text: Floor value Kth root of a number using Recursive Binary Search | Java program for the above approach ; Function to calculate x raised to the power y in O ( logn ) ; Function to find the Kth root of the number N using BS ; If the range is still valid ; Find the mid - value of range ; Base Case ; Condition to check if the left search space is useless ; Driver Code ; Given N and K ; Function Call
code: class GFG { static int power ( int x , int y ) { int temp ; if ( y == 0 ) return 1 ; temp = power ( x , y / 2 ) ; if ( y % 2 == 0 ) return temp * temp ; else return x * temp * temp ; } static int nthRootSearch ( int low , int high , int N , int K ) { if ( low <= high ) { int mid = ( low + high ) / 2 ; if ( ( power ( mid , K ) <= N ) && ( power ( mid + 1 , K ) > N ) ) { return mid ; } else if ( power ( mid , K ) < N ) { return nthRootSearch ( mid + 1 , high , N , K ) ; } else { return nthRootSearch ( low , mid - 1 , N , K ) ; } } return low ; } public static void main ( String s [ ] ) { int N = 16 , K = 4 ; System . out . println ( nthRootSearch ( 0 , N , N , K ) ) ; } }