text: Function to return no of ways to build a binary string of length N such that 0 s always occur in groups of size K
code: static int noOfBinaryStrings ( int N , int k ) { int [ ] dp = new int [ 100002 ] ; for ( int i = 1 ; i <= k - 1 ; i ++ ) { dp [ i ] = 1 ; } dp [ k ] = 2 ; for ( int i = k + 1 ; i <= N ; i ++ ) { dp [ i ] = ( dp [ i - 1 ] + dp [ i - k ] ) % mod ; } return dp [ N ] ; }