text: Maximum count of common divisors of A and B such that all are co | C # implementation of the above approach ; Function to return the count of common factors of a and b such that all the elements are co - prime to one another ; GCD of a and b ; Include 1 initially ; Find all the prime factors of the gcd ; If gcd is prime ; Return the required answer ; Driver code
code: using System ; class GFG { static int gcd ( int a , int b ) { if ( b == 0 ) return a ; return gcd ( b , a % b ) ; } static int maxCommonFactors ( int a , int b ) { int __gcd = gcd ( a , b ) ; int ans = 1 ; for ( int i = 2 ; i * i <= __gcd ; i ++ ) { if ( __gcd % i == 0 ) { ans ++ ; while ( __gcd % i == 0 ) __gcd /= i ; } } if ( __gcd != 1 ) ans ++ ; return ans ; } public static void Main ( String [ ] args ) { int a = 12 , b = 18 ; Console . WriteLine ( maxCommonFactors ( a , b ) ) ; } }