text: Check if frequency of character in one string is a factor or multiple of frequency of same character in other string | Python3 implementation of above approach ; Function that checks if the frequency of character are a factor or multiple of each other ; map store frequency of each character ; if any frequency is 0 , then continue as condition is satisfied ; if factor or multiple , then condition satisfied ; if condition not satisfied ; Driver code
code: from collections import defaultdict NEW_LINE def multipleOrFactor ( s1 , s2 ) : NEW_LINE INDENT m1 = defaultdict ( lambda : 0 ) NEW_LINE m2 = defaultdict ( lambda : 0 ) NEW_LINE for i in range ( 0 , len ( s1 ) ) : NEW_LINE INDENT m1 [ s1 [ i ] ] += 1 NEW_LINE DEDENT for i in range ( 0 , len ( s2 ) ) : NEW_LINE INDENT m2 [ s2 [ i ] ] += 1 NEW_LINE DEDENT for it in m1 : NEW_LINE INDENT if it not in m2 : NEW_LINE INDENT continue NEW_LINE DEDENT if ( m2 [ it ] % m1 [ it ] == 0 or m1 [ it ] % m2 [ it ] == 0 ) : NEW_LINE INDENT continue NEW_LINE DEDENT else : NEW_LINE INDENT return False NEW_LINE DEDENT DEDENT return True NEW_LINE DEDENT if __name__ == " _ _ main _ _ " : NEW_LINE INDENT s1 = " geeksforgeeks " NEW_LINE s2 = " geeks " NEW_LINE if multipleOrFactor ( s1 , s2 ) : print ( " YES " ) NEW_LINE else : print ( " NO " ) NEW_LINE DEDENT