text: Count pairs with given sum | Set 2 | Java implementation of the approach ; Function to return the count of pairs from arr [ ] with the given sum ; To store the count of pairs ; Sort the given array ; Take two pointers ; If sum is greater ; If sum is lesser ; If sum is equal ; Find the frequency of arr [ i ] ; Find the frequency of arr [ j ] ; If arr [ i ] and arr [ j ] are same then remove the extra number counted ; Return the required answer ; Driver code
code: import java . util . Arrays ; import java . io . * ; class GFG { static int pairs_count ( int arr [ ] , int n , int sum ) { int ans = 0 ; Arrays . sort ( arr ) ; int i = 0 , j = n - 1 ; while ( i < j ) { if ( arr [ i ] + arr [ j ] < sum ) i ++ ; else if ( arr [ i ] + arr [ j ] > sum ) j -- ; else { int x = arr [ i ] , xx = i ; while ( ( i < j ) && ( arr [ i ] == x ) ) i ++ ; int y = arr [ j ] , yy = j ; while ( ( j >= i ) && ( arr [ j ] == y ) ) j -- ; if ( x == y ) { int temp = i - xx + yy - j - 1 ; ans += ( temp * ( temp + 1 ) ) / 2 ; } else ans += ( i - xx ) * ( yy - j ) ; } } return ans ; } public static void main ( String [ ] args ) { int arr [ ] = { 1 , 5 , 7 , 5 , - 1 } ; int n = arr . length ; int sum = 6 ; System . out . println ( pairs_count ( arr , n , sum ) ) ; } }