text: Remove even frequency characters from the string | Java implementation of the approach ; Function that removes the characters which have even frequencies in the string ; create a map to store the frequency of each character ; to store the new string ; remove the characters which have even frequencies ; if the character has even frequency then skip ; else concatenate the character to the new string ; display the modified string ; Driver code ; remove the characters which have even frequencies
code: import java . util . * ; class GFG { static void solve ( String s ) { HashMap < Character , Integer > m = new HashMap < > ( ) ; for ( int i = 0 ; i < s . length ( ) ; i ++ ) { if ( m . containsKey ( s . charAt ( i ) ) ) m . put ( s . charAt ( i ) , m . get ( s . charAt ( i ) ) + 1 ) ; else m . put ( s . charAt ( i ) , 1 ) ; } String new_string = " " ; for ( int i = 0 ; i < s . length ( ) ; i ++ ) { if ( m . get ( s . charAt ( i ) ) % 2 == 0 ) continue ; new_string = new_string + s . charAt ( i ) ; } System . out . println ( new_string ) ; } public static void main ( String [ ] args ) { String s = " aabbbddeeecc " ; solve ( s ) ; } }