text: Find M such that GCD of M and given number N is maximum | Java program for the above approach ; Function to find the integer M such that gcd ( N , M ) is maximum ; Initialize a variable ; Find all the divisors of N and return the maximum divisor ; Check if i is divisible by N ; Update max_gcd ; Return the maximum value ; Driver Code ; Given Number ; Function Call
code: import java . util . * ; class GFG { static int findMaximumGcd ( int n ) { int max_gcd = 1 ; for ( int i = 1 ; i * i <= n ; i ++ ) { if ( n % i == 0 ) { if ( i > max_gcd ) max_gcd = i ; if ( ( n / i != i ) && ( n / i != n ) && ( ( n / i ) > max_gcd ) ) max_gcd = n / i ; } } return max_gcd ; } public static void main ( String [ ] args ) { int N = 10 ; System . out . print ( findMaximumGcd ( N ) ) ; } }