text: Generate number with given operation and check if it is palindrome | Java implementation of the approach ; Function that returns true if str is a palindrome ; Function that returns true if the generated string is a palindrome ; sub contains N as a string ; Calculate the sum of the digits ; Repeat the substring until the length of the resultant string < sum ; If length of the resultant string exceeded sum then take substring from 0 to sum - 1 ; If the generated string is a palindrome ; Driver code
code: class GFG { static boolean isPalindrome ( String str ) { int len = str . length ( ) ; for ( int i = 0 ; i < len / 2 ; i ++ ) { if ( str . charAt ( i ) != str . charAt ( len - 1 - i ) ) return false ; } return true ; } static boolean createStringAndCheckPalindrome ( int N ) { String sub = " " + N , res_str = " " ; int sum = 0 ; while ( N > 0 ) { int digit = N % 10 ; sum += digit ; N = N / 10 ; } while ( res_str . length ( ) < sum ) res_str += sub ; if ( res_str . length ( ) > sum ) res_str = res_str . substring ( 0 , sum ) ; if ( isPalindrome ( res_str ) ) return true ; return false ; } public static void main ( String args [ ] ) { int N = 10101 ; if ( createStringAndCheckPalindrome ( N ) ) System . out . println ( " Yes " ) ; else System . out . println ( " No " ) ; } }