text: A program to check if a binary tree is BST or not |  ; false if left is > than node ; false if right is < than node ; false if , recursively , the left or right is not a BST ; passing all that , it 's a BST
code: int isBST ( struct node * node ) { if ( node == NULL ) return 1 ; if ( node -> left != NULL && node -> left -> data > node -> data ) return 0 ; if ( node -> right != NULL && node -> right -> data < node -> data ) return 0 ; if ( ! isBST ( node -> left ) || ! isBST ( node -> right ) ) return 0 ; return 1 ; }