text: Check if a given value can be reached from another value in a Circular Queue by K | Java program for the above approach ; Function to return GCD of two numbers a and b ; Base Case ; Recursively Find the GCD ; Function to check of B can be reaced from A with a jump of K elements in the circular queue ; Find GCD of N and K ; If A - B is divisible by gcd then print Yes ; Otherwise ; Driver Code ; Function Call
code: import java . util . * ; class solution { static int GCD ( int a , int b ) { if ( b == 0 ) return a ; return GCD ( b , a % b ) ; } static void canReach ( int N , int A , int B , int K ) { int gcd = GCD ( N , K ) ; if ( Math . abs ( A - B ) % gcd == 0 ) { System . out . println ( " Yes " ) ; } else { System . out . println ( " No " ) ; } } public static void main ( String args [ ] ) { int N = 5 , A = 2 , B = 1 , K = 2 ; canReach ( N , A , B , K ) ; } }