text: Maximum size subset with given sum | A Dynamic Programming solution for subset sum problem + maximal subset value . ; Returns size of maximum sized subset if there is a subset of set [ ] with sun equal to given sum . It returns - 1 if there is no subset with given sum . ; The value of subset [ i ] [ j ] will be true if there is a subset of set [ 0. . j - 1 ] with sum equal to i ; If sum is 0 , then answer is true ; If sum is not 0 and set is empty , then answer is false ; Fill the subset table in bottom up manner ; Driver program to test above function
code: class sumofSub { static int isSubsetSum ( int set [ ] , int n , int sum ) { boolean subset [ ] [ ] = new boolean [ sum + 1 ] [ n + 1 ] ; int count [ ] [ ] = new int [ sum + 1 ] [ n + 1 ] ; for ( int i = 0 ; i <= n ; i ++ ) { subset [ 0 ] [ i ] = true ; count [ 0 ] [ i ] = 0 ; } for ( int i = 1 ; i <= sum ; i ++ ) { subset [ i ] [ 0 ] = false ; count [ i ] [ 0 ] = - 1 ; } for ( int i = 1 ; i <= sum ; i ++ ) { for ( int j = 1 ; j <= n ; j ++ ) { subset [ i ] [ j ] = subset [ i ] [ j - 1 ] ; count [ i ] [ j ] = count [ i ] [ j - 1 ] ; if ( i >= set [ j - 1 ] ) { subset [ i ] [ j ] = subset [ i ] [ j ] || subset [ i - set [ j - 1 ] ] [ j - 1 ] ; if ( subset [ i ] [ j ] ) count [ i ] [ j ] = Math . max ( count [ i ] [ j - 1 ] , count [ i - set [ j - 1 ] ] [ j - 1 ] + 1 ) ; } } } return count [ sum ] [ n ] ; } public static void main ( String args [ ] ) { int set [ ] = { 2 , 3 , 5 , 10 } ; int sum = 20 ; int n = set . length ; System . out . println ( isSubsetSum ( set , n , sum ) ) ; } }