text: We can also use binary search here as digits after index are sorted in increasing order . Find the biggest digit in the right of arr [ index ] which is smaller than arr [ index ]
code: int smallGreatDgt = - 1 ; for ( int i = len - 1 ; i > index ; i -- ) { if ( str . charAt ( i ) < str . charAt ( index ) ) { if ( smallGreatDgt == - 1 ) { smallGreatDgt = i ; } else if ( str . charAt ( i ) >= str . charAt ( smallGreatDgt ) ) { smallGreatDgt = i ; } } }