text: Minimum count of increment of K size subarrays required to form a given Array | C ++ implementation to find the minimum number of operations required to change an array of all zeros such that every element is greater than the given array ; Function to find the minimum number of operations required to change all the array of zeros such that every element is greater than the given array ; Declaring the difference array of size N ; Number of operations ; First update the D [ i ] value with the previous value ; The index i has to be incremented ; We have to perform ( b [ i ] - d [ i ] ) operations more ; Increment the range i to i + k by need ; Check if i + k is valid index ; Driver Code ; Function Call
code: #include <bits/stdc++.h> NEW_LINE using namespace std ; int find_minimum_operations ( int n , int b [ ] , int k ) { int d [ n + 1 ] = { 0 } ; int operations = 0 , need ; for ( int i = 0 ; i < n ; i ++ ) { if ( i > 0 ) { d [ i ] += d [ i - 1 ] ; } if ( b [ i ] > d [ i ] ) { operations += b [ i ] - d [ i ] ; need = b [ i ] - d [ i ] ; d [ i ] += need ; if ( i + k <= n ) { d [ i + k ] -= need ; } } } cout << operations << endl ; } int main ( ) { int n = 5 ; int b [ ] = { 1 , 2 , 3 , 4 , 5 } ; int k = 2 ; find_minimum_operations ( n , b , k ) ; return 0 ; }