text: Count numbers from a given range that are not divisible by any of the array elements | Java program for the above approach ; Function to find the non - multiples till k ; Stores all unique multiples ; Iterate the array ; For finding duplicates only once ; Inserting all multiples into the set ; Returning only the count of numbers that are not divisible by any of the array elements ; Function to count the total values in the range [ L , R ] ; Count all values in the range using exclusion principle ; Driver code ; Function Call
code: import java . io . * ; import java . util . * ; class GFG { public static int findNonMultiples ( int [ ] arr , int n , int k ) { Set < Integer > multiples = new HashSet < Integer > ( ) ; for ( int i = 0 ; i < n ; ++ i ) { if ( ! multiples . contains ( arr [ i ] ) ) { for ( int j = 1 ; j <= k / arr [ i ] ; j ++ ) { multiples . add ( arr [ i ] * j ) ; } } } return k - multiples . size ( ) ; } public static int countValues ( int [ ] arr , int N , int L , int R ) { return findNonMultiples ( arr , N , R ) - findNonMultiples ( arr , N , L - 1 ) ; } public static void main ( String [ ] args ) { int [ ] arr = { 2 , 3 , 4 , 5 , 6 } ; int N = arr . length ; int L = 1 ; int R = 20 ; System . out . println ( countValues ( arr , N , L , R ) ) ; } }