text: Range Query on array whose each element is XOR of index value and previous element | function return derived formula value . ; finding xor value of range [ y ... x ] ; function to solve query for l and r . ; if l or r is 0. ; finding x is divisible by 2 or not . ; Driver Code
code: def fun ( x ) : NEW_LINE INDENT y = ( x // 4 ) * 4 NEW_LINE ans = 0 NEW_LINE for i in range ( y , x + 1 ) : NEW_LINE INDENT ans ^= i NEW_LINE DEDENT return ans NEW_LINE DEDENT def query ( x ) : NEW_LINE INDENT if ( x == 0 ) : NEW_LINE INDENT return 0 NEW_LINE DEDENT k = ( x + 1 ) // 2 NEW_LINE if x % 2 == 0 : NEW_LINE INDENT return ( ( fun ( k - 1 ) * 2 ) ^ ( k & 1 ) ) NEW_LINE DEDENT else : NEW_LINE INDENT return ( 2 * fun ( k ) ) NEW_LINE DEDENT DEDENT def allQueries ( q , l , r ) : NEW_LINE INDENT for i in range ( q ) : NEW_LINE INDENT print ( query ( r [ i ] ) ^ query ( l [ i ] - 1 ) ) NEW_LINE DEDENT DEDENT q = 3 NEW_LINE l = [ 2 , 2 , 5 ] NEW_LINE r = [ 4 , 8 , 9 ] NEW_LINE allQueries ( q , l , r ) NEW_LINE