text: If letter is ' I ' Calculate number of next consecutive D 's  available
code: j = i + 1 NEW_LINE while j < len ( arr ) and arr [ j ] == " D " : NEW_LINE INDENT noOfNextD += 1 NEW_LINE j += 1 NEW_LINE DEDENT if i == 0 : NEW_LINE INDENT curr_max = noOfNextD + 2 NEW_LINE last_entry += 1 NEW_LINE DEDENT