text: Smallest number greater than or equal to X whose sum of digits is divisible by Y | Java program to find the smallest number greater than or equal to X and divisible by Y ; Function that returns the sum of digits of a number ; Initialize variable to store the sum ; Add the last digit of the number ; Remove the last digit from the number ; Function that returns the smallest number greater than or equal to X and divisible by Y ; Initialize result variable ; Loop through numbers greater than equal to X ; Calculate sum of digits ; Check if sum of digits is divisible by Y ; Driver code
code: class GFG { static final int MAXN = 10000000 ; static int sumOfDigits ( int n ) { int sum = 0 ; while ( n > 0 ) { sum += n % 10 ; n /= 10 ; } return sum ; } static int smallestNum ( int X , int Y ) { int res = - 1 ; for ( int i = X ; i < MAXN ; i ++ ) { int sum_of_digit = sumOfDigits ( i ) ; if ( sum_of_digit % Y == 0 ) { res = i ; break ; } } return res ; } public static void main ( String [ ] args ) { int X = 5923 , Y = 13 ; System . out . print ( smallestNum ( X , Y ) ) ; } }