text: Divide a number into two parts such that sum of digits is maximum | Java implementation of above approach Returns sum of digits of x ; Returns sum of digits of x ; Returns closest number to x in terms of 9 's. ; Driver code
code: import java . util . * ; import java . lang . * ; import java . io . * ; class GFG { static int sumOfDigitsSingle ( int x ) { int ans = 0 ; while ( x != 0 ) { ans += x % 10 ; x /= 10 ; } return ans ; } static int closest ( int x ) { int ans = 0 ; while ( ans * 10 + 9 <= x ) ans = ans * 10 + 9 ; return ans ; } static int sumOfDigitsTwoParts ( int N ) { int A = closest ( N ) ; return sumOfDigitsSingle ( A ) + sumOfDigitsSingle ( N - A ) ; } public static void main ( String args [ ] ) { int N = 35 ; System . out . print ( sumOfDigitsTwoParts ( N ) ) ; } }