text: Count the number of primes in the prefix sum array of the given array | Java implementation of the approach ; returns the max element ; Function to return the count of primes in the given array ; Find maximum value in the array ; USE SIEVE TO FIND ALL PRIME NUMBERS LESS THAN OR EQUAL TO max_val Create a boolean array " prime [ 0 . . n ] " . A value in prime [ i ] will finally be false if i is Not a prime , else true . ; Remaining part of SIEVE ; If prime [ p ] is not changed , then it is a prime ; Update all multiples of p ; Find all primes in arr [ ] ; Function to generate the prefix array ; Fill the prefix array ; Driver code ; Prefix array of arr [ ] ; Count of primes in the prefix array
code: import java . util . * ; class GFG { static int max_element ( int a [ ] ) { int m = a [ 0 ] ; for ( int i = 0 ; i < a . length ; i ++ ) m = Math . max ( a [ i ] , m ) ; return m ; } static int primeCount ( int arr [ ] , int n ) { int max_val = max_element ( arr ) ; boolean prime [ ] = new boolean [ max_val + 1 ] ; for ( int p = 0 ; p <= max_val ; p ++ ) prime [ p ] = true ; prime [ 0 ] = false ; prime [ 1 ] = false ; for ( int p = 2 ; p * p <= max_val ; p ++ ) { if ( prime [ p ] == true ) { for ( int i = p * 2 ; i <= max_val ; i += p ) prime [ i ] = false ; } } int count = 0 ; for ( int i = 0 ; i < n ; i ++ ) if ( prime [ arr [ i ] ] ) count ++ ; return count ; } static int [ ] getPrefixArray ( int arr [ ] , int n , int pre [ ] ) { pre [ 0 ] = arr [ 0 ] ; for ( int i = 1 ; i < n ; i ++ ) { pre [ i ] = pre [ i - 1 ] + arr [ i ] ; } return pre ; } public static void main ( String args [ ] ) { int arr [ ] = { 1 , 4 , 8 , 4 } ; int n = arr . length ; int pre [ ] = new int [ n ] ; pre = getPrefixArray ( arr , n , pre ) ; System . out . println ( primeCount ( pre , n ) ) ; } }