text: If the frequency of current character is even then increment it by x
code: if ( freq [ str [ i ] . charCodeAt ( 0 ) - ' ' . charCodeAt ( 0 ) ] % 2 == 0 ) { var pos = ( str [ i ] . charCodeAt ( 0 ) - ' ' . charCodeAt ( 0 ) + x ) % MAX ; str [ i ] = String . fromCharCode ( pos + ' ' . charCodeAt ( 0 ) ) ; }