text: encoded [ i + j ] = ' e ' , ' e ' - ' a ' = 5 , 5 + 26 = 31 , ' e ' has 31 st position in char_set .
code: else if ( encoded [ i + j ] >= ' a ' && encoded [ i + j ] <= ' z ' ) num = num | ( encoded [ i + j ] - ' a ' + 26 ) ;