text: Find k ordered pairs in array with minimum difference d | Java implementation of the approach ; Function to find the required pairs ; There has to be atleast 2 * k elements ; To store the pairs ; Sort the given array ; For every possible pair ; If the current pair is valid ; Insert it into the pair vector ; If k pairs are not possible ; Print the pairs ; Driver code
code: import java . util . * ; class GFG { static class pair { int first , second ; public pair ( int first , int second ) { this . first = first ; this . second = second ; } } static void findPairs ( int arr [ ] , int n , int k , int d ) { if ( n < 2 * k ) { System . out . print ( - 1 ) ; return ; } Vector < pair > pairs = new Vector < pair > ( ) ; Arrays . sort ( arr ) ; for ( int i = 0 ; i < k ; i ++ ) { if ( arr [ n - k + i ] - arr [ i ] >= d ) { pair p = new pair ( arr [ i ] , arr [ n - k + i ] ) ; pairs . add ( p ) ; } } if ( pairs . size ( ) < k ) { System . out . print ( - 1 ) ; return ; } for ( pair v : pairs ) { System . out . println ( " ( " + v . first + " , ▁ " + v . second + " ) " ) ; } } public static void main ( String [ ] args ) { int arr [ ] = { 4 , 6 , 10 , 23 , 14 , 7 , 2 , 20 , 9 } ; int n = arr . length ; int k = 4 , d = 3 ; findPairs ( arr , n , k , d ) ; } }