text: Find the person who will finish last | C # program for the above approach ; Function to find the person who will finish last ; To keep track of rows and columns having 1 ; Available rows and columns ; Minimum number of choices we have ; If number of choices are odd ; P1 will finish last ; Otherwise , P2 will finish last ; Driver code
code: using System ; using System . Collections . Generic ; class GFG { static void findLast ( int [ , ] mat ) { int m = 3 ; int n = 3 ; HashSet < int > rows = new HashSet < int > ( ) ; HashSet < int > cols = new HashSet < int > ( ) ; for ( int i = 0 ; i < m ; i ++ ) { for ( int j = 0 ; j < n ; j ++ ) { if ( ( mat [ i , j ] > 0 ) ) { rows . Add ( i ) ; cols . Add ( j ) ; } } } int avRows = m - rows . Count ; int avCols = n - cols . Count ; int choices = Math . Min ( avRows , avCols ) ; if ( ( choices & 1 ) != 0 ) Console . WriteLine ( " P1" ) ; else Console . WriteLine ( " P2" ) ; } static public void Main ( ) { int [ , ] mat = { { 1 , 0 , 0 } , { 0 , 0 , 0 } , { 0 , 0 , 1 } } ; findLast ( mat ) ; } }