text: Queries to find longest subsequence having no similar adjacent elements with updates | Function to find the length of the longest subsequence such that no two adjacent elements are equal ; Replace element at index x with y ; Since x is 1 - indexed , decrement x by 1 ; Keep track of number of elements in subsequence ; If previous element is not same as current element ; Print the desired count ; Driver Code ; Function Call
code: def longestSubsequence ( N , Q , arr , Queries ) : NEW_LINE INDENT for i in range ( Q ) : NEW_LINE INDENT x = Queries [ i ] [ 0 ] NEW_LINE y = Queries [ i ] [ 1 ] NEW_LINE arr [ x - 1 ] = y NEW_LINE count = 1 NEW_LINE for j in range ( 1 , N ) : NEW_LINE INDENT if ( arr [ j ] != arr [ j - 1 ] ) : NEW_LINE INDENT count += 1 NEW_LINE DEDENT DEDENT print ( count , end = ' ▁ ' ) NEW_LINE DEDENT DEDENT if __name__ == " _ _ main _ _ " : NEW_LINE INDENT arr = [ 1 , 1 , 2 , 5 , 2 ] NEW_LINE N = len ( arr ) NEW_LINE Q = 2 NEW_LINE Queries = [ [ 1 , 3 ] , [ 4 , 2 ] ] NEW_LINE longestSubsequence ( N , Q , arr , Queries ) NEW_LINE DEDENT