text: Count the number of pairs ( i , j ) such that either arr [ i ] is divisible by arr [ j ] or arr [ j ] is divisible by arr [ i ] | Java implementation of the approach ; Function to find number of unordered pairs ; Maximum element from the array ; Array to store the frequency of each element ; Stores the number of unordered pairs ; Store the frequency of each element ; Find the number of unordered pairs ; If the number j divisible by ith element is present in the array ; If the ith element of the array has frequency more than one ; Driver code
code: import java . util . Arrays ; class GFG { static int freqPairs ( int arr [ ] , int n ) { int max = Arrays . stream ( arr ) . max ( ) . getAsInt ( ) ; int freq [ ] = new int [ max + 1 ] ; int count = 0 ; for ( int i = 0 ; i < n ; i ++ ) { freq [ arr [ i ] ] ++ ; } for ( int i = 0 ; i < n ; i ++ ) { for ( int j = 2 * arr [ i ] ; j <= max ; j += arr [ i ] ) { if ( freq [ j ] >= 1 ) { count += freq [ j ] ; } } if ( freq [ arr [ i ] ] > 1 ) { count += freq [ arr [ i ] ] - 1 ; freq [ arr [ i ] ] -- ; } } return count ; } public static void main ( String [ ] args ) { int arr [ ] = { 3 , 2 , 4 , 2 , 6 } ; int n = arr . length ; System . out . println ( freqPairs ( arr , n ) ) ; } }