text: The lines are parallel . This is simplified by returning a pair of ( 10.0 ) * * 19
code: return [ ( 10.0 ) ** 19 , ( 10.0 ) ** 19 ] NEW_LINE else : NEW_LINE x = ( b2 * c1 - b1 * c2 ) // determinant NEW_LINE y = ( a1 * c2 - a2 * c1 ) // determinant NEW_LINE return [ x , y ] NEW_LINE def findCircumCenter ( P , Q , R ) : NEW_LINE