| This is an interactive problem! | |
| Timofey is writing a competition called Capture the Flag (or CTF for short). He has one task left, which involves hacking a security system. The entire system is based on polynomial hashes$^{\text{∗}}$. | |
| Timofey can input a string consisting of lowercase Latin letters into the system, and the system will return its polynomial hash. To hack the system, Timofey needs to find the polynomial hash parameters ($p$ and $m$) that the system uses. | |
| Timofey doesn't have much time left, so he will only be able to make $3$ queries. Help him solve the task. | |
| $^{\text{∗}}$ The polynomial hash of a string $s$, consisting of lowercase Latin letters of length $n$, based on $p$ and modulo $m$ is $(\mathrm{ord}(s_1) \cdot p ^ 0 + \mathrm{ord}(s_2) \cdot p ^ 1 + \mathrm{ord}(s_3) \cdot p ^ 2 + \ldots + \mathrm{ord}(s_n) \cdot p ^ {n - 1}) \bmod m$. Where $s_i$ denotes the $i$-th character of the string $s$, $\mathrm{ord}(\mathrm{chr})$ denotes the ordinal number of the character $\mathrm{chr}$ in the English alphabet, and $x \bmod m$ is the remainder of $x$ when divided by $m$. | |
| Each test consists of multiple test cases. The first line contains an integer $t$ ($1 \leq t \leq 10^3$) — the number of test cases. | |
| It is guaranteed that the $p$ and $m$ used by the system satisfy the conditions: $26 < p \leq 50$ and $p + 1 < m \leq 2 \cdot 10^9$. | |
| Answer for the first query is $(ord(a) \cdot 31^0 + ord(a) \cdot 31^1) \mod 59 = (1 + 1 \cdot 31) \mod 59 = 32$. | |
| Answer for the second query is $(ord(y) \cdot 31^0 + ord(b) \cdot 31^1) \mod 59 = (25 + 2 \cdot 31) \mod 59 = 28$. |