text: noOfWays [ i ] will store count for value i . 3 extra values are to take care of corner case n = 0
code: noOfWays = [ 0 ] * ( n + 3 ) NEW_LINE noOfWays [ 0 ] = 1 NEW_LINE noOfWays [ 1 ] = 1 NEW_LINE noOfWays [ 2 ] = 1 + 1 NEW_LINE