
}
|
add(multiply(18.00, add(const_3, const_4)), multiply(14.00, subtract(23, add(const_3, const_4))))
|
add(const_3,const_4)|multiply(n0,#0)|subtract(n2,#0)|multiply(n1,#2)|add(#1,#3)|
|
"total number of days of stay = 23 charge of staying in first week = 18 * 7 = 126 $ charge of staying for additional days = ( 23 - 7 ) * 14 = 16 * 14 = 224 $ total charge = 126 + 224 = 350 $ answer b"
|
general
|
math_qa__r1Gt9Ad0OnMALV9S
|
Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 125 mangoes. Choose the correct choice from the following answers.
A) 360 B) 380 C) 400 D) 416 E) 412
|
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">360 / (9/10)</gadget>
<output>400</output>
<gadget id="calculator">400 - 360</gadget>
<output>40</output>
<gadget id="calculator">40 / 12</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">(10/3) * 125</gadget>
<output>1_250/3 = around 416.666667</output>
<result>D</result>
|
D
| 416 |
Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 125 mangoes.
|
{
"A": "360",
"B": "380",
"C": "400",
"D": "416",
"E": "412"
}
|
multiply(divide(subtract(divide(360, subtract(const_1, divide(const_1, 10))), 360), 12), 125)
|
divide(const_1,n1)|subtract(const_1,#0)|divide(n0,#1)|subtract(#2,n0)|divide(#3,n2)|multiply(n3,#4)|
|
"mr . john used to purchase certain number of mangoes for $ 360 since the price of mangoes is reduced by 10 % he got 12 more mangoes today . find the original price of 120 mangoes . method 1 : let price per mango = x . let number of mangoes be n . then , nx = 360 . now price = 0.9 x ; number of mangoes = n + 12 . total amount = 0.9 x * ( n + 12 ) = 360 . nx = 0.9 nx + 10.8 x = > 0.1 nx = 10.8 x = > n = 108 = > x = 360 / 108 = 3.33 original price of 125 mangoes = 125 * 3.33 = 416 . answer d"
|
gain
|
math_qa__fKY41N5Syu2l5JUb
|
Calculate the time it will take for a full tank of water to become completely empty due to a leak given that the tank could be filled in 10 hours, but due to the leak in its bottom it takes 11 hours to be filled ?
Choose the correct option
A) 90 hours B) 80 hours C) 50 hours D) 120 hours E) 110 hours
|
<gadget id="calculator">10 * 11</gadget>
<output>110</output>
<gadget id="calculator">110 / 10</gadget>
<output>11</output>
<gadget id="calculator">110 / 11</gadget>
<output>10</output>
<gadget id="calculator">11 - 10</gadget>
<output>1</output>
<gadget id="calculator">110 / 1</gadget>
<output>110</output>
<result>E</result>
|
E
| 110 |
Calculate the time it will take for a full tank of water to become completely empty due to a leak given that the tank could be filled in 10 hours, but due to the leak in its bottom it takes 11 hours to be filled ?
|
{
"A": "90 hours",
"B": "80 hours",
"C": "50 hours",
"D": "120 hours",
"E": "110 hours"
}
|
divide(multiply(10, 11), subtract(divide(multiply(10, 11), 10), divide(multiply(10, 11), 11)))
|
multiply(n0,n1)|divide(#0,n0)|divide(#0,n1)|subtract(#1,#2)|divide(#0,#3)
|
part filled without leak in 1 hour = 1 / 10 part filled with leak in 1 hour = 1 / 11 work done by leak in 1 hour = 1 / 10 â ˆ ’ 1 / 11 = 110 hours answer : e
|
physics
|
math_qa__h12eSgYI38zMeJEK
|
In the first 25 overs of a cricket game, the run rate was only 5.4. What should be the run rate in the remaining 25 overs to reach the target of 400 runs? Select the correct option
A) 16.5
B) 13.2
C) 10.6
D) 11.2
E) 7.25
|
<gadget id="calculator">25 * 5.4</gadget>
<output>135</output>
<gadget id="calculator">400 - 135</gadget>
<output>265</output>
<gadget id="calculator">265 / 25</gadget>
<output>53/5 = around 10.6</output>
<result>C</result>
|
C
| 10.6 |
In the first 25 overs of a cricket game, the run rate was only 5.4. What should be the run rate in the remaining 25 overs to reach the target of 400 runs?
|
{
"A": "16.5",
"B": "13.2",
"C": "10.6",
"D": "11.2",
"E": "7.25"
}
|
divide(subtract(400, multiply(25, 5.4)), 25)
|
multiply(n0,n1)|subtract(n3,#0)|divide(#1,n2)|
|
required run rate = 400 - ( 5.4 x 25 ) / 25 = 265 / 25 = 10.6 option c
|
gain
|
math_qa__td211p8NG4RaAmoc
|
A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12100 after a year? Answers.
A) 3630 B) 3877 C) 2667 D) 2977 E) 2378
|
<gadget id="calculator">6_300 + 4_200</gadget>
<output>10_500</output>
<gadget id="calculator">10_500 + 10_500</gadget>
<output>21_000</output>
<gadget id="calculator">6_300 / 21_000</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 12_100</gadget>
<output>3_630</output>
<result>A</result>
|
A
| 3,630 |
A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12100 after a year?
|
{
"A": "3630",
"B": "3877",
"C": "2667",
"D": "2977",
"E": "2378"
}
|
multiply(divide(6300, add(add(6300, 4200), 10500)), 12100)
|
add(n0,n1)|add(n2,#0)|divide(n0,#1)|multiply(n3,#2)|
|
"explanation : 6300 : 4200 : 10500 3 : 2 : 5 3 / 10 * 12100 = 3630 answer : a"
|
gain
|
math_qa__HBfgnC3NXie8M7Qq
|
What is the unit digit in 4^100? Select: A) 0 B) 1 C) 6 D) 3 E) 5
|
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">16 % 10</gadget>
<output>6</output>
<result>C</result>
|
C
| 6 |
What is the unit digit in 4^100?
|
{
"A": "0",
"B": "1",
"C": "6",
"D": "3",
"E": "5"
}
|
reminder(power(4, const_2), const_10)
|
power(n0,const_2)|reminder(#0,const_10)
|
unit digit in 4 ^ 100 = unit digit in [ ( 4 ^ 4 ) ^ 25 ] but unit digit in 4 ^ 4 = 6 unit digit 4 ^ 100 = 6 answer is c
|
general
|
math_qa__uO3l3KLs05ovAuOy
|
Pipe A can fill a tank in 12 hours. Due to a leak at the bottom, it takes 18 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank? Choose the correct answer: A) 36 B) 87 C) 40 D) 37 E) 86
|
<gadget id="calculator">18 * 12</gadget>
<output>216</output>
<gadget id="calculator">18 - 12</gadget>
<output>6</output>
<gadget id="calculator">216 / 6</gadget>
<output>36</output>
<result>A</result>
|
A
| 36 |
Pipe A can fill a tank in 12 hours. Due to a leak at the bottom, it takes 18 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank?
|
{
"A": "36",
"B": "87",
"C": "40",
"D": "37",
"E": "86"
}
|
divide(multiply(18, 12), subtract(18, 12))
|
multiply(n0,n1)|subtract(n1,n0)|divide(#0,#1)|
|
"let the leak can empty the full tank in x hours 1 / 12 - 1 / x = 1 / 18 = > 1 / x = 1 / 12 - 1 / 18 = ( 3 - 2 ) / 36 = 1 / 36 = > x = 36 . answer : a"
|
physics
|
math_qa__dI521ZNVbZUWPtYo
|
If one and a half women, drink one and a half tea in one and a half minutes.
How many tea can 9 women drink in 3 minutes ?
Options:
A) 11
B) 8
C) 37
D) 15
E) 18
|
<gadget id="calculator">9 * 3</gadget>
<output>27</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">27 / (3/2)</gadget>
<output>18</output>
<result>E</result>
|
E
| 18 |
If one and a half women, drink one and a half tea in one and a half minutes.
How many tea can 9 women drink in 3 minutes ?
|
{
"A": "11",
"B": "8",
"C": "37",
"D": "15",
"E": "18"
}
|
divide(multiply(9, 3), divide(const_3, const_2))
|
divide(const_3,const_2)|multiply(n0,n1)|divide(#1,#0)
|
e 18 explanation : more minutes implies more tea . more women implies more tea . the time become twice ( 3 minutes / 1.5 minutes ) . women become six times ( 9 / 1.5 ) . number of tea = 2 * 6 * original ( 1.5 )
|
physics
|
math_qa__QF507Slesed03a9G
|
A can run 2 km distance in 2 min 20 seconds, while B can run this distance in 3 min 5 sec. . By how much distance can A beat B? Pick
A) 900 m B) 500 m C) 120 m D) 180 m E) 190 m
|
<gadget id="calculator">2 * 1_000</gadget>
<output>2_000</output>
<gadget id="calculator">3 * 60</gadget>
<output>180</output>
<gadget id="calculator">180 + 5</gadget>
<output>185</output>
<gadget id="calculator">2_000 / 185</gadget>
<output>400/37 = around 10.810811</output>
<gadget id="calculator">2 * 60</gadget>
<output>120</output>
<gadget id="calculator">120 + 20</gadget>
<output>140</output>
<gadget id="calculator">(400/37) * 140</gadget>
<output>56_000/37 = around 1_513.513514</output>
<gadget id="calculator">2_000 - (56_000/37)</gadget>
<output>18_000/37 = around 486.486486</output>
<result>B</result>
|
B
| 500 |
A can run 2 km distance in 2 min 20 seconds, while B can run this distance in 3 min 5 sec. . By how much distance can A beat B?
|
{
"A": "900 m",
"B": "500 m",
"C": "120 m",
"D": "180 m",
"E": "190 m"
}
|
subtract(multiply(2, const_1000), multiply(divide(multiply(2, const_1000), add(multiply(3, const_60), 5)), add(multiply(2, const_60), 20)))
|
multiply(n0,const_1000)|multiply(n0,const_60)|multiply(n3,const_60)|add(n2,#1)|add(n4,#2)|divide(#0,#4)|multiply(#3,#5)|subtract(#0,#6)
|
a takes time 2.20 minutes = 140 sec b takes time 3 minutes = 185 sec difference = 185 - 140 = 45 sec now we are to find distance covered in 40 sec by b 180 sec = 2000 m 1 sec = 100 / 9 m 45 sec = 45 x 100 / 9 = 500 m answer : b
|
physics
|
math_qa__2ETCEZvxjRCHdNdg
|
The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is: Choose the correct choice from the following
A) rs . 3900 B) rs . 3990 C) rs . 4000 D) rs . 4100 E) rs . 4200
|
<gadget id="calculator">4 / 10</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">15 * (2/5)</gadget>
<output>6</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">4_000 / 8</gadget>
<output>500</output>
<gadget id="calculator">500 * 3</gadget>
<output>1_500</output>
<gadget id="calculator">(2/5) * 500</gadget>
<output>200</output>
<gadget id="calculator">200 * 12</gadget>
<output>2_400</output>
<gadget id="calculator">1_500 + 2_400</gadget>
<output>3_900</output>
<result>A</result>
|
A
| 3,900 |
The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is:
|
{
"A": "rs . 3900",
"B": "rs . 3990",
"C": "rs . 4000",
"D": "rs . 4100",
"E": "rs . 4200"
}
|
add(multiply(divide(4000, add(multiply(15, divide(4, 10)), 2)), 3), multiply(multiply(divide(4, 10), divide(4000, add(multiply(15, divide(4, 10)), 2))), 12))
|
divide(n1,n0)|multiply(n2,#0)|add(n3,#1)|divide(n4,#2)|multiply(n6,#3)|multiply(#0,#3)|multiply(n5,#5)|add(#4,#6)|
|
"let the cost of a chair and that of a table be rs . x and rs . y respectively . then , 10 x = 4 y or y = 5 x . 2 15 x + 2 y = 4000 15 x + 2 x 5 x = 4000 2 20 x = 4000 x = 200 . so , y = 5 x 200 = 500 . 2 hence , the cost of 12 chairs and 3 tables = 12 x + 3 y = rs . ( 2400 + 1500 ) = rs . 3900 . a"
|
general
|
math_qa__zZsO6ohYrgWrl2Xu
|
If the remainder is 15 when the integer n is divided by 28, what is the remainder when 2n is divided by 14? Choose one
A) 0 B) 1 C) 2 D) 3 E) 4
|
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">30 - 28</gadget>
<output>2</output>
<result>C</result>
|
C
| 2 |
If the remainder is 15 when the integer n is divided by 28, what is the remainder when 2n is divided by 14?
|
{
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
}
|
subtract(multiply(15, 2), 28)
|
multiply(n0,n2)|subtract(#0,n1)|
|
"n = 28 k + 15 2 n = 2 ( 28 k + 15 ) = 4 k * 14 + 30 = 4 k * 14 + 2 * 14 + 2 = 14 j + 2 the answer is c ."
|
general
|
math_qa__XUQaRLX3meU4gEoL
|
Rice weighing 25/2 pounds was divided equally and placed in 4 containers. How many ounces of rice were in each container? (Note that 1 pound = 16 ounces)
Choose the correct choice.
A) 40 B) 50 C) 60 D) 70 E) 80
|
<gadget id="calculator">25 / 2</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 16</gadget>
<output>200</output>
<gadget id="calculator">200 / 4</gadget>
<output>50</output>
<result>B</result>
|
B
| 50 |
Rice weighing 25/2 pounds was divided equally and placed in 4 containers. How many ounces of rice were in each container? (Note that 1 pound = 16 ounces)
|
{
"A": "40",
"B": "50",
"C": "60",
"D": "70",
"E": "80"
}
|
divide(multiply(divide(25, 2), 16), 4)
|
divide(n0,n1)|multiply(n4,#0)|divide(#1,n2)|
|
"25 / 2 ÷ 4 = 25 / 8 pounds in each container 25 / 8 pounds * 16 ounces / pound = 50 ounces in each container the answer is b ."
|
general
|
math_qa__UP2qSAxIbej3u6tr
|
A man sold 18 toys for Rs. 21000, gaining thereby the cost price of 3 toy find the cost price of a toy
Choose the correct choice from the following choices
A) s . 600 B) s . 800 C) s . 500 D) s . 900 E) s . 1000
|
<gadget id="calculator">18 + 3</gadget>
<output>21</output>
<gadget id="calculator">21_000 / 21</gadget>
<output>1_000</output>
<result>E</result>
|
E
| 1,000 |
A man sold 18 toys for Rs. 21000, gaining thereby the cost price of 3 toy find the cost price of a toy
|
{
"A": "s . 600",
"B": "s . 800",
"C": "s . 500",
"D": "s . 900",
"E": "s . 1000"
}
|
divide(21000, add(18, 3))
|
add(n0,n2)|divide(n1,#0)|
|
"let the cost of one toy = x . then , cost of 18 toys = 18 x . gain = 3 x . sp of 18 toys = rs . 21000 . gain = sp â € “ cp 3 x = 21000 â € “ 18 x 21 x = 21000 x = rs . 1000 . answer : option e"
|
gain
|
math_qa__N5kbUkpy3204NVGd
|
In a school of 700 students, 45% wear blue shirts, 23% wear red shirts, 15% wear green shirts, and the remaining students wear other colors. How many students wear other colors (not blue, not red, not green)? Select:
A) 109
B) 119
C) 129
D) 139
E) 149
|
<gadget id="calculator">45 / 100</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">(9/20) * 700</gadget>
<output>315</output>
<gadget id="calculator">23 / 100</gadget>
<output>23/100 = around 0.23</output>
<gadget id="calculator">(23/100) * 700</gadget>
<output>161</output>
<gadget id="calculator">315 + 161</gadget>
<output>476</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 700</gadget>
<output>105</output>
<gadget id="calculator">476 + 105</gadget>
<output>581</output>
<gadget id="calculator">700 - 581</gadget>
<output>119</output>
<result>B</result>
|
B
| 119 |
In a school of 700 students, 45% wear blue shirts, 23% wear red shirts, 15% wear green shirts, and the remaining students wear other colors. How many students wear other colors (not blue, not red, not green)?
|
{
"A": "109",
"B": "119",
"C": "129",
"D": "139",
"E": "149"
}
|
subtract(700, add(add(multiply(divide(45, const_100), 700), multiply(divide(23, const_100), 700)), multiply(divide(15, const_100), 700)))
|
divide(n1,const_100)|divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#0)|multiply(n0,#1)|multiply(n0,#2)|add(#3,#4)|add(#6,#5)|subtract(n0,#7)
|
45 + 23 + 15 = 83 % 100 – 83 = 17 % 700 * 17 / 100 = 119 the answer is b .
|
gain
|
math_qa__O5YsiGdDpytSvIVX
|
Two brother X and Y appeared for an exam. The probability of selection of X is 1/7 and that of B is 2/9. Find the probability that both of them are selected. Choose the correct choice from the following answers
A) 2 / 69 B) 2 / 60 C) 2 / 63 D) 2 / 29 E) 2 / 10
|
<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">2 / 9</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">(1/7) * (2/9)</gadget>
<output>2/63 = around 0.031746</output>
<result>C</result>
|
C
| 0.031746 |
Two brother X and Y appeared for an exam. The probability of selection of X is 1/7 and that of B is 2/9. Find the probability that both of them are selected.
|
{
"A": "2 / 69",
"B": "2 / 60",
"C": "2 / 63",
"D": "2 / 29",
"E": "2 / 10"
}
|
multiply(divide(1, 7), divide(2, 9))
|
divide(n0,n1)|divide(n2,n3)|multiply(#0,#1)|
|
"explanation : let a be the event that x is selected and b is the event that y is selected . p ( a ) = 1 / 7 , p ( b ) = 2 / 9 . let c be the event that both are selected . p ( c ) = p ( a ) × p ( b ) as a and b are independent events : = ( 1 / 7 ) × ( 2 / 9 ) = 2 / 63 answer : c ) 2 / 63"
|
general
|
math_qa__c4I045nmsNAZlFHx
|
150 metres long yard, 11 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees Choose the correct choice from the following answers.
A) 10 B) 15 C) 14 D) 16 E) 17
|
<gadget id="calculator">11 - 2</gadget>
<output>9</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">150 / 10</gadget>
<output>15</output>
<result>B</result>
|
B
| 15 |
150 metres long yard, 11 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees
|
{
"A": "10",
"B": "15",
"C": "14",
"D": "16",
"E": "17"
}
|
divide(150, add(subtract(11, 2), const_1))
|
subtract(n1,n2)|add(#0,const_1)|divide(n0,#1)|
|
"11 trees have 10 gaps between them , required distance ( 150 / 10 ) = 15 b"
|
physics
|
math_qa__pyWdHFND9Mr1dxuW
|
A sells a Cricket Bat to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays $231 for it, the cost price of the Cricket Bat for A is: Choose the correct choice from the following answers: A) 150 B) 120 C) 154 D) 160 E) 210
|
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(6/5) * (5/4)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">231 / (3/2)</gadget>
<output>154</output>
<result>C</result>
|
C
| 154 |
A sells a Cricket Bat to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays $231 for it, the cost price of the Cricket Bat for A is:
|
{
"A": "150",
"B": "120",
"C": "154",
"D": "160",
"E": "210"
}
|
divide(231, multiply(add(const_1, divide(20, const_100)), add(const_1, divide(25, const_100))))
|
divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(#2,#3)|divide(n2,#4)
|
125 % of 120 % of a = 231 125 / 100 * 120 / 100 * a = 231 a = 231 * 2 / 3 = 154 . answer c
|
gain
|
math_qa__KWB0PPtZOhBvO1os
|
The length of the bridge, which a train 150 m long and traveling at 45 km/hr can cross in 30 sec is? Choices:
A) 377 B) 225 C) 237 D) 245 E) 267
|
<gadget id="calculator">1_000 / 1</gadget>
<output>1_000</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">3_600 / 1</gadget>
<output>3_600</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 150</gadget>
<output>225</output>
<result>B</result>
|
B
| 225 |
The length of the bridge, which a train 150 m long and traveling at 45 km/hr can cross in 30 sec is?
|
{
"A": "377",
"B": "225",
"C": "237",
"D": "245",
"E": "267"
}
|
subtract(multiply(divide(multiply(45, speed(const_1000, const_1)), speed(const_3600, const_1)), 30), 150)
|
speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)|
|
"speed = 45 * 5 / 18 = 25 / 2 m / sec . time = 30 sec let the length of bridge be x meters . then , ( 150 + x ) / 30 = 25 / 2 x = 225 m . answer : b"
|
physics
|
math_qa__ZCflz3XlrqjtqK87
|
A farmer used 1,034 acres of land for beans, wheat, and corn in the ratio of 5 : 2 : 4, respectively. How many W acres were used for corn? Answers:
A) 188
B) 258
C) 376
D) 470
E) 517
|
<gadget id="calculator">1_000 * 1</gadget>
<output>1_000</output>
<gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">30 + 4</gadget>
<output>34</output>
<gadget id="calculator">1_000 + 34</gadget>
<output>1_034</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">7 + 4</gadget>
<output>11</output>
<gadget id="calculator">1_034 / 11</gadget>
<output>94</output>
<gadget id="calculator">94 * 4</gadget>
<output>376</output>
<result>C</result>
|
C
| 376 |
A farmer used 1,034 acres of land for beans, wheat, and corn in the ratio of 5 : 2 : 4, respectively. How many W acres were used for corn?
|
{
"A": "188",
"B": "258",
"C": "376",
"D": "470",
"E": "517"
}
|
multiply(divide(add(multiply(const_1000, const_1), add(multiply(const_10, const_3), 4)), add(add(5, 2), 4)), 4)
|
add(n1,n2)|multiply(const_10,const_3)|multiply(const_1,const_1000)|add(n3,#1)|add(n3,#0)|add(#3,#2)|divide(#5,#4)|multiply(n3,#6)|
|
"consider 5 x acres of land used for bean consider 2 x acres of land used for wheat consider 4 x acres of land used for corn total given is 1034 acres 11 x = 1034 x = 94 land used for corn w = 4 * 94 = 376 correct option - c"
|
other
|
math_qa__7R2p5hJavk5yiobO
|
3 models ( f , g , and h ) of cars are distributed among 3 showrooms . the number of cars in each showrooms must be equal and each model must be represented by at least one car in every showroom . there are 19 cars of model f , 17 cars of model g , and 15 cars of model h . what is the maximum number of cars of model f in any showroom ? Select the correct option.
A) 17 B) 16 C) 15 D) 14 E) 13
|
<gadget id="calculator">19 + 17</gadget>
<output>36</output>
<gadget id="calculator">36 + 15</gadget>
<output>51</output>
<gadget id="calculator">51 / 3</gadget>
<output>17</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">17 - 2</gadget>
<output>15</output>
<result>C</result>
|
C
| 15 |
3 models ( f , g , and h ) of cars are distributed among 3 showrooms . the number of cars in each showrooms must be equal and each model must be represented by at least one car in every showroom . there are 19 cars of model f , 17 cars of model g , and 15 cars of model h . what is the maximum number of cars of model f in any showroom ?
|
{
"A": "17",
"B": "16",
"C": "15",
"D": "14",
"E": "13"
}
|
subtract(divide(add(add(19, 17), 15), 3), subtract(3, const_1))
|
add(n2,n3)|subtract(n0,const_1)|add(n4,#0)|divide(#2,n0)|subtract(#3,#1)
|
the total number of cars is 51 . so each showroom has 17 cars ( since the number of cars in each showrooms should be equal 51 / 3 = 17 ) . moreover that the number of model f is maximum means that the numbers of model g and h should be minimum . since each model must be represented by at least one car in every showroom that minimum number should be 1 . so maximum number of model f is 17 - 2 = 15 . the answer is ( c )
|
general
|
math_qa__N6A2fW8bs4hTK1O9
|
A train 285 m long, running with a speed of 54 km / hr will pass a tree in
Pick: A) 19 sec B) 15 sec C) 16 sec D) 20 sec E) none
|
<gadget id="calculator">54 * 1_000</gadget>
<output>54_000</output>
<gadget id="calculator">285 / 54_000</gadget>
<output>19/3_600 = around 0.005278</output>
<gadget id="calculator">(19/3_600) * 3_600</gadget>
<output>19</output>
<result>A</result>
|
A
| 19 |
A train 285 m long, running with a speed of 54 km / hr will pass a tree in
|
{
"A": "19 sec",
"B": "15 sec",
"C": "16 sec",
"D": "20 sec",
"E": "none"
}
|
multiply(divide(285, multiply(54, const_1000)), const_3600)
|
multiply(n1,const_1000)|divide(n0,#0)|multiply(#1,const_3600)|
|
"sol . speed = ( 54 x 5 / 18 ) m / sec . = 15 m / sec . time taken = ( 285 x 1 / 15 ) sec = 19 sec answer a"
|
physics
|
math_qa__kmqTgvXfu2O3JeIq
|
A group of 55 adults and 70 children go for trekking. If there is meal for either 70 adults or 90 children and if 7 adults have their meal, find the total number of children that can be catered with the remaining food. Choose the correct answer:
A) 33 B) 54 C) 81 D) 17 E) 01
|
<gadget id="calculator">70 - 7</gadget>
<output>63</output>
<gadget id="calculator">90 / 70</gadget>
<output>9/7 = around 1.285714</output>
<gadget id="calculator">63 * (9/7)</gadget>
<output>81</output>
<result>C</result>
|
C
| 81 |
A group of 55 adults and 70 children go for trekking. If there is meal for either 70 adults or 90 children and if 7 adults have their meal, find the total number of children that can be catered with the remaining food.
|
{
"A": "33",
"B": "54",
"C": "81",
"D": "17",
"E": "01"
}
|
multiply(subtract(70, 7), divide(90, 70))
|
divide(n3,n1)|subtract(n1,n4)|multiply(#0,#1)|
|
"explanation : as there is meal for 70 adults and 7 have their meal , the meal left can be catered to 63 adults . now , 70 adults = 90 children 7 adults = 9 children therefore , 63 adults = 81 children hence , the meal can be catered to 81 children . answer : c"
|
general
|
math_qa__MQkH4UhJw0c1X8zP
|
A began business with Rs.36000 and was joined afterwards by B with Rs.54000. When did B join if the profits at the end of the year were divided in the ratio of 2:1? Choose the correct choice from the following answers
A) 1
B) 6
C) 7
D) 8
E) 2
|
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">36_000 * 12</gadget>
<output>432_000</output>
<gadget id="calculator">432_000 / 54_000</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<result>D</result>
|
D
| 8 |
A began business with Rs.36000 and was joined afterwards by B with Rs.54000. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
|
{
"A": "1",
"B": "6",
"C": "7",
"D": "8",
"E": "2"
}
|
subtract(multiply(const_4, const_3), divide(divide(multiply(36000, multiply(const_4, const_3)), 54000), 2))
|
multiply(const_3,const_4)|multiply(n0,#0)|divide(#1,n1)|divide(#2,n2)|subtract(#0,#3)|
|
"36 * 12 : 54 * x = 2 : 1 x = 4 12 - 4 = 8 answer : d"
|
other
|
math_qa__JsVPOvkRYMglGcLG
|
How many of the positive factors of 24 are not factors of 25 Choose the correct option.
A) 2 B) 3 C) 4 D) 1 E) 5
|
<gadget id="calculator">25 / 24</gadget>
<output>25/24 = around 1.041667</output>
<result>D</result>
|
D
| 1 |
How many of the positive factors of 24 are not factors of 25
|
{
"A": "2",
"B": "3",
"C": "4",
"D": "1",
"E": "5"
}
|
divide(25, 24)
|
divide(n1,n0)|
|
"factors of 24 - 1 , 2 , 3 , 4 , 6 , 8 , 12,24 factors of 25 - 1,5 , 25 comparing both , we have 1 factor of 24 which are not factors of 25 - 1 answer : d"
|
other
|
math_qa__QCozVvyxERiMVGYX
|
A man can do a piece of work in 4 days, but with the help of his daughter, he can do it in 3 days. In what time can his daughter do it alone? Choose the correct choice from the following:
A) 12
B) 28
C) 26
D) 19
E) 112
|
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">12 / 1</gadget>
<output>12</output>
<result>A</result>
|
A
| 12 |
A man can do a piece of work in 4 days, but with the help of his daughter, he can do it in 3 days. In what time can his daughter do it alone?
|
{
"A": "12",
"B": "28",
"C": "26",
"D": "19",
"E": "112"
}
|
divide(multiply(4, 3), subtract(4, 3))
|
multiply(n0,n1)|subtract(n0,n1)|divide(#0,#1)
|
explanation : daughter ’ s 1 day ’ s work = ( 1 / 3 – 1 / 4 ) = 1 / 12 daughter alone can do the work in 12 / 1 = 12 days answer : a
|
physics
|
math_qa__lJRpyEZ5rSojWU6Z
|
John had a stock of 900 books in his bookshop. He sold 75 on Monday, 50 on Tuesday, 64 on Wednesday, 78 on Thursday and 135 on Friday. What percentage of the books were not sold? Choices.
A) 50.4 % B) 23.8 % C) 66.5 % D) 34.9 % E) 55.3 %
|
<gadget id="calculator">75 + 50</gadget>
<output>125</output>
<gadget id="calculator">64 + 78</gadget>
<output>142</output>
<gadget id="calculator">125 + 142</gadget>
<output>267</output>
<gadget id="calculator">267 + 135</gadget>
<output>402</output>
<gadget id="calculator">900 - 402</gadget>
<output>498</output>
<gadget id="calculator">498 / 900</gadget>
<output>83/150 = around 0.553333</output>
<gadget id="calculator">(83/150) * 100</gadget>
<output>166/3 = around 55.333333</output>
<result>E</result>
|
E
| 55.3 |
John had a stock of 900 books in his bookshop. He sold 75 on Monday, 50 on Tuesday, 64 on Wednesday, 78 on Thursday and 135 on Friday. What percentage of the books were not sold?
|
{
"A": "50.4 %",
"B": "23.8 %",
"C": "66.5 %",
"D": "34.9 %",
"E": "55.3 %"
}
|
multiply(divide(subtract(900, add(add(add(75, 50), add(64, 78)), 135)), 900), const_100)
|
add(n1,n2)|add(n3,n4)|add(#0,#1)|add(n5,#2)|subtract(n0,#3)|divide(#4,n0)|multiply(#5,const_100)|
|
"let n be the total number of books sold . hence n = 75 + 50 + 64 + 78 + 135 = 402 let m be the books not sold m = 900 - n = 900 - 402 = 498 percentage books not sold / total number of books = 498 / 900 = 0.553 = 55.3 % correct answer e"
|
gain
|
math_qa__bWmATeesvoClHPnZ
|
the age of father 7 years ago was 5 times the age of his son . 5 years hence , father ' s age will be thrice that of his son . the ratio of their present ages is : Pick.
A) 67 : 19
B) 65 : 17
C) 61 : 19
D) 63 : 15
E) 67 : 17
|
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<gadget id="calculator">35 - 7</gadget>
<output>28</output>
<gadget id="calculator">15 + 28</gadget>
<output>43</output>
<gadget id="calculator">43 - 5</gadget>
<output>38</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">38 / 2</gadget>
<output>19</output>
<gadget id="calculator">5 * 19</gadget>
<output>95</output>
<gadget id="calculator">95 - 28</gadget>
<output>67</output>
<gadget id="calculator">67 / 19</gadget>
<output>67/19 = around 3.526316</output>
<result>A</result>
|
A
| 3.526316 |
the age of father 7 years ago was 5 times the age of his son . 5 years hence , father ' s age will be thrice that of his son . the ratio of their present ages is :
|
{
"A": "67 : 19",
"B": "65 : 17",
"C": "61 : 19",
"D": "63 : 15",
"E": "67 : 17"
}
|
divide(subtract(multiply(5, divide(subtract(add(multiply(5, const_3), subtract(multiply(7, 5), 7)), 5), subtract(5, const_3))), subtract(multiply(7, 5), 7)), divide(subtract(add(multiply(5, const_3), subtract(multiply(7, 5), 7)), 5), subtract(5, const_3)))
|
multiply(n1,const_3)|multiply(n0,n1)|subtract(n1,const_3)|subtract(#1,n0)|add(#0,#3)|subtract(#4,n1)|divide(#5,#2)|multiply(n1,#6)|subtract(#7,#3)|divide(#8,#6)
|
let the ages of father and son 7 years ago be 5 x and x years respectively . then , ( 5 x + 7 ) + 5 = 3 [ ( x + 7 ) + 5 ] 5 x + 12 = 3 x + 36 x = 12 . required ratio = ( 5 x + 7 ) : ( x + 7 ) = 67 : 19 . answer : option a
|
general
|
math_qa__03s4AGZYilX4zzDD
|
Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that measures 14 inches on a side and costs $10, and a large pizza that measures 21 inches on a side and costs $20. If two friends go to Huey's with $30 apiece, how many more square inches of pizza can they buy if they pool their money than if they each purchase pizza alone? Choose the most appropriate option.
A) 5 square inches B) 10 square inches C) 49 square inches D) 25 square inches E) 350 square inches
|
<gadget id="calculator">21 ** 2</gadget>
<output>441</output>
<gadget id="calculator">441 * 3</gadget>
<output>1_323</output>
<gadget id="calculator">14 ** 2</gadget>
<output>196</output>
<gadget id="calculator">196 + 441</gadget>
<output>637</output>
<gadget id="calculator">637 + 637</gadget>
<output>1_274</output>
<gadget id="calculator">1_323 - 1_274</gadget>
<output>49</output>
<result>C</result>
|
C
| 49 |
Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that measures 14 inches on a side and costs $10, and a large pizza that measures 21 inches on a side and costs $20. If two friends go to Huey's with $30 apiece, how many more square inches of pizza can they buy if they pool their money than if they each purchase pizza alone?
|
{
"A": "5 square inches",
"B": "10 square inches",
"C": "49 square inches",
"D": "25 square inches",
"E": "350 square inches"
}
|
subtract(multiply(power(21, const_2), const_3), add(add(power(14, const_2), power(21, const_2)), add(power(14, const_2), power(21, const_2))))
|
power(n2,const_2)|power(n0,const_2)|add(#1,#0)|multiply(#0,const_3)|add(#2,#2)|subtract(#3,#4)|
|
"in the first case each can buy one pizza of $ 10 and one pizza of $ 20 . in square inches that would be ( 14 * 14 = 196 ) for the small pizza and ( 21 * 21 = 441 ) for the large pizza . in total sq inches that would be ( 196 + 441 ) * 2 = 1274 sq inches . in the second case if they pool their money together they can buy 3 large pizzas . in terms of square inches that would be 3 * 441 = 1323 sq inches . hence , the difference is 49 square inches more ( 1323 - 1274 ) . the correct answer is c"
|
geometry
|
math_qa__Wjf6aMHUAzLHZ33o
|
If the LCM of A and B is 72 and their HCF is 6, what is the product of A & B? Select.
A) 432 B) 433 C) 434 D) 435 E) 436
|
<gadget id="calculator">6 * 72</gadget>
<output>432</output>
<result>A</result>
|
A
| 432 |
If the LCM of A and B is 72 and their HCF is 6, what is the product of A & B?
|
{
"A": "432",
"B": "433",
"C": "434",
"D": "435",
"E": "436"
}
|
multiply(6, 72)
|
multiply(n0,n1)
|
the most important property of lcm ( the least common multiple ) and gcd ( the greatest common divisors ) is : for any positive integers x and y , x ∗ y = gcd ( x , y ) ∗ lcm ( x , y ) so ab = 72 * 6 = 432 . answer : a
|
physics
|
math_qa__FrCKAIxg6Agdys6O
|
In a 120 meters race A beats B by 56 m or 7 seconds. A's time over the course is: Choose the correct choice from the following:
A) 22 seconds
B) 12 seconds
C) 10 seconds
D) 8 seconds
E) 28 seconds
|
<gadget id="calculator">7 / 56</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 120</gadget>
<output>15</output>
<gadget id="calculator">15 - 7</gadget>
<output>8</output>
<result>D</result>
|
D
| 8 |
In a 120 meters race A beats B by 56 m or 7 seconds. A's time over the course is:
|
{
"A": "22 seconds",
"B": "12 seconds",
"C": "10 seconds",
"D": "8 seconds",
"E": "28 seconds"
}
|
subtract(multiply(divide(7, 56), 120), 7)
|
divide(n2,n1)|multiply(n0,#0)|subtract(#1,n2)|
|
"b runs 56 m in 7 sec . = > b runs 120 m in 7 / 56 * 120 = 15 seconds since a beats b by 7 seconds , a runs 120 m in ( 15 - 7 ) = 8 seconds hence , a ' s time over the course = 8 seconds answer : d"
|
physics
|
math_qa__dR8JInQ4yhaU9VVa
|
The average of 20 number is zero of them at the most, how many may be greater than zero ? Pick.
A) 0 B) 1 C) 10 D) 19 E) 20
|
<gadget id="calculator">20 - 1</gadget>
<output>19</output>
<result>D</result>
|
D
| 19 |
The average of 20 number is zero of them at the most, how many may be greater than zero ?
|
{
"A": "0",
"B": "1",
"C": "10",
"D": "19",
"E": "20"
}
|
subtract(20, const_1)
|
subtract(n0,const_1)
|
solution average of 20 numbers = 0 . ∴ sum of 20 numbers = ( 0 × 20 ) = 0 . it is quite possible that 19 of these number may be positive and if their sum is a , then 20 th number is ( - a ) . answer d
|
general
|
math_qa__HiCvPYYSZ2ap6HFq
|
Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1792? Choose the correct answer:
A) 1600 B) 2777 C) 2889 D) 27670 E) 2771
|
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">12 / 5</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 5</gadget>
<output>12</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) + 1</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">1_792 / (28/25)</gadget>
<output>1_600</output>
<result>A</result>
|
A
| 1,600 |
Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1792?
|
{
"A": "1600",
"B": "2777",
"C": "2889",
"D": "27670",
"E": "2771"
}
|
divide(1792, add(divide(multiply(divide(add(multiply(2, 5), 2), 5), 5), const_100), const_1))
|
multiply(n1,n3)|add(n1,#0)|divide(#1,n3)|multiply(n0,#2)|divide(#3,const_100)|add(#4,const_1)|divide(n4,#5)|
|
"1792 = p [ 1 + ( 5 * 12 / 5 ) / 100 ] p = 1600 . answer : a"
|
general
|
math_qa__CqoKpPjhLGVI5S64
|
There are 200 female managers in a certain company. Find the total number R of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers. Choose the correct option
A) r = 300
B) r = 400
C) r = 500
D) 600
E) none of these
|
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">200 / (2/5)</gadget>
<output>500</output>
<result>C</result>
|
C
| 500 |
There are 200 female managers in a certain company. Find the total number R of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers.
|
{
"A": "r = 300",
"B": "r = 400",
"C": "r = 500",
"D": "600",
"E": "none of these"
}
|
divide(200, divide(2, 5))
|
divide(n1,n2)|divide(n0,#0)|
|
"{ managers } = { female managers } + { male managers } ; we are told that the total number of managers in the company is 2 / 5 of all the employees , thus { managers } = 2 / 5 ( m + f ) , where m and f are number of female and male employees , respectively . also , we know that 2 / 5 of all male employees are managers : { male managers } = 2 / 5 * mas well as there are total of 200 female managers : { female managers } = 200 ; thus : 2 / 5 ( m + f ) = 200 + 2 / 5 * m - - > f = 500 . answer : c ."
|
general
|
math_qa__UqIl26PokNj7x7Mz
|
In a certain boys camp, 20% of the total boys are from school A and 30% of those study science. If there are 49 boys in the camp that are from school A but do not study science then what is the total number of boys in the camp? Pick:
A) 70
B) 245
C) 150
D) 35
E) 350
|
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(7/10) * (1/5)</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">49 / (7/50)</gadget>
<output>350</output>
<result>E</result>
|
E
| 350 |
In a certain boys camp, 20% of the total boys are from school A and 30% of those study science. If there are 49 boys in the camp that are from school A but do not study science then what is the total number of boys in the camp?
|
{
"A": "70",
"B": "245",
"C": "150",
"D": "35",
"E": "350"
}
|
divide(49, multiply(divide(subtract(const_100, 30), const_100), divide(20, const_100)))
|
divide(n0,const_100)|subtract(const_100,n1)|divide(#1,const_100)|multiply(#2,#0)|divide(n2,#3)|
|
"since 30 % of the boys from school a study science , then 70 % of the boys from school a do not study science and since 20 % of the total number of boys are from school a , then 0.2 * 0.7 = 0.14 , or 14 % of the boys in the camp are from school a and do not study science . we are told that this number equals to 49 , so 0.14 * { total } = 49 - - > { total } = 350 . answer : e ."
|
gain
|
math_qa__k5gHb2VXcEVVYxhE
|
How many litres of pure acid are there in 8 litres of a 20% solution?
Select the correct option
A) 2 litres B) 1.4 litres C) 1 litres D) 1.6 litres E) none of these
|
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 8</gadget>
<output>8/5 = around 1.6</output>
<result>D</result>
|
D
| 1.6 |
How many litres of pure acid are there in 8 litres of a 20% solution?
|
{
"A": "2 litres",
"B": "1.4 litres",
"C": "1 litres",
"D": "1.6 litres",
"E": "none of these"
}
|
multiply(divide(20, const_100), 8)
|
divide(n1,const_100)|multiply(n0,#0)|
|
"explanation : quantity of pure acid = 8 × ( 20 / 100 ) = 1.6 answer : option d"
|
gain
|
math_qa__ovwBRkgEsYfoS15a
|
A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 500 m long? Choose the most appropriate option.
A) 266 sec B) 170 sec C) 776 sec D) 166 sec E) 997 sec
|
<gadget id="calculator">1_200 + 500</gadget>
<output>1_700</output>
<gadget id="calculator">1_200 / 120</gadget>
<output>10</output>
<gadget id="calculator">1_700 / 10</gadget>
<output>170</output>
<result>B</result>
|
B
| 170 |
A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 500 m long?
|
{
"A": "266 sec",
"B": "170 sec",
"C": "776 sec",
"D": "166 sec",
"E": "997 sec"
}
|
divide(add(1200, 500), divide(1200, 120))
|
add(n0,n2)|divide(n0,n1)|divide(#0,#1)|
|
"l = s * t s = 1200 / 120 s = 10 m / sec . total length ( d ) = 1700 m t = d / s t = 1700 / 10 t = 170 sec answer : b"
|
physics
|
math_qa__61uows1O0PjCoxWX
|
What is the least number which when divided by 6, 7, 9 and 18 leaves remainder 4 in each care? Choose one
A) 130 B) 140 C) 136 D) 156 E) 166
|
<gadget id="calculator">lcm(6, 7)</gadget>
<output>42</output>
<gadget id="calculator">lcm(9, 18)</gadget>
<output>18</output>
<gadget id="calculator">lcm(42, 18)</gadget>
<output>126</output>
<gadget id="calculator">126 + 4</gadget>
<output>130</output>
<result>A</result>
|
A
| 130 |
What is the least number which when divided by 6, 7, 9 and 18 leaves remainder 4 in each care?
|
{
"A": "130",
"B": "140",
"C": "136",
"D": "156",
"E": "166"
}
|
add(lcm(lcm(6, 7), lcm(9, 18)), 4)
|
lcm(n0,n1)|lcm(n2,n3)|lcm(#0,#1)|add(n4,#2)|
|
"explanation : lcm of 6 , 7 , 9 and 18 is 126 required number = 126 + 4 = 130 answer : option a"
|
general
|
math_qa__rey4dFfC0twtFmSe
|
The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 50% profit?
Select the correct option: A) 277 B) 960 C) 277 D) 266 E) 121
|
<gadget id="calculator">832 - 448</gadget>
<output>384</output>
<gadget id="calculator">384 / 2</gadget>
<output>192</output>
<gadget id="calculator">832 - 192</gadget>
<output>640</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">640 * (3/2)</gadget>
<output>960</output>
<result>B</result>
|
B
| 960 |
The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 50% profit?
|
{
"A": "277",
"B": "960",
"C": "277",
"D": "266",
"E": "121"
}
|
multiply(subtract(832, divide(subtract(832, 448), const_2)), add(const_1, divide(50, const_100)))
|
divide(n2,const_100)|subtract(n0,n1)|add(#0,const_1)|divide(#1,const_2)|subtract(n0,#3)|multiply(#2,#4)|
|
"let c . p . = rs . x . then , 832 - x = x - 448 2 x = 1280 = > x = 640 required s . p . = 150 % of rs . 640 = 150 / 100 * 640 = rs . 960 . answer : b"
|
gain
|
math_qa__EEC6EcWKVLCJG58C
|
Roja and Pooja start moving in the opposite directions from a pole. They are moving at the speeds of 5 km/hr and 3 km/hr respectively. After 4 hours what will be the distance between them? Choose the correct choice from the following options
A) 32 km B) 20 km C) 65 km D) 18 km E) 16 km
|
<gadget id="calculator">5 + 3</gadget>
<output>8</output>
<gadget id="calculator">8 * 4</gadget>
<output>32</output>
<result>A</result>
|
A
| 32 |
Roja and Pooja start moving in the opposite directions from a pole. They are moving at the speeds of 5 km/hr and 3 km/hr respectively. After 4 hours what will be the distance between them?
|
{
"A": "32 km",
"B": "20 km",
"C": "65 km",
"D": "18 km",
"E": "16 km"
}
|
multiply(add(5, 3), 4)
|
add(n0,n1)|multiply(n2,#0)|
|
"distance = relative speed * time = ( 5 + 3 ) * 4 = 32 km [ they are travelling in the opposite direction , relative speed = sum of the speeds ] . answer : a"
|
physics
|
math_qa__38nQlF3Z3i0M938N
|
The number which exceeds 16% of it by 105 is : Options: A) 125 B) 52 C) 58 D) 60 E) 62
|
<gadget id="calculator">105 * 100</gadget>
<output>10_500</output>
<gadget id="calculator">100 - 16</gadget>
<output>84</output>
<gadget id="calculator">10_500 / 84</gadget>
<output>125</output>
<result>A</result>
|
A
| 125 |
The number which exceeds 16% of it by 105 is :
|
{
"A": "125",
"B": "52",
"C": "58",
"D": "60",
"E": "62"
}
|
divide(multiply(105, const_100), subtract(const_100, 16))
|
multiply(n1,const_100)|subtract(const_100,n0)|divide(#0,#1)
|
solution solution let the number be x . x - 16 % of x = 105 x - 16 / 100 x = 105 x - 4 / 25 x = 105 21 / 25 x = 105 x = ( 105 x 25 / 21 ) = 125 answer a
|
gain
|
math_qa__JHyauRoaH1eXouIC
|
Sachin is younger than Rahul by 7 years. If the ratio of their ages is 6:9, find the age of Sachin
Choose the correct choice from the following:
A) 24.5
B) 14
C) 24.21
D) 27
E) 25
|
<gadget id="calculator">9 - 6</gadget>
<output>3</output>
<gadget id="calculator">7 / 3</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">(7/3) * 6</gadget>
<output>14</output>
<result>B</result>
|
B
| 14 |
Sachin is younger than Rahul by 7 years. If the ratio of their ages is 6:9, find the age of Sachin
|
{
"A": "24.5",
"B": "14",
"C": "24.21",
"D": "27",
"E": "25"
}
|
multiply(divide(7, subtract(9, 6)), 6)
|
subtract(n2,n1)|divide(n0,#0)|multiply(n1,#1)|
|
"explanation : if rahul age is x , then sachin age is x - 7 , so , 9 x - 63 = 6 x 3 x = 63 x = 21 so sachin age is 21 - 7 = 14 answer : b ) 14"
|
other
|
math_qa__7vOaR0haNP2Whq9x
|
A man has some hens and cows. If the number of heads be 44 and the number of feet equals 140, then the number of hens will be: Choose one:
A) 22 B) 23 C) 18 D) 26 E) 28
|
<gadget id="calculator">44 * 4</gadget>
<output>176</output>
<gadget id="calculator">176 - 140</gadget>
<output>36</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<result>C</result>
|
C
| 18 |
A man has some hens and cows. If the number of heads be 44 and the number of feet equals 140, then the number of hens will be:
|
{
"A": "22",
"B": "23",
"C": "18",
"D": "26",
"E": "28"
}
|
divide(subtract(multiply(44, const_4), 140), const_2)
|
multiply(n0,const_4)|subtract(#0,n1)|divide(#1,const_2)|
|
"let hens be x and cows be y now , feet : x * 2 + y * 4 = 140 heads : x * 1 + y * 1 = 44 implies , 2 x + 4 y = 140 and x + y = 44 solving these two equations , we get x = 18 and y = 26 therefore , hens are 26 . answer : c"
|
general
|
math_qa__SaFabBwZiwF8FWgl
|
in the x - y plane , there are 4 points ( 00 ) , ( 04 ) , ( 54 ) , and ( 50 ) . if these 4 points makes a rectangle , what is the probability that x + y < 4 ?
Choose the most appropriate option:
A) 2 / 3 B) 2 / 5 C) 3 / 4 D) 3 / 7 E) 5 / 8
|
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<gadget id="calculator">50 / 10</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<result>B</result>
|
B
| 0.4 |
in the x - y plane , there are 4 points ( 00 ) , ( 04 ) , ( 54 ) , and ( 50 ) . if these 4 points makes a rectangle , what is the probability that x + y < 4 ?
|
{
"A": "2 / 3",
"B": "2 / 5",
"C": "3 / 4",
"D": "3 / 7",
"E": "5 / 8"
}
|
divide(divide(4, const_2), divide(50, const_10))
|
divide(n0,const_2)|divide(n4,const_10)|divide(#0,#1)
|
the line y = - x + 4 intersects the rectangle and these three points of intersection ( 0,0 ) , ( 0,4 ) and ( 4,0 ) form a triangle . the points below the line y = - x + 4 satisfy x + y < 4 . the area of this triangle is ( 1 / 2 ) ( 4 ) ( 4 ) = 8 the area of the rectangle is 20 . p ( x + y < 4 ) = 8 / 20 = 2 / 5 the answer is b .
|
general
|
math_qa__capMpPpI8aHItneY
|
The probability of two events A and B are0.25 and 0.35 respectively. The probability that both A and B occur is 0.15. The probability that neither A nor B occur is _________ Choose the correct choice:
A) 0.55 B) 0.4 C) 0.5 D) 0.05 E) 0.6
|
<gadget id="calculator">0.25 + 0.35</gadget>
<output>0.6</output>
<gadget id="calculator">0.6 - 0.15</gadget>
<output>0.45</output>
<gadget id="calculator">1 - 0.45</gadget>
<output>0.55</output>
<result>A</result>
|
A
| 0.55 |
The probability of two events A and B are0.25 and 0.35 respectively. The probability that both A and B occur is 0.15. The probability that neither A nor B occur is _________
|
{
"A": "0.55",
"B": "0.4",
"C": "0.5",
"D": "0.05",
"E": "0.6"
}
|
subtract(const_1, subtract(add(0.25, 0.35), 0.15))
|
add(n0,n1)|subtract(#0,n2)|subtract(const_1,#1)|
|
"we are apply that formula . . . . . . . . . . . . . . p ( aorb ) = p ( a ) + p ( b ) - p ( a and b ) = . 25 + . 35 - . 15 = . 45 but the probability of neither a nor b = 1 - . 45 = 0.55 answer : a"
|
other
|
math_qa__pcshkX8Ge7e1KK2C
|
In a certificate by mistake a candidate gave his height as 25% more than actual height. In the interview panel, he clarified that his height was 5 feet 8 nches. Find the % correction made by the candidate from his stated height to his actual height?
Options.
A) 10 B) 20 C) 30 D) 17 E) 50
|
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + (1/4)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">25 + (1/2)</gadget>
<output>51/2 = around 25.5</output>
<gadget id="calculator">(51/2) - 5</gadget>
<output>41/2 = around 20.5</output>
<gadget id="calculator">100 + (41/2)</gadget>
<output>241/2 = around 120.5</output>
<gadget id="calculator">(41/2) / (241/2)</gadget>
<output>41/241 = around 0.170124</output>
<gadget id="calculator">(41/241) * 100</gadget>
<output>4_100/241 = around 17.012448</output>
<result>D</result>
|
D
| 17 |
In a certificate by mistake a candidate gave his height as 25% more than actual height. In the interview panel, he clarified that his height was 5 feet 8 nches. Find the % correction made by the candidate from his stated height to his actual height?
|
{
"A": "10",
"B": "20",
"C": "30",
"D": "17",
"E": "50"
}
|
multiply(divide(subtract(add(25, add(const_0_25, const_0_25)), 5), add(const_100, subtract(add(25, add(const_0_25, const_0_25)), 5))), const_100)
|
add(const_0_25,const_0_25)|add(n0,#0)|subtract(#1,n1)|add(#2,const_100)|divide(#2,#3)|multiply(#4,const_100)|
|
"his height was = 5 feet 8 inch = 8 + 60 = 68 inch . required % correction = 68 * ( 1.25 - 1 ) = 17 d"
|
gain
|
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