text: Counting sets of 1 s and 0 s in a binary matrix | Java program to compute number of sets in a binary matrix . ; no of columns ; no of rows ; function to calculate the number of non empty sets of cell ; stores the final answer ; traverses row - wise ; traverses column wise ; at the end subtract n * m as no of single sets have been added twice . ; Driver code
code: class GFG { static final int m = 3 ; static final int n = 2 ; static long countSets ( int a [ ] [ ] ) { long res = 0 ; for ( int i = 0 ; i < n ; i ++ ) { int u = 0 , v = 0 ; for ( int j = 0 ; j < m ; j ++ ) { if ( a [ i ] [ j ] == 1 ) u ++ ; else v ++ ; } res += Math . pow ( 2 , u ) - 1 + Math . pow ( 2 , v ) - 1 ; } for ( int i = 0 ; i < m ; i ++ ) { int u = 0 , v = 0 ; for ( int j = 0 ; j < n ; j ++ ) { if ( a [ j ] [ i ] == 1 ) u ++ ; else v ++ ; } res += Math . pow ( 2 , u ) - 1 + Math . pow ( 2 , v ) - 1 ; } return res - ( n * m ) ; } public static void main ( String [ ] args ) { int a [ ] [ ] = { { 1 , 0 , 1 } , { 0 , 1 , 0 } } ; System . out . print ( countSets ( a ) ) ; } }