text: Count of cyclic permutations having XOR with other binary string as 0 | Java program to find bitwise XOR between binary string A and all the cyclic permutations of binary string B ; Implementation of Z - algorithm for linear time pattern searching ; Function to get the count of the cyclic permutations of b that given 0 when XORed with a ; concatenate b with b ; new b now contains all the cyclic permutations of old b as it 's sub-strings ; concatenate pattern with text ; Fill z array used in Z algorithm ; pattern occurs at index i since z value of i equals pattern length ; Driver Code
code: public class GFG { static void compute_z ( String s , int z [ ] ) { int l = 0 , r = 0 ; int n = s . length ( ) ; for ( int i = 1 ; i <= n - 1 ; i ++ ) { if ( i > r ) { l = i ; r = i ; while ( r < n && s . charAt ( r - l ) == s . charAt ( r ) ) r ++ ; z [ i ] = r - l ; r -- ; } else { int k = i - l ; if ( z [ k ] < r - i + 1 ) { z [ i ] = z [ k ] ; } else { l = i ; while ( r < n && s . charAt ( r - l ) == s . charAt ( r ) ) r ++ ; z [ i ] = r - l ; r -- ; } } } } static int countPermutation ( String a , String b ) { b = b + b ; b = b . substring ( 0 , b . length ( ) - 1 ) ; int ans = 0 ; String s = a + " $ " + b ; int n = s . length ( ) ; int z [ ] = new int [ n ] ; compute_z ( s , z ) ; for ( int i = 1 ; i <= n - 1 ; i ++ ) { if ( z [ i ] == a . length ( ) ) ans ++ ; } return ans ; } public static void main ( String [ ] args ) { String a = "101" ; String b = "101" ; System . out . println ( countPermutation ( a , b ) ) ; } }