text: Sum of elements in an array having prime frequency | Java program to find sum of elements in an array having prime frequency ; Function to create Sieve to check primes ; False here indicates that it is not prime ; If prime [ p ] is not changed , then it is a prime ; Update all multiples of p , set them to non - prime ; Function to return the sum of elements in an array having prime frequency ; Map is used to store element frequencies ; Traverse the map ; Count the number of elements having prime frequencies ; Driver code
code: import java . util . * ; class GFG { static void SieveOfEratosthenes ( boolean prime [ ] , int p_size ) { prime [ 0 ] = false ; prime [ 1 ] = false ; for ( int p = 2 ; p * p <= p_size ; p ++ ) { if ( prime [ p ] ) { for ( int i = p * 2 ; i <= p_size ; i += p ) prime [ i ] = false ; } } } static int sumOfElements ( int arr [ ] , int n ) { boolean prime [ ] = new boolean [ n + 1 ] ; Arrays . fill ( prime , true ) ; SieveOfEratosthenes ( prime , n + 1 ) ; int i , j ; HashMap < Integer , Integer > m = new HashMap < > ( ) ; for ( i = 0 ; i < n ; i ++ ) { if ( m . containsKey ( arr [ i ] ) ) m . put ( arr [ i ] , m . get ( arr [ i ] ) + 1 ) ; else m . put ( arr [ i ] , 1 ) ; } int sum = 0 ; for ( Map . Entry < Integer , Integer > entry : m . entrySet ( ) ) { int key = entry . getKey ( ) ; int value = entry . getValue ( ) ; if ( prime [ value ] ) { sum += ( key ) ; } } return sum ; } public static void main ( String args [ ] ) { int arr [ ] = { 5 , 4 , 6 , 5 , 4 , 6 } ; int n = arr . length ; System . out . println ( sumOfElements ( arr , n ) ) ; } }