text: Count of elements to be inserted to make Array sum twice the XOR of Array | Java program to find the count of elements to be inserted to make Array sum twice the XOR of Array ; Function to find the minimum number of elements that need to be inserted such that the sum of the elements of the array is twice the XOR of the array ; Variable to store the Xor of all the elements ; Variable to store the sum of all elements ; Loop to find the Xor and the sum of the array ; If sum = 2 * Xor ; No need to insert more elements ; We insert one more element which is Sum ; We insert two more elements Sum + Xor and Xor . ; Print the number of elements inserted in the array ; Print the elements that are inserted in the array ; Driver code
code: class GFG { static void insert_element ( int a [ ] , int n ) { int Xor = 0 ; int Sum = 0 ; for ( int i = 0 ; i < n ; i ++ ) { Xor ^= a [ i ] ; Sum += a [ i ] ; } if ( Sum == 2 * Xor ) { System . out . println ( "0" ) ; return ; } if ( Xor == 0 ) { System . out . println ( "1" ) ; System . out . println ( Sum ) ; return ; } int num1 = Sum + Xor ; int num2 = Xor ; System . out . print ( "2" ) ; System . out . println ( num1 + " ▁ " + num2 ) ; } public static void main ( String [ ] args ) { int a [ ] = { 1 , 2 , 3 } ; int n = a . length ; insert_element ( a , n ) ; } }