text: The expression " one ▁ & ▁ arr [ i ] " gives the bits that are there in both ' ones ' and new element from arr [ ] . We add these bits to ' twos ' using bitwise OR Value of ' twos ' will be set as 0 , 3 , 3 and 1 after 1 st , 2 nd , 3 rd and 4 th iterations respectively
code: twos = twos | ( ones & arr [ i ] ) ;